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- Question 8, Exercise 1.1
- ight)i}{16+49}\\ &=\dfrac{50-120i}{65}\\ &=\dfrac{10-24i}{13}\\ &=\dfrac{10}{13}-\dfrac{24i}{13}\end{align} =====Question 8(ii)===== Express the $\dfrac{... 4i}\times \dfrac{-5+4i}{-5+4i}\\ &=\dfrac{\left( -10-12 \right)+\left( 8-15 \right)i}{25+16}\\ &=\dfra... ign="right"><btn type="success">[[fsc-part1-kpk:sol:unit01:ex1-1-p8|Question 9 & 10 >]]</btn></text>
- Question 2, Exercise 1.2
- {align} z_1(z_2 z_3)&=(-1+i)\cdot (2-10i)\\ &=(-2+10)+(2+10)i\\ &=8+12i \ldots (3)\end{align} Now, we take \begin{align} z_1 z_2 &=(-1+i)\cdot (3-2i)\\ &... align} (z_1 z_2) z_3&=(-1+5i)\cdot (2-2i)\\ &=(-2+10)+(10+2)i\\ &=8+12i \ldots (4)\end{align} From (3) and (4), we get the required result. ==== Go To ===
- Question 9 & 10, Exercise 1.1
- ====== Question 9 & 10, Exercise 1.1 ====== Solutions of Question 9 & 10 of Exercise 1.1 of Unit 01: Complex Numbers. This i... 3}{25}+\dfrac{16}{25}i\end{align} =====Question 10===== Evalute ${{\left[ {{i}^{18}}+{{\left( \dfr
- Question 7, Exercise 1.2
- }{5+2i} \quad \text{by rationalizing} \\ =&\dfrac{10-6+15i+4i}{25+4}\\ =&\dfrac{4+19i}{29}\\ =&\dfrac{... \\ =&\dfrac{-3-12+4i-9i}{1+9}\\ =&\dfrac{-15-5i}{10}\\ =&\dfrac{-3}{2}-\dfrac{1}{2}i\end{align} Rea... mes \dfrac{-5-12i}{-5-12i}\\ =&\dfrac{45-480+200i+108i}{25+144}\\ =&\dfrac{-435+308i}{169}\\ =&\dfrac{
- Question 2, Exercise 1.3
- \downarrow & -2 & 4 & -20 \\ \hline & 1 & -2 & 10 & 0 \\ \end{array}$$ This gives \begin{align} P(z)&=(z+2)(z^2-2z+10)\\ &=(z+2)\left(z^2-2z+1+9\right)\\ &=(z+2)\left
- Question 11, Exercise 1.1
- align="left"><btn type="primary">[[fsc-part1-kpk:sol:unit01:ex1-1-p8|< Question 9, 10]]</btn></text>