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- Exercise 2.6 (Solutions) @matric:9th_science:unit_02
- dot\sqrt{-3} = 3$\\ (ii) $i^{73}=-i$\\ (iii) $i^{10} = -1$\\ (iv) Complex conjugate of $(-6i + i^2) ... (ii) $$\begin{array}{cl} 2(5+4i)-3(7+4i) &= 10+8i-21-12i\\ &= 10-21+8i-12i\\ &= -11-4i \end{array}$$ (iii) $$\begin{array}{cl} -(-3+5i)-(4+... = 2(3-2i)-2i(3-2i)\\ &= 6-4i-6i+4i^2\\ &= 6-10i+4(-1)\\ &= 6-4-10i\\ &= 2-10i \end{array}$
- Exercise 6.1
- ns.\\ (i) $39x^7y^3z$ and $91x^5y^6 z^7$ \\ (ii) $102xy^2z$, $85x^2yz$ and $187xyz^2$ \\ **Solution:*... mes x^5 y^6 z^7$\\ H.C.F = $13 x^5y^3z$ \\ (ii) $102xy^2z=2\times 3\times 17 xy^2z$\\ $85x^2yz=3\tim... ization.\\ (i) $39x^7y^3z$, $91x^5y^6z^7$ \\ (ii)$102xy^2z$, $85x^2yz$ , $187xyz^2$ **Solution:**\\ ... =273 x^7y^6z^7 \end{align}$ (ii) $\begin{align} 102xy^2z &=2 \times 3 \times 17 xyyz\end{align}$\\ $
- Exercise 2.1 (Solutions) @matric:9th_science:unit_02
- )$$ Only one digit 5 is being repeated, multiply 10 on both sides $$10x = (0.5555.....) \times 10$$ $$10x = 5.5555..... \qquad (2)$$ Subtract (1) from (2), we get $$9x = 5$$ $$\therefore \,\, x = \
- Review exercise
- pe="radio"> A. $5 x^2 y^2$ | B. $20 x^3 y^3$| C. $100 x^5 y^5$ | D. $5 xy$</question> </quizlib> (iii... nd{align}$\\ $\begin{align}4x^2-20x+25 &= 4x^2-10x-10x+25\\&=2x(2x-5)-5(2x-5)\\&= (2x-5)(2x-5)\end{align}$\\ $\begin{align} L.C.M. &= 3(2x+5)(2x-5)(3... ization.\\ $\left(x^2+\frac{1}{x^2}\right)+10\left(x+\frac{1}{x}\right)+27, (x \neq 0)$\\
- Exercise 2.4 (Solutions) @matric:9th_science:unit_02
- ^{{-1}\times\frac{1}{2}}}\\ &= \frac{3^{\frac{-10}{3}}2^{-1}}{14^{-1}}\\ &= \frac{3^\frac{-10}{3}2^{-1}}{2^{-1}\times7^{-1}}\\ &= \frac{3^{\frac{-10}{3}}}{7^{-1}}\\ &= \frac{7}{3^{\frac{10}{3}}}\\ &= \frac{7}{3^{(9)\times\frac{1}{3}}\times3^\fr
- Exercise 6.2
- frac{(x-2)^2}{(x-3)^2}\end{align}$ ====Question 10:==== $\frac{x^3-8}{x^2-4} \times \frac{x^2+6x+8}