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  • Unit 11: Parallelograms and Triangles
  • Exercise 11.1 (Solutions)

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Exercise 2.6 (Solutions) @matric:9th_science:unit_02
19 Hits, Last modified: 5 months ago
(vi) If $(a-1)-(b+3)i = 5+8i$, then a = 6 & b = -11\\ (vii) Product of complex number and its conjuga... &= 10+8i-21-12i\\ &= 10-21+8i-12i\\ &= -11-4i \end{array}$$ (iii) $$\begin{array}{cl} -(-3+... ac{-4}{20}-\frac{22i}{20}\\ &=\frac{-1}{5}-\frac{11i}{10}\\ * (a) \overline{z} = \frac{-1}{5} +\frac{11i}{10}\\ * (b) z + \overline{z}\\ &= (\frac{
Unit 11: Parallelograms and Triangles
14 Hits, Last modified: 5 months ago
====== Unit 11: Parallelograms and Triangles ====== On this page notes of Unit 11 of Mathematics 9 written by Dr. Karamat H. Dar an... fan-ul-Haq are given. {{ :matric:9th_science:unit-11-9th-science-ptb.jpg?nolink|Unit 08: Linear Graph ... ype="success" icon="fa fa-download"> * Exercise 11.1 | VIEW [[:matric:9th_science:unit11:11-1|View O
Exercise 11.1 (Solutions) @matric:9th_science:unit11
6 Hits, Last modified: 5 months ago
====== Exercise 11.1 (Solutions) ====== On this page solutions of Exercise of Unit 11: Parallelograms and Triangles of Mathematics 9 wr... s.** **Solution:**\\ {{ :matric:9th_science:unit11:ex11-1-9th-science-ptb-q-1.svg?nolink |Picture for Question 1}} In a parallelogram $ABCD$, $m\angle
Exercise 6.3
4 Hits, Last modified: 5 months ago
3)(x^2+5x+6)$ \\ (ix) $(x^2+8x+7)(2x^2-x-3)(2X^2+11x-21)$\\ (i) $4x^2-12xy +9y^2$\\ **Solution:**... \end{align}$\\ (ix) $(x^2+8x+7)(2x^2-x-3)(2X^2+11x-21)$\\ **Solution:**\\ $\begin{align}(x^2+8x+7)(2x^2-x-3)(2X^2+11x-21)&= (x^2+x+7x+7)(2x^2-3x+2x-3)(2x^2+14x-3x-21)... $\begin{align} \sqrt{(x^2+8x+7)(2x^2-x-3)(2X^2+11x-21)}&= \pm (x+1)^2(x+7)^2(2x-3)^2\end{align}$\\
Exercise 6.1
3 Hits, Last modified: 5 months ago
2z$\\ $85x^2yz=3\times 17 x^2 y z$\\ $187xyz^2 = 11\times 17 xyz^2$\\ H.C.F= $17 xyz$ ====Question 2... s 17 xxyz\end{align}$\\ $\begin{align} 187xyz^2 &=11 \times 17 xyzz\end{align}$\\ $\begin{align} L.C.M.&= (17xyz)(2 \times 5 \times 11xyz)\\ &=5610 x^2y^2z^2\end{align}$ ====Question
Exercise 6.2
1 Hits, Last modified: 5 months ago
+2x+4)(x+4)}{(x-1)^2}\end{align}$ ====Question 11:==== $\frac{x^4-8x}{2x^2+5x-3} \times \frac{2x-1
Exercise 2.1 (Solutions) @matric:9th_science:unit_02
1 Hits, Last modified: 5 months ago
* (i) o.68 * (ii) 4.75 * (iii) 7.125 * (iv) 11.3889 * (v) 0.625 * (vi) .65789 ====Question