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Exercise 2.6 (Solutions)

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(i^2)^{\times8}-6(i^2)^{\times9}(i)+4(i^2)^{\times12}(i)\\ &= -2 -6i+3+6i+4i\\ &= 1+4i \end{ar... 9i-6i^2\\ &= 6-5i-6(-1)\\ &= 6+6-5i\\ &= 12-5i \end{array}$$ ====Question 4==== * Simplify ... =\frac{8-16i-6i+12i^2}{4-16(-1)}\\ &=\frac{8-22i+12(-1)}{4+16}\\ &=\frac{-4-22i}{20}\\ &=\frac{-4}{... -(\frac{11i}{10})^2\\ &= \frac{1}{25} - \frac{121i^2}{100}\\ &= \frac{1}{25} + \frac{121}{100}

Exercise 2.4 (Solutions)

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ft(-3\right)}}\\ &=\frac{y^{-6}}{x^{-18} z^{-12}}\\ &=\frac{x^{18} z^{12}}{y^6} \end{array}$$ (iv) $$\begin{array}{cl} \frac{\left(81\right)^n.

Exercise 2.5 (Solutions)

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(ii) $i^{50}$ (iii) $i^{12}$ ... &= -1 \end{array}$$ (iii) $$\begin{array}{cl} i^{12} &= (i^2 )^6\\ &= {-1}^6\\ &= 1 \en