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- Exercise 2.6 (Solutions)
- \begin{array}{cl} 2(5+4i)-3(7+4i) &= 10+8i-21-12i\\ &= 10-21+8i-12i\\ &= -11-4i \end{array}$$ (iii) $$\begin{array}{cl} -(-3+5i)-(4+9i) ... 9i-6i^2\\ &= 6-5i-6(-1)\\ &= 6+6-5i\\ &= 12-5i \end{array}$$ ====Question 4==== * Simplify ... c{2(4+i)+3i(4+i)}{(4-i)(4+i)}\\ &= \frac{8+2i+12i+3i^2}{16-i^2}\\ &= \frac{8+14i-3}{16+1}\\
- Exercise 2.3 (Solutions)
- e following radical expression * (i) $\sqrt[3]{-125}$ * (ii) $\sqrt[4]{32}$ * (iii) $\sqrt[5]{\f... luton**\\ (i) $$\begin{array}{cl} \sqrt[3]{-125} &= \sqrt[3]{-5^3}\\ & = {-5}^{3\times\frac{1}{3
- Exercise 2.4 (Solutions)
- ft(-3\right)}}\\ &=\frac{y^{-6}}{x^{-18} z^{-12}}\\ &=\frac{x^{18} z^{12}}{y^6} \end{array}$$ (iv) $$\begin{array}{cl} \frac{\left(81\right)^n.
- Exercise 2.5 (Solutions)
- (ii) $i^{50}$ (iii) $i^{12}$ ... &= -1 \end{array}$$ (iii) $$\begin{array}{cl} i^{12} &= (i^2 )^6\\ &= {-1}^6\\ &= 1 \en
- Exercise 2.1 (Solutions)
- ation**\\ * (i) o.68 * (ii) 4.75 * (iii) 7.125 * (iv) 11.3889 * (v) 0.625 * (vi) .65789