====== Chapter 14: Solutions of Trigonometric Equation ======
{{ :fsc:fsc_part_1_solutions:fsc-1-chap-14-ptb.jpg?nolink|Chapter 14: Solutions of Trigonometric Equation}}
Notes (Solutions) of Chapter 14: Solutions of Trigonometric Equation, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

====Contents & summary====
  * Introduction
  * Solution of General Trigonometric Equations
    * Exercise 14

====Some important formulas====
  * ${\sin ^{ - 1}}A + {\sin ^{ - 1}}B = {\sin ^{ - 1}}\left( {A\sqrt {1 - {B^2}}  + B\sqrt {1 - {A^2}} } \right)$
  * ${\sin ^{ - 1}}A - {\sin ^{ - 1}}B = {\sin ^{ - 1}}\left( {A\sqrt {1 - {B^2}}  - B\sqrt {1 - {A^2}} } \right)$
  * ${\cos ^{ - 1}}A + {\cos ^{ - 1}}B = {\cos ^{ - 1}}\left( {AB - \sqrt {\left( {1 - {A^2}} \right)\left( {1 - {B^2}} \right)} } \right)$
  * ${\cos ^{ - 1}}A - {\cos ^{ - 1}}B = {\cos ^{ - 1}}\left( {AB + \sqrt {\left( {1 - {A^2}} \right)\left( {1 - {B^2}} \right)} } \right)$
  * ${\tan ^{ - 1}}A + {\tan ^{ - 1}}B = {\tan ^{ - 1}}\frac{{A + B}}{{1 - AB}}$
  * ${\tan ^{ - 1}}A - {\tan ^{ - 1}}B = {\tan ^{ - 1}}\frac{{A - B}}{{1 + AB}}$
====Solutions====
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  * Exercise 14   | [[vfsc1>ch14:view&cp=01&p=13&ch=14&fp=Ex-14-FSC-part1-ver3|View Online]]     | {{ :fsc:fsc_part_1_solutions:ex-14-fsc-part1-ver3.pdf |Download PDF}} UPD
 
  * Exercise 14 by Prof Amir | [[vfsc1>ch14:view&cp=01&p=07&ch=14&fp=Ex-14-FSc-part1-Prof-Amir|View Online]] | {{ :fsc:fsc_part_1_solutions:ex-14-fsc-part1-prof-amir.pdf |Download PDF}} 
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====Short Questions====
The following short questions was send by Mr. [[people:akhtar]].
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  * Chapter 14 | [[aafsc1>short-question-ch14-fsc-part1-akhtar-abbas|View Online]] | {{:fsc:fsc_part_1_mcqs:short-question-ch14-fsc-part1-akhtar-abbas.pdf|Download PDF}} NEW
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====Here is a previous chapter====
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