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- Question 20 and 21, Exercise 4.4
- We have given $a_1=3$ and $a_5=48$. Assume $r$ be common difference, then by general formula for nt... We have given $a_1=3$ and $a_5=48$. Assume $r$ be common difference, then by general formula for nt... n. ** We have $a_1=1$ and $a_4=8$. Assume $r$ to be the common ratio. Then, by the general formula fo
- Question 11 and 12, Exercise 4.2
- pattern is consistent, how many plants will there be in the eighth row? ** Solution. ** Given sequen... d{align*} Hence $a_8=7$, that is, $7$ plants will be there in the 8th row. GOOD ====Go to ==== <text
- Question 16 and 17, Exercise 4.2
- 5$ and $17$. ** Solution. ** Let $A_1$ and $A_2$ be two arithmetic means between $5$ and $17$.\\ Then... 17$. ** Solution. ** Let $A_1$, $A_2$ and $A_3$ be thre arithmetic means between $2$ and $-18$.\\ Th
- Question 22 and 23, Exercise 4.4
- ave $a_1=8$ and $a_6=\frac{1}{4}$. Assume $r$ to be the common ratio. Then, by the general formula fo... ** We have $a_1=3$ and $a_3=75$. Assume $r$ to be the common ratio. Then, by the general formula fo
- Question 24 and 25, Exercise 4.4
- ** We have $a_1=5$ and $a_5=80$. Assume $r$ to be the common ratio. \\ Then, by the general formula... We have $a_1=7$ and $a_6=112$.\\ Assume $r$ to be the common ratio. \\ Then, by the general formul
- Question 26 and 27, Exercise 4.4
- ing by $3 \%$ each year. What will the population be in $15^{\text {th }}$ years? ** Solution. ** He... ign*} Hence, the population after $15$ years will be $155,797$. GOOD ====Go to ==== <text align=
- Question 9 and 10, Exercise 4.5
- }$, $a_6 = \frac{3}{32}$ and $n = 6$.\\ Let $a_1$ be first term and $r$ be common ratio, then general term of geometric series is given as $$a_n=a_1 r^{n-
- Question 15, Exercise 4.5
- a rubber ball is dropped into a $30 ft$ hollow tube that is calibrated so that the scientist can meas... times \frac{2}{5} = \frac{48}{25} ft$ \\ Let $D$ be the total distance covered by the ball. Then $$D=
- Question 16, Exercise 4.5
- 90\%$ as far as in the previous minute, what will be its maximum altitude if it is allowed to rise wit... {align} Hence maximum altitude of the baloon will be $800 ft$. GOOD ====Go to ==== <text align="le
- Question 27 and 28, Exercise 4.7
- c{7}{3}+\frac{9}{9}+\frac{11}{27}+\ldots$$ It can be written as: $$ 5\times 1+7\times\frac{1}{3}+9\ti... \frac{3}{25} + \frac{4}{125} + \ldots \] It can be rewritten as:\\ \[ 1 \times 1 + 2 \times \frac{1}
- Question 29 and 30, Exercise 4.7
- :\\ \[ 1 + 4x + 7x^2 + 10x^3 + \ldots \] It can be rewritten as:\\ \[ 1 \times 1 + 4 \times x + 7 \t... ac{9}{100} + \frac{12}{1000} + \ldots \] It can be rewritten as:\\ \[ 3 \times 1 + 6 \times \frac{1}
- Question 21 and 22, Exercise 4.1
- 6}, \sqrt{8}, \sqrt{10}, \ldots$$ The terms can be rewritten as: \begin{align*} &a_1=\sqrt{2 \cdot 1
- Question 14 and 15, Exercise 4.2
- answer given at the end of the book, question can be as follows: * Find '$b$' if $25$ is A.M between
- Question 23 and 24, Exercise 4.3
- OD m( =====Question 24===== How many poles will be in a pile of telephone poles if there are 50 in t
- Question 30, Exercise 4.4
- Then the total rise in river after five days will be $$S_n=a_1+a_2+a_3+a_4+a_5.$$ </callout> ====Go t