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- Question 5, Exercise 2.6 @math-11-nbf:sol:unit02
- x_{3}=10$\\ ** Solution. ** The above system may be written as $A X=B$; where, \begin{align*} &A = \b... x_{3}=-1$\\ ** Solution. ** The above system maybe written as $AX = B $, where: \begin{align*} &A = ... 3 x_{3}=5$\\ ** Solution. ** The above system maybe written as $AX = B $, where: \begin{align*} &A =
- Question 20 and 21, Exercise 4.4 @math-11-nbf:sol:unit04
- We have given $a_1=3$ and $a_5=48$. Assume $r$ be common difference, then by general formula for nt... We have given $a_1=3$ and $a_5=48$. Assume $r$ be common difference, then by general formula for nt... n. ** We have $a_1=1$ and $a_4=8$. Assume $r$ to be the common ratio. Then, by the general formula fo
- Question 9, Exercise 1.4 @math-11-nbf:sol:unit01
- at maximum distance from mean position as it can be seen under microscope at this point. Calculate th... at maximum distance from mean position as it can be seen under microscope at this point. If $x=2+3 i$
- Question 11 and 12, Exercise 4.2 @math-11-nbf:sol:unit04
- pattern is consistent, how many plants will there be in the eighth row? ** Solution. ** Given sequen... d{align*} Hence $a_8=7$, that is, $7$ plants will be there in the 8th row. GOOD ====Go to ==== <text
- Question 16 and 17, Exercise 4.2 @math-11-nbf:sol:unit04
- 5$ and $17$. ** Solution. ** Let $A_1$ and $A_2$ be two arithmetic means between $5$ and $17$.\\ Then... 17$. ** Solution. ** Let $A_1$, $A_2$ and $A_3$ be thre arithmetic means between $2$ and $-18$.\\ Th
- Question 22 and 23, Exercise 4.4 @math-11-nbf:sol:unit04
- ave $a_1=8$ and $a_6=\frac{1}{4}$. Assume $r$ to be the common ratio. Then, by the general formula fo... ** We have $a_1=3$ and $a_3=75$. Assume $r$ to be the common ratio. Then, by the general formula fo
- Question 24 and 25, Exercise 4.4 @math-11-nbf:sol:unit04
- ** We have $a_1=5$ and $a_5=80$. Assume $r$ to be the common ratio. \\ Then, by the general formula... We have $a_1=7$ and $a_6=112$.\\ Assume $r$ to be the common ratio. \\ Then, by the general formul
- Question 26 and 27, Exercise 4.4 @math-11-nbf:sol:unit04
- ing by $3 \%$ each year. What will the population be in $15^{\text {th }}$ years? ** Solution. ** He... ign*} Hence, the population after $15$ years will be $155,797$. GOOD ====Go to ==== <text align=
- Question 9 and 10, Exercise 4.5 @math-11-nbf:sol:unit04
- }$, $a_6 = \frac{3}{32}$ and $n = 6$.\\ Let $a_1$ be first term and $r$ be common ratio, then general term of geometric series is given as $$a_n=a_1 r^{n-
- Question 15, Exercise 4.5 @math-11-nbf:sol:unit04
- a rubber ball is dropped into a $30 ft$ hollow tube that is calibrated so that the scientist can meas... times \frac{2}{5} = \frac{48}{25} ft$ \\ Let $D$ be the total distance covered by the ball. Then $$D=
- Question 16, Exercise 4.5 @math-11-nbf:sol:unit04
- 90\%$ as far as in the previous minute, what will be its maximum altitude if it is allowed to rise wit... {align} Hence maximum altitude of the baloon will be $800 ft$. GOOD ====Go to ==== <text align="le
- Question 27 and 28, Exercise 4.7 @math-11-nbf:sol:unit04
- c{7}{3}+\frac{9}{9}+\frac{11}{27}+\ldots$$ It can be written as: $$ 5\times 1+7\times\frac{1}{3}+9\ti... \frac{3}{25} + \frac{4}{125} + \ldots \] It can be rewritten as:\\ \[ 1 \times 1 + 2 \times \frac{1}
- Question 29 and 30, Exercise 4.7 @math-11-nbf:sol:unit04
- :\\ \[ 1 + 4x + 7x^2 + 10x^3 + \ldots \] It can be rewritten as:\\ \[ 1 \times 1 + 4 \times x + 7 \t... ac{9}{100} + \frac{12}{1000} + \ldots \] It can be rewritten as:\\ \[ 3 \times 1 + 6 \times \frac{1}
- Question 6 and 7, Exercise 5.1 @math-11-nbf:sol:unit05
- Solution. ** Suppose $p(x)=x^3-7x+6$.\\ $1$ will be zero of $p(x)$ if $p(1)=0$. Thus \begin{align*} p... $1$ is the zero of p(x). \\ Similarly, $-2$ will be zero of $p(x)$ if f $p(-2)=0$. \begin{align*} p(-
- Question 1, Review Exercise @math-11-nbf:sol:unit05
- }-2 x^{2}+5$ is divided by $x+1$, then $x+1$ will be its:\\ * (a) divisor as well as factor\\ ... $x^{3}+5 x^{2}-4 x+k$, then the value of $k$ will be:\\ * (a) $-4$ * (b) $-20$ * %%(c)%%