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Exercise 2.8 (Solutions) @fsc-part1-ptb:sol:ch02

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{{a}^{-1}}*a \right)*x={{a}^{-1}}*b\,\,\,\, \text{by associative law}\\ \Rightarrow \,\,\,\,& e*x={{a}^{-1}}*b \,\,\,\,\text{by inverse law.}\\ \Rightarrow \,\,\,\,& x={{a}^{-1}}*b\,\,\,\, \text{by identity law.}\end{align} And for \begin{align}... ( a*{{a}^{-1}} \right)=b*{{a}^{-1}}\,\,\,\, \text{by associative law}\\ \Rightarrow \,\,\,\, & x*e=b*{

Exercise 1.1 (Solutions) @fsc-part1-ptb:sol:ch01

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col sm="6"> <panel> **Question 6(i)** Simplify by justifying each step: $$\frac{4+16x}{4}$$ **Sol... }$ <panel></panel> **Question 6(ii)** Simplify by justifying each step: $$\frac{\frac{1}{4}+\frac{... } <panel></panel> **Question 6(iii)** Simplify by justifying each step: $$\frac{\frac{a}{b}+\frac{c... n} <panel></panel> **Question 6(iv)** Simplify by justifying each step: $$\frac{\frac{1}{a}+\frac{1