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Question 8 and 9, Exercise 5.1
2 Hits, Last modified: 5 months ago
.e. $x+3=0$ or $2x+1=0$ $\implies$ $x=-3$ or $x=-\dfrac{1}{2}$. Hence $2$, $3$ and $-\dfrac{1}{2}$ are the roots of given polynomial. GOOD =====Question 9==
Question 7 and 8, Exercise 5.2
1 Hits, Last modified: 5 months ago
===== Factorize $2 x^{3}-15 x^{2}+27 x-10$ if ' $\dfrac{1}{2}$ ' is one of its zero. ** Solution. ** Us
Question 5, Exercise 5.3
1 Hits, Last modified: 5 months ago
= $3x+4$ Now Length of side of square $ABFG$ = $\dfrac{1}{2}(2 x+8)$ = $x+4$ Area of square $ABFG$ = (x