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- Chapter 06: Sequences and Series @fsc:fsc_part_1_solutions
- ign}l=a_1+(p-1)d,\\ m=a_1+(q-1)d,\\ n=a_1+(r-1)d.\end{align}$$ Now $$\begin{align}L.H.S &= l(q-r)+m(r-... )dr+(r-q)dp\\ &=[pq-qr+qr-pr+pr-pq]d=(0)d=0=R.H.S\end{align}$$ **Exercise 6.4⇒ Question 3(ii)** An eq
- MCQs with key @fsc:fsc_part_2_mcqs
- bola * The locus of the revolving line with one end fixed and other end on the circumference of the circle is called * (A) a sphere * (B) a circle
- Unit 02: Differentiation @fsc:fsc_part_2_solutions
- \frac{x-1-x-1}{(x-1)^2}\\ &= \frac{-2}{(x-1)^2} \end{aligned} $$ ===Method 2=== By converting improper... t)\\ &= 0-2(x-1)^{-2}(1)\\ &= \frac{-2}{(x-1)^2} \end{aligned} $$ This was a simple example but try it
- Chap 04: Formulas Introduction to Analytics Geometry
- e Equation A PDF file can be downloaded from the end of the page. {{gview 700px noreference> :fsc:ch
- FSc Part 1 (KPK Boards)
- he notation $^nC_r=\left(\begin{smallmatrix}n\\ r\end{smallmatrix} \right)=\frac{n!}{r!(n-r)!}$, its de
- FSc-I Mathematics KPK: View Online @fsc:kpk-fsc-part1-km
- y [[:people:khalid]]. Link to PDF is given at the end of preview. {{include>fsc-part1-viewer-kpk-km.ph
- FSc-II Mathematics KPK: View Online @fsc:kpk-fsc-part2-km
- y [[:people:khalid]]. Link to PDF is given at the end of preview. {{include>fsc-part2-viewer-kpk-km.ph