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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.8

Solutions of Question 11 and 12 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=1}^{n} \frac{1}{k(k+2)}$$T_k$$k$\begin{align*}
T_k &amp;= \frac{1}{k(k+2)}.
\end{align*}\begin{align*}
\frac{1}{k(k+2)} = \frac{A}{k} + \frac{B}{k+2} \ldots (1)
\end{align*}$k(k+2)$\begin{align*}
	1 = A(k+2) + Bk \ldots (2)
\end{…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 20 and 21, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 20 and 21, Exercise 4.4

Solutions of Question 20 and 21 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$3 , \_\_\_ , \_\_\_ , \_\_\_ , 48$$$a_1=3$$a_5=48$$r$$$
a_n=ar^{n-1}.
$$\begin{align*}
&amp;a_5=a_1 r^4 \\
\implies &amp; 48=3r^4 \\
\implies &amp; r^4 = 16 \\
\implies &amp; r^4 = 2^4 \\
\implies &amp; r = 2.
\end{align*}\begin{align*}
&amp; a_2=a_1 r= (3…</description>
    </item>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 20, 21 and 22, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 20, 21 and 22, Exercise 4.3

Solutions of Question 20, 21 and 22 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=7$$a_{n}=139$$S_{n}=876$$a_{1}=7$$a_{n}=139$$S_{n}=876$$n$$d$\begin{align}
&amp;S_n=\frac{n}{2}[a_1+a_n]\\
\implies &amp; 876=\frac{n}{2}[7+139]\\
\implies &amp; 1752=146n\\
\implies &amp; n=\frac{1752}{146}=12.
\end{align}\begin{align…</description>
    </item>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 22 and 23, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 22 and 23, Exercise 4.4

Solutions of Question 22 and 23 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$8 , \_\_\_, \_\_\_, \_\_\_, \_\_\_, \dfrac{1}{4}$$$a_1=8$$a_6=\frac{1}{4}$$r$$n$$a_n = a_1 r^{n-1}.$\begin{align*}
a_6 &amp;= a_1 r^5 \\
\implies \frac{1}{4} &amp;= 8 \cdot r^5 \\
\implies r^5 &amp;= \frac{1}{4 \cdot 8} \\
\implies r^5 &amp;= \frac…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 24 and 25, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p12?rev=1737476039&amp;do=diff</link>
        <description>Question 24 and 25, Exercise 4.4

Solutions of Question 24 and 25 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$5 , \_\_\_, \_\_\_, \_\_\_, 80$$$a_1=5$$a_5=80$$r$$n$$$a_n = a_1 r^{n-1}.$$\begin{align*}
a_5 &amp;= a_1 r^4 \\
\implies 80 &amp;= 5 \cdot r^4 \\
\implies r^4 &amp;= \frac{80}{5} \\
\implies r^4 &amp;= 16 \\
\implies r &amp;= 2.
\end{align*}\begin{alig…</description>
    </item>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 14, Exercise 4.5

Solutions of Question 14 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $0.444...$$$0.444... = 0.4+0.04+0.004+...$$$a_1=0.4$$r=\frac{0.04}{0.4}=0.1$$|r|=0.1 &lt; 1$\begin{align*}
S-\infty &amp; = \frac{a_1}{1-r} \\
&amp; = \frac{0.4}{1.0.1} = \frac{0.4}{0.9} \\
&amp; = \frac{4}{9}.
\end{align*}$S_{\infty} =\dfrac{4}{9}$$9.99999 ...$$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.8

Solutions of Question 7 and 8 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$$\frac{1}{1 \times 4}+\frac{1}{4 \times 7}+\frac{1}{7 \times 10}+\ldots$$$$\frac{1}{1 \times 4}+\frac{1}{4 \times 7}+\frac{1}{7 \times 10}+\dots$$$T_k$\begin{align*}
T_k &amp;=\frac{1}{(3k-2)(3k+1)}.
\end{align*}\begin{align*}
\frac{1}{(3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 4.2

Solutions of Question 1 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=4, d=3$$a_1= 4$$d=3$$$a_n = a_1 + (n - 1)d.$$\begin{align*}
a_2&amp;=4+(2-1)3=4+3=7\\
a_3 &amp;= 4+ (3-1) 3 = 4 + 6 = 10\\
a_4&amp;=4+(4-1)3=4+9=13
\end{align*}$a_1=4$$a_2=7$$a_3=10$$a_4=13$$a_1=7$$d=5$$a_1= 7$$d=5$$$a_n = a_1 + (n - 1)d.$$\begin{align*}
…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 4.2

Solutions of Question 2 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $5,9,13, \ldots$$$5, 9, 13, \ldots $$$a_1=5$$d=9-5=4$$$a_n=a_1+(n-1)d.$$\begin{align*}
a_4 &amp;=5+(4-1)(4)=5+12=17\\
a_5 &amp;=5+(5-1)(4)=5+16=21\\
a_6 &amp;=5+(6-1)(4)=5+20=25
\end{align*}$17$$21$$25$$11,14,17, \ldots$$$11, 14, 17, \ldots$$$a_1=11$$d=14-11=3$$…</description>
    </item>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.2

Solutions of Question 9 and 10 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1}{a}, b, \dfrac{1}{c}$$\dfrac{a-c}{2 a c}$$\dfrac{1}{a}, b, \dfrac{1}{c}$\begin{align*}
d&amp;=b-\frac{1}{a}\cdots (i)\\
\end{align*}\begin{align*}
d&amp;=\frac{1}{c}-b \cdots (ii)
\end{align*}\begin{align*}
b-\frac{1}{a}&amp;=\frac{1}{c}-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p11?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 23 and 24, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 23 and 24, Exercise 4.3

Solutions of Question 23 and 24 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$ 14+16+18+...+a_{25}.$$$a_1=14$$d=16-14=2$$n=25$$a_25$$S_25$\begin{align}
a_n&amp;=a_1+(n-1)d\\
\implies a_{25}&amp;= 14+(25-1)(2)\\
&amp;=62.
\end{align}\begin{align}
S_n&amp;=\frac{n}{2}[a_1+a_n]\\
\implies S_{25}&amp; =\frac{25}{2}[14+62]\\
&amp; =25 \t…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p12?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 25 and 26, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p12?rev=1737476039&amp;do=diff</link>
        <description>Question 25 and 26, Exercise 4.3

Solutions of Question 25 and 26 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$ 6000+70,000+...+a_{20}.$$$a_1=6,000$$d=70,000-6,000=64,000$$n=20$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d]\\
\implies S_{20}&amp; =\frac{20}{2}[2(6,000)+(20-1)(64,000)]\\
&amp; =10 \times [12,000+1,216,000]\\
&amp; =12,280,000.
\end{ali…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p14?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 28 and 29, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p14?rev=1737476039&amp;do=diff</link>
        <description>Question 28 and 29, Exercise 4.4

Solutions of Question 28 and 29 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $=a_1= 1$$= a_2 = 2$$= a_3 = 2(2)=4$$= a_7$$$
1+2+4+...+a_7
$$$a_1=1$$r=2$$n=7$$$
S_n=\frac{a_1\left(1-r^n \right)}{1-r}, \quad r\neq 1.
$$\begin{align*}
S_6&amp;=\frac{(1)\left(1-2^7 \right)}{1-2} \\
&amp;=\frac{1-128}{-2}\\
&amp;=127
\end{align…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p1?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.8

Solutions of Question 1 and 2 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3+7+13+21+\ldots$$n$$$ S_{n}=3+7+13+21+31+\ldots +T_{n} $$$$ S_{n}=3+7+13+21+\ldots +T_{n-1}+T_{n}.$$\begin{align*}
S_{n}-S_{n}&amp; =3+7+13+21+31+\ldots +T_{n}  \\
&amp; -\left(3+7+13+21+\ldots +T_{n-1}+T_{n}\right)
\end{align*}\begin{align*}
\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.8

Solutions of Question 3 and 4 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $1+4+13+40+121+ \ldots$$n$$$ S_{n}=1+4+13+40+121+\ldots +T_{n} $$$$ S_{n}=1+4+13+40+\ldots +T_{n-1}+T_{n}. $$\begin{align*}
	S_{n}-S_{n}&amp; =1+4+13+40+121+\ldots +T_{n}  \\
	&amp; -\left(1+4+13+40+\ldots +T_{n-1}+T_{n}\right)
\end{align*}\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.8

Solutions of Question 5 and 6 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3+4+6+10+18+34+66+\dots$$n$$$ S_{n}=3+4+6+10+18+\ldots +T_{n} $$$$ S_{n}=3+4+6+10+\ldots +T_{n-1}+T_{n}. $$\begin{align*}
S_{n}-S_{n}&amp; =3+4+6+10+18+\ldots +T_{n}  \\
&amp; -\left(3+4+6+10+\ldots +T_{n-1}+T_{n}\right)
\end{align*}\begin{align…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 17, 18 and 19, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 17, 18 and 19, Exercise 4.3

Solutions of Question 17, 18 and 19 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $6+12+18+\ldots+96$$$6+12+18+\ldots+96.$$$a_{1}=6$$d=12-6=6$$a_{n}=96$$n=?$\begin{align} 
&amp; a_n=a_1+(n-1)d \\
\implies &amp; 96=6+(n-1)(6) \\
\implies &amp; 96=6+6n-6 \\
\implies &amp; 6n=96 \\
\implies &amp;  n = 24.
\end{align}\begin{align}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, 12 and 13, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11, 12 and 13, Exercise 4.5

Solutions of Question 11, 12 and 13 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}$$S_{n}=244, r=-3, n=5$$S_{n}=244$$r=-3$$n=5$$$ S_n =\frac{a_1(1-r^n)}{1-r}, \quad r\neq 1.$$\begin{align*}
&amp; 244=\frac{a_1(1-(-3)^5)}{1-(-3)} \\
\implies &amp; 244=\frac{a_1(1+243)}{4} \\
\implies &amp; 976=244a_1\\
\implies &amp; …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p11?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 21 and 22, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p11?rev=1737476040&amp;do=diff</link>
        <description>Question 21 and 22, Exercise 4.7

Solutions of Question 21 and 22 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1 \times 4+2 \times 7+3 \times 10+\cdots$$4+7+10+\ldots$$a_k=4+(k-1)(3)=4+3k-3=3k+1$$1+2+3+...$$k$$k(3k+1)$$T_k$$k$\begin{align*}T_k&amp;=k(3k+1) \\
&amp;=3k^2+k. \end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (3k^2 +k)\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, 14 and 15, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 13, 14 and 15, Exercise 4.8

Solutions of Question 13, 14 and 15 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{5 \cdot 11}+\frac{1}{7 \cdot 13}+\frac{1}{9 \cdot 15}+\ldots \ldots$$n$$T_k$$k$\begin{align*}
T_k &amp;= \frac{1}{(2k+3)(2k+9)}.
\end{align*}\begin{align*}
\frac{1}{(2k+3)(2k+9)} = \frac{A}{2k+3} + \frac{B}{2k+9} \ldots …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.2

Solutions of Question 11 and 12 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $1000$$3000$$2$$5000$$3$$20$$$1000, 3000, 5000, \dots, \text{ upto 20 terms}.$$$a_1 = 1000$$d=3000-1000=2000$$S_20=?$$$S_n =\frac{n}{2}[2a_1+(n-1)d],$$\begin{align*}
S_{20} &amp;= \frac{20}{2}[2(1000)+(20-1)2000]\\
&amp;= 10 [2000+(19)2000] \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15 and 16, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 15 and 16, Exercise 4.3

Solutions of Question 15 and 16 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $S_n$$a_{1}=91$$d=-4$$a_{n}=15$$a_{1}=91$$d=-4$$a_{n}=15$$n=?$\begin{align} 
&amp; a_n=a_1+(n-1)d \\
\implies &amp; 15=91+(n-1)(-4) \\
\implies &amp; 15=91-4n+4 \\
\implies &amp; 4n=95-15 \\
\implies &amp;  4n = 80\\ \implies &amp; n = 20.
\end{align}\begin{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p13?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 26 and 27, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p13?rev=1737476039&amp;do=diff</link>
        <description>Question 26 and 27, Exercise 4.4

Solutions of Question 26 and 27 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $16\,\, ft$$6$$16\,\,ft$$a_1$$a_2$$a_3,...$$$a_1 = 16\times \dfrac{1}{4} = 4\,\, ft.$$$r=\dfrac{1}{4}$$a_6$$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
a_{6}&amp;=a_{1} r^5 \\
&amp;=(4)\left(\dfrac{1}{4} \right)^5 \\
&amp; = \dfrac{1}{256}
\end{align*}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.5

Solutions of Question 5 and 6 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=7, r=2, n=14$$a_1 = 7$$r = 2$$n = 14$$n$$$S_n = \frac{a_1 \left(1 - r^n\right)}{1 - r}, \quad r \neq 1.$$\begin{align*}
S_{14} &amp;= \frac{7 \left(1 - 2^{14}\right)}{1 - 2} \\
&amp;= \frac{7 \left(1 - 16384\right)}{-1} \\
&amp;= \frac{7 \time…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14, 15 and 16, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 14, 15 and 16, Exercise 4.7

Solutions of Question 14, 15 and 16 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$n$$n+1$$T_n$$n$$$
T_{n} = n+1.
$$\begin{align*}\sum_{n=1}^{\infty} T_{n} &amp;= \sum_{n=1}^{\infty} (n+1)\\
&amp; = \sum_{n=1}^{\infty} n + \sum_{n=1}^{\infty} 1 \\
&amp; = \frac{n(n+1)}{2} + n \\
&amp; = \frac{n(n+1)}{2} + \frac{2n}{2} \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p8?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 17 and 18, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 17 and 18, Exercise 4.7

Solutions of Question 17 and 18 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$2^{2}+5^{2}+8^{2}+\ldots$$2+5+8+\ldots$$a_k=2+(k-1)(3)=2+3k-3=3k-1$$T_k$$k$\begin{align*}T_k&amp;=(3k-1)^2 \\
&amp;=9k^2-6k+1. \end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (9k^{2} - 6k + 1)\\
&amp; = 9\sum_{k=1}^{n} k^{2} …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p9?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19 and 20, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 19 and 20, Exercise 4.7

Solutions of Question 19 and 20 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1^{3}+3^{3}+5^{3}+$$1+3+5+\ldots$$a_k=1+(k-1)(2)=1+2k-2=2k-1$$T_k$$k$\begin{align*}T_k&amp;=(2k-1)^3 \\
&amp;=(2k)^3+3(2k)^2(-1)+3(2k)(-1)^2+(-1)^3 \\
&amp;=8k^3-12k^2+6k+1
\end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (8k^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p10?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19 and 20, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 19 and 20, Exercise 4.7

Solutions of Question 19 and 20 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1^{3}+3^{3}+5^{3}+$$1+3+5+\ldots$$a_k=1+(k-1)(2)=1+2k-2=2k-1$$T_k$$k$\begin{align*}T_k&amp;=(2k-1) \\
&amp;=9k^2-6k+1. \end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (2k - 1)\\
&amp; = 2 \sum_{k=1}^{n} k - \sum_{k=1}^{n} 1 \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p15?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 29 and 30, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p15?rev=1737476040&amp;do=diff</link>
        <description>Question 29 and 30, Exercise 4.7

Solutions of Question 29 and 30 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$1+4 x+7 x^{2}+10 x^{3}+\ldots$$\[
1 + 4x + 7x^2 + 10x^3 + \ldots
\]\[
1 \times 1 + 4 \times x + 7 \times x^2 + 10 \times x^3 + \ldots
\]\(1, 4, 7, 10, \ldots\)\(a = 1\)\(d = 4 - 1 = 3\)\(1, x, x^2, x^3, \ldots\)\(1\)\(r = x\)\[
S_{\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.8

Solutions of Question 9 and 10 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\frac{1}{1 \cdot 3}+\frac{1}{2 \cdot 5}+\frac{1}{3 \cdot 7}+\ldots \ldots \text{ up to } \infty$$$\sum_{k=3}^{n} \dfrac{1}{(k+1)(k+2)}$\begin{align*}
T_k &amp;= \frac{1}{(k+1)(k+2)}.
\end{align*}\begin{align*}
\frac{1}{(k+1)(k+2)} = \frac…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.1

Solutions of Question 9 and 10 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{15}$$a_{n}=(-1)^{n}(n+3)$$n$$a_{10}$$a_{15}$$$a_{n}=(-1)^{n+1}(3 n-5).$$$$a_n = (-1)^{n+1}(3n - 5).$$\begin{align*}
a_1 &amp;= (-1)^{1+1}(3(1) - 5) = (1)(3 - 5) = -2 \\
a_2 &amp;= (-1)^{2+1}(3(2) - 5) = (-1)(6 - 5) = -1 \\
a_3 &amp;=…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19 and 20, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 19 and 20, Exercise 4.1

Solutions of Question 19 and 20 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}$$1,3,5,7,9, \ldots$$$1, 3, 5, 7, 9, \ldots$$$a_1=1$$d=3-1=2$$$a_n = a_1 + (n - 1) d$$\begin{align*}
\implies a_n &amp;= 1 + (n - 1) \cdot 2\\
 &amp;= 1 + 2n - 2\\
&amp;= 2n - 1 \end{align*}$a_n = 2n - 1$$a_{n}$$3,9,27,81,243, \ldots$\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p11?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 21 and 22, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 21 and 22, Exercise 4.1

Solutions of Question 21 and 22 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}$$\sqrt{2}, \sqrt{4}, \sqrt{6}, \sqrt{8}, \sqrt{10}, \ldots$$$\sqrt{2}, \sqrt{4}, \sqrt{6}, \sqrt{8}, \sqrt{10}, \ldots$$\begin{align*}
&amp;a_1=\sqrt{2 \cdot 1}, \\
&amp;a_2=\sqrt{4}=\sqrt{2 \cdot 2} \\
&amp;a_3=\sqrt{6}=\sqrt{2 \cdot 3}\\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.2

Solutions of Question 3 and 4 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $0.07,0.12,0.7, \ldots$$$0.07,0.12,0.7, \ldots$$$a_1 = 0.07$$d=0.05$$a_{11}=?$\begin{align*}
a_n&amp;=a_1+(n-1)d \\
\implies a_{11}&amp;= 0.07+(11-1)(0.05)\\
&amp;=0.07+(10)(0.05)\\
&amp;=0.57
\end{align*}$a_{11}=0.57.$$a_3 = 14$$a_9 = -1$$$a_n = a_1 + (…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.3

Solutions of Question 9 and 10 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $1$$99$$1$$99$$$1+3+5+...+99 (50 \text{ terms}).$$$a_{1}=1$$n=50$$d=3-1=2$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d] \\
\implies S_{50}&amp;=\frac{50}{2}[2(1)+(50-1)(2)]\\
&amp;=25\times [2+98]\\
&amp;=2500.
\end{align}$1$$99$$2500$$14$$523$$…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p15?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 30, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p15?rev=1737476039&amp;do=diff</link>
        <description>Question 30, Exercise 4.4

Solutions of Question 30 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $=a_1= 1$$=a_2= 3$$=a_3=3\times 3 = 9$$=a_4=3\times 9 = 27$$=a_5=3\times 27 = 81$$81$$a_1=1$$r=3$$a_5=?$$$a_n=a_1 r^{n-1}.$$\begin{align*}
a_5&amp;=a_1 r^4 \\
&amp;=(1)(3)^4 = 81
\end{align*}$$S_n=a_1+a_2+a_3+a_4+a_5.$$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.5

Solutions of Question 1 and 2 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $16+16+16+\ldots$$a_1=16$$r=\dfrac{16}{16}=1$$r\neq 1$\begin{align*}
&amp;16+16+16+\ldots \text{ to 11 terms}\\
=&amp;11(16) \\
=&amp; 176
\end{align*}$75+15+3+...$$75+15+3+...$$a_1= 75$$r = \frac{15}{75} = \frac{1}{5}$$n = 10$$n$$$ S_n = \frac{a_1 \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p8?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 15, Exercise 4.5

Solutions of Question 15 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $30 ft$$\frac{2}{5}$$= 30 ft$$= 30 \times \frac{2}{5} = 12 ft$$= 12 \times \frac{2}{5} = \frac{24}{5} ft$$= \frac{24}{5} \times \frac{2}{5} = \frac{48}{25} ft$$D$$$D=30+2\left(12+\frac{24}{5}+\frac{24}{5}+... \right)$$$$
12+\frac{24}{5}+\frac{24}{5…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 4.6

Solutions of Question 9 &amp; 10 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{7}, \frac{1}{6},-1,-\frac{1}{3}, \ldots$$$\frac{1}{7}, \frac{1}{6}, -1, -\frac{1}{3}, \ldots \text{ is in H.P.}$$$$7, 6, -1, -3, \ldots \text{ is in A.P.}$$$a_1 = 7$$d = 6 - 7 = -1$$a_8=?$$$
a_n = a_1 + (n-1)d.
$$\begin{align*}
a_…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p14?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 27 and 28, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p14?rev=1737476040&amp;do=diff</link>
        <description>Question 27 and 28, Exercise 4.7

Solutions of Question 27 and 28 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$5+\frac{7}{3}+\frac{9}{9}+\frac{11}{27}+\ldots$$$$5+\frac{7}{3}+\frac{9}{9}+\frac{11}{27}+\ldots$$$$
5\times 1+7\times\frac{1}{3}+9\times\frac{1}{9}+11\times\frac{1}{27}+\ldots
$$$5,7,9,11,4,\ldots$$a=5$$d=7-5=2$$1, \dfrac{1}{3}, \d…</description>
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