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We are going to add short questions and MCQs for Real Analysis. The subject is similar to calculus but little bit more abstract. This is a compulsory subject in MSc and BS Mathematics in most of the universities of Pakistan. The author of this page is Dr. $\left\{\frac{1}{n+1} \right\}$$\left\{\frac{n+2}{n+1} \right\}$$\{x_n\}$$\{y_n\}$$\lim_{n\to\infty z_n}$$z_n=x_n-2y_n$$\{x_n\}$$\{y_n\}$$\lim_{n\to\infty z_n}$$x_n=2y_n…</description>
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Solutions of Question 1 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos \theta=\frac{\sqrt{3}}{2}$$\sin \theta=$$\frac{1}{2}$$-\frac{1}{2}$$\sqrt{3}$$-\frac{2}{\sqrt{3}}$$\tan (-15 \pi)=$$ 0$$-1$$1$$2 \sin \theta+\frac{1}{2}cosec \theta \theta $$\theta=45^{\circ}$$\frac{1}{\sqrt{2}}$$\frac{1}{3}$$\frac{3}{…</description>
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Solutions of Question 1 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \left(45^{\circ}-30^{\circ}\right)=\ldots$$\frac{\sqrt{6}-\sqrt{2}}{4}$$\frac{\sqrt{6}+\sqrt{2}}{4}$$\frac{\sqrt{6}-\sqrt{2}}{2}$$\frac{\sqrt{3}-\sqrt{2}}{2}$$\tan \left(\frac{\pi}{6}+\frac{\pi}{4}\right)=\ldots$$\frac{\sqrt{3}-1}…</description>
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        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 Review Exercise 7

Solutions of Question 1 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.
Chose the correct option.
&lt;panel&gt;$O, P, Q, R, S, T, U$$2520$$9040$$5140$$4880$$\{1,2,3,4,5,6,7\}$$14$$42$$28$$21$$\{1,2,3,4,6,7,8\}$$3$$7$$120$$180$$144$$96$$\dfrac{(n+2) !(n-2) !}{(n+1) !(n-1) !}$$(n-3)$$(\dot{n}-1)$$\dfrac{n+1}{n…</description>
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        <title>Question 1, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Review Exercise

Solutions of Question 1 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\operatorname{part}(\mathrm{s})$$z$$z$$(0,0)$$(1,0)$$(0,1)$$(1,1)$$z$$|z|$$1 / z$$-z$$\bar{z}$$x$$y$$x y$$z_{1}=3+2 i$$z_{2}=5+6 i$$z_{1}&gt;z_{2}$$z_{1}&lt;z_{2}$$\overline{z_{1}}=\overline{z_{2}}$$\overline{z_{1}}=-\overline{z_{2}}$$\mathrm{z}=3+4 i$$…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/re-ex-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Review Exercise

Solutions of Question 1 of Review Exercise of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$m \times n$$B$$n \times p$$A B$$n \times p$$m \times p$$p \times m$$n \times n$$A$$1 \times n$$A^{t} A$$1 \times n$$n \times 1$$1 \times 1$$n \times n$$a_{i j}$$A$$a_{i j}=(-1)^{i+j} A_{i j}$$a_{i j}=(-1)^{i+j} M_{i j}$$\frac{A_{i j}}…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>MCQs: Math 11 NBF</title>
        <link>https://beta.mathcity.org/math-11-nbf/mcqs?rev=1737476039&amp;do=diff</link>
        <description>MCQs: Math 11 NBF

&lt;lead&gt;Multiple Choice Questions (MCQs) of the Model Textbook of Mathematics for Class XI is published by National Book Foundation (NBF), Islamabad, Pakistan. NBF can be considered as Federal Textbook Board Islamabad. &lt;/lead&gt;

Unit 01: Complex Numbers
$\operatorname{part}(\mathrm{s})$$z$$z$$(0,0)$$(1,0)$$(0,1)$$(1,1)$$z$$|z|$$1 / z$$-z$$\bar{z}$$x$$y$$x y$$z_{1}=3+2 i$$z_{2}=5+6 i$$z_{1}&gt;z_{2}$$z_{1}&lt;z_{2}$$\overline{z_{1}}=\overline{z_{2}}$$\overline{z_{1}}=-\overline{z_{2}}$$…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise 10</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Review Exercise 10

Solutions of Question 1 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{50}^{\circ }}5{0}&#039;\cos {{9}^{\circ }}1{0}&#039;-\sin {{50}^{\circ }}5{0}&#039;\sin {{9}^{\circ }}1{0}&#039;=$$0$$\dfrac{1}{2}$$1$$\dfrac{\sqrt{3}}{2}$$\tan {{15}^{\circ }}=2-\sqrt{3}$${{\cot }^{2}}{{75}^{\circ }}$$7+\sq…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Review Exercise 3

Solutions of Question 1 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

$\hat{i} \cdot(\hat{j} \times \hat{k})+\hat{j} \cdot(\hat{i} \times \hat{k})+\hat{k} \cdot(\hat{i} \times \hat{j})$$0$$1$$1$$3$$3 \hat{i}+5 \hat{j}+2 \hat{k}$$2 \hat{i}-3 \hat{j}-5 \hat{k}$$5 \hat{i}+2 \hat{j}-3 \hat{k}$$\hat{i}-2 \hat{i}+\hat{j}+3 \…</description>
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        <title>Question 1 Review Exercise 5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Review Exercise 5

Solutions of Question 1 of Review Exercise 5 of Unit 05: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

$t_n=6 n+5$$t_{n+1}=$$6 n-1$$6 n+11$$6 n+6$$6 n-5$$1+\dfrac{2}{3}+\dfrac{6}{3^2}+\dfrac{10}{3^3}+\dfrac{14}{3^4}+\ldots$$6$$2$$3$$4$$1+2.2+3.2^2+\cdots+100.2^{\prime \prime}$$99.2^{100}$$100.2^{100}$$99.2^{100}+1$$1000.2^{100}$$n^{t h}$$1.2+2.3+3.4+\…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise 10</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Review Exercise 10

Solutions of Question 1 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{50}^{\circ }}5{0}&#039;\cos {{9}^{\circ }}1{0}&#039;-\sin {{50}^{\circ }}5{0}&#039;\sin {{9}^{\circ }}1{0}&#039;=$$0$$\dfrac{1}{2}$$1$$\dfrac{\sqrt{3}}{2}$$\tan {{15}^{\circ }}=2-\sqrt{3}$${{\cot }^{2}}{{75}^{\circ }}$$7+\sq…</description>
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        <title>Question 1, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Review Exercise

Solutions of Question 1 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1
$-2-x+x^{2}$$(x-2)(x-1)$$(x+1)(x+2)$$(x+2)(x-1)$$(x+1)(x-2)$$9 y^{2}+9 y-10$$3 y-2$$ 0$$1$$2$$3$$\frac{x^{2}-x-9}{x-3}=x+2+\frac{?}{x-3}$$-27$$-3$$\frac{3}{x-3}+x+2$$ 3$$3 x^{3}-2 x^{2}+5$$x+1$$x+1$$x^{3}+5 x^{2}-4 x+k$$k$$-4$$-20$$20$$0$$…</description>
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        <title>Question 1, Review Exercise 1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Review Exercise 1

Solutions of Question 1 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1
${{\left( \dfrac{2i}{1+i} \right)}^{2}}$$i$$2i$$1-i$$i+1$$\dfrac{5+2i}{4-3i}$$-\dfrac{7}{25}+\dfrac{26}{25}i$$\dfrac{5}{4}-\dfrac{2}{3}i$$\dfrac{14}{25}+\dfrac{23}{25}i$$\dfrac{26}{7}+\dfrac{23}{7}i$${{i}^{57}}+\frac{1}{{{i}^{25}}}$$0$$2i$$-2…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise 1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Review Exercise 1

Solutions of Question 1 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1
${{\left( \dfrac{2i}{1+i} \right)}^{2}}$$i$$2i$$1-i$$i+1$$\dfrac{5+2i}{4-3i}$$-\dfrac{7}{25}+\dfrac{26}{25}i$$\dfrac{5}{4}-\dfrac{2}{3}i$$\dfrac{14}{25}+\dfrac{23}{25}i$$\dfrac{26}{7}+\dfrac{23}{7}i$${{i}^{57}}+\frac{1}{{{i}^{25}}}$$0$$2i$$-2…</description>
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        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc/ICS Part 2 (Mathematics): PTB</title>
        <link>https://beta.mathcity.org/fsc-part2-ptb?rev=1737476042&amp;do=diff</link>
        <description>FSc/ICS Part 2 (Mathematics): PTB

[Calculus and Analytic Geometry, MATHEMATICS 12]
&lt;lead&gt;Calculus and Analytic Geometry, MATHEMATICS 12 (Mathematics FSc/ICS Part 2 or HSSC-II), Punjab Textbook Board (PTB) Lahore, Pakistan. There are total seven (7) units in this book.&lt;/lead&gt; 
One this page we have posted Notes (Solutions), MCQs, short question, sample papers and old papers related to this subject. This book has wide scope and it is part of syllabus of Mathematics in FSc/ICS from all board (Boar…</description>
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        <title>FSc Part 1 (Mathematics): KPK</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk?rev=1737476042&amp;do=diff</link>
        <description>FSc Part 1 (Mathematics): KPK

[A Textbook of Mathematics for Class XI]
&lt;lead&gt;A Textbook of Mathematics for Class XI is published by Khybar Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. The book has total of twelve (12) chapters. &lt;/lead&gt; 
&lt;callout type=“info” icon=“true</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc/ICS Part 1 (Mathematics): PTB</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb?rev=1737476042&amp;do=diff</link>
        <description>FSc/ICS Part 1 (Mathematics): PTB

[Textbook of Algebra and Trigonometry Class XI]
&lt;lead&gt;Textbook of Algebra and Trigonometry Class XI is published by Punjab Textbook Board (PTB) Lahore, Pakistan. The book has total of 14 chapters.&lt;/lead&gt; 
One this page, we have posted Notes (Solutions), MCQs, short question, sample papers and old papers related to this subject. This book has wide scope and it is part of syllabus of Mathematics in FSc/ICS from all board (Board of Intermediate and Secondary Educa…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc/ICS Part 1 (Mathematics): KPK</title>
        <link>https://beta.mathcity.org/math-11-kpk?rev=1737476042&amp;do=diff</link>
        <description>FSc/ICS Part 1 (Mathematics): KPK

[A Textbook of Mathematics for Class XI]
&lt;lead&gt;A Textbook of Mathematics for Class XI is published by Khybar Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. The book has total of twelve (12) chapters. &lt;/lead&gt; 
&lt;callout type=“info” icon=</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematics 1 for FSc ICS (NBF)</title>
        <link>https://beta.mathcity.org/math-11-nbf?rev=1737476042&amp;do=diff</link>
        <description>Mathematics 1 for FSc ICS (NBF)

[A Textbook of Mathematics for Class XI]
&lt;lead&gt;Model Textbook of Mathematics for Class XI is published by National Book Foundation (NBF), Islamabad, Pakistan. NBF can be considered as Federal Textbook Board Islamabad. The book has total of nine (9) chapters. &lt;/lead&gt; 
&lt;callout type=</description>
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        <dc:date>2025-01-21T16:13:54+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>MTH211: Discrete Mathematics (Fall 2020)</title>
        <link>https://beta.mathcity.org/atiq/sp21-mth211?rev=1737476034&amp;do=diff</link>
        <description>MTH211: Discrete Mathematics (Fall 2020)



Course Objectives:

Discrete Mathematics is branch of Mathematics which deals with discrete structures
like logic. sequences, graphs, relations in contrast to Calculus. where we enjoy the
continuity of functions and the set of real numbers. This course is introduction to
discrete structures which are not the part of main stream courses.
Discrete Mathematics has applications in Computer Science. Economics and Decision
Making etc. This course will help t…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc Part 2 (KPK Boards)</title>
        <link>https://beta.mathcity.org/fsc/kpk_fsc_part_2?rev=1737476036&amp;do=diff</link>
        <description>FSc Part 2 (KPK Boards)

[A Textbook of Mathematics For Class XII]
Notes of FSc Part 2 of “A Textbook of Mathematics For Class XII” published by Khyber Pakhtunkhwa Textbook Board, Peshawar. We are posting the notes chapter-wise. These notes are shared as open educational resources. This page will be continuously updated.$y=x^n$$y=(ax+b)^n$</description>
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        <title>Complex Analysis (Easy Notes of Complex Analysis)</title>
        <link>https://beta.mathcity.org/notes/complex-analysis-dr-amir-mahmood?rev=1737476041&amp;do=diff</link>
        <description>Complex Analysis (Easy Notes of Complex Analysis)

[Complex Analysis (Easy Notes of Complex Analysis) ]
The study of complex numbers, together with their manipulation, derivatives, and other characteristics, is known as complex integration. Contour integration is a technique for analysing specific integrals along pathways in the complex plane in the field of complex analysis mathematics. The complex analytic technique known as the calculus of residues and contour integration are closely linked.</description>
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        <title>Vector &amp; Tensor Analysis by Dr Nawazish Ali (Solutions)</title>
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        <description>Vector &amp; Tensor Analysis by Dr Nawazish Ali (Solutions)

[Vector &amp; Tensor Analysis by Dr Nawazish Ali (Solutions)]

We are very thankful to Prof. Fazal Abbas Sajid for sharing these solutions. Vector &amp; Tensor Analysis for Scientists and Engineers,
by Prof. Dr. Nawazish Ali Shah is a famous book taught in different universities of the Pakistan. On this page, we have added the solutions of the exercises of the book. Solutions of Chapter 5 is written by</description>
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        <title>Question 2 &amp; 3, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2 &amp; 3, Exercise 1.1

Solutions of Question 2 &amp; 3 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
${{i}^{107}}+{{i}^{112}}+{{i}^{122}}+{{i}^{153}}=0$\begin{align}L.H.S.&amp;={{i}^{107}}+{{i}^{112}}+{{i}^{122}}+{{i}^{153}}\\
&amp;=i\cdot i^{106}+i^{112}+i^{122}+i\cdot i^{152}\\
&amp;=i.{{\left( {{i}^{2}} \right)}^{53}}+{{\left( {{i}^{2}} \right)}^{56}}+…</description>
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        <title>Question 4, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 4, Exercise 1.1

Solutions of Question 4 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)
$\left( a,0 \right)\left( 2,-b \right)$\begin{align}&amp;\left( a,0 \right)-\left( 2,-b \right)\\
&amp;=\left( a+0i \right)-\left( 2-bi \right)\\
&amp;=\left( a-2 \right)+\left( 0+b \right)i\\
&amp;=\left( a-2 \right)+bi\end{align}$\left( -3,\dfrac{1}{2} \right)\le…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p4?rev=1737476036&amp;do=diff</link>
        <description>Question 5, Exercise 1.1

Solutions of Question 5 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$8i+11,-7+5i$\begin{align}&amp;(8i+11)\times (-7+5i)\\
&amp;=\left( 11+8i \right)\times \left( -7+5i \right)\\
&amp;=\left( -77+40{{i}^{2}} \right)+\left( 55-56 \right)i\\
&amp;=\left( -77+40\left( -1 \right) \right)+\left( 55-56 \right)i\\
&amp;=\left( -77-40 \right)+…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p5?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p5?rev=1737476036&amp;do=diff</link>
        <description>Question 6, Exercise 1.1

Solutions of Question 6 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
$\dfrac{4+i}{3+5i}$$a+ib$\begin{align}\dfrac{4+i}{3+5i}&amp;=\dfrac{4+i}{3+5i}\times \dfrac{3-5i}{3-5i}\\
&amp;=\dfrac{\left( 12+5 \right)+\left( 3-20 \right)i}{9-25{{i}^{2}}}\\
&amp;=\dfrac{17-17i}{9+25}\\
&amp;=\dfrac{17}{34}-\dfrac{17}{34}i\\
&amp;=\dfrac{1}{2}-\dfr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p6?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p6?rev=1737476036&amp;do=diff</link>
        <description>Question 7, Exercise 1.1

Solutions of Question 7 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
${{z}_{1}}=1+2i$${{z}_{2}}=2+3i$$|{{z}_{1}}+{{z}_{2}}|$$z_1=1+2i$$z_2=2+3i$\begin{align}
{{z}_{1}}+{{z}_{2}}&amp;=1+2i+2+3i\\
&amp;=1+2+2i+3i\\
&amp;=3+5i
\end{align}\begin{align}
|z_1+z_2|&amp;=\sqrt{3^2+5^2}\\
&amp;=\sqrt{9+25}\\ 
&amp;=\sqrt{34}\end{align}${{z}_{1}}=1+2…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p7?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p7?rev=1737476036&amp;do=diff</link>
        <description>Question 8, Exercise 1.1

Solutions of Question 8 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$\dfrac{1-2i}{2+i}+\dfrac{4-i}{3+2i}$$a+ib.$\begin{align}&amp;\dfrac{1-2i}{2+i}+\dfrac{4-i}{3+2i}\\
&amp;=\dfrac{\left( 3+2i \right)\left( 1-2i \right)+\left( 2+i \right)\left( 4-i \right)}{\left( 2+i \right)\left( 3+2i \right)}\\
&amp;=\dfrac{\left( 3+4+2i-6i …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p8?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p8?rev=1737476036&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 1.1

Solutions of Question 9 &amp; 10 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$\dfrac{\left( 3-2i \right)\left( 2+3i \right)}{\left( 1+2i \right)\left( 2-i \right)}$\begin{align}z&amp;=\dfrac{\left( 3-2i \right)\left( 2+3i \right)}{\left( 1+2i \right)\left( 2-i \right)}\\
&amp;=\dfrac{6+6+9i-4i}{2+2+4i-i}\\
&amp;=\dfrac{12+5i}{4+3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p2?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 1.2

Solutions of Question 2 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2

$z_1=-1+i$, $z_2=3-2i$${{z}_{3}}=2-2i$${{z}_{1}}=-1+i$${{z}_{2}}=3-2i$${{z}_{3}}=2-2i$$$(z_1+z_2)+z_3=z_1+(z_2+z_3).$$\begin{align} 
{{z}_{1}}+{{z}_{2}}&amp;=\left( -1+i \right)+\left( 3-2i \right)\\
&amp;=2-i\end{align}\begin{align}
\left( {{z}_{1}}+{{z}_{2}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p3?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 1.2

Solutions of Question 3 &amp; 4 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
${{z}_{1}}=\sqrt{3}+\sqrt{2}i$${{z}_{2}}=\sqrt{2}-\sqrt{3}i$${{z}_{3}}=2+3i$${{z}_{1}}=\sqrt{3}+\sqrt{2}i$${{z}_{2}}=\sqrt{2}-\sqrt{3}i$${{z}_{3}}=2+3i$\begin{align}{{z}_{1}}\left( {{z}_{2}}+{{z}_{3}} \right)&amp;={{z}_{1}}{{z}_{2}}+{{z}_{1}}{{z}_{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p4?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p4?rev=1737476036&amp;do=diff</link>
        <description>Question 5, Exercise 1.2

Solutions of Question 5 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
${{z}_{1}}=2+4i$${{z}_{2}}=1-3i$$\overline{{{z}_{1}}+{{z}_{2}}}=\overline{{{z}_{1}}}+\overline{{{z}_{2}}}$${{z}_{1}}=2+4i$${{z}_{2}}=1-3i$$\overline{{{z}_{1}}}=2-4i$$\overline{{{z}_{2}}}=1+3i$\begin{align}z_1+z_2&amp;=2+4i+1-3i\\
&amp;=3+i \end{align}\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p5?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p5?rev=1737476036&amp;do=diff</link>
        <description>Question 6, Exercise 1.2

Solutions of Question 6 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
${{z}_{1}}$${{z}_{2}}$$|{{z}_{1}}{{z}_{2}}|=|{{z}_{1}}||{{z}_{2}}|$${{z}_{1}}=a+bi$${{z}_{2}}=c+di$$|z_1=\sqrt{a^2+b^2}|$$|z_2=\sqrt{c^2+d^2}|$\begin{align}
L.H.S.&amp;=|{{z}_{1}}{{z}_{2}}|\\
&amp;=|(a+bi)(c+di)|\\ 
&amp;=|ac-bd+(ad+bc)i|\\
&amp;=\sqrt{{{(ac-bd)}^{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p6?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p6?rev=1737476036&amp;do=diff</link>
        <description>Question 7, Exercise 1.2

Solutions of Question 7 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$\dfrac{2+3i}{5-2i}$\begin{align}&amp;\dfrac{2+3i}{5-2i} \\
=&amp;\dfrac{2+3i}{5-2i}\times \dfrac{5+2i}{5+2i} \quad \text{by rationalizing} \\
=&amp;\dfrac{10-6+15i+4i}{25+4}\\
=&amp;\dfrac{4+19i}{29}\\
=&amp;\dfrac{4}{29}+\dfrac{19}{29}i \end{align}$=\dfrac{4}{29}$$=\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p7?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p7?rev=1737476036&amp;do=diff</link>
        <description>Question 8, Exercise 1.2

Solutions of Question 8 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$z+\overline{z}=2\operatorname{Re}\left( z \right)$$z=a+ib$$\overline{z}=a-ib$\begin{align}z+\overline{z}&amp;=\left( a+ib \right)+\left( a-ib \right)\\
&amp;=a+ib+a-ib\\
&amp;=2a\\
z+\overline{z}&amp;=2\operatorname{Re}\left( z \right)\end{align}$z-\overline{z}=2i…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p2?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 1.3

Solutions of Question 2 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$P(z)$$$P\left( z \right)={{z}^{3}}+6z+20$$$$p\left( z \right)={{z}^{3}}+6z+20$$$(z-a)$$P(z)$$P(a)=0$$z=-2$\begin{align}
P(-2)&amp;=(-2)^3+6(-2)+20\\
&amp;=-8-12+20\\
&amp;=0\end{align}$z+2$${{z}^{3}}+6z+20$$$\begin{array}{c|cccc}
-2 &amp; 1 &amp; 0 &amp; 6 &amp; 20 \\  
 &amp; \d…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p3?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 1.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 1.3

Solutions of Question 3 &amp; 4 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
${{z}_{1}}=-1+i$${{z}_{2}}=-1-i$${{z}^{2}}+2z+2=0$$$z^2+2z_1+2=0\quad \ldots (i)$$$z_1=-1+i$\begin{align}L.H.S &amp;= (-1+i)^2+2(-1+i)+2\\
&amp;=1-2i-1-2+2i+2\\
&amp;=0=R.H.S\end{align}$z_1=-1+i$$z_2=-1-i$\begin{align}
L.H.S&amp;=(-1-i)^2+2(-1-i)+2\\
&amp;=1+2i-1-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p4?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p4?rev=1737476036&amp;do=diff</link>
        <description>Question 5, Exercise 1.3

Solutions of Question 5 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
${{z}^{2}}+z+3=0$${{z}^{2}}+z+3=0$$a=1,\,\,\,b=1$$c=3$\begin{align}z&amp;=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\\ 
z&amp;=\dfrac{-\left( 1 \right)\pm \sqrt{{{\left( 1 \right)}^{2}}-4\left( 1 \right)\left( 3 \right)}}{2\left( 1 \right)}\\
z&amp;=\dfrac{-1\pm \s…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p2?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3, Review Exercise 1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2 &amp; 3, Review Exercise 1

Solutions of Question 2 &amp; 3 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{i}^{n}}+{{i}^{n+1}}+{{i}^{n+2}}+{{i}^{n+3}}=0$$\forall n\in N$\begin{align}{{i}^{n}}+{{i}^{n+1}}+{{i}^{n+2}}+{{i}^{n+3}}&amp;=0\\
L.H.S.&amp;={{i}^{n}}+{{i}^{n}}\cdot i+{{i}^{n}}\cdot {{i}^{2}}+{{i}^{n}}\cdot {{i}^{3}}\\
&amp;={{i}^{n}}\left( 1+i+{{i}^{2}}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p3?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise 1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise 1

Solutions of Question 4 &amp; 5 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{z}_{1}}=2-i$${{z}_{2}}=1+i,$$|\dfrac{{{z}_{1}}+{{z}_{2}}+1}{{{z}_{1}}-{{z}_{2}}+1}|$\begin{align}{{z}_{1}}&amp;=2-i,\\
{{z}_{2}}&amp;=1+i,\\
\dfrac{{{z}_{1}}+{{z}_{2}}+1}{{{z}_{1}}-{{z}_{2}}+1}&amp;=\dfrac{\left( 2-i \right)+\left( 1+i \right)+1}{\left( 2-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p2?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 10.1

Solutions of Question 2 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \dfrac{\pi }{12}$$\dfrac{\pi }{12}$$\dfrac{\pi }{3}-\dfrac{\pi }{4}$\begin{align}\sin (\alpha -\beta )=\sin \alpha \cos \beta -\cos \alpha \sin.\end{align}\begin{align} \Rightarrow \quad \sin \left( \frac{\pi }{3}-\f…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p3?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3, Exercise 10.1

Solutions of Question 3 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin u=\dfrac{3}{5}$$\sin v=\dfrac{4}{5}$$u$$v$$0$$\dfrac{\pi }{2}$$\cos \left( u+v \right)$$\sin u=\dfrac{3}{5},$$0\le u\le \dfrac{\pi }{2}.$$\sin v=\dfrac{4}{5},$$0\le v\le \dfrac{\pi }{2}.$$\cos u=\pm \sqrt{1-{{\sin }^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p4?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p4?rev=1737476036&amp;do=diff</link>
        <description>Question, Exercise 10.1

Solutions of Question 4 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \alpha =-\dfrac{4}{5}$$\cos \beta =-\dfrac{12}{13}$$\alpha $$\beta $$\sin \left( \alpha -\beta  \right)$$\sin \alpha=-\dfrac{4}{5}$$\alpha$$\sin \beta=-\dfrac{12}{13}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$$\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p5?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p5?rev=1737476036&amp;do=diff</link>
        <description>Question 5, Exercise 10.1

Solutions of Question 5 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\tan \alpha =\dfrac{3}{4}$$\sec \beta =\dfrac{13}{5}$$\alpha$$\beta$$\sin \left( \alpha +\beta  \right)$$\tan\alpha =\dfrac{3}{4}$$\tan\alpha$$\alpha$\begin{align}{{\sec}^{2}}\alpha &amp;=1+{{\tan}^{2}}\alpha\\
\Rightarrow \q…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p6?rev=1737476036&amp;do=diff</link>
        <description>Question 6, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos \alpha =2{{\cos }^{2}}\dfrac{\alpha }{2}-1=1-2{{\sin }^{2}}\dfrac{\alpha }{2}$\begin{align}L.H.S&amp;=\cos \alpha \\
\cos \alpha &amp;=\cos 2\dfrac{\alpha }{2}\\
&amp;={{\cos }^{2}}\dfrac{\alpha }{2}-{{\sin }^{2}}\dfrac{\alpha }…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p7?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p7?rev=1737476036&amp;do=diff</link>
        <description>Question 7, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cot \left( \alpha +\beta  \right)=\dfrac{\cot \alpha \cot \beta -1}{\cot \alpha +\cot \beta }$\begin{align}L.H.S.&amp;=\cot (\alpha +\beta )\\
&amp;=\dfrac{1}{\tan (\alpha +\beta )}\\
&amp;=\dfrac{1}{\,\dfrac{\tan \alpha +\tan \beta…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p8?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p8?rev=1737476036&amp;do=diff</link>
        <description>Question 8, Exercise 10.1

Solutions of Question 8 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\tan \left( \dfrac{\pi }{4}+\theta  \right)=\dfrac{\cos \theta +\sin \theta }{\cos \theta -\sin \theta }$\begin{align}L.H.S.&amp;=\tan \left( \dfrac{\pi }{4}+\theta  \right)\\ 
&amp;=\dfrac{\sin \left( \dfrac{\pi }{4}+\theta  \ri…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p9?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p9?rev=1737476036&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 10.1

Solutions of Question 9 and 10 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{\sin \theta }{\sec 4\theta }+\dfrac{\cos \theta }{\cos ec4\theta }=\sin 5\theta $\begin{align}L.H.S.&amp;=\dfrac{\sin \theta }{\sec 4\theta }+\dfrac{\cos \theta }{\cos ec4\theta }\\
&amp;=\dfrac{\sin \theta }…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question11 and 12, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p10?rev=1737476036&amp;do=diff</link>
        <description>Question11 and 12, Exercise 10.1

Solutions of Question 11 and 12 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\alpha$$\beta$$\gamma$$ABC$$\cot \dfrac{\alpha }{2}+\cot \dfrac{\beta }{2}+\cot \dfrac{\gamma }{2}=\cot \dfrac{\alpha }{2}\cot \dfrac{\beta }{2}\cot \dfrac{\gamma }{2}$$\alpha$$\beta$$\gamma$\begin{align}&amp;\…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 10.2

Solutions of Question 2 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \theta =\dfrac{5}{13}$$\theta $$\sin 2\theta $$\sin \theta =\dfrac{5}{13}$$$\cos \theta =\pm \sqrt{1-{{\sin }^{2}}\theta }.$$$\theta$$\cos$\begin{align}\cos\theta &amp;=-\sqrt{1-{{\sin }^{2}}\theta }\\
&amp;=-\sqrt{1-\left(\…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3, Exercise 10.2

Solutions of Question 3 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \theta =\dfrac{4}{5}$$\theta$$\sin2\theta$$\sin \theta =\dfrac{4}{5}$$\theta$$\cos \theta =-\dfrac{3}{5}$\begin{align}\sin 2\theta &amp;=2\sin \theta \cos \theta \\
&amp;=2\left( \dfrac{4}{5} \right)\left( -\dfrac{3}{5} \rig…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 and 5, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p4?rev=1737476036&amp;do=diff</link>
        <description>Question 4 and 5, Exercise 10.2

Solutions of Question 4 and 5 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos \theta =-\dfrac{3}{7}$$\theta $$\sin \dfrac{\theta }{2}$$\cos \theta =-\dfrac{3}{7}$$\theta$\begin{align}&amp;\pi &lt; \theta &lt; \dfrac{3\pi}{2} \\
\implies &amp;\frac{\pi}{2} &lt; \frac{\theta}{2} &lt; \dfrac{3\pi}{4}\end…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p5?rev=1737476036&amp;do=diff</link>
        <description>Question 6, Exercise 10.2

Solutions of Question 6 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{15}^{\circ }}$${{15}^{\circ }}=\dfrac{{{30}^{\circ }}}{2}$$\dfrac{\theta }{2}=\dfrac{{{30}^{\circ }}}{2}$$\cos {{15}^{\circ }}$\begin{align}\cos {{15}^{\circ }}&amp;=\cos \dfrac{{{30}^{\circ }}}{2}=\sqrt{\dfrac{1+\cos …</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p6?rev=1737476036&amp;do=diff</link>
        <description>Question 7, Exercise 10.2

Solutions of Question 7 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\cos }^{4}}\theta -{{\sin }^{4}}\theta =\dfrac{1}{\sec 2\theta }$\begin{align}L.H.S&amp;={{\cos }^{4}}\theta -{{\sin }^{4}}\theta \\ 
&amp;=\left( {{\cos }^{2}}\theta -{{\sin }^{2}}\theta  \right)\left( {{\cos }^{2}}\theta +{{\…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 10.3

Solutions of Question 2 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\sin {{37}^{\circ }}+\sin {{43}^{\circ }}.$$$$\sin \alpha +\sin \beta =2\sin \left( \dfrac{\alpha +\beta }{2} \right)\cos \left( \dfrac{\alpha -\beta }{2} \right).$$$\alpha ={{37}^{\circ }}$$\beta ={{43}^{\circ }}$\begin…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3, Exercise 10.3

Solutions of Question 3 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\dfrac{\cos {{75}^{\circ }}+\cos {{15}^{\circ }}}{\sin {{75}^{\circ }}-\sin {{15}^{\circ }}}=\sqrt{3}.$$$$\cos \alpha +\cos \beta =2\cos \left( \dfrac{\alpha +\beta }{2} \right)\cos \left( \dfrac{\alpha -\beta }{2} \righ…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 10.3

Solutions of Question 5 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\cos {{20}^{\circ }}\cos {{40}^{\circ }}\cos {{60}^{\circ }}\cos {{80}^{\circ }}=\dfrac{1}{16}.$$$2\cos \alpha \cos \beta =\cos \left( \alpha +\beta  \right)+\cos \left( \alpha -\beta  \right)$\begin{align}L.H.S.&amp;=\cos {…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Review Exercise 10</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 and 3, Review Exercise 10

Solutions of Question 2 and 3 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{2\sin \theta \sin 2\theta }{\cos \theta +\cos 3\theta }=\tan 2\theta \tan \theta $\begin{align}L.H.S.&amp;=\dfrac{2\sin \theta \sin 2\theta }{\cos \theta +\cos 3\theta }\\
&amp;=\dfrac{2\sin \theta \s…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise 10</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise 10

Solutions of Question 4 &amp; 5 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\sin }^{2}}\dfrac{\theta }{2}=\dfrac{\sin \theta \tan \dfrac{\theta }{2}}{2}$\begin{align}R.H.S.&amp;=\dfrac{\sin \theta \tan \dfrac{\theta }{2}}{2}\\
&amp;=\dfrac{\sin \theta \sin \dfrac{\theta }{2}}{2\cos \d…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7, Review Exercise 10</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 6 &amp; 7, Review Exercise 10

Solutions of Question 6 &amp; 7 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos 4\theta =1-8{{\sin }^{2}}\theta {{\cos }^{2}}\theta $\begin{align}L.H.S&amp;=\cos 4\theta \\
&amp;=\cos 2\left( 2\theta  \right)\\
&amp;=1-2si{{n}^{2}}2\theta \\
&amp;=1-2{{\left( 2sin\theta \cos \theta  \right)}^{…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 &amp; 3, Exercise 1.1

Solutions of Question 2 &amp; 3 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
${{i}^{107}}+{{i}^{112}}+{{i}^{122}}+{{i}^{153}}=0$\begin{align}L.H.S.&amp;={{i}^{107}}+{{i}^{112}}+{{i}^{122}}+{{i}^{153}}\\
&amp;=i\cdot i^{106}+i^{112}+i^{122}+i\cdot i^{152}\\
&amp;=i.{{\left( {{i}^{2}} \right)}^{53}}+{{\left( {{i}^{2}} \right)}^{56}}+…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 4, Exercise 1.1

Solutions of Question 4 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)
$\left( a,0 \right)\left( 2,-b \right)$\begin{align}&amp;\left( a,0 \right)-\left( 2,-b \right)\\
&amp;=\left( a+0i \right)-\left( 2-bi \right)\\
&amp;=\left( a-2 \right)+\left( 0+b \right)i\\
&amp;=\left( a-2 \right)+bi\end{align}$\left( -3,\dfrac{1}{2} \right)\le…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p4?rev=1737476037&amp;do=diff">
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 1.1

Solutions of Question 5 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$8i+11,-7+5i$\begin{align}&amp;(8i+11)\times (-7+5i)\\
&amp;=\left( 11+8i \right)\times \left( -7+5i \right)\\
&amp;=\left( -77+40{{i}^{2}} \right)+\left( 55-56 \right)i\\
&amp;=\left( -77+40\left( -1 \right) \right)+\left( 55-56 \right)i\\
&amp;=\left( -77-40 \right)+…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 6, Exercise 1.1

Solutions of Question 6 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
$\dfrac{4+i}{3+5i}$$a+ib$\begin{align}\dfrac{4+i}{3+5i}&amp;=\dfrac{4+i}{3+5i}\times \dfrac{3-5i}{3-5i}\\
&amp;=\dfrac{\left( 12+5 \right)+\left( 3-20 \right)i}{9-25{{i}^{2}}}\\
&amp;=\dfrac{17-17i}{9+25}\\
&amp;=\dfrac{17}{34}-\dfrac{17}{34}i\\
&amp;=\dfrac{1}{2}-\dfr…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 1.1

Solutions of Question 7 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
${{z}_{1}}=1+2i$${{z}_{2}}=2+3i$$|{{z}_{1}}+{{z}_{2}}|$$z_1=1+2i$$z_2=2+3i$\begin{align}
{{z}_{1}}+{{z}_{2}}&amp;=1+2i+2+3i\\
&amp;=1+2+2i+3i\\
&amp;=3+5i
\end{align}\begin{align}
|z_1+z_2|&amp;=\sqrt{3^2+5^2}\\
&amp;=\sqrt{9+25}\\ 
&amp;=\sqrt{34}\end{align}${{z}_{1}}=1+2…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 8, Exercise 1.1

Solutions of Question 8 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$\dfrac{1-2i}{2+i}+\dfrac{4-i}{3+2i}$$a+ib.$\begin{align}&amp;\dfrac{1-2i}{2+i}+\dfrac{4-i}{3+2i}\\
&amp;=\dfrac{\left( 3+2i \right)\left( 1-2i \right)+\left( 2+i \right)\left( 4-i \right)}{\left( 2+i \right)\left( 3+2i \right)}\\
&amp;=\dfrac{\left( 3+4+2i-6i …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 1.1

Solutions of Question 9 &amp; 10 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$\dfrac{\left( 3-2i \right)\left( 2+3i \right)}{\left( 1+2i \right)\left( 2-i \right)}$\begin{align}z&amp;=\dfrac{\left( 3-2i \right)\left( 2+3i \right)}{\left( 1+2i \right)\left( 2-i \right)}\\
&amp;=\dfrac{6+6+9i-4i}{2+2+4i-i}\\
&amp;=\dfrac{12+5i}{4+3…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 1.2

Solutions of Question 2 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2

$z_1=-1+i$, $z_2=3-2i$${{z}_{3}}=2-2i$${{z}_{1}}=-1+i$${{z}_{2}}=3-2i$${{z}_{3}}=2-2i$$$(z_1+z_2)+z_3=z_1+(z_2+z_3).$$\begin{align} 
{{z}_{1}}+{{z}_{2}}&amp;=\left( -1+i \right)+\left( 3-2i \right)\\
&amp;=2-i\end{align}\begin{align}
\left( {{z}_{1}}+{{z}_{2}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 1.2

Solutions of Question 3 &amp; 4 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
${{z}_{1}}=\sqrt{3}+\sqrt{2}i$${{z}_{2}}=\sqrt{2}-\sqrt{3}i$${{z}_{3}}=2+3i$${{z}_{1}}=\sqrt{3}+\sqrt{2}i$${{z}_{2}}=\sqrt{2}-\sqrt{3}i$${{z}_{3}}=2+3i$\begin{align}{{z}_{1}}\left( {{z}_{2}}+{{z}_{3}} \right)&amp;={{z}_{1}}{{z}_{2}}+{{z}_{1}}{{z}_{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 1.2

Solutions of Question 5 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
${{z}_{1}}=2+4i$${{z}_{2}}=1-3i$$\overline{{{z}_{1}}+{{z}_{2}}}=\overline{{{z}_{1}}}+\overline{{{z}_{2}}}$${{z}_{1}}=2+4i$${{z}_{2}}=1-3i$$\overline{{{z}_{1}}}=2-4i$$\overline{{{z}_{2}}}=1+3i$\begin{align}z_1+z_2&amp;=2+4i+1-3i\\
&amp;=3+i \end{align}\begin…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 6, Exercise 1.2

Solutions of Question 6 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
${{z}_{1}}$${{z}_{2}}$$|{{z}_{1}}{{z}_{2}}|=|{{z}_{1}}||{{z}_{2}}|$${{z}_{1}}=a+bi$${{z}_{2}}=c+di$$|z_1=\sqrt{a^2+b^2}|$$|z_2=\sqrt{c^2+d^2}|$\begin{align}
L.H.S.&amp;=|{{z}_{1}}{{z}_{2}}|\\
&amp;=|(a+bi)(c+di)|\\ 
&amp;=|ac-bd+(ad+bc)i|\\
&amp;=\sqrt{{{(ac-bd)}^{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 1.2

Solutions of Question 7 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$\dfrac{2+3i}{5-2i}$\begin{align}&amp;\dfrac{2+3i}{5-2i} \\
=&amp;\dfrac{2+3i}{5-2i}\times \dfrac{5+2i}{5+2i} \quad \text{by rationalizing} \\
=&amp;\dfrac{10-6+15i+4i}{25+4}\\
=&amp;\dfrac{4+19i}{29}\\
=&amp;\dfrac{4}{29}+\dfrac{19}{29}i \end{align}$=\dfrac{4}{29}$$=\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 8, Exercise 1.2

Solutions of Question 8 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$z+\overline{z}=2\operatorname{Re}\left( z \right)$$z=a+ib$$\overline{z}=a-ib$\begin{align}z+\overline{z}&amp;=\left( a+ib \right)+\left( a-ib \right)\\
&amp;=a+ib+a-ib\\
&amp;=2a\\
z+\overline{z}&amp;=2\operatorname{Re}\left( z \right)\end{align}$z-\overline{z}=2i…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 1.3

Solutions of Question 2 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$P(z)$$$P\left( z \right)={{z}^{3}}+6z+20$$$$p\left( z \right)={{z}^{3}}+6z+20$$$(z-a)$$P(z)$$P(a)=0$$z=-2$\begin{align}
P(-2)&amp;=(-2)^3+6(-2)+20\\
&amp;=-8-12+20\\
&amp;=0\end{align}$z+2$${{z}^{3}}+6z+20$$$\begin{array}{c|cccc}
-2 &amp; 1 &amp; 0 &amp; 6 &amp; 20 \\  
 &amp; \d…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 1.3

Solutions of Question 3 &amp; 4 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
${{z}_{1}}=-1+i$${{z}_{2}}=-1-i$${{z}^{2}}+2z+2=0$$$z^2+2z_1+2=0\quad \ldots (i)$$$z_1=-1+i$\begin{align}L.H.S &amp;= (-1+i)^2+2(-1+i)+2\\
&amp;=1-2i-1-2+2i+2\\
&amp;=0=R.H.S\end{align}$z_1=-1+i$$z_2=-1-i$\begin{align}
L.H.S&amp;=(-1-i)^2+2(-1-i)+2\\
&amp;=1+2i-1-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 1.3

Solutions of Question 5 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
${{z}^{2}}+z+3=0$$${{z}^{2}}+z+3=0.$$$a=1$$b=1$$c=3$\begin{align}z&amp;=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\\ 
&amp;=\dfrac{-1\pm \sqrt{{{\left( 1 \right)}^{2}}-4\left( 1 \right)\left( 3 \right)}}{2\left( 1 \right)}\\
&amp;=\dfrac{-1\pm \sqrt{1-12}}{2}\\
&amp;=\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3, Review Exercise 1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 &amp; 3, Review Exercise 1

Solutions of Question 2 &amp; 3 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{i}^{n}}+{{i}^{n+1}}+{{i}^{n+2}}+{{i}^{n+3}}=0$$\forall n\in N$\begin{align}{{i}^{n}}+{{i}^{n+1}}+{{i}^{n+2}}+{{i}^{n+3}}&amp;=0\\
L.H.S.&amp;={{i}^{n}}+{{i}^{n}}\cdot i+{{i}^{n}}\cdot {{i}^{2}}+{{i}^{n}}\cdot {{i}^{3}}\\
&amp;={{i}^{n}}\left( 1+i+{{i}^{2}}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise 1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise 1

Solutions of Question 4 &amp; 5 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{z}_{1}}=2-i$${{z}_{2}}=1+i,$$\left|\dfrac{{{z}_{1}}+{{z}_{2}}+1}{{{z}_{1}}-{{z}_{2}}+1}\right|$$z_1=2-i$$z_2=1+i$\begin{align}
\dfrac{{{z}_{1}}+{{z}_{2}}+1}{{{z}_{1}}-{{z}_{2}}+1}&amp;=\dfrac{\left( 2-i \right)+\left( 1+i \right)+1}{\left( 2-i \rig…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 2.1

Solutions of Question 2 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$A=\begin{bmatrix}2 &amp; -5 &amp; 1\\ 3 &amp; 0 &amp; -4\end{bmatrix}$$B=\begin{bmatrix}1 &amp; -2 &amp; -3 \\ 0 &amp; -1 &amp; 5\end{bmatrix}$$C=\begin{bmatrix}0 &amp; 1 &amp; -2\\0 &amp; -1 &amp; -1\end{bmatrix}$$2A+3B-4C.$$A=\begin{bmatrix}2 &amp; -5 &amp; 1\\ 3 &amp; 0 &amp; -4\end{bmatrix}$$B=\begin…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3, Exercise 2.1

Solutions of Question 3 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3(i)
$A=\begin{bmatrix}x &amp; y &amp; z\end{bmatrix}$$B=\begin{bmatrix}a &amp; h &amp; g\\h &amp; b &amp; f\\g &amp; f &amp; c\end{bmatrix}$$C=\begin{bmatrix}x\\y\\z\end{bmatrix}$$\left( AB \right)C=A\left( BC \right)$$A=\begin{bmatrix}x &amp; y &amp; z\end{bmatrix}$$B=\begin{bmatri…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 4, Exercise 2.1

Solutions of Question 4 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$A= \begin{bmatrix}1 &amp; 4 &amp; 4  \\ 4 &amp; 1 &amp; 4  \\ 4 &amp; 4 &amp; 1 \end{bmatrix}$$\dfrac{1}{3}A^2-2A-9I=0$$A=\begin{bmatrix} 1 &amp; 4 &amp; 4  \\ 4 &amp; 1 &amp; 4  \\ 4 &amp; 4 &amp; 1 \end{bmatrix}$\begin{align}\frac{1}{3}A^2&amp;=\frac{1}{3}\left[ \begin{matrix}
   1 &amp; 4 &amp; 4 …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 5 &amp; 6, Exercise 2.1

Solutions of Question 5 &amp; 6 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$A= \begin{bmatrix} 0 &amp; 2b &amp; -2  \\ 3 &amp; 1 &amp; 3  \\ 3a &amp; 3 &amp; -1 \end{bmatrix}$$a$$b$$A=\begin{bmatrix} 0 &amp; 2b &amp; -2  \\ 3 &amp; 1 &amp; 3  \\ 3a &amp; 3 &amp; -1 \end{bmatrix}$$$A^t=\left[ \begin{matrix}
   0 &amp; 3 &amp; 3a  \\
   2b &amp; 1 &amp; 3  \\
   -2 &amp; 3 &amp; -1  \\
\end{ma…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 2.1

Solutions of Question 7 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$ A=\begin{bmatrix}1 &amp; 0 &amp; -1 &amp; 2  \\3 &amp; 1 &amp; 2 &amp; \quad 5  \\0 &amp; -2 &amp; 1 &amp; 6\end{bmatrix}$$ B=\begin{bmatrix} 2 &amp; -1 &amp; 3 &amp; 1  \\1 &amp; 3 &amp; -1 &amp; 4  \\3 &amp; 1 &amp; 2 &amp; -1 \end{bmatrix}$$( A+B )^t=A^t+B^t$$A=\left[  \begin{matrix}1 &amp; 0 &amp; -1 &amp; 2  \\3 &amp; 1 &amp;…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 8, Exercise 2.1

Solutions of Question 8 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$A=\begin{bmatrix}1 &amp; 2 &amp; 0  \\3 &amp; -1 &amp; 4 \end{bmatrix}$$( A^t )^t=A$$$A=\left[ \begin{matrix}
   1 &amp; 2 &amp; 0  \\
   3 &amp; -1 &amp; 4  \\
\end{matrix}  \right]$$$$A^t=\left[  \begin{matrix}
   1 &amp; 3  \\
   2 &amp; -1  \\
   0 &amp; 4  \\
\end{matrix} \rig…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 9, Exercise 2.1

Solutions of Question 9 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)
$A=\begin{bmatrix}2 &amp; -1 &amp; 3  \\1 &amp; \quad 0 &amp; 1 \end{bmatrix},$$B=\begin{bmatrix}1 &amp; 2  \\2 &amp; 2  \\ 3 &amp; 0 \end{bmatrix}$$( AB )^t=B^tA^t$$$A=\left[  \begin{matrix}
   2 &amp; -1 &amp; 3  \\
   1 &amp; \quad 0 &amp; 1  \\
\end{matrix}  \right],$$$$B=\left[…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p9?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p9?rev=1737476037&amp;do=diff</link>
        <description>Question 10, Exercise 2.1

Solutions of Question 10 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 10
$A=\begin{bmatrix}1 &amp; -3 &amp; 4  \\-3 &amp; 2 &amp; -5  \\4 &amp; -5 &amp; 0 \end{bmatrix}$$B=\begin{bmatrix}5 &amp; 6 &amp; 7 \\6 &amp; -8 &amp; 3  \\7 &amp; 3 &amp; 1 \end{bmatrix}$$A$$B$$A+B$$$A=\left[ \begin{matrix}
   1 &amp; -3 &amp; 4  \\
   -3 &amp; 2 &amp; -5  \\
   4 &amp; -5 &amp; 0  \\
\end{ma…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p10?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p10?rev=1737476037&amp;do=diff</link>
        <description>Question 11, Exercise 2.1

Solutions of Question 11 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11
$A=\begin{bmatrix}0 &amp; 1 &amp; -2  \\-1 &amp; 0 &amp; 3  \\2 &amp; -3 &amp; 0 \end{bmatrix}$$B=\begin{bmatrix}0 &amp; -6 &amp; 11  \\6 &amp; 0 &amp; -7  \\-11 &amp; 7 &amp; 0 \end{bmatrix}$$A+B$$$A=\left[ \begin{matrix}
   0 &amp; 1 &amp; -2  \\
   -1 &amp; 0 &amp; 3  \\
   2 &amp; -3 &amp; 0  \\
\end{matri…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p11?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p11?rev=1737476037&amp;do=diff</link>
        <description>Question 12, Exercise 2.1

Solutions of Question 12 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 12(i)
$A=\begin{bmatrix}3 &amp; 2 &amp; 1  \\4 &amp; 5 &amp; 6  \\-2 &amp; 3 &amp; 4\end{bmatrix}$$A+A^t$$$A=\left[ \begin{matrix}
   3 &amp; 2 &amp; 1  \\
   4 &amp; 5 &amp; 6  \\
   -2 &amp; 3 &amp; 4  \\
\end{matrix} \right]$$$$A^t=\left[ \begin{matrix}
   3 &amp; 4 &amp; -2  \\
   2 &amp; 5 &amp; 3  \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 2.2

Solutions of Question 2 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$$\left| \begin{matrix}
   1 &amp; 2 &amp; 0  \\
   3 &amp; 1 &amp; 0  \\
   -1 &amp; 2 &amp; 0  \\
\end{matrix} \right|=0$$$\left| \begin{matrix}1 &amp; 2 &amp; 3  \\-8 &amp; 4 &amp; -12  \\2 &amp; -1 &amp; 3 \end{matrix} \right|=0$$$\left| \begin{matrix}
   1 &amp; 2 &amp; 3  \\
   -8 &amp; 4 &amp; -…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3, Exercise 2.2

Solutions of Question 3 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
$A$$3,$$|A^t|=|A|$$$A=\begin{bmatrix}
   a_{11} &amp; a_{12} &amp; a_{13}  \\
   a_{21} &amp; a_{22} &amp; a_{23}  \\
   a_{31} &amp; a_{32} &amp; a_{33}  \\
\end{bmatrix}$$\begin{align}|A|&amp;=a_{11} \left( a_{22} a_{33}-a_{23} a_{32} \right)-a_{12}\left( a_{21}a_{33}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 4, Exercise 2.2

Solutions of Question 4 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)
$\left| \begin{matrix}0 &amp; 1 &amp; 3  \\-1 &amp; 2 &amp; 1  \\2 &amp; 1 &amp; 1 \end{matrix} \right|.$\begin{align}&amp;\left| \begin{matrix}
   0 &amp; 1 &amp; 3  \\
   -1 &amp; 2 &amp; 1  \\
   2 &amp; 1 &amp; 1  \\
\end{matrix} \right| \\
=&amp;0\left( 2-1 \right)-1\left( -1-2 \right)+3\l…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 2.2

Solutions of Question 5 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$\begin{vmatrix}a &amp; b &amp; c\\l &amp; m &amp; n\\x &amp; y &amp; z \end{vmatrix}=\begin{vmatrix}a &amp; l &amp; x\\b &amp; m &amp; y\\c &amp; n &amp; z \end{vmatrix}$\begin{align}L.H.S.&amp;=\begin{vmatrix}
a &amp; b &amp; c  \\
l &amp; m &amp; n  \\
x &amp; y &amp; z
\end{vmatrix}\\
&amp;=\begin{vmatrix}
a &amp; b &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 6, Exercise 2.2

Solutions of Question 6 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Questiopn 6(i)
$\left| \begin{matrix}a-b &amp; b-c &amp; c-a  \\b-c &amp; c-a &amp; a-b  \\c-a &amp; a-b &amp; b-c  \end{matrix} \right|=0$\begin{align} L.H.S&amp;=\left| \begin{matrix}
a-b &amp; b-c &amp; c-a  \\
b-c &amp; c-a &amp; a-b  \\
c-a &amp; a-b &amp; b-c  \\
\end{matrix} \right| \\ 
&amp;=\left| \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 2.2

Solutions of Question 7 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$\left| \begin{matrix}3860 &amp; 3861  \\3862 &amp; 3863 \end{matrix} \right|$$$\left| \begin{matrix}
   3860 &amp; 3861  \\
   3862 &amp; 3863  \\
\end{matrix} \right|=14911180-14911182$$$$=-2$$$\left| \begin{matrix}81 &amp; 82 &amp; 83  \\84 &amp; 85 &amp; 86  \\87 &amp; 8…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8,9 &amp; 10, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 8,9 &amp; 10, Exercise 2.2

Solutions of Questions 8,9 &amp; 10 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\left| \begin{matrix}1+x &amp; y &amp; z  \\x &amp; 1+y &amp; z  \\x &amp; y &amp; 1+z \end{matrix} \right|=1+x+y+z$$$L.H.S.=\left| \begin{matrix}
   1+x &amp; y &amp; z  \\
   x &amp; 1+y &amp; z  \\
   x &amp; y &amp; 1+z  \\
\end{matrix} \right|$$$$=\left| \begin{matrix}
   1 &amp; 0 &amp; -…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p9?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p9?rev=1737476037&amp;do=diff</link>
        <description>Question 11, Exercise 2.2

Solutions of Question 11 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11(i)
$\left[ \begin{matrix}7 &amp; 1 &amp; 3  \\6 &amp; 2 &amp; -2  \\5 &amp; 1 &amp; 1\end{matrix} \right]$$$A=\left[ \begin{matrix}
   7 &amp; 1 &amp; 3  \\
   6 &amp; 2 &amp; -2  \\
   5 &amp; 1 &amp; 1  \\
\end{matrix} \right]$$$$|A|=7(2+2)-1(6+10)+3(6-10)$$$$=28-16-12$$$$|A|=0$$$A$$\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p10?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p10?rev=1737476037&amp;do=diff</link>
        <description>Question 12, Exercise 2.2

Solutions of Question 12 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 12
$\lambda $$A$$A=\begin{bmatrix}-\lambda  &amp; 1 &amp; 0  \\1 &amp; -\lambda  &amp; 1  \\0 &amp; 1 &amp; -\lambda \end{bmatrix}$$$A=\left[ \begin{matrix}
   -\lambda  &amp; 1 &amp; 0  \\
   1 &amp; -\lambda  &amp; 1  \\
   0 &amp; 1 &amp; -\lambda   \\
\end{matrix} \right]$$$$|A|=-\lamb…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p11?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p11?rev=1737476037&amp;do=diff</link>
        <description>Question 13, Exercise 2.2

Solutions of Question 13 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 13(i)
$x,$$\left| \begin{matrix}x &amp; 2 &amp; 3  \\0 &amp; -1 &amp; 1  \\0 &amp; 4 &amp; 5 \end{matrix} \right|=9$$$\left| \begin{matrix}
   x &amp; 2 &amp; 3  \\
   0 &amp; -1 &amp; 1  \\
   0 &amp; 4 &amp; 5  \\
\end{matrix} \right|=9$$$$x(-5-4)-2(0)+3(0)=9$$$$-9x=9$$$$x=-1$$$x,$$\left…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p12?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 &amp; 15, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p12?rev=1737476037&amp;do=diff</link>
        <description>Question 14 &amp; 15, Exercise 2.2

Solutions of Questions 14 &amp; 15 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$A=\begin{bmatrix}0 &amp; 2 &amp; 2  \\-1 &amp; 3 &amp; 2  \\1 &amp; 0 &amp; 5\end{bmatrix}$$A^{-1}$$$A=\left[ \begin{matrix}
   0 &amp; 2 &amp; 2  \\
   -1 &amp; 3 &amp; 2  \\
   1 &amp; 0 &amp; 5  \\
\end{matrix} \right]$$$A^{-1}$$$A^{-1}=\dfrac{Adj\,\,A}{|A|}$$$$Adj\,\,A={{\left[ \begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p13?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 16 &amp; 17, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p13?rev=1737476037&amp;do=diff</link>
        <description>Question 16 &amp; 17, Exercise 2.2

Solutions of Questions 16 &amp; 17 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$A=\begin{bmatrix}3 &amp; -1  \\4 &amp; 2\end{bmatrix}$$|A^{-1}|=\dfrac{1}{|A|}$$$A=\left[ \begin{matrix}
   3 &amp; -1  \\
   4 &amp; 2  \\
\end{matrix} \right]$$$$|A|=6+4$$$$\Rightarrow |A|=10\ldots (1)$$$$A^{-1}=\dfrac{1}{|A|}AdjA$$$$AdjA=\left[ \begin{ma…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p14?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 18, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p14?rev=1737476037&amp;do=diff</link>
        <description>Question 18, Exercise 2.2

Solutions of Question 18 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 18(i)
$A$$B$$( A^{-1})^{-1}=A$$A$$2\times 2$$$A=\left[ \begin{matrix}
   a_{11} &amp; a_{12}  \\
   a_{21} &amp; a_{22}  \\
\end{matrix} \right]$$$$|A|=a_{11}a_{22}-a_{12}a_{21}$$$$AdjA=\left[ \begin{matrix}
   a_{22} &amp; -a_{12}  \\
   -a_{21} &amp; a_{11…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 2.3

Solutions of Question 2 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$$\begin{bmatrix}4 &amp; -2 &amp; 5 \\ 2 &amp; 1 &amp; 0  \\ -1 &amp; 2 &amp; 3  \end{bmatrix}$$$$A=\begin{bmatrix}
4 &amp; -2 &amp; 5  \\
2 &amp; 1 &amp; 0  \\
-1 &amp; 2 &amp; 3 \end{bmatrix}.$$\begin{align}|A|&amp;=\begin{vmatrix}4 &amp; -2 &amp; 5  \\ 2 &amp; 1 &amp; 0  \\ -1 &amp; 2 &amp; 3 \end{vmatrix}\\
&amp;=…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3, Exercise 2.3

Solutions of Question 3 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3(i)
$$\left[ \begin{matrix}
   1 &amp; 0 &amp; -2  \\
   2 &amp; 2 &amp; 1  \\
   -1 &amp; 2 &amp; 3  \\
\end{matrix} \right]$$\begin{align}&amp;\begin{bmatrix}
1 &amp; 0 &amp; -2  \\
2 &amp; 2 &amp; 1  \\
-1 &amp; 2 &amp; 3 \end{bmatrix}\\
\underset{\sim}{R}&amp; \begin{bmatrix}
1 &amp; 0 &amp; -2  \\
0 &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 3.2

Solutions of Question 2 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)

Find unit vector having the same direction as the vector $3\hat{i}.$$$\overset{\scriptscriptstyle\rightharpoonup}{a}=3\hat{i}$$$$|\overset{\scriptscriptstyle\rightharpoonup}{a}|=\sqrt{{{(3)}^{2}}}=3$$$$\hat{a}=\dfrac{{\overset{\scriptscriptstyle\rightharpo…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 3.2

Solutions of Question 3 &amp; 4 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3

If $\vec{r}=\hat{i}-9\hat{j}$$\vec{a}=\hat{i}+2\hat{j}$$\vec{b}=5\hat{i}-\hat{j}$$p$$q$$\vec{r}=p\vec{a}+q\vec{b}$$$\vec{r}=p\vec{a}+q\vec{b}.$$$\vec{r},\vec{a}$$\vec{b}$$$\hat{i}-9\hat{j}=p(\hat{i}+2\hat{j})+q(5\hat{i}-\hat{j})$$$$\implies \hat{i}-9\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5 &amp; 6, Exercise 3.2

Solutions of Question 5 &amp; 6 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5

Find the length of the vector $\overrightarrow{AB}$$\vec{A}(-3,5)$$\vec{B}(7,9)$$\overrightarrow{AB}$$\vec{A}$$\vec{B}$$$\overrightarrow{OA}=-3\hat{i}+5\hat{j},$$$$\overrightarrow{OB}=7\hat{i}+9\hat{j}.$$\begin{align}\overrightarrow{AB}&amp;=\overrightarr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 3.2

Solutions of Question 7 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)

Find the components and the magnitude of $\overrightarrow{PQ}$$P(-1,2)$$Q(2,-1)$\begin{align}\overrightarrow{PQ}&amp;=\overrightarrow{OQ}-\overrightarrow{OP}\\ 
&amp;=(2\hat{i}-\hat{j})-(-\hat{i}+2\hat{j})\\ 
&amp;=3\hat{i}-3\hat{j}\end{align}\begin{align}|\overrighta…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 3.2

Solutions of Question 7 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)

Find the components and the magnitude of $\overrightarrow{PQ}$$P(-1,2)$$Q(2,-1)$\begin{align}\overrightarrow{PQ}&amp;=\overrightarrow{OQ}-\overrightarrow{OP}\\ 
&amp;=(2\hat{i}-\hat{j})-(-\hat{i}+2\hat{j})\\ 
&amp;=3\hat{i}-3\hat{j}\end{align}\begin{align}|\overrighta…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 3.2

Solutions of Question 9 &amp; 10 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$\overrightarrow{a}=\hat{i}+\hat{j}+\hat{k}, $$$ and $$, find a vector of magnitude of $$ unit which is parallel to the vector $\begin{align}2\overrightarrow{a}-\overrightarrow{b}+3\overrightarrow{c}&amp;=2(\hat{i}+\hat{j}+\hat{k})-(4\hat{i}-2\hat{j}+3\h…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 11, Exercise 3.2

Solutions of Question 11 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11(i)

Find the position vectors of the point of division of the line segments joining point $C$$5\hat{j}$$D$$4\hat{i}+\hat{j}$$2:5$$C$$\overrightarrow{OC}=5\hat{j}$$D$$\overrightarrow{OD}=4\hat{i}+\hat{j}$$H$$\overline{CD}$$2:5$$H$\begin{align}\overrightarrow…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3 Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 and 3 Exercise 3.3

Solutions of Question 2 and 3 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$$\vec{a}=2 \hat{i} + 2 \hat{j}-5 \hat{k}, \quad \vec{b}=2 \hat{i}+\hat{j}-7 \hat{k}$$\begin{align}\vec{a}+\vec{b}&amp;=(2 \hat{i}+2 \hat{j}-5 \hat{k})+(2 \hat{i}+\hat{j}-7 \hat{k}) \\
\Rightarrow &amp;=4 \hat{i}+3 \hat{j}-12 \hat{k}\\
\Rightarrow|\vec{a}+\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 and 5 Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 4 and 5 Exercise 3.3

Solutions of Question 4 and 5 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\hat{i}+7 \hat{j} + 3 \hat{k}$$\hat{i}-\hat{j}+2 \hat{k}$$2 \hat{i}-$$\hat{j}+3 \hat{k}$$\vec{a}=\hat{i}+7 \hat{j}+3 \hat{k}$$\vec{b}=\hat{i}-\hat{j}+2 \hat{k}$$\vec{c} = 2 \hat{i}-\hat{j}-3 \hat{k}$\begin{align}\vec{a} \cdot \vec{b}&amp;=(\hat{i}+7 \h…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 6 Exercise 3.3

Solutions of Question 6 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)

Let $\vec{a}=\hat{i}+3 \hat{j}-4 \hat{k}$ and $\vec{b}=2 \hat{i}-3 \hat{j}-5 \hat{k}$$m$$\vec{a}+m \vec{b}$$\vec{a}$\begin{align}
\vec{a}+m \vec{b}&amp; =\hat{i}+3 \hat{j}-4 \hat{k}+m(2 \hat{i}-3 \hat{j}+5 \hat{k}) \\
&amp; =(1+2 m) \hat{i}+(3-3 m) \hat{j}+(5 m-4) …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 3.3

Solutions of Question 7 &amp; 8 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$\vec{a}$$\vec{b}$$\vec{a}=-\dfrac{3}{2} \hat{j}+\dfrac{4}{5} \hat{k} \cdot \vec{b}=\hat{i}-2 \hat{j}-2 \hat{k}$$\vec{a}$$\vec{b}$$\vec{b}$$\vec{a}$$\vec{a}=-\dfrac{3}{2} \hat{j}+\dfrac{4}{5} \hat{k}\quad$$\vec{b}=\hat{i}-2 \hat{j}-2 \hat{k}$\begin{a…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 3.3

Solutions of Question 9 &amp; 10 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$\vec{k}-2 \hat{i}+3 \hat{j}+\hat{k}$$\vec{S}=2 \hat{i}+\hat{j}-\hat{k}$\begin{align}W &amp;=\vec{F} \cdot s \\
\Rightarrow W &amp;=(2 \hat{i}+3 \hat{j}+\hat{k}) \cdot(2 \hat{i}+\hat{j}-\hat{k}) \\
\Rightarrow W &amp;=2(2) \div 3(1)+1(-1) \\
\Rightarrow W &amp;=4+3 …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 11, Exercise 3.3

Solutions of Question 11 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11 (i)

Show that the vectors $3 \hat{i}-2 \hat{j}+$$\hat{k} . \quad \hat{i}-3 \hat{j}-5 \hat{k}$$2 \hat{i}+\hat{j}-4 \hat{k}$$\vec{a}=3 \hat{i}-2 \hat{j}+\hat{k}$$\vec{b}=\hat{i}-3 \hat{j}+5 \hat{k}$$\vec{c}=2 \hat{i}+\hat{j}-4 \hat{k}$\begin{align}|\vec{a}|&amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 Exercise 3.4

Solutions of Question 2 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)

Show in two different ways that the vectors $\vec{a}$$\vec{b}$$\vec{a}=-\hat{i}+2 \hat{j}-3 \hat{k}, \quad \vec{b}=2 \hat{i}-4 \hat{j}+$$6 \hat{k}$\begin{align}\vec{a} \times \vec{b}&amp;=\left|\begin{array}{ccc}
\hat{i} &amp; \hat{j} &amp; \hat{k} \\
-1 &amp; 2 &amp; -3 \\
2 …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3 Exercise 3.4

Solutions of Question 3 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3(i)

Find a unit vector that is orthogonal to
the given vector $\vec{a}=\hat{i}- 2 \hat{j}+3 \hat{k}, \quad \vec{b}=2 \hat{i}+\hat{j}-\hat{k}$$\hat{n}$$\vec{a}$$\vec{b}$\begin{align}\hat{n}&amp;=\dfrac{\vec{a} \times \vec{b}}{\mid \vec{a} \times \vec{b}} \\
\text { …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 4 Exercise 3.4

Solutions of Question 4 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)

If $\vec{a}=3 \hat{i}-6 \hat{j}+5 \hat{k},\quad\vec{b}=2\hat{i}-\hat{j}+4 \hat{k} \quad$ and $\quad \vec{c}=\hat{i}+\hat{j} \quad \hat{k},\quad$$\vec{a} \times \vec{b}$\begin{align}\vec{a} \times \vec{b}&amp;=\left|\begin{array}{ccc}
\hat{i} &amp; \hat{j} &amp; \hat{k}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 5 Exercise 3.4

Solutions of Question 5 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)

Use the vector product to compute the area of the triangle with the given vertices $P(-2,-3), \quad Q(3,2)\quad$$\quad R(-1,-8)$$P Q$$\bar{P} R$\begin{align}\text{Area of triangle}&amp;=\dfrac{1}{2}|\overrightarrow{P Q} \times \overrightarrow{P R}| \\
\text { S…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 6 Exercise 3.4

Solutions of Question 6 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)

A force $\vec{F}=3 \hat{i}-2 \hat{j}+5 \hat{k}$$(1,-2,2)$$\vec{r}$$P(1,-2.2)$$O(0,0,0)$\begin{align}\vec{r}&amp;=\overrightarrow{O P}\\
&amp;=(1,-2,2)-(0,0,0) \\
\Rightarrow \vec{r}&amp;=(1,-2,2).\\
\text { Hence } \vec{M}-\vec{r} \times \vec{F}&amp;=\left|\begin{array}{cc…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 3.4

Solutions of Question 7 &amp; 8 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7

If $\vec{A}+\vec{B}+\vec{C}=\vec{O}$$$\vec{A} \times \vec{B}=\vec{B} \times \vec{C}=\vec{C} \times \vec{A}.$$$$\vec{A}+\vec{B}+\vec{C}=\vec{O} \text {. }$$$\vec{A}$$$\vec{A} \times(\vec{A}+\vec{B}+\vec{C})=0$$\begin{align}\Rightarrow \vec{A} \times \ve…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 &amp; 4 Exercise 3.5

Solutions of Question 3 &amp; 4 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3

For the vectors $\vec{a}=3 \hat{i}+2 \hat{k}$$\vec{b}=\hat{i}+2 \hat{j}+\hat{k}\quad$$\quad\vec{c}=-\hat{j}+4 \hat{k}$$\vec{a} \cdot \vec{b} \times \vec{c}=\vec{b} \cdot \vec{c} \times \vec{a}=\vec{c} \cdot \vec{a} \times \vec{b}$$\vec{a} \cdot \vec{b}…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5(i) &amp; 5(ii) Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5(i) &amp; 5(ii) Exercise 3.5

Solutions of Question 5(i) &amp; 5(ii) of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$\vec{a}=a_1 \hat{i}+a_2 \hat{j}+a_3 \hat{k}\quad$$\quad\vec{b}=b_1 \hat{i}+b_2 \hat{j}+b_3 \hat{k}\quad$$\vec{a} \times \vec{b}\quad$$\vec{a} \times \vec{b}$$\vec{a}$$\vec{b}$$\vec{a} \times \vec{b}$$\vec{a}$$\vec{b}$$\vec{a} \times \v…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5(iii) &amp; 5(iv) Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 5(iii) &amp; 5(iv) Exercise 3.5

Solutions of Question 5(iii) &amp; 5(iv) of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\vec{a}=a_1 \hat{i}+a_2 \hat{j}+a_3 \hat{k}\quad$$\quad\vec{b}=b_1 \hat{i}+b_2 \hat{j}+b_3 \hat{k}\quad$$(\vec{a}. \vec{b})^2,\quad|a|^2,\quad|b|^2$\begin{align}\vec{a} \cdot \vec{b}&amp;=(a_1 \hat{i}+a_2 \hat{j} + a_3 \hat{k}) \cdot(b_1 \hat{i}+b_2 \…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 3.5

Solutions of Question 6 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6

Do the points $(4. 2.1)$$(5,1,6)$$(2.2,-5)$$(3.5 .0)$$A(4,-2,1), B(5,1,6)$$C(2,2,-5)$$D(3,5.0)$$A, \overrightarrow{O A}=4 \hat{i}-2 \hat{j}+\hat{k}$$B, \overrightarrow{O B}=5 \hat{i}+\hat{j}+6 \hat{k}$$C, \overrightarrow{O C}=2 \hat{i}+2 \hat{i}-5 \hat{k}$$D, …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 3.5

Solutions of Question 7 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)

For what value of $c$$\vec{u}=\hat{i}+2 \hat{j}+3 \hat{k}$$\vec{v}=2 \hat{i}-3 \hat{j}+4 \hat{k} \cdot \vec{w}=3 \hat{i}+\hat{j}+c \hat{k}$\begin{align}\vec{u} \cdot \vec{v} \times \vec{w}&amp;=0\\
\vec{u} \cdot \vec{v} \times \vec{w}&amp;=0\\
\Rightarrow\left|\beg…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 3.5

Solutions of Question 8 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)

Find the volume of tetrahedron with the Vectors as coterminous edges
\begin{align}\vec{a}&amp;=\hat{i}+2 \hat{j}+3 \hat{k},\\ 
\vec{b}&amp;=4 \hat{i}+5 \hat{j}+6 \hat{k}, \\
\vec{c}&amp;=7 \hat{j}+8 \hat{k}\end{align}\begin{align}V&amp;=\dfrac{1}{6}[\vec{u} \cdot \vec{v} \…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Review Exercise 3

Solutions of Question 2 &amp; 3 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$\lambda$$\mu$$$(\hat{i}+3 \hat{j}+9 \hat{k}) \times(3 \hat{i}-\lambda \hat{j}+\mu \hat{k})=\overrightarrow{0} \text {. }$$\begin{align}(\hat{i}+3 \hat{j}+9 \hat{k}) \times(3 \hat{i}-\lambda \hat{j}+\mu \hat{k})&amp;=\vec{O} \\
\Rightarrow\left|\b…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 &amp; 5 Review Exercise 3

Solutions of Question 4 &amp; 5 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\vec{r}=x \hat{i}+y \hat{j}+z \hat{k}$$(\vec{r} \times \hat{i}) \cdot(\bar{r} \times \hat{j})+x y$$$(\vec{r} \times \hat{i}) \cdot(\vec{r} \times \hat{j})+x y $$\begin{align}\text { Now } \vec{r} \times \hat{i}&amp;=\left|\begin{array}{ccc}
\hat{…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 6 &amp; 7 Review Exercise 3

Solutions of Question 6 &amp; 7 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6
$\lambda$$\vec{a}=\hat{i}+3 \hat{j}+\hat{k}$$\bar{b}=2 \hat{i}-\hat{j}-\hat{k}$$\vec{c}=\lambda \hat{j}+3 \hat{k}$\begin{align}\vec{a} \cdot \vec{b} \times \vec{c}&amp;=0 \\
\Rightarrow\left|\begin{array}{ccc}
1 &amp; 3 &amp; 1 \\
2 &amp; -1 &amp; -1 \\
0 &amp; \lamb…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 &amp; 9 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 8 &amp; 9 Review Exercise 3

Solutions of Question 8 &amp; 9 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8
$(0,0,2),(-1,3,2),(1,0,4)$$A(0,0,2)$$B(-1,3,2)$$C(1,0,4)$$\vec{a}=\overrightarrow{A B}=(-1,3,2)-(0,0,2)$$\Rightarrow \vec{a}=(-1,3,0)$$\vec{b}=\overrightarrow{B C}=(1,0,4)-(-1,3,2)$$\Rightarrow \vec{b}=(2,-3,2)$$$ \text{Area of triangle} =\dfr…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4 Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-1-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 and 4 Exercise 4.1

Solutions of Question 3 and 4 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{1}{2}, \dfrac{2}{3} \dfrac{3}{4}, \dfrac{4}{5}, \ldots$$$\dfrac{1}{1+1}, \dfrac{2}{2+1}, \dfrac{3}{3+1}, \dfrac{4}{4+1},...$$$\dfrac{n}{n+1}$$2,-4,6,-8,10, \ldots$\begin{align}
&amp;(-1)^2 \cdot 2 \cdot 1, (-1)^3 \cdot 2 \cdot 2, (-1)^4 \cdot 2 \…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-1-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 4.1

Solutions of Question 5 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$\sum_{j=1}^6(2 j-3)$\begin{align}\sum_{j=1}^6(2 j-3)&amp;=(2.1-3)+(2.2-3)+(2.3-3)+(2.4-3)\\&amp;+(2.5-3)+(2.6-3) \\
\implies \sum_{j=1}^6(2 j-3)&amp;=-1+1+3+5+7+9 .\end{align}$\sum_{k=1}^5(-1)^k 2^{k-1}$\begin{align}\sum_{k=1}^5(-1)^k 2^{k-1}&amp; =(-1)^1 2^{1-…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 and 4 Exercise 4.2

Solutions of Question 3 and 4 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$6,9,12, \ldots, 78$$a_1=6$$d=9-6=3$$a_n=78$$$a_n=a_1+(n-1) d$$\begin{align}&amp;78=6+(n-1) 3 \\
\implies &amp;3(n-1)=78-6 \\
\implies &amp;n-1=\dfrac{72}{3} \\
\implies &amp;n=24+1=25.\end{align}$25$$n$$a_n=2n+7$$$a_n=2 n+7. --- (1)$$\begin{align}a_{n+1}=2(n+1)+7=2…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 4.2

Solutions of Question 5 and 6 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\log a, \log (a b), \log \left(a b^2\right), \log \left(a b^3\right), \ldots$$$n$$\log$$a$$b$$b$$$a_n=\log (a b^{n-1}).$$\begin{align}a_n&amp;=\log(a b^{n-1}). \end{align}\begin{align}
d&amp;=a_{n+1}-a_n \\
&amp;=\log (a b^n)-\log (a b^{n-1}) \\
&amp;=\log \left(\…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 4.2

Solutions of Question 7 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$a_6+a_4=6$$a_6-a_4=\dfrac{2}{3}$$a_1$$d$\begin{align} &amp;a_6+a_4=6 \\
\implies &amp; a_1+5d+a_1+3d=6\\
\implies &amp; 2a_1+8d=6\\
\implies &amp; a_1+4d=3 --- (1)
\end{align}\begin{align} &amp;a_6-a_4=\dfrac{2}{3} \\
\implies &amp; a_1+5d-a_1-3d=\dfrac{2}{3}\\
\implies &amp;…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 4.2

Solutions of Question 8 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8
$\dfrac{b+c-a}{a}, \dfrac{c+a-b}{b}, \dfrac{a+b-c}{c}$$\dfrac{1}{a}, \dfrac{1}{b}, \dfrac{1}{c}$$\dfrac{b+c-a}{a}, \dfrac{c+a-b}{b}, \dfrac{a+b-c}{c}$\begin{align}\therefore \dfrac{c+a-b}{b}-\dfrac{b+c-a}{a}&amp;=\dfrac{a+b-c}{c}-\dfrac{c+a-b}{b} \\
\te…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 4.2

Solutions of Question 9 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$24m$$21m$$18m$$$a_1=24,$$$$a_2=21,$$$$a_3=18.$$$$d=21-24=18-21=-3,$$\begin{align} a_8&amp;=a_1+7d\\
&amp;=24+7(-3)=3.
\end{align}$3m$</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 4.2

Solutions of Question 10 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 10
$500$$a_1$$$a_1=20135.$$$d=-500$$a_{11}$\begin{align}
a_{11}&amp;=a_1+10d \\
&amp;=20135+10(-500)\\
&amp;=15135. \end{align}$1070$$15135$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Exercise 4.2

Solutions of Question 11 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11
$a_1$$$a_1=1000.$$$= d=100$$a_n=5400$$n$\begin{align}
&amp;a_n=a_1+(n-1)d \\
 \implies &amp;5400=1000+(n-1)100\\
 \implies &amp;5400=900+100n \\
 \implies &amp;100n=5400-900\\
 \implies &amp;100n=4500\\
 \implies &amp;n=45.\end{align}</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p9?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 &amp; 13 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p9?rev=1737476038&amp;do=diff</link>
        <description>Question 12 &amp; 13 Exercise 4.2

Solutions of Question 12 &amp; 13 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$a_1$$$a_1=3500.$$$=d=750$$a_{21}$\begin{align}
a_{21}&amp;=a_1+20d\\
&amp;=3500+20(750) \\
&amp;=18500. \end{align}$12$$18$$a=12, b=18$$A$\begin{align}A&amp;=\dfrac{a+b}{2}\\&amp;=\dfrac{12+18}{2}\\&amp;=\dfrac{30}{2}=15.\end{align}$\dfrac{1}{3}$$\dfrac{1}{4}$$a=\dfrac{1}{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p10?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p10?rev=1737476038&amp;do=diff</link>
        <description>Question 14 Exercise 4.2

Solutions of Question 14 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 14(i)
$A_1, A_2, A_3$$6, A_1, A_2, A_3, 41$$$a_1=6 \text{ and } a_6=41.$$\begin{align}&amp; a_5=11\\
\Rightarrow &amp;a_1+4 d=41 \\
\Rightarrow &amp;6+4 d=41 \\
\Rightarrow &amp;d=\dfrac{41-6}{4}\\
&amp;=\dfrac{35}{4}.\end{align}\begin{align} A_1&amp;=a+d=6+\dfrac{35}{4} \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p11?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p11?rev=1737476038&amp;do=diff</link>
        <description>Question 15 Exercise 4.2

Solutions of Question 15 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 15
$n, \dfrac{a^{n+1}+b^{n+1}}{a^n+b^n}$$a$$b$$a$$b$$A$$a$$b$$$
A=\dfrac{a+b}{2}. --- (1)
$$$$
A=\dfrac{a^{n+1}+b^{n+1}}{a^n+b^n}. --- (2)
$$\begin{align}&amp;\dfrac{a+b}{2}=\dfrac{a^{n+1}+b^{n+1}}{a^n+b^n}, --- (3) \\
	\implies &amp;(a^n+b^n)(a+b)=2(a^{n+1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p12?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 16 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p12?rev=1737476038&amp;do=diff</link>
        <description>Question 16 Exercise 4.2

Solutions of Question 16 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 16
$5$$8$$5$$8$$A_1, A_2, A_3, A_4, A_5$$5$$8$$5, A_1, A_2, A_3, A_4, A_5, 8$$$a_1=5 \text{ and } a_7=8.$$\begin{align}&amp;a_7=a+6d\\
\implies &amp;8=5+6d\\
\implies &amp;6d=8-5\\
\implies &amp;d=\dfrac{3}{6}=\dfrac{1}{2}.
\end{align}\begin{align}
A_1&amp;=a+d=5+\dfra…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 4.3

Solutions of Question 2 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$a_1, a_n, n, d$$S_n$$a_1=2, n=17, d=3$$a_1=2, n=17, d=3$$a_{17}$$S_{17}$$$a_{n}=a_1+(n-1)d.$$$$a_{17}=2+(17-1)(3)=50.$$$$S_n=\dfrac{n}{2}[a_1+a_n]$$\begin{align}S_{17}&amp;=\dfrac{17}{2}(a_1+a_17) \\
&amp;=\dfrac{17}{2}(2+50)=442.\end{align}$a_{17}=50$$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 &amp; 4 Exercise 4.3

Solutions of Question 3 &amp; 4 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
$5$$25$$350$$5$$25$$350$$$25,30,35, \ldots, 350.$$$a_1=25, d=5$$a_n=350$$n$\begin{align}a_n&amp;=a_1+(n-1) d\end{align}\begin{align}
350&amp;=25+(n-1)(5) \\
\Rightarrow 5 n-5+25&amp;=350 \\
\Rightarrow 5 n&amp;=350-20=330 \\
\Rightarrow n&amp;=66, \text { now f…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 5 &amp; 6 Exercise 4.3

Solutions of Question 5 &amp; 6 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5
$20$$120$$$a-2 d, a-d, a+d, a+2 d,$$$Condition-1$$20$\begin{align}a-3 d+a-d+a+d+a+3 d&amp;=20 \\
\Rightarrow 4 a&amp;=20\\
\Rightarrow a&amp;=5 .\end{align}$Condition-2$$120$\begin{align}(a-3 d)^2+(a-d)^2+(a+d)^2+(a+2 d)^2&amp;=120 \\
\Rightarrow a^2-6 a d+…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 4.3

Solutions of Question 7 &amp; 8 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$1+3-5+7+9-11+13+15-$$17+\ldots$$3 n$\begin{align}&amp;(1+7+13+\ldots)+(3+9+15+\ldots)- \\
&amp; (5+11+17+\ldots) \ldots \ldots \ldots . . .(1)\end{align}$\mathrm{n}$$n$$3 n$$$1+7+13+\ldots$$$$a_1=1, d=7-1=6$$$n$\begin{align}S_n&amp;=\dfrac{n}{2}[2 a_1+…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p6?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 &amp; 10 Exercise 4.3

Solutions of Question 9 &amp; 10 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$$306,315,324,333, \ldots, 693$$$a=306$$$d=(315-306) = 9 \text { and } a_n=693 .$$$n$\begin{align}a_n&amp;=a_1+(n-1) d \text { becomes } \\
\Rightarrow a_1+(n-1) d&amp;=693 \\
\Rightarrow 306+(n-1) \cdot 9&amp;=693 \\
\Rightarrow 9 n&amp;=396 \\
\Rightarr…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 &amp; 12 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 11 &amp; 12 Exercise 4.3

Solutions of Question 11 &amp; 12 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$16 \mathrm{ft}$$48 \mathrm{ft}$$80 \mathrm{ft}$$a_1=16 \mathrm{ft}$$2^{\text {nd }}$$a_2=48 \mathrm{ft}$$a_3=80 \mathrm{ft}$$16,48,80, \ldots \quad$$d=48-16=32$$S_6$\begin{align}S_n&amp;=\dfrac{n}{2}[2 a_1+(n-1) d] \\
\therefore S_6&amp;=\dfrac{6}{2}(2.16+5…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Exercise 4.4

Solutions of Question 2 &amp; 3 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$27$$243$$$a_3=27 \quad\text{and}\quad a_5=243$$\begin{align}a_3&amp;=a_1 r^2=27\\
a_5&amp;=a_1 r^4=243.\end{align}\begin{align}\dfrac{a_1 r^4}{a_1 r^2}&amp;=\dfrac{243}{27}=9 \\
\Rightarrow r^2&amp;=9 \text { or } r= \pm 3 .\end{align}$$a_1(9)=27 \quad \te…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 &amp; 5 Exercise 4.4

Solutions of Question 4 &amp; 5 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\dfrac{1}{64}$$r=\dfrac{1}{2}$$a_1=16$$a_n=\dfrac{1}{64}$$r=\dfrac{1}{2}$$n$$$a_n=a_1 r^{n-1} \quad \text{then}$$\begin{align}\dfrac{1}{64}&amp;=16(\dfrac{1}{2})^{n-1} \\
\Rightarrow(\dfrac{1}{2})^{n-1}&amp;=\dfrac{1}{64 \times 16}=\dfrac{1}{1024} …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 6 &amp; 7 Exercise 4.4

Solutions of Question 6 &amp; 7 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6
$a_{10}=l, a_{13}=m$$a_{16}=n;\quad$$\ln =m^2$$a_n=a_1 r^{n-1}$\begin{align}a_{10}&amp;=a_1 r^9=l \\
a_{13}&amp;=a_1 r^{12}=m\\
\text{and} \quad a_{16}&amp;=a_1 e^{\mathbf{A 5}}=n\end{align}\begin{align}a_{10} \cdot a_{16}&amp;=\ln =(a_1 r^9)(a_1 r^{15})\\
…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 4.4

Solutions of Question 8 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$3.14$$2.71$$a=3.14$$b=2.71$$$G= \pm \sqrt{(3.14)(2.71)}= \pm 2.94$$$$G=2.94 \quad \text{or} \quad -2.94$$$-6$$-216$$a=-6$$b=-216$\begin{align}G&amp;= \pm \sqrt{(-6)(-216)}= \pm \sqrt{1296} \\
\Rightarrow G&amp;= \pm 36\end{align}$$G=36 \quad \text{or} \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p6?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 4.4

Solutions of Question 9 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)
$3 \dfrac{5}{9}=\dfrac{32}{9}\quad$$\quad40 \dfrac{1}{2}=\dfrac{81}{2}$$G_1, G_2, G_3, G_4$$G_5$$\dfrac{32}{9}$$\dfrac{81}{2}$$\dfrac{32}{9}, G_1, G_2, G_3, G_4, G_5, \dfrac{81}{2}$$a_7=\dfrac{81}{2}$$a_1=\dfrac{32}{9}$\begin{align}a_1 r^6&amp;=\dfra…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 4.4

Solutions of Question 10 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 10
$48$$18$$a$$b$$1$$48$$$\quad a-b=48....(i)$$$a$$b$$$G=\sqrt{a b}$$$a$$b$$$A=\dfrac{a+b}{2}$$$2$$A \cdot M=G \cdot M+18$$A \cdot M-G \cdot M=18$$$\Rightarrow \dfrac{a+b}{2}-\sqrt{a b}=18$$$$(a+b)-2 \sqrt{a b}=36 \text {. }$$$a=b+48$\begin{align}(b…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Exercise 4.4

Solutions of Question 11 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11
$\mathrm{n}$$a$$b$$nth$$G_1, G_2, G_9, \ldots, G_n$$n$$a$$b$$a, G_1, G_2, G_3, \ldots, G_n, b$$n+2$$a_{n+2}=b$$a_n=a_1 r^{n-1}$$n$$n+2$\begin{align}a_{n+2}&amp;=a_1 r^{n i 1}=a r^{n+1}=b \\
\because a_1&amp;=a \\
\Rightarrow \quad r^{n+1}&amp;=\dfrac{b}{a} .…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 4.5

Solutions of Question 2 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$a_1, a_n, n_2 r$$S_n$$a_1=1, \quad r=-2, \quad a_n=64$$n$$S_n$$a_n=a_1 r^{n-1}$\begin{align}64&amp;=(-2)^{n-1}\\
\Rightarrow(-2)^{n-1}&amp;=(-2)^6 \\
\Rightarrow n-1&amp;=6 \\
\Rightarrow n&amp;=7\\
S_7&amp;=\dfrac{a_1[r^{\prime \prime}-1]}{r-1}\\
\text{then}\\
S_7…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 4.5

Solutions of Question 3 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
$a_2=2$$a_3=1$$a_1$$r$$$a_n=a_1 r^{n-1}$$$$a_2=a_1 r=2....(i)$$$$a_3=a_1 r^2=1...(ii)$$\begin{align}\dfrac{a_1 r^2}{a_1 r}&amp;=\dfrac{1}{2}\\
\Rightarrow r&amp;=\dfrac{1}{2} \text {, }\end{align}\begin{align}\dfrac{a_1}{2}&amp;=2\\
\Rightarrow a_1&amp;=4 \text {. …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 4.5

Solutions of Question 4 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)
$0 . \overline{8}$$$0 . \overline{8}=0.888888 \ldots$$\begin{align}0 . \overline{8}&amp;=0.8+0.08+0.008 \div 0.0008+ \ldots\\
\text { or } 0 . \overline{8}&amp;=0.8+(0.1)(0.8) +(0.1)^2(0.8)+\ldots \ldots \ldots \ldots .(\mathrm{i})\end{align}$$a_1=0.8, \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 &amp; 6 Exercise 4.5

Solutions of Question 5 &amp; 6 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5
$r$$S_{10}=244 S_5$$$S_n=\dfrac{a_1(r^n-1)}{r-1}$$$$S_{10}=\dfrac{a_1(r^{10}-1)}{r-1} \quad \text{and}\quad S_5=\dfrac{a_1(r^5-1)}{r-1}$$$S_{10}$$S_S$\begin{align}\dfrac{a_1(r^{10}-1)}{r-1}&amp;=244 \dfrac{a_1(r^5-1)}{r-1} \\
\Rightarrow r^{10}-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p6?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 4.5

Solutions of Question 7 &amp; 8 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$\operatorname{sum} S_n$$n$$\{(\dfrac{1}{2})^n\}$$$\{(\dfrac{1}{2})^n\}=\dfrac{1}{2}, \dfrac{1}{2^2}, \dfrac{1}{2^3}, \ldots$$$$a_1=\dfrac{1}{2}$$$$r=\dfrac{\dfrac{1}{2^2}}{\dfrac{1}{2}}=\dfrac{1}{2}$$\begin{align}S_n&amp;=\dfrac{a_1(1-r^n)}{1-r…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 9 &amp; 10 Exercise 4.5

Solutions of Question 9 &amp; 10 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$9$$n$$r$$a_1$$$S_n=\dfrac{a_1[r^n-1]}{r-1}$$$$S_6=\dfrac{a_1(r^5-1)}{r-1}$$$$S_3=\dfrac{a_1(r^3-1)}{r-1} \text {. }$$$3$$9$$6$\begin{align} \dfrac{a_1(r^6-1)}{r-1}&amp;=9 \dfrac{a_1(r^3-1)}{r-1} \\
\Rightarrow r^6-1-9(r^3-1) \\
\Rightarrow r^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 &amp; 12 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 11 &amp; 12 Exercise 4.5

Solutions of Question 11 &amp; 12 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$p^{t h}, q^{t h}$$r^{t h}$$a, b, c$$a^{q-r} b^{r-p} c^{p-q}=1$$a_n=a_1 r^{n-1}$$a_p=a_1 r^{p-1}=a \quad a_q=a_1 r^{q-1}=b$$a_r=a_1 r^{r-1}$\begin{align}a^{q-r}&amp;=(a_1 r^{p-1})^{q-r} . \\
b^{r-p}&amp;=(a_1 r^{q-1})^{r-p}, \text { and } \\
c^{p-q}&amp;=(a_1 r^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p9?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 &amp; 14 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p9?rev=1737476038&amp;do=diff</link>
        <description>Question 13 &amp; 14 Exercise 4.5

Solutions of Question 13 &amp; 14 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$y=\dfrac{x}{3}+\dfrac{x^2}{3^2}+\dfrac{x^3}{3^3}+\ldots$$0&lt;x&lt;3$$x=\dfrac{3 y}{1+y}$$$1+y=1+\dfrac{x}{3}+\dfrac{x^2}{3^2}+\dfrac{x^3}{3^3}$$$a_1=1$$r=\dfrac{x}{3}$$|r|=\dfrac{x}{3}&lt;1$$0&lt;x&lt;3$$S_{\infty}=\dfrac{a_1}{1-r}$$a_1, \quad r$$$S_{\infty}=\dfr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Exercise 5.1

Solutions of Question 2 &amp; 3 of Exercise 5.1 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Q2 Find the sum $1.2+2.3+3.4+\ldots+99.100$$1+2+3+\ldots+99$$2+3+4+\ldots+100$$n^{\text {th }}$$n(n+1)$$n^{\text {th }}$$\quad T_j=j(j+1)=j^2+j$$j=1$$j=99$$$
\begin{aligned}
&amp; \sum_{j=1}^{99} \tau_j=\sum_{j=1}^{99} j^2+\sum_{j=1}^{99} j \\
&amp; =\frac{99…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 &amp; 5 Exercise 5.1

Solutions of Question 4 &amp; 5 of Exercise 5.1 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$2+(2+5)+(2+5+8)+\ldots$$n$\begin{align}&amp; T_j=\dfrac{j}{2}[2(2)+3(j-1)]\\
&amp;=\dfrac{j(3 j+1)}{2} \\
&amp; =\dfrac{1}{2}(3 j^2+j)\end{align}\begin{align}&amp; \sum_{j=1}^n T_i=\dfrac{1}{2}[3 \sum_{j=1}^n j^2+\sum_{j=1}^n j] \\
&amp; =\dfrac{1}{2}[3 \dfra…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 5.1

Solutions of Question 6 of Exercise 5.1 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6
$1.2 \cdot 3+2 \cdot 3.4+3.4 .5+\ldots$$n$$1+2+3+\ldots, \quad 2+3+4+5+\ldots$$3+4+5+6+7+\ldots$$n^{t h}$$j, j+1$$j+2$$n^{t h}$\begin{align}
&amp; T_j=j(j+1)(j+2)-j(j^2+3 j+2) \\
&amp; =j^3+3 j^2+2 j\end{align}\begin{align}
&amp; \sum_{j=1}^n T_j=\sum_{j=1}^n …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 5.1

Solutions of Question 7 &amp; 8 of Exercise 5.1 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$n$$1.5 .9+2.6 .10+3.7 .11+\ldots$$T_j=j(j+4)(j+8)$\begin{align}
&amp; =j(j^2+12 j+32) \\
&amp; =j^3+12 j^2+32 j\end{align}\begin{align}
&amp; \sum_{j=1}^n T_j=\sum_{j=1}^n j^3+12 \sum_{j=1}^n j^2+32 \sum_{j=1}^n j \\
&amp; =(\dfrac{n(n+1)}{2})^2+12 \dfrac…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-2-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-2-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Exercise 5.2

Solutions of Question 2 &amp; 3 of Exercise 5.2 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$1+3^2 x+5^2 x^2+7^2 x^3+\ldots, x&lt;1$\begin{align}
&amp; S_{\infty}=1+3^2 x+5^2 x^2+7^2 x^3+\ldots ..(1)\\
&amp; x S_{\infty}=x+3^2 x^2+5^2 x^3+7^2 x^4+\ldots..(2)\end{align}\begin{align}&amp; (1-x) S_{\infty}=1^2+(3^2-1^2) x+(5^2-3^2) x^2+(7^2-5^2) x^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 5.3

Solutions of Question 2 of Exercise 5.3 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$n$$n$$4+14+30+52+80+114+\ldots$\begin{align}
&amp; a_2-a_1=14-4=10 \\
&amp; a_3-a_2=30-14=16 \\
&amp; a_4-a_3=52-30=22 \\
&amp; \cdots \quad \cdots \quad \cdots \\
&amp; \cdots \quad \cdots \quad \cdots \\
&amp; a_n-a_{n-1}=(\mathrm{n}-1)\text{ term of the sequence} 10,1…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 5.3

Solutions of Question 3 of Exercise 5.3 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
$n$$n$$4+10+18+28+40+\ldots$\begin{align}
&amp; a_2-a_1=10-4=6 \\
&amp; a_3-a_2=18-10=8 \\
&amp; a_4-a_3=28-18=10 \\
&amp; \text {... ... ... } \\
&amp; \text {... ... ... } \\
&amp; a_n-a_{n \quad 1}=(\mathrm{n}-1) \text { term of the sequence } \end{align}$6,10,8, \ldot…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 5.3

Solutions of Question 4 of Exercise 5.3 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$n$$n$$3+5+11+29+83+245+\ldots$\begin{align}
&amp; a_2-a_1=5-3=2 \\
&amp; a_3-a_2=11-5=6 \\
&amp; a_4-a_3=29-11=18 \\
&amp; \text {... ... ... } \\
&amp; \text {... ... ... } \\
&amp; a_n-a_{n-1}=(\mathrm{n}-1) \text { term ofthe sequence }\end{align}$6,10,18, \ldots$\beg…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 5.3

Solutions of Question 5 of Exercise 5.3 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5
$n$$n$$3+9+21+45+93+189+\ldots$\begin{align}
&amp; a_2-a_1=9-3=6 \\
&amp; a_3-a_2=21-9=12 \\
&amp; a_4-a_3=45-21=24\\
&amp; \text {... ... ... } \\
&amp; \text {... ... ... } \\
&amp;a_n-a_{n-1}=(\mathrm{n}-1)\quad \text{ term of the sequence}\quad 6,12,24, \ldots\end{ali…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Exercise 5.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Exercise 5.4

Solutions of Question 2 &amp; 3 of Exercise 5.4 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$\sum_{k=1}^n \dfrac{1}{9 k^2+3 k-2}$\begin{align}\text { Let } S_n&amp;=\sum_{k=1}^n \dfrac{1}{9 k^2+3 k-2} \\
S_n&amp;=\sum_{k=1}^n \dfrac{1}{9 k^2+6 k-3 k-2} \\
&amp; =\sum_{k=1}^n \dfrac{1}{3 k(3 k+2)-1(3 k+2)} \\
S_n&amp;=\sum_{k=1}^n \dfrac{1}{(3 k-1…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Review Exercise

Solutions of Question 2 &amp; 3 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n$$1.2+2.3+3.4+\ldots$$n^{\text {th }}$$$a_n=n(n+1)=n^2+n$$\begin{align}
\sum_{r=1}^n a_r&amp;=\sum_{r=1}^n r^2+\sum_{r=1}^n r \\
&amp; =\dfrac{n(n+1)(2 n+1)}{6}+\dfrac{n(n+1)}{2} \\
&amp; =\dfrac{n(n+1)}{2}[\dfrac{2 n+1}{3}+1] \\
&amp; =\dfrac{n(n+1)}{2} \cdot …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Review Exercise

Solutions of Question 4 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\dfrac{1}{1.4 .7}+\dfrac{1}{4.7 .10}+\dfrac{1}{7.10 .13}+\ldots$$1,4,7, \ldots$$$a_n=\dfrac{1}{(3 n-2)(3 n+1)(3 n+4)}$$\begin{align}
\dfrac{1}{(3 n-2)(3 n+1)(3 n+4)}&amp;=\dfrac{A}{3 n-2}+\dfrac{B}{3 n+1}+\dfrac{C}{3 n+4}\end{align}$(3 n-2)(3 n+…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 5 &amp; 6 Review Exercise

Solutions of Question 5 &amp; 6 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$5+12 x+19 x^2+26 x^3+\ldots$$n$\begin{align}S_n&amp;=5+12 x+19 x^2+26 x^3+\cdots+(7 n-2) x^{n-1}...(i)\\ 
x S_n&amp;=5 x+12 x^2+19 x^3+\cdots+(7 n-9) x^{n-1}+(7 n-1) x^n....(ii)\end{align}\begin{align}(1-x) S_n&amp;=5+(12-5) x+(19-12) x^2+\cdots\\
&amp;+[7 n-2-(…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Review Exercise

Solutions of Question 7 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$1.2^2+3.3^2+5.4^2+\ldots$$n$$1,3,5, \ldots,(2 n-1)$$2^2, 3^2, 4^2, \ldots,(n+1)^2$\begin{align}
&amp; a_n=(2 n-1)(n+1)^2 \\
&amp; a_n=(2 n-1)(n^2+2 n+1) \\
&amp; a_n=2 n^3+3 n^2-1\end{align}\begin{align}
\sum_{r=1}^n a_r&amp;=2 \sum_{r=1}^n r^3+\sum_{r=1…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Review Exercise

Solutions of Question 8 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$n$$n^{t h}$$n^3+3^n.$$n^h$$$a_n=n^3+3^n$$\begin{align}\sum_{r=1}^n a_r&amp;=\sum_{r=1}^n r^3+\sum_{r=1}^n 3^r \\
&amp; =[\dfrac{n(n+1)}{2}]^2+\dfrac{3(3^n-1)}{3-1} \\
&amp; =\dfrac{n^2(n+1)^2}{4}+\dfrac{3}{2}(3^n-1) \end{align}$n$$$S_n=\dfrac{n^2(n+1…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Review Exercise

Solutions of Question 9 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)
$n$$3+7+13+21+31+\ldots$\begin{align}
&amp; a_2-a_1=7-3=4 \\
&amp; a_3-a_2=13-7=6 \\
&amp; a_4-a_3=21-13=8 \\
&amp; \ldots \quad \ldots \quad \ldots \\
&amp; \ldots \quad \cdots \quad \ldots \\
&amp; a_n-a_{n-1}=(n-1) \text { term of the series } \\
&amp; 4,6,8, \ldo…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Exercise 6.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 &amp; 4 Exercise 6.1

Solutions of Question 3 &amp; 4 of Exercise 6.1 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{1}{6 !}+\dfrac{2}{7 !}+\dfrac{3}{8 !}=\dfrac{75}{8 !}$\begin{align}\dfrac{1}{6 !}+\dfrac{2}{7 !}+\dfrac{3}{8 !}&amp;=\dfrac{1}{6 !}+\dfrac{2}{7.6 !}+\dfrac{3}{8.7 .6 !} \\
&amp; =\dfrac{56+16+3}{8 !}\\
&amp;=\dfrac{75}{8 !}\end{align}$\df…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 6.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 6.1

Solutions of Question 4 of Exercise 6.1 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 and 4 Exercise 6.2

Solutions of Question 3 and 4 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$^n P_r=n(^{n-1} P_{r-1})$$$^n P_r=n({ }^{n-1} P_{r-1})$$\begin{align}n(^{n-1} P_{r-1})&amp;=n \dfrac{(n-1) !}{((n-1)-(r-1)) !} \\
&amp; =\dfrac{n(n-1) !}{(n-r) !}\\
&amp;=\dfrac{n !}{(n-r) !}\\
&amp;=^n P_r\end{align}$^n P_r=^{n-1} P_r+r(^{n-1} …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 6.2

Solutions of Question 5 and 6 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$7.$$7$$7$\begin{align}^7 P_7&amp;=\dfrac{7 !}{(7-7) !}\\
&amp; =7 !\\
&amp;=5,040 \end{align}$2,4,5,7,9$$2,4,5,7,9$$\mathrm{n} . \mathrm{m}$$e$$$=5.4 .3 .2=120\quad \text{or}$$$$^5 P_4=\dfrac{5 !}{5-4} !=120$$$2$$4$$3$$E_1$$m_1=2$$E_2$$m_2=3…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 7 and 8 Exercise 6.2

Solutions of Question 7 and 8 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1,2,3,4$$E_1$$m_1=5$$E_2$$\cdot m_2=5$$E_3$$m_3=5$$$m_1 \cdot m_2 \cdot m_3=5.5 \cdot 5=125$$$1,2,3,4$$E_1$$m_1=5$$E_2$$m_2=4$$E_3$$m_3=3$$$m_1 \cdot m_2 \cdot m_3=5 \cdot 4 \cdot 3=60$$$8$$5$$=4$$=4$$=5$$=3$$4 ! \cdot 5 ! \cdot …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 6.2

Solutions of Question 9 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$=^6 P_1=6$$s=^6 P_2=30$$=^6 P_3=120$$=^6 P_4=360$$=^6 P_5=720$$=^6 P_6=720$$6+30+120+360+720+720=1956$</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 6.2

Solutions of Question 10 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n=8$$r=5$\begin{align}^8 P_5&amp;=\dfrac{8 !}{(8-5) !}\\
&amp;=\dfrac{8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 !}{3 !}\\
&amp;=6720\end{align}\begin{align}^2 P_2 \times^7 P_4&amp;=2 \times \dfrac{7 !}{(7-4) !}\\
&amp;=2 \times\dfrac{7.6 .5 .4 .3 !}{3 !}\\
&amp;=…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Exercise 6.2

Solutions of Question 11 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$10$$1000$$2.3,4,0,8,9$$10$$1000$$10$$100$$E_1$$m_1=5$$E_2$$m_2=5$$10$$100$$$m_1 \cdot m_2=5.5=25$$$100$$1000$$0$$E_1$$m_1=5$$E_2$$\boldsymbol{m}_2=5$$E_3$$m_3=4$$100$$1000$$$m_1 \cdot m_2 \cdot m_3=5.5 \cdot 4=100$$$10$$1000$$$100 + 25=125…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 12 Exercise 6.2

Solutions of Question 12 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$8.$$n=8$$\mathrm{O}$$m_1=3$\begin{align}
 \left(\begin{array}{c}
n \\
m 1
\end{array}\right)&amp;=\left(\begin{array}{l}
8 \\
3
\end{array}\right) \\
&amp; =\dfrac{8 !}{3 !}\\
&amp;=\dfrac{8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 !}{3 !}\\
&amp;=6,720 \e…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p9?rev=1737476038&amp;do=diff</link>
        <description>Question 13 Exercise 6.2

Solutions of Question 13 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\mathrm{E}$$n=10$$m_1=4$$E, m_2=2$$L$$m_3=2$$C$\begin{align}\text{total number of permutations are}
 &amp;=\left(\begin{array}{c}
n \\
m_1, m_2, m_3
\end{array}\right)\\&amp;=\left(\begin{array}{c}
10 \\
4,2,2
\end{array}\right) \\
&amp; =\dfrac{10 !}…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 6.3

Solutions of Question 2 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n$$r$${ }^n P_r=840$${ }^n C_r=35$\begin{align}
&amp;^n P_r=\dfrac{n !}{(n-r) !}=840 ....(i)\\
&amp;^n C_r=\dfrac{n !}{(n-r) ! r !}=35....(ii)\end{align}\begin{align}\dfrac{n !}{(n-r) !} \cdot \dfrac{(n-r) ! r !}{n !}&amp;=\dfrac{840}{35}\\
r!&amp;=24\\
\te…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 6.3

Solutions of Question 3 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n$$^{2 n} C_3:^n C_2=36: 3$\begin{align}
&amp; { }^{2 n} C_3:{ }^n C_2=36: 3 . \\
&amp; \Rightarrow \dfrac{(2 n) !}{(2 n-3) ! 3 !} \times \dfrac{(n-2) ! 2 !}{n !}=12 \\
&amp; \Rightarrow \dfrac{2 n(2 n-1)(2 n-2)(2 n-3) !}{(2 n-3) ! 3 !}\times\dfrac{(n-2…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 6.3

Solutions of Question 4 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${ }^{n-1} C_r+{ }^{n-1} C_{r-1}={ }^n C_r$$${ }^n{ }^1 C_r+{ }^n{ }^1 C_{r-1}={ }^n C_s$$\begin{align}
{ }^{n-1} C_r+{ }^{n-1} C_{r-1}&amp;=\dfrac{(n-1) !}{(n-r-1) ! r !}+\dfrac{(n-1) !}{(n-1-(r-1)) !(r-1) !} \\
&amp; =\dfrac{(n-1) !}{(n-r-1) ! r(r-…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 6.3

Solutions of Question 5 and 6 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$12$$n=12$${ }^{12} C_2=66$$12$$n=12$${ }^{12} C_3=220$$${ }^6 C_2=\dfrac{6 !}{(6-2) ! 2 !}=15 $$$6$$\quad 15-6=9$</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 7 and 8 Exercise 6.3

Solutions of Question 7 and 8 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$20$\begin{align}{ }^{20} C_2&amp;=\dfrac{20 !}{(20-2)2!}!\\
&amp;=\dfrac{20!}{18!\cdot 2!}\\
&amp;=190\end{align}$7$$10$$3$$7$$10$$${ }^{10} C_7=\dfrac{10 !}{(10-7) ! 7 !}=120$$$7$$4.$$4$$${ }^7 C_4=\dfrac{7 !}{(7-4) ! 4 !}=35.$$$35$$10.$</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 6.4

Solutions of Question 2 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$4$$5$$6$$3$$4+5+6=15$$${ }^{15} C_3=\dfrac{15 !}{(15-3) ! 3 !}=455 $$$${ }^6 C_4=\dfrac{6 !}{(6-4) ! 4 !}=15$$$$=\dfrac{15}{455}=\dfrac{3}{91}$$$4$$5$$6$$3$$4+5+6=15$$${ }^{15} C_3=\dfrac{15 !}{(15-3) ! 3 !}=455 $$$${ }^4 C_3=\dfrac{4 !}{(4-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p3?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 6.4

Solutions of Question 3 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$8$$8$$2^8$$$n(S)=256$$$$\dfrac{1}{256}$$$8$$$A=\{8\}$$$${ }^8 C_8=\dfrac{8 !}{(8-8) ! 8 !}=1$$$8$$$P(A)=\dfrac{1}{256}$$$7$$8$$2^8$$$n(S)=256$$$$\dfrac{1}{256}$$$7$$$B=\{7\}$$$7$$8$$$n(B)={ }^8 C_7=\dfrac{8 !}{(8-7) ! 7 !}=8$$$7$$8$$$P(B)=\d…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 6.4

Solutions of Question 4 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.\begin{align}S&amp;=(HHII,HHT.HTH.HTT.THII.THT.TTH,TT7),\\
\text{then} n(S)&amp;=2^3=8\end{align}$$A=\{H H H\}$$$$n(A)=1$$$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{1}{8}$\begin{align}S&amp;=(HHII,HHT.HTH.HTT.THII.THT.TTH,TT7),\\ 
\text{then} n(S)&amp;=2^3=8\end{align}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 6.4

Solutions of Question 5 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$6$$4$$3$$2$$=6+4=10$$5$$10$\begin{align}{ }^{10)} C_5 &amp;=\dfrac{10 !}{(10-5) ! 5 !}\\
&amp;=252\\ 
n(S)&amp;=252\end{align}$3$$2$$3$$2$\begin{align}{ }^6 \mathrm{C}_3\cdot{ }^{4} \mathrm{C}_2&amp;=\dfrac{6 !}{(6-3) ! 3 !} \cdot \dfrac{4 !}{(4-2) ! 2 !}\\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p6?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 6.4

Solutions of Question 6 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$52$$$=52$$$=4$$$=\dfrac{4}{52}=\dfrac{1}{13}$$$52$$=52$$13$$13$$$\dfrac{13}{52}+ \dfrac{13}{52}=\dfrac{1}{4}+\dfrac{1}{4}=\dfrac{2}{4}=\dfrac{1}{2}$$$52$$=52$$13.$$$=\dfrac{13}{52}=\dfrac{1}{4}$$$52$$=52$$12.$$$=\dfrac{12}{52}=\dfrac{3}{13}$…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p2?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 and 4 Exercise 6.5

Solutions of Question 3 and 4 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$P(A)=0.5$$P(A \cup B)=0.6$$P(B)$$A$$B$$\mathrm{A}$$B$$A \cap B=\emptyset$\begin{align}P(A \cup B)&amp;=P(A)+P(B)\\
\Rightarrow P(B)&amp;=P(A \cup B)-P(A)\\
&amp;=0.6-.0 .5=0.1 \end{align}$30$$1$$30.$\begin{align}S&amp;=\{1,2,3, \ldots, 50\} \tex…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 6.5

Solutions of Question 5 and 6 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{8}{9}$$$E=\{ event\, passing\, the\, test \}$$$$E^{\prime}=\{ event\, failing\, the\, test \}$$$E$$E^{\prime}$$P(E)=\dfrac{8}{9}$\begin{align}P(E^{\prime})&amp;=1-P(E)=1-\dfrac{8}{9}=\dfrac{1}{9}\end{align}$4$$4$\begin{align}S…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p4?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 6.5

Solutions of Question 7 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$52$$52$$26$$26$$13$$13$$13$$13$$13$$10,9,8,7,6,5,4,3$$2.$$$=\dfrac{13}{52}=\dfrac{1}{4}$$$$=\dfrac{4}{52}=\dfrac{1}{13}$$\begin{align}
P(A \cup B)&amp;=P(A)+P(B) \\
&amp; =\dfrac{1}{4}+\dfrac{1}{13}=\dfrac{17}{52} \end{align}$$=1-\dfrac{17}{52}=\dfr…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p5?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 6.5

Solutions of Question 8 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$7$$11.$\begin{align}s&amp;=(i i, j): i, j-1,2,3,4,5,6\}\\
&amp;=\left[\begin{array}{llllll}
(1.1) &amp; (1.2) &amp; (1.3) &amp; (1.4) &amp; (1.5) &amp; (1.6) \\
(2.1) &amp; (2.2) &amp; (2.3) &amp; (2.4) &amp; (2.5) &amp; (2.6) \\
(3.1) &amp; (3.2) &amp; (3.3) &amp; (3.4) &amp; (3.5) &amp; (3.6) \\
(4.1) &amp; (4…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p6?rev=1737476038&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 6.5

Solutions of Question 9 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2$$\dfrac{1}{7}$$\dfrac{1}{5}$\begin{align}
P(\text { Ajmal scicction })&amp;=\dfrac{1}{7} \\
\Rightarrow P(\text { Ajmal not selected })&amp;=\dfrac{6}{7} \\
P(\text { Bushra selection })&amp;=\dfrac{1}{5} \\
\Rightarrow P(\text { Bushra not selected }…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Review Exercise 6

Solutions of Question 2 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${ }^{2 n} C_r={ }^{2 n} C_{r+2}$$r$\begin{align}
{ }^{2 n} C_r&amp;={ }^{2 n} C_{r+2} \\
\Rightarrow \dfrac{(2 n) !}{(2 n-r) ! r !}&amp;=\dfrac{(2 n) !}{(2 n-(r+2)) !(r+2) !}\end{align}$(2 n)$\begin{align}
\Rightarrow \dfrac{1}{(2 n-r) ! r…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p3?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 &amp; 4 Review Exercise 6

Solutions of Question 3 &amp; 4 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${ }^{56} P_{r+6}:{ }^{54} P_{r+3}=30800: 1$$r$\begin{align}
{ }^{56} P_{r+6}:{ }^{54} P_r+3&amp;=30800: 1  \\
\Rightarrow \dfrac{\dfrac{56 !}{[56-(r+6)] !}}{\dfrac{54 !}{[54-(r+3)] !}}&amp;=\dfrac{30800}{1} \\
\Rightarrow \dfrac{56…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p4?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 5 &amp; 6 Review Exercise 6

Solutions of Question 5 &amp; 6 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$n=6$$$$(n-1) !=(6-1) !=5 !=120$$$120-24=96$$n=6$$(n-1) !=(6-1) !=5 !=120$$$(n-1) !=(5-1) !=4 !=24$$$$(n-1) !=(6-1) !=5 !=120$$$$4 ! \cdot 2 !=48$$$(5-1) !$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 7 &amp; 8 Review Exercise 6

Solutions of Question 7 &amp; 8 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$P(A)=0.8, P(B)=0.5$$P(B / A)=0.4$$P(A \cap B)$\begin{align}
P(B \mid A)&amp;=\dfrac{P(A \cap B)}{P(A)} \\
\Rightarrow P(A \cap B)&amp;=P(B \mid A) \cdot P(A)\\
&amp;=0.4 \times 0.8=0.32\end{align}$P(A)=0.8, P(B)=0.5$$P(B / A)=0.4$$P(A …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 &amp; 10 Review Exercise 6

Solutions of Question 9 &amp; 10 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2,3,0,3,4,2,3$$1$$=100,0000$$$=\dfrac{7 !}{3 ! \cdot 2 !}=420 $$$1$$0$$7$$0$$$=\dfrac{6 !}{2 ! 3 !}=60 $$$1$$420-50=360$$n$$n$$(n-1)$$(n - 1)$$(n-1)$$(n-2) !$$2$$2 !$$n$$$(n-2) ! \cdot 2 !=2(n-2) ! $$</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 7.1

Solutions of Question 2 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1+5+9+\ldots+(4 n-3)=n(2 n-1)$$n=1$$$1=1(2.1-1)=1$$$n=1$$n=k$\begin{align}1+5+9+\ldots+(4 k-3)\\
&amp; =k(2 k-1)....(i) \\
\end{align}$n=k+1$$k+1$$$a_{k-1}=4(k+1)-3=4 k+1 $$$(k+1)^{t h}$\begin{align}1+5+9+\ldots+(4 k-3)+(4 k+1)&amp; =k(2 k-1)+4 k+1 …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 7.1

Solutions of Question 3 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$3+6+9+\ldots+3 n=\dfrac{3 n(n+1)}{2}$$n=1$$3=\dfrac{3.1(1+1)}{2}=3$$n=1$$n=k$$$3+6+9+\ldots+3 k=\dfrac{3 k(k+1)}{2}....(i)$$$n=k+1$$(k+1)$$a_{k+1}=3(k+1)$$(k+1)^{t h}$\begin{align}3+6+9+\ldots+3 k+3(k+1) &amp; =\dfrac{3 k(k+1)}{2}+3(k+1) \\
&amp; =3…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p4?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 7.1

Solutions of Question 4 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$3+7+11+\cdots+(4 n-1)=n(2 n+1)$$n=1$$$3=1(2+1)=3 $$$n=1$$n=k$\begin{align}3+7+11+\cdots+(4 k-1) 
&amp; =k(2 k+1)....(i) \end{align}$n=k+1$$(k+1)$$a_{k+1}=4(k+1)-1$$(k+1)^{t h}$\begin{align}
3+7+11+\cdots+(4 k-1)+[4(k+1)-1] &amp; =k(2 k+1)+4(k+1)-1 \…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 7.1

Solutions of Question 5 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1^3+2^3+3^3+\ldots+n^3=\left[\dfrac{n(n+1)}{2}\right]^2$$n=1$$1^3=1=\left[\dfrac{1(1+1)}{2}\right]^2=1$$n=1$$n=k_1$\begin{align}1^3+2^3+3^3+\ldots+k^3&amp; =[\dfrac{k(k+1)}{2}]^2....(i)\end{aligned}
3. Now $$ the $$ term of the given series on l…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p6?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 7.1

Solutions of Question 6 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1(1 !)+2(2 !)+3(3 !)+\ldots+n(n !)= -(n+1) !-1$$n=1$$$1(1 !)=1=(1+1) !-1=2 !-1=1 $$$n=1$$n=k$\begin{align}1(1 !)+2(2 !)+3(3 !)+\ldots+k(k !)&amp; =(k+1) !-1  \ldots . .(i)\end{align}$n=k+1$$(k+1)^{t h}$$a_{k+1}=(k+1)[(k+1) !]$$a_{k-1}$\begin{ali…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 7.1

Solutions of Question 7 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1.2+2.3+3.4+\ldots+n(n+1)=\dfrac{n(n+1)(n+2)}{3}$$n=1$$$1.2=2=\dfrac{1(1+1)(1+2)}{3}=2 $$$n=1$$n=k$\begin{align}1.2+2.3+3.4+\ldots+k(k+1)&amp; =\dfrac{k(k+1)(k+2)}{3}....(i)\end{align}$n=k+1$$(k-1)^{t h}$$a_{k+1}=(k+1)(k+ 2)$$(k+1)^{\text {th }}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p8?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 7.1

Solutions of Question 8 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1+2+2^2+2^3+\ldots+2^n 1=2^n-1$$n=1$$1=2^1-1=1$$n=1$$n-k&gt;1$\begin{align}1+2+2^2+2^3+\ldots+2^{k-1} \\
&amp; =2^k-1 ....(i)\end{align}$n-k-1$$(k+1)^{t h}$$a_{k+1}=2^k$$a_{k+1}$\begin{align}1+2+2^2+2^3+\ldots+2^{k-1}-2^k &amp; =2^k-12^k \\
&amp; =2^k+2^k-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p9?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p9?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 7.1

Solutions of Question 9 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\ldots+\dfrac{1}{3^n}=\dfrac{1}{2}[1-\dfrac{1}{3^n}]$$n=1$$$\dfrac{1}{3}-\dfrac{1}{2}[1-\dfrac{1}{3}]-\dfrac{1}{2} \dfrac{2}{3}=\dfrac{1}{3} $$$n=1$$n=k$$$\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\ldots…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p10?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p10?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 7.1

Solutions of Question 10 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\left(\begin{array}{1}5 \\5 \end{array}\right)+\left(\begin{array}{l}6 \\ 5\end{array}\right)+\left(\begin{array}{l}7 \\ 5\end{array}\right)+\ldots+\left(\begin{array}{c}n+4 \\ 5\end{array}\right)=\left(\begin{array}{c}n+5 \\ 6\end{array}\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p11?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p11?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Exercise 7.1

Solutions of Question 11 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.\begin{align}
&amp; \left(\begin{array}{l}
2 \\
2
\end{array}\right)+\left(\begin{array}{l}
3 \\
2
\end{array}\right)+\left(\begin{array}{l}
4 \\
2
\end{array}\right)+\ldots+\left(\begin{array}{l}
n \\
2
\end{array}\right)=\left(\begin{array}{c…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p12?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p12?rev=1737476038&amp;do=diff</link>
        <description>Question 12 Exercise 7.1

Solutions of Question 12 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{5^{2 n}-1}{24}$$n=1$$$\dfrac{5^{2 n}-1}{24}=\dfrac{5^{2.1}-1}{24}=\dfrac{24}{24}=1 \in \mathbb{Z}$$$n=1$$n=k&gt;1$$$\dfrac{5^{2 k}-1}{24} \in \mathbb{Z}$$$n=k+1$\begin{align}\dfrac{5^{2(k+1)}-1}{24}&amp;=\dfrac{5^{2 k+2}-1}{24} \\
&amp; =\dfra…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p13?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p13?rev=1737476038&amp;do=diff</link>
        <description>Question 13 Exercise 7.1

Solutions of Question 13 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2^n&gt;n \forall n \in \mathbf{N}$$n=1$$2^n=2^1=2$$n=1$$2&gt;1$$n=1$$n=l&gt;I$$2^k&gt;k\cdots(i)$$n=k+1$\begin{align}
&amp; 2^{k+1}=2^k \cdot 2&gt;k \cdot 2 \quad \text { by (i) } \\
&amp; \Rightarrow 2^{k+1}&gt;2 k=k+k \\
&amp;\Rightarrow 2^{k+1}&gt;k+1 \text {. as } k&gt;1…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p14?rev=1737476038&amp;do=diff</link>
        <description>Question 14 Exercise 7.1

Solutions of Question 14 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$5$$3^{2 n-1}+2^{2 n-1}$$n$$n=1$$$3^{2 n-1}+2^{2 n-1}=3^{2.1-1}+2^{2.1-1}=5 \text {. }$$$5$$5$$5$$5.$$n=1$$n=k&gt;1$$54$$3^{2 k} 1+2^{2 k} \quad 1$$$3^{2 k-1}+2^{2 k-1}=5 Q$$$Q$$n=k+1$\begin{align}
3^{2(k+1)-1}+2^{2(k+1)-1} &amp; =3^{2 k+2-1}+2^{2…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 7.2

Solutions of Question 2 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$4^{th}$$(2+a)^7$$\ln$$n=7$$a=2$$b=a$$$T_{r+1}=\frac{7 !}{(7-r) ! r !}(2)^{7-r } a^r $$$4^{\text {th }}$$r=3$\begin{align}
&amp; T_{3+1}=\dfrac{7 !}{(7-3) ! 3 !} 2^{7-3} a^3 \\
&amp; \Rightarrow T_4=\dfrac{7 !}{4 ! 3 !} \cdot 2^4 a^3 \\
&amp; \Rightarrow…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 7.2

Solutions of Question 3 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x$$(\dfrac{4 x^2}{3}-\dfrac{3}{2 x})$$n=9, \quad a=\dfrac{4 x^2}{3}$$b=-\dfrac{3}{2 x}$$T_{r+1}$$x$$T_{r+1}$\begin{align}T_{r+1}&amp;=\dfrac{9 !}{(9-r) ! r !}(\dfrac{4 x^2}{3})^{9-r}(-\dfrac{3}{2 x})^r \\
&amp; =\dfrac{9 !}{(9-r) ! r !} \cdot \dfrac…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 7.2

Solutions of Question 4 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x^{23}$$(x^2-x)^{20}$$n=20, \quad a=x^2$$b=-x$$T_{r, 1}$$x^{23}$\begin{align}T_{r-1}&amp;=\dfrac{20 !}{(20-r) ! r !}(x^2)^{20 r}(-x)^r \\
&amp; =\dfrac{20 !}{(20-r) ! r !}(-1)^r \cdot x^{40-2 r+r} \\
&amp; =\dfrac{20 !}{(20-r) ! r !}(-1)^r x^{40-r}\end{…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 7.2

Solutions of Question 5 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(\dfrac{a}{x}+b x)^8$$a=\dfrac{a}{x}$$b=b x$$n=8$$n-8$$8+1=9$$$(\dfrac{8+2}{2})^{t h}=5^{t h}$$T_{r+1}$$$T_{r+1}=\dfrac{8 !}{(8-r) ! r !}(\dfrac{a}{x})^{8-r}(b x)^r$$$T_5$$r=4$\begin{align}T_5&amp;=\dfrac{8 !}{(8-4) ! 4 !}(\dfrac{a}{x})^{8-4}(b …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 7.2

Solutions of Question 6 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(2 \sqrt{x}-\dfrac{3}{x \sqrt{x}})^{23}$$a=2 \sqrt{x}$$b=-\dfrac{3}{x \sqrt{x}}$$n=23$$x$\begin{align}
T_{r+1}&amp;=\dfrac{23 !}{(23-r) ! r !}(2 \sqrt{x})^{23-r}(-\dfrac{3}{x \sqrt{x}})^r \\
&amp; =\dfrac{23 !}{(23-r) ! r !} \cdot 2^{23-r} \cdot(-3)…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 7.2

Solutions of Question 7 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(2+\sqrt{3})^5+(2-\sqrt{3})^5$\begin{align}(2+\sqrt{3})^5+(2 \cdot \sqrt{3})^5&amp; =[(2)^5+{ }^5 C_1 \cdot 2^4 \cdot \sqrt{3}+{ }^5 C_2 \cdot 2^3 \cdot(\sqrt{3})^2 \\
&amp; +^5 C_3 \cdot 2^2 \cdot(\sqrt{3})^4+{ }^5 C_4 \cdot 2 \cdot(\sqrt{3})^4 \\
…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 7.2

Solutions of Question 8 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(3-2 x)^{10}$$x=\frac{3}{4}$$\left(3-2,1^{10}=3^{10}\left(1-\frac{3 x}{2}\right)^{10}\right.$$\left(1-\frac{3 x}{2}\right)^{10}$$p+1$$: 3-\mathbf{2}_1 1^{10}$$T_{5} !=\left(\begin{array}{c}10 \\ 5\end{array}\right) 3^{10} 5-2 \gamma^{15}$$x=…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 9 Exercise 7.2

Solutions of Question 9 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(x-y)=&quot;$$x=12$$y-4$$x=12$$$
\begin{aligned}
&amp; \left(x \quad y=20(12-y)^{20}\right. \\
&amp; =12^{2 n}\left(\begin{array}{ll}
1 &amp; \frac{y}{12}
\end{array}\right)^{31}
\end{aligned}
$$$\frac{(n+1) \cdot x}{1+|x|}$$\left(\frac{1}{12}\right)^2 \cdot…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p10?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 7.2

Solutions of Question 10 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n=2 ;$$s=2^{n-1}$$$
\left.(1+x)^n=\left(\begin{array}{l}
n \\
\vdots
\end{array}\right)+\left(\begin{array}{l}
m \\
1
\end{array}\right) x+\left(\begin{array}{l}
n \\
2
\end{array}\right) x^2-\ldots+i_n^*\right) x^n \cdot
$$$x=1$$(1 \div 1…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2 Exercise 7.3

Solutions of Question 2 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sqrt{26}$$$
\begin{aligned}
&amp; \sqrt{26}=\sqrt{25+1} \\
&amp; =\sqrt{25} \sqrt{1+\frac{1}{25}}=5\left[1+\frac{1}{25}\right]^{\frac{1}{2}}
\end{aligned}
$$$$
\begin{aligned}
&amp; \sqrt{26}=5\left[1+\frac{1}{25}\right]^{\frac{1}{2}} \\
&amp; =5\left[1+\f…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3 Exercise 7.3

Solutions of Question 3 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sqrt{\frac{1-x}{1+x}}$$x^3$$\sqrt{\frac{1-x}{1+x}}$$$
=(1-x)^{\frac{1}{2}}(1+x)^{-\frac{1}{2}} \text {. }
$$$$
\begin{aligned}
&amp; (1-x)^{\frac{1}{2}}(1+x)^{\frac{1}{2}} \\
&amp; =\left[1-\frac{x}{2}+\frac{\frac{1}{2}\left(\frac{1}{2}-1\right)}{2…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4 Exercise 7.3

Solutions of Question 4 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x$$x^2$$x$$$
\sqrt{\frac{1-3 x}{1+4 x}}=1-\frac{7 x}{2}
$$$$
\sqrt{\frac{1-3 x}{1-4 x}}=(1-3 x)^{\frac{1}{2}}(1+4 x)^{-\frac{1}{2}}
$$$x^2$$x$$$
\begin{aligned}
&amp; =\left(1-\frac{3 x}{2}\right) \times\left(1-\frac{4 x}{2}\right) \\
&amp; =\left(1…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 7.3

Solutions of Question 5 and 6 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x$$x^2$$x$$$
\frac{(8+3 x)^{\frac{2}{3}}}{(2+3 x) \sqrt{4-5 x}}=1-\frac{5 x}{8}
$$$$
\frac{\sqrt[4]{3}-3 x j^{\frac{2}{3}}}{2 \cdot 3 x+4-5 x}
$$$$
\begin{aligned}
&amp; =\frac{8^{\frac{2}{3}}\left(1+\frac{3 x}{8}\right)^{\frac{2}{3}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8 Exercise 7.3

Solutions of Question 7 and 8 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x^4$$(1-x)^{\frac{1}{4}}+(1-x)^{\frac{1}{4}}=a-b x^2$$a$$b$$$
\begin{aligned}
&amp; (1+x)^{\frac{1}{4}}+(1-x)^{\frac{1}{4}} \\
&amp; =\left[1+\frac{x}{4}+\frac{\frac{1}{4}\left(\frac{1}{4}-1\right)}{2 !} x^2+\right. \\
&amp; \left.\frac{\fra…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 9 Exercise 7.3

Solutions of Question 9 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x^{\prime \prime}$$\left(\frac{1+x}{1-x}\right)^2$$$
\begin{aligned}
&amp; \left(\frac{1+x}{1-x}\right)^2=(1+x)^2(1-x)^{-2} \\
&amp; =\left(x^2+2 x+1\right)(1-x)^2
\end{aligned}
$$$$
\begin{aligned}
&amp; =\left(x^2+2 x+1\right)[1+2 x+ \\
&amp; \frac{-2(-2-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 10 Exercise 7.3

Solutions of Question 10 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1-\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}+\ldots$$(1+x)^n$$$
\begin{aligned}
&amp; 1+n x+\frac{n(n-1)}{2 !} x^2 \\
&amp; +\frac{n(n-1(n-2))}{3 !} x^3+\ldots
\end{aligned}
$$$n x=-\frac{1}{4}$$\frac{n(n-1)}{2 !} x^2=\frac{1.3}{2 !} \cdot …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p9?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 11 Exercise 7.3

Solutions of Question 11 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$y=\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}+\frac{1 \cdot 3 \cdot 5}{3 !} \cdot \frac{1}{2^6}+\ldots$$y^2+2 y-1=0$$y=\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}+\frac{1.3 \cdot 5}{3 !} \cdot \frac{1}{2^6}+\ldots$$$
S=y+1=1+\f…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 12 Exercise 7.3

Solutions of Question 12 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2 y=\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}+\frac{1.3 \cdot 5}{3 !} \cdot \frac{1}{2^6}+\ldots$$4 y^2+4 y-1=0$$$
2 y=\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}-\frac{1.3 \cdot 5}{3 !} \cdot \frac{1}{2^6}+\ldots
$$$S=2 y+1=…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p11?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 13 Exercise 7.3

Solutions of Question 13 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x$$x^3$$x$$n^{\text {th }}$$1+x$$\frac{2 n+(n+1) x}{2 n+(n-1) x}$$$
\begin{aligned}
&amp; (1+x)^{\frac{1}{n}}=\frac{2 n+(n+1) x}{2 n+(n-1) x} \\
&amp; \frac{2 n+(n+1) x}{2 n+(n-1) x} \\
&amp; =1+\frac{1}{n} x+\frac{\frac{1}{n}\left(\frac{1}{n}-1\right…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2 Review Exercise 7

Solutions of Question 2 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\left(2 x^3+3 y\right)^8$$a=2 x^3$$b=3 y$$n=8$$n=8$$\frac{8+2}{2}=5$$$
\begin{aligned}
&amp; T_5=\frac{8 !}{(8-4) ! 4 !}\left(2 x^3\right)^{8-4}(3 y)^4 \\
&amp; T_5=70.2^4 \cdot 3^4 \cdot x^{12} \cdot y^4 \\
&amp; =90720 x^{12} y^4
\end{aligne…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p3?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3 &amp; 4 Review Exercise 7

Solutions of Question 3 &amp; 4 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(2 x-4 y)^7$$n=7, a=2 x$$b=-4 y$$$
\begin{aligned}
&amp; T_{3+1}=\frac{7 !}{(7-3) ! 3 !}(2 x)^{7 \cdot 3}(-4 y)^3 \\
&amp; =\frac{7 !}{(7-3) ! 3 !} \cdot\left(2^4\right) \cdot(-4)^3 \cdot x^4 y^3 \\
&amp; \Rightarrow T_4=-35840 x^4 y^3…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 5 &amp; 6 Review Exercise 7

Solutions of Question 5 &amp; 6 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\left(\frac{2}{x^2}+\frac{x^2}{2}\right)^{10}$$n=10, a^{\prime}=\frac{2}{x^2}$$b=\frac{x^2}{2}$$T_{r+1}$$x$$$
\begin{aligned}
&amp; T_{r+1}=\frac{10 !}{(10-r) ! r !}\left(\frac{2}{x^2}\right)^{10 r}\left(\frac{x^2}{2}\right)^r …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p6?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10 Review Exercise 7

Solutions of Question 9 and 10 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 10.1

Solutions of Question 2 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \dfrac{\pi }{12}$$\dfrac{\pi }{12}$$\dfrac{\pi }{3}-\dfrac{\pi }{4}$\begin{align}\sin (\alpha -\beta )=\sin \alpha \cos \beta -\cos \alpha \sin.\end{align}\begin{align} \Rightarrow \quad \sin \left( \frac{\pi }{3}-\f…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p3?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 10.1

Solutions of Question 3 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin u=\dfrac{3}{5}$$\sin v=\dfrac{4}{5}$$u$$v$$0$$\dfrac{\pi }{2}$$\cos \left( u+v \right)$$\sin u=\dfrac{3}{5},$$0\le u\le \dfrac{\pi }{2}.$$\sin v=\dfrac{4}{5},$$0\le v\le \dfrac{\pi }{2}.$$\cos u=\pm \sqrt{1-{{\sin }^…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p4?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p4?rev=1737476039&amp;do=diff</link>
        <description>Question, Exercise 10.1

Solutions of Question 4 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \alpha =-\dfrac{4}{5}$$\cos \beta =-\dfrac{12}{13}$$\alpha $$\beta $$\sin \left( \alpha -\beta  \right)$$\sin \alpha=-\dfrac{4}{5}$$\alpha$$\sin \beta=-\dfrac{12}{13}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$$\…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 10.1

Solutions of Question 5 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\tan \alpha =\dfrac{3}{4}$$\sec \beta =\dfrac{13}{5}$$\alpha$$\beta$$\sin \left( \alpha +\beta  \right)$$\tan\alpha =\dfrac{3}{4}$$\tan\alpha$$\alpha$\begin{align}{{\sec}^{2}}\alpha &amp;=1+{{\tan}^{2}}\alpha\\
\Rightarrow \q…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos \alpha =2{{\cos }^{2}}\dfrac{\alpha }{2}-1=1-2{{\sin }^{2}}\dfrac{\alpha }{2}$\begin{align}\cos \alpha &amp;=\cos 2\dfrac{\alpha }{2}\\
&amp;={{\cos }^{2}}\dfrac{\alpha }{2}-{{\sin }^{2}}\dfrac{\alpha }{2}\\ 
&amp;={{\cos }^{2}}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p7?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cot \left( \alpha +\beta  \right)=\dfrac{\cot \alpha \cot \beta -1}{\cot \alpha +\cot \beta }$\begin{align}L.H.S.&amp;=\cot (\alpha +\beta )\\
&amp;=\dfrac{1}{\tan (\alpha +\beta )}\\
&amp;=\dfrac{1}{\,\dfrac{\tan \alpha +\tan \beta…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p8?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 8, Exercise 10.1

Solutions of Question 8 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\tan \left( \dfrac{\pi }{4}+\theta  \right)=\dfrac{\cos \theta +\sin \theta }{\cos \theta -\sin \theta }$\begin{align}L.H.S.&amp;=\tan \left( \dfrac{\pi }{4}+\theta  \right)\\ 
&amp;=\dfrac{\sin \left( \dfrac{\pi }{4}+\theta  \ri…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p9?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 10.1

Solutions of Question 9 and 10 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{\sin \theta }{\sec 4\theta }+\dfrac{\cos \theta }{\cos ec4\theta }=\sin 5\theta $\begin{align}L.H.S.&amp;=\dfrac{\sin \theta }{\sec 4\theta }+\dfrac{\cos \theta }{\cos ec4\theta }\\
&amp;=\dfrac{\sin \theta }…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p10?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question11 and 12, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p10?rev=1737476039&amp;do=diff</link>
        <description>Question11 and 12, Exercise 10.1

Solutions of Question 11 and 12 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\alpha$$\beta$$\gamma$$ABC$$\cot \dfrac{\alpha }{2}+\cot \dfrac{\beta }{2}+\cot \dfrac{\gamma }{2}=\cot \dfrac{\alpha }{2}\cot \dfrac{\beta }{2}\cot \dfrac{\gamma }{2}$$\alpha$$\beta$$\gamma$\begin{align}&amp;\…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 10.2

Solutions of Question 2 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \theta =\dfrac{5}{13}$$\theta $$\sin 2\theta $$\sin \theta =\dfrac{5}{13}$$$\cos \theta =\pm \sqrt{1-{{\sin }^{2}}\theta }.$$$\theta$$\cos$\begin{align}\cos\theta &amp;=-\sqrt{1-{{\sin }^{2}}\theta }\\
&amp;=-\sqrt{1-\left(\…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 10.2

Solutions of Question 3 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \theta =\dfrac{4}{5}$$\theta$$\sin2\theta$$\sin \theta =\dfrac{4}{5}$$\theta$$\cos \theta =-\dfrac{3}{5}$\begin{align}\sin 2\theta &amp;=2\sin \theta \cos \theta \\
&amp;=2\left( \dfrac{4}{5} \right)\left( -\dfrac{3}{5} \rig…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 and 5, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4 and 5, Exercise 10.2

Solutions of Question 4 and 5 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos \theta =-\dfrac{3}{7}$$\theta $$\sin \dfrac{\theta }{2}$$\cos \theta =-\dfrac{3}{7}$$\theta$\begin{align}&amp;\pi &lt; \theta &lt; \dfrac{3\pi}{2} \\
\implies &amp;\frac{\pi}{2} &lt; \frac{\theta}{2} &lt; \dfrac{3\pi}{4}\end…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 10.2

Solutions of Question 6 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{15}^{\circ }}$${{15}^{\circ }}=\dfrac{{{30}^{\circ }}}{2}$$\dfrac{\theta }{2}=\dfrac{{{30}^{\circ }}}{2}$$\cos {{15}^{\circ }}$\begin{align}\cos {{15}^{\circ }}&amp;=\cos \dfrac{{{30}^{\circ }}}{2}=\sqrt{\dfrac{1+\cos …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p6?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 10.2

Solutions of Question 7 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\cos }^{4}}\theta -{{\sin }^{4}}\theta =\dfrac{1}{\sec 2\theta }$\begin{align}L.H.S&amp;={{\cos }^{4}}\theta -{{\sin }^{4}}\theta \\ 
&amp;=\left( {{\cos }^{2}}\theta -{{\sin }^{2}}\theta  \right)\left( {{\cos }^{2}}\theta +{{\…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 10.3

Solutions of Question 2 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\sin {{37}^{\circ }}+\sin {{43}^{\circ }}.$$$$\sin \alpha +\sin \beta =2\sin \left( \dfrac{\alpha +\beta }{2} \right)\cos \left( \dfrac{\alpha -\beta }{2} \right).$$$\alpha ={{37}^{\circ }}$$\beta ={{43}^{\circ }}$\begin…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 10.3

Solutions of Question 3 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\dfrac{\cos {{75}^{\circ }}+\cos {{15}^{\circ }}}{\sin {{75}^{\circ }}-\sin {{15}^{\circ }}}=\sqrt{3}.$$$$\cos \alpha +\cos \beta =2\cos \left( \dfrac{\alpha +\beta }{2} \right)\cos \left( \dfrac{\alpha -\beta }{2} \righ…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p4?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 10.3

Solutions of Question 5 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\cos {{20}^{\circ }}\cos {{40}^{\circ }}\cos {{60}^{\circ }}\cos {{80}^{\circ }}=\dfrac{1}{16}.$$$2\cos \alpha \cos \beta =\cos \left( \alpha +\beta  \right)+\cos \left( \alpha -\beta  \right)$\begin{align}L.H.S.&amp;=\cos {…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p2?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Review Exercise 10</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2 and 3, Review Exercise 10

Solutions of Question 2 and 3 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{2\sin \theta \sin 2\theta }{\cos \theta +\cos 3\theta }=\tan 2\theta \tan \theta $\begin{align}L.H.S.&amp;=\dfrac{2\sin \theta \sin 2\theta }{\cos \theta +\cos 3\theta }\\
&amp;=\dfrac{2\sin \theta \s…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p3?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise 10</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise 10

Solutions of Question 4 &amp; 5 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\sin }^{2}}\dfrac{\theta }{2}=\dfrac{\sin \theta \tan \dfrac{\theta }{2}}{2}$\begin{align}R.H.S.&amp;=\dfrac{\sin \theta \tan \dfrac{\theta }{2}}{2}\\
&amp;=\dfrac{\sin \theta \sin \dfrac{\theta }{2}}{2\cos \d…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p4?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7, Review Exercise 10</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 6 &amp; 7, Review Exercise 10

Solutions of Question 6 &amp; 7 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos 4\theta =1-8{{\sin }^{2}}\theta {{\cos }^{2}}\theta $\begin{align}L.H.S&amp;=\cos 4\theta \\
&amp;=\cos 2\left( 2\theta  \right)\\
&amp;=1-2\sin^2 2\theta \\
&amp;=1-2{{\left( 2\sin\theta \cos \theta  \right)}^{2}}…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 1.1

Solutions of Question 2 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2(i)
$x+iy$$(3+2i)+(2+4i)$\begin{align}&amp;(3+i2)+(2+i4)\\
=&amp;(3+2)+(i2+i4)\\
=&amp;5+i6\end{align}$x+iy$$(4+3i)-(2+5i)$\begin{align}&amp;(4+3i)-(2+5i)\\
=&amp;(4-2)+(3i-5i)\\
=&amp;2-2i\end{align}$x+iy$$(4+7i)+(4-7i)$\begin{align}
&amp;(4+7i)+(4-7i)\\
=&amp;(4+4)+(7i-7i…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 1.1

Solutions of Question 3 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3(i)
$\dfrac{(2+i)(3-2i)}{1+i}$\begin{align}&amp;\dfrac{(2+i)(3-2i)}{1+i}\\
=&amp;\dfrac{6-2i^2+3i-4i}{1+i}\\
=&amp;\dfrac{8-i}{1+i}\\
=&amp;\dfrac{8-i}{1+i}\times \dfrac{1-i}{1-i}\\
=&amp;\dfrac{8+i^2-8i-i}{1^2-i^2}\\
=&amp;\dfrac{7-9i}{2}\\
=&amp;\dfrac{7}{2}-\dfrac{9}…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 1.1

Solutions of Question 4 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 4(i)
$x$$y$$(2+3i)x+(1+3i)y+2=0$\begin{align}&amp;(2+3i)x+(1+3i)y+2=0\\
\implies &amp;(2x+y+2)+(3x+3y)i=0.\end{align}\begin{align}
2x+y+2&amp;=0 \quad \cdots(1)\\
3x+3y&amp;=0\quad \cdots (2)
\end{align}\begin{align}
&amp;3x=-3y \\
x=-y \quad ... (3) \end{align}$…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 1.1

Solutions of Question 5 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 5
$z$$4z-3\bar{z}=\dfrac{1-18i}{2-i}$$z=x+iy$$\bar{z}=x-iy$\begin{align}&amp;4z-3\bar{z}=\dfrac{1-18i}{2-i}\\
\implies &amp;4(x+iy)-3(x-iy)=\dfrac{1-18i}{2-i}\times \dfrac{2+i}{2+i}\\
\implies &amp;4x+4iy-3x+3iy=\dfrac{(1-18i)(2+i)}{2^2-i^2} \end{align}\b…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 1.1

Solutions of Question 6 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 6(i)
$4-3 i$$z=4-3 i$$\bar{z}=4+3i$$3 i+8$$2+\sqrt{\dfrac{-1}{5}}$\begin{align}z=&amp;2+\sqrt{\dfrac{-1}{5}}\\
=&amp;2+\sqrt{\dfrac{1}{5}}i,\end{align}$$\bar{z}=2-\sqrt{\dfrac{1}{5}}i$$$\dfrac{5 }{2}i-\dfrac{7}{8}$$z=\dfrac{5 }{2}i-\dfrac{7}{8},$$\bar…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 1.2

Solutions of Question 2 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2
$$
\left(z_{1} z_{2}\right)\left(z_{3} z_{4}\right)=\left(z_{1} z_{3}\right)\left(z_{2} z_{4}\right)=z_{3}\left(z_{1} z_{2}\right) z_{4}
$$\begin{align}
&amp;(z_1 z_2)(z_3 z_4) \\
=&amp;(z_1 z_2)z_5 \quad \text {Let }z_5=z_3 z_4 \\
=&amp;z_1 (z_2 z_5) \…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 1.2

Solutions of Question 3 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3(i)
$z \in \mathbb{C}$$z$$z=\bar{z}$$$z=a+ib\quad \text{where}\quad a,b\in \mathbb{R}\, ... (1)$$$z$$\overline{z}=z$$z$$z$$b=0$\begin{align}
&amp;z=a \\
\implies &amp;\bar{z}=a \end{align}$z=\bar{z}$$\overline{z}=z$$z$\begin{align}&amp; z=\bar{z}\\
\Righ…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 1.2

Solutions of Question 4 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 4
$z_{1}=2-3 i$$\left|z_{1} z_{2}\right|=16$$\left|z_{2}\right|$$$z_{1}=2-3i$$\begin{align}|z_1|&amp;=\sqrt{(2)^2+(-3)^2}\\
&amp;=\sqrt{13}\end{align}\begin{align}&amp;|z_{1} z_{2}|=16\\
\Rightarrow \quad &amp;|z_{1}|| z_{2}|=16\\
\Rightarrow \quad &amp; \sqrt{13…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 1.2

Solutions of Question 5 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 5
$z_1$$z_2$$|z_1+z_2|^2-|z_1-z_2|^2=4Re(z_1)Re(z_2)$\begin{align}z_1&amp;=x_1+iy_1 \text{ and } z_2&amp;=x_2+iy_2\end{align}\begin{align}z_1+z_2&amp;=x_1+iy_1+x_2+iy_2\\
 &amp;=x_1+x_2+i(y_1+y_2)\\
|z_1+z_2|^2&amp;=(x_1+x_2)^2+(y_1+y_2)^2\\
 &amp;=x^2_1+x^2_2+2x_1x_…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 1.2

Solutions of Question 6 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 6
$\lambda$$\left|\dfrac{z_{1}}{z_{2}}+\lambda\right|=\sqrt{\lambda+2}$$z_{1}=3+i$$z_{2}=1+i$\begin{align} &amp;z_{1}=3+i\text{ and } z_{2}=1+i.\end{align}\begin{align}
\dfrac{z_1}{z_2} &amp;= \dfrac{3+i}{1+i}\\
&amp;=\dfrac{(3+i)(1-i)}{(1+i)(1-i)} \\
&amp;=\…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 1.2

Solutions of Question 7 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 7
$\sqrt{2}|z| \geq|\operatorname{Re}(z)|+|\operatorname{Im}(z)| \quad$$\left(|x|-|y|)^{2} \geq 0\right)$\begin{align}
&amp;\left(|x|-|y|)^{2} \geq 0\right) \\
\implies &amp; |x|^2+|y|^2-2|x||y| \geq 0 \\
\implies &amp; |x|^2+|y|^2 \geq 2|x||y| \\
\implie…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 8, Exercise 1.2

Solutions of Question 8 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 8(i)
$|2 z-i|=4$$x$$y$$z=x+i y$$$|2z-i|=4.$$$z=x+i y$\begin{align}
&amp; |2(x+iy)-i|=4 \\
\implies &amp; |2x+i(2y-1)|=4 \\
\implies &amp; \sqrt{(2x)^2+(2y-1)^2}=4
\end{align}\begin{align}
&amp; (2x)^2+(2y-1)^2 = 16\\
\implies &amp; 4x^2+4y^2-4y+1-16=0 \\
\implies…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 9, Exercise 1.2

Solutions of Question 9 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 9(i)
$(2+4 i)^{-1}$$z=2+4i$\begin{align}
Re(2+4i)^{-1} &amp; = Re(z^{-1}) = \dfrac{Re(z)}{|z|^2} \\
&amp; =\dfrac{2}{2^2+4^2} = \dfrac{2}{20}\\ 
&amp;= \dfrac{1}{10}.
\end{align}\begin{align}
Im(2+4i)^{-1} &amp; = Im(z^{-1}) = -\dfrac{Im(z)}{|z|^2} \\
&amp; =-\df…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 1.3

Solutions of Question 2 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2(i)
$z^{2}-6 z+2=0$\begin{align} &amp; z^2 - 6z + 2 = 0 \\
\implies &amp; z^2 - 2(3)(z)+9-9+2=0 \\
\implies &amp; (z - 3)^2+7= 0 \\
\implies &amp;  (z - 3)^2 = 7.
\end{align}\begin{align} &amp;z - 3 = \pm \sqrt{7} \\
 \implies &amp;z = 3 \pm \sqrt{7}\end{align}$\{3 …</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 1.3

Solutions of Question 3 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3(i)
$\dfrac{1}{3} z^{2}+2 z-16=0$\begin{align}&amp;\dfrac{1}{3}z^{2}+2 z-16=0\\
\implies &amp;z^{2} + 6z - 48 = 0 \end{align}$$ z = \dfrac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a},$$$$a = 1,\quad  b = 6,\quad \text{and}\quad  c = -48.$$\begin{align} 
z&amp; = \d…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 1.4

Solutions of Question 2 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2(i)
$\left(\cos \dfrac{\pi}{6}+i \sin \dfrac{\pi}{6}\right)\left(\cos \dfrac{\pi}{3}+i \sin \dfrac{\pi}{3}\right)$$z_1=\cos \dfrac{\pi}{6}+i \sin \dfrac{\pi}{6}=e^{i\frac{\pi}{6}}$$z_2=\cos \dfrac{\pi}{3}+i \sin \dfrac{\pi}{3}=e^{i\frac{\pi}{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 1.4

Solutions of Question 3 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3(i)
$\left(x_{1}+i y_{1}\right)\left(x_{2}+i y_{2}\right)\left(x_{3}+i y_{3}\right) \ldots\left(x_{n}+i y_{n}\right)=a+i b$$\left(x_{1}^{2}+y_{1}^{2}\right)\left(x_{2}^{2}+y_{2}^{2}\right)\left(x_{3}^{2}+y_{3}^{2}\right) \ldots\left(x_{n}^{2}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p4?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 1.4

Solutions of Question 4 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 4
$\dfrac{1+z}{1-z}=\cos 2 \theta+i \sin 2 \theta$$z=i \tan \theta$\begin{align}&amp;\dfrac{1+z}{1-z}=\cos 2 \theta+i \sin 2 \theta\\
\implies &amp;\dfrac{1+z}{1-z}=e^{i2\theta}\\
\implies &amp;(1+z)=(1-z)e^{i2\theta}\\
\implies &amp;z+z e^{i2\theta}=e^{i2\th…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 1.4

Solutions of Question 5 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 5
$\cos \alpha+\cos \beta+\cos \gamma=\sin \alpha+\sin \beta+\sin \gamma=0$$\cos 3 \alpha+\cos 3 \beta+\cos 3 \gamma=3 \cos (\alpha+\beta+\gamma)$$\sin 3 \alpha+\sin 3 \beta+\sin 3 \gamma=3 \sin (\alpha+\beta+\gamma)$\begin{align}
\cos \alpha …</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6(i-ix), Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6(i-ix), Exercise 1.4

Solutions of Question 6(i-ix) of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sqrt{2}\left(\cos 315^{\circ}+i \sin 315^{\circ}\right)$\begin{align}
&amp;\sqrt{2}\left(\cos 315^{\circ}+i \sin 315^{\circ}\right) \\
=&amp; \sqrt{2} \left(\dfrac{1}{\sqrt{2}}-\dfrac{i}{\sqrt{2}} \right) \\
=&amp; 1-i.
\end{align}$5\left(\cos 210^{\ci…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6(x-xvii), Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 6(x-xvii), Exercise 1.4

Solutions of Question 6(x-xvii) of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $7 \sqrt{2}\left(\cos \dfrac{5 \pi}{4}+i \sin \dfrac{5 \pi}{4}\right)$$10 \sqrt{2}\left(\cos \dfrac{7 \pi}{4}+i \sin \dfrac{7 \pi}{4}\right)$$2\left(\cos\dfrac{5\pi}{2}+i \sin \dfrac{5\pi}{2}\right)$$\dfrac{1}{\sqrt{2}}\left(\cos \dfrac{\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p8?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 1.4

Solutions of Question 7 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 7(i)
$\arg (z-1)=-\dfrac{\pi}{4}$$z=x+iy$\begin{align*}
&amp;\arg (z-1)=-\dfrac{\pi}{4} \\
\implies &amp; \arg(x+iy-1) = -\dfrac{\pi}{4} \\
\implies &amp; \arg(x-1+iy) = -\dfrac{\pi}{4} \\
\implies &amp; \tan^{-1}\left(\dfrac{y}{x-1}\right) = -\dfrac{\pi}{4} …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p9?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 8, Exercise 1.4

Solutions of Question 8 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 8(i)
$0.004 \mathrm{~mm}$$\dfrac{\pi}{4}$$$x_{\max}=0.004, \quad \theta=\dfrac{\pi}{4}.$$\begin{align}
x&amp;=x_{\max} e^{i\theta} \\
&amp;=0.004 e^{i\dfrac{\pi}{4}} \\
&amp;=\frac{4}{1000} \left(\cos\left(\dfrac{\pi}{4}\right) +i \sin\left(\dfrac{\pi}{4}…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 9, Exercise 1.4

Solutions of Question 9 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 9(i)
$x=2+3 i$$x_{\max }=1+4 i$$\mathrm{t}=0$$$x=2+3i$$$$x_{\max}=1+4 i$$$$\implies x=x_{\max} e^{i\theta}$$$$2+3i=(1+4 i) e^{i\theta}$$\begin{align}
\implies e^{i\theta}&amp;=\dfrac{2+3i}{1+4i} \\
&amp;=\dfrac{(2+3i)(1-4i)}{(1+4i)(1-4i)} \\
&amp;=\dfrac{…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Review Exercise

Solutions of Question 2 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $i^{2}+i^{4}+i^{6}+\cdots+i^{100}$\begin{align*}
&amp; i^{2}+i^{4}+i^{6}+\ldots+i^{100} \\
=&amp; i^2 + (i^2)^2 + (i^2)^3 + (i^2)^4 + \ldots +(i^2)^{49} +(i^2)^{50} \\
=&amp; -1 + (-1)^2 + (-1)^3 + (-1)^4 + \ldots + (-1)^{49}+(-1)^{50} \\
=&amp; -1+1-1+1- \ldots -…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Review Exercise

Solutions of Question 3 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3 x^{2}+108$\begin{align*}
&amp; 3 x^{2}+108\\
=&amp;3 (x^{2}+36)\\
=&amp;3 (x^{2}-(6i)^2)\\
=&amp;3 (x+6i)(x-6i)
\end{align*}$4 x^{2}+40$\begin{align*}
&amp;4 x^{2}+40\\
=&amp;4 (x^{2}+10)\\
=&amp;4 (x^{2}+(\sqrt{10}i)^2)\\
=&amp;4 (x+\sqrt{10}i)(x-\sqrt{10}i)
\end{align*}</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Review Exercise

Solutions of Question 4 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $z=x+i y$$\left|\dfrac{z+2 i}{z-2 i}\right|=1$$z = x + iy$\begin{align*}
&amp; \left|\dfrac{z + 2i}{z - 2i}\right| = 1\\
\implies &amp; |z + 2i| = |z - 2i|\\
\implies &amp; |x + i(y + 2)| = |x + i(y - 2)|\\
\implies &amp;  \sqrt{x^2 + (y + 2)^2} = \sqrt{x^2 + (y -…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Review Exercise

Solutions of Question 5 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $z$$(z-3 i)(2+5 i)=3-4 i$$z$$(z-3 i)(2+5 i)=3-4 i$\begin{align*}
&amp;(z-3 i)(2+5 i)=3-4 i \\
\implies &amp; z-3 i=\dfrac{3-4 i}{2+5 i} \\
\implies &amp; z-3 i=\dfrac{(3-4 i)(2-5i)}{(2+5 i)(2-5i)}\\
\implies &amp; z-3 i=\dfrac{6-20-15i-8i}{4+25}\\
\implies &amp; z-3 i…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p6?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Review Exercise

Solutions of Question 6 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\dfrac{1}{i^{10}}+(2-i)^{2}+\sqrt{-25}\right]^{3}$\begin{align*}
&amp;\left[\dfrac{1}{i^{10}} + (2 - i)^2 + \sqrt{-25}\right]^3\\
=&amp;\left[\dfrac{1}{(i^2)^5} + ( 4 - 4i + i^2) + 5i \right]^3\\
=&amp;\left[\dfrac{1}{(-1)^5} + ( 4 - 4i -1) + 5i \right]…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Review Exercise

Solutions of Question 7 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 z^{2}-11 z+16=0$\begin{align*}
&amp;2 z^{2}-11 z+16=0\\
\implies&amp;z^2 - \dfrac{11}{2}z + 8 = 0\\
\implies&amp; z^2 - \dfrac{11}{2}z = -8\\
\implies&amp; z^2 - 2z\dfrac{11}{4}z + \dfrac{121}{16} = -8 + \dfrac{121}{16}\\
\implies&amp;\left(z-\dfrac{11}{4}\right)^2…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 2.1

Solutions of Question 2 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\quad A=\left[\begin{array}{lll}3 &amp; 6 &amp; 2 \\ 2 &amp; 1 &amp; 9\end{array}\right]$$B=\left[\begin{array}{ll}\frac{1}{3} &amp; 1 \\ 2 &amp; 6\end{array}\right]$$C=\left[\begin{array}{l}3 \\ 2 \\ 8\end{array}\right]$$D=\left[\begin{array}{lll}1 &amp; 6 &amp; 9 \\ 2 &amp; 0 …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.1

Solutions of Question 3 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$A=\begin{bmatrix}
3 &amp; 0 &amp; 0 \\
0 &amp; 1 &amp; 0 \\
2 &amp; 6 &amp; 0
\end{bmatrix}$$$$B=\begin{bmatrix}
-6 &amp; 0 &amp; 0 \\
0 &amp; -6 &amp; 0 \\
0 &amp; 0 &amp; -6
\end{bmatrix}$$$$C=\begin{bmatrix}
1 &amp; 0 \\
2 &amp; 0
\end{bmatrix}$$$$D=\begin{bmatrix}
1 &amp; 0 &amp; 0 \\
0 &amp; 1 &amp; 0 \\
0 &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.2

Solutions of Question 3 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}3 &amp; -1 &amp; 2 \\ 0 &amp; 6 &amp; 1 \\ -1 &amp; 0 &amp; -3\end{array}\right]$$B=\left[\begin{array}{ccc}2 &amp; 1 &amp; 7 \\ 0 &amp; 2 &amp; -1 \\ -3 &amp; 4 &amp; 2\end{array}\right]$$C$$A+B+C=0$$$A+B+C=0,$$$$C=-A-B.$$\begin{align*}
C&amp;=-\begin{bmatrix}3 &amp; -1 &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.2

Solutions of Question 3 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}3 &amp; -1 &amp; 2 \\ 0 &amp; 6 &amp; 1 \\ -1 &amp; 0 &amp; -3\end{array}\right]$$B=\left[\begin{array}{ccc}2 &amp; 1 &amp; 7 \\ 0 &amp; 2 &amp; -1 \\ -3 &amp; 4 &amp; 2\end{array}\right]$$C$$A+B+C=0$$$A+B+C=0,$$$$C=-A-B.$$\begin{align*}
C&amp;=-\begin{bmatrix}3 &amp; -1 &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 2.2

Solutions of Question 4 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$\begin{align}\left[\begin{array}{cc} 2 &amp; 1 \\  3 &amp; 2 \end{array}\right]A\left[\begin{array}{cc} 1 &amp; 3 \\  2 &amp; 4 \end{array}\right]&amp;=\left[\begin{array}{cc} 1 &amp; 0 \\  0 &amp; 1 \end{array}\right]\end{align}$ B = \left[\begin{array}{cc} 2 &amp; 1 \\ 3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 2.2

Solutions of Question 5 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $X=\left[\begin{array}{lll}1 &amp; 2 &amp; 2 \\ 2 &amp; 1 &amp; 2 \\ 2 &amp; 2 &amp; 1\end{array}\right]$$X^{2}-4 X-5 I=0$\begin{align}L.H.S. &amp; =X^{2}-4 X-5 I \\
&amp;=\begin{bmatrix}
1 &amp; 2 &amp; 2 \\
2 &amp; 1 &amp; 2 \\
2 &amp; 2 &amp; 1
\end{bmatrix}
\begin{bmatrix}
1 &amp; 2 &amp; 2 \\
2 &amp; 1 &amp; 2…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 2.2

Solutions of Question 6 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{cc}2 &amp; 1 \\ 3 &amp; -3\end{array}\right]$$\alpha$$\beta$$A^{2}+\alpha I=\beta A$\begin{align}
&amp; A^{2}+\alpha I=\beta A\\
\implies &amp;\begin{bmatrix}
2 &amp; 1 \\
3 &amp; -3
\end{bmatrix}
\begin{bmatrix}
2 &amp; 1 \\
3 &amp; -3
\end{bmatrix}+\a…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 2.2

Solutions of Question 7 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ll}x &amp; 0 \\ y &amp; 1\end{array}\right]$$n, A^{n}=\left[\begin{array}{cc}x^{n} &amp; 0 \\ \dfrac{y\left(x^{n}-1\right)}{x-1} &amp; 1\end{array}\right]$$$A = \begin{bmatrix} x &amp; 0 \\ y &amp; 1 \end{bmatrix}.$$$n = 1$\begin{align}A^1 =\beg…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 8, Exercise 2.2

Solutions of Question 8 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$B$$2 \times 3$$3 \times 2$$(A B)^{t}=B^{t} A^{t}$\( A \)\( B \)\( 2 \times 3 \)\( 3 \times 2 \)\begin{align*}
	A &amp;= \begin{bmatrix}
	a_{11} &amp; a_{12} &amp; a_{13} \\
	a_{21} &amp; a_{22} &amp; a_{23}
\end{bmatrix}\\
B &amp;= \begin{bmatrix}
	b_{11} &amp; b_{12}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 9, Exercise 2.2

Solutions of Question 9 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$B$$3 \times 3$$(A+B)^{t}=A^{t}+B^{t}$\begin{align*}
A &amp;= \begin{pmatrix} 
a_{11} &amp; a_{12} &amp; a_{13} \\ 
a_{21} &amp; a_{22} &amp; a_{23} \\ 
a_{31} &amp; a_{32} &amp; a_{33} 
\end{pmatrix} \\
B &amp;= \begin{pmatrix} 
b_{11} &amp; b_{12} &amp; b_{13} \\ 
b_{21} &amp; b_{22…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 10, Exercise 2.2

Solutions of Question 10 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$B$$A B=B$$B A=A$$A^{2}+B^{2}$$$AB = B$$$$BA = A$$\begin{align*}
A^2 &amp;= AA\\
&amp; = A(BA)\\
&amp;=(AB)A\\
&amp;=BA\\
&amp;=A
\end{align*}\begin{align*}
B^2&amp;= BB \\
&amp;=B(AB)\\
&amp; = (BA)B\\
&amp;=AB\\
&amp;=B\end{align*}$$A^2 + B^2 = A + B$$$AB = B$$BA = A$$$A^2 + B…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p11?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 11, Exercise 2.2

Solutions of Question 11 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[a_{i j}\right]$$3 \times 3$$a_{i j}=i^{2}-j^{2}$$A$$A=\left[a_{i j}\right]$$a_{ij}=a+{ji}$$a_{ij}=-a_{ji}$$a_{i j}=i^{2}-j^{2}$\begin{align}
a_{ji} &amp; = j^2 -i^2 \\
&amp;= - (i^2 -j^2) \\
&amp;= - a_{ij}
\end{align}$a_{ij}=-a_{ji}$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p12?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p12?rev=1737476039&amp;do=diff</link>
        <description>Question 12, Exercise 2.2

Solutions of Question 12 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$\left(A^{n}\right)^{t}=\left(A^{t}\right)^{n}$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 2.3

Solutions of Question 2 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{lll}3 &amp; 2 &amp; 3 \\ 4 &amp; 5 &amp; 1 \\ 2 &amp; 1 &amp; 0\end{array}\right]$\(R_1\)\(a_{11} = 3\)\(a_{12} = 2\)\(a_{13} = 3\)\begin{align*}
A &amp;= \left[\begin{array}{ccc} 3 &amp; 2 &amp; 3 \\ 4 &amp; 5 &amp; 1 \\ 2 &amp; 1 &amp; 0 \end{array}\right]\\
&amp; A_{11} = (-1…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.3

Solutions of Question 3 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}3 &amp; 1 &amp; 2 \\ 2 &amp; 3 &amp; 1 \\ -4 &amp; 1 &amp; -3\end{array}\right]$\begin{align*}
A &amp;= \left[\begin{array}{ccc} 3 &amp; 1 &amp; 2 \\ 2 &amp; 3 &amp; 1 \\ -4 &amp; 1 &amp; -3\end{array}\right]\end{align*}\(3 \times 3\)\begin{align*}
|A| &amp;= 3(3 \cdot (-3) …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 2.3

Solutions of Question 4 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\lambda$$\left[\begin{array}{lll}\lambda &amp; 1 &amp; 3 \\ 2 &amp; 1 &amp; 8 \\ 0 &amp; 3 &amp; 1\end{array}\right]$\begin{align*}
A &amp;= \left[\begin{array}{ccc}
\lambda &amp; 1 &amp; 3 \\
2 &amp; 1 &amp; 8 \\
0 &amp; 3 &amp; 1
\end{array}\right]\\
|A| &amp;= \lambda \cdot (-23) - 1 \cdot 2 + 3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 2.3

Solutions of Question 5 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}1 &amp; -1 &amp; 1 \\ 2 &amp; 1 &amp; -1 \\ 1 &amp; -2 &amp; -1\end{array}\right]$\begin{align*}
A &amp;= \left[\begin{array}{ccc}
1 &amp; -1 &amp; 1 \\
2 &amp; 1 &amp; -1 \\
1 &amp; -2 &amp; -1
\end{array}\right]\\
|A|&amp;=  1 [-1 - 2] + 1 [-2 + 1] + 1 [-4 - 1] \\
&amp;= 1 \cd…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 2.3

Solutions of Question 6 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}2 &amp; 1 &amp; -3 \\ 0 &amp; 1 &amp; 0 \\ 2 &amp; 1 &amp; 6\end{array}\right]$$A^{-1}$$A A^{-1}=A^{-1} A=I_{3}$\begin{align*} A &amp;= \begin{bmatrix}
2 &amp; 1 &amp; -3 \\
0 &amp; 1 &amp; 0 \\
2 &amp; 1 &amp; 6
\end{bmatrix} \end{align*}$ A^{-1} $$ A $\begin{align*}
…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-5-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-5-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 2.5

Solutions of Question 2 of Exercise 2.5 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}5 &amp; 9 &amp; 3 \\ 3 &amp; -5 &amp; 6 \\ 2 &amp; 10 &amp; 6\end{array}\right]$\begin{align*}&amp;\quad\left[ \begin{array}{ccc}
5 &amp; 9 &amp; 3 \\ 
3 &amp; -5 &amp; 6 \\ 
2 &amp; 10 &amp; 6 
\end{array} \right]\\
\sim &amp; \text{R}\left[ \begin{array}{ccc}
1 &amp; \frac{9}{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 2.6

Solutions of Question 2 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\lambda$$\lambda$$2 x_{1}-\lambda x_{2}+x_{3}=0$$2 x_{1}+3 x_{2}-x_{3}=0$$3 x_{1}-2 x_{2}+4 x_{3}=0$\begin{align*}
&amp;2 x_{1}-\lambda x_{2}+x_{3}=0 \cdots(i)\\
&amp;2 x_{1}+3 x_{2}-x_{3}=0\cdots(ii)\\
&amp;3 x_{1}-2 x_{2}+4 x_{3}=0\cdots(iii)\\
\end{ali…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.6

Solutions of Question 3 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x+3 y+4 z=2$$2 x+y+z=5$$3 x-2 y+z=-3$\begin{align*}
\begin{aligned}
2x + 3y + 4z &amp;= 2 \\
2x + y + z &amp;= 5 \\
3x - 2y + z &amp;= -3
\end{aligned}\end{align*}\begin{align*}
A_{b} &amp;=\quad \left[\begin{array}{cccc}
2 &amp; 3 &amp; 4 &amp; 2 \\
2 &amp; 1 &amp; 1 &amp; 5 \\
3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 2.6

Solutions of Question 4 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x_{1}-x_{2}-x_{3}=2$$3 x_{1}-4 x_{2}+3 x_{3}=7$$4 x_{1}+2 x_{2}-5 x_{3}=10$\begin{align*}
2x_1 - x_2 - x_3 &amp;= 2, \\
3x_1 - 4x_2 + 3x_3 &amp;= 7, \\
4x_1 + 2x_2 - 5x_3 &amp;= 10,
\end{align*}\begin{align*}	
A_b &amp;= \begin{bmatrix}
2 &amp; -1 &amp; -1 &amp; : &amp; 2 …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 2.6

Solutions of Question 5 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $x_{1}+x_{2}+2 x_{3}=8$$-x_{1}-2 x_{2}+3 x_{3}=1$$3 x_{1}-7 x_{2}+4 x_{3}=10$$A X=B$\begin{align*}
&amp;A = \begin{bmatrix}
1 &amp; 1 &amp; 2 \\
-1 &amp; -2 &amp; 3 \\
3 &amp; -7 &amp; 4
\end{bmatrix}, \quad
X = \begin{bmatrix}
x_1 \\
x_2 \\
x_3
\end{bmatrix}, \quad
B = \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 2.6

Solutions of Question 6 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $5 x+3 y+z=6$$2 x+y+3 z=19$$x+2 y+4 z=25$\begin{align*}
A &amp;= \begin{bmatrix}
5 &amp; 3 &amp; 1 \\
2 &amp; 1 &amp; 3 \\
1 &amp; 2 &amp; 4
\end{bmatrix}, \quad
X = \begin{bmatrix}
x \\
y \\
z
\end{bmatrix}, \quad
B = \begin{bmatrix}
6 \\
19 \\
25
\end{bmatrix}
\end{alig…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 2.6

Solutions of Question 7 and 8 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}3 &amp; 2 &amp; 1 \\ 4 &amp; -1 &amp; 2 \\ 7 &amp; 3 &amp; -3\end{array}\right]$$A^{-1}$$3 x+4 y+7 z=14 ; 2 x-y+3 z=4 ; \quad x+2 y-3 z=0$\begin{align*}
A &amp;= \begin{bmatrix}
3 &amp; 2 &amp; 1 \\
4 &amp; -1 &amp; 2 \\
7 &amp; 3 &amp; -3
\end{bmatrix}\\
|…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/re-ex-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/re-ex-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2 and 3, Review Exercise

Solutions of Question 2 and 3 of Review Exercise of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}1 &amp; 2 &amp; 0 \\ -3 &amp; 4 &amp; 9 \\ 2 &amp; 1 &amp; 6\end{array}\right]$$A_{13}, A_{23}$$A_{33}$$|A|$\begin{align*}
A&amp;=\left[\begin{array}{ccc}1 &amp; 2 &amp; 0 \\ -3 &amp; 4 &amp; 9 \\ 2 &amp; 1 &amp; 6\end{array}\right]\\
A_{13} &amp;= (-1)^{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.1

Solutions of Question 3 and 4 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{n}=\frac{n}{n+1}$$$a_n = \frac{n}{n+1}.$$\begin{align*}

a_1 &amp;= \frac{1}{1+1} = \frac{1}{2}\\
a_2 &amp;= \frac{2}{2+1} = \frac{2}{3}\\
a_3 &amp;= \frac{3}{3+1} = \frac{3}{4}\\
a_4 &amp;= \frac{4}{4+1} = \frac{4}{5}\\
\end{align*}\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.1

Solutions of Question 5 and 6 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{15}$$a_{n}=n^{2}-2 n$$$a_n = n^2 - 2n.$$\begin{align*}
a_1 &amp;= (1)^2 - 2(1) = 1 - 2 = -1\\
a_2 &amp;= (2)^2 - 2(2) = 4 - 4 = 0\\
a_3 &amp;= (3)^2 - 2(3) = 9 - 6 = 3\\
a_4 &amp;= (4)^2 - 2(4) = 16 - 8 = 8\\
\end{align*}\begin{align*}
a_{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.1

Solutions of Question 7 and 8 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{15}$$a_{n}=\left(\frac{-1}{2}\right)^{n-1}$$$a_n = \left( \frac{-1}{2} \right)^{n-1}.$$\begin{align*}a_1 &amp;= \left( \frac{-1}{2} \right)^{1-1} = \left( \frac{-1}{2} \right)^0 = 1 \\
a_2 &amp;= \left( \frac{-1}{2} \right)^{2-1} =…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.1

Solutions of Question 9 and 10 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{15}$$a_{n}=(-1)^{n}(n+3)$$n$$a_{10}$$a_{15}$$$a_{n}=(-1)^{n+1}(3 n-5).$$$$a_n = (-1)^{n+1}(3n - 5).$$\begin{align*}
a_1 &amp;= (-1)^{1+1}(3(1) - 5) = (1)(3 - 5) = -2 \\
a_2 &amp;= (-1)^{2+1}(3(2) - 5) = (-1)(6 - 5) = -1 \\
a_3 &amp;=…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.1

Solutions of Question 11 and 12 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}=4 n-3; a_8$$$a_n = 4n - 3.$$\begin{align*}
a_8 &amp;= 4(8) - 3 \\
&amp;= 32 - 3 \\
&amp;= 29
\end{align*}$a_8 = 29$$a_{n}=5 n+11 ; a_{9}$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 and 14, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 13 and 14, Exercise 4.1

Solutions of Question 13 and 14 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}=(3 n+4)(2 n-5) ; a_{7}$$a_{n}=(-1)^{n-1}(3.4 n-17.3) ; a_{12}$$$a_n = (-1)^{n-1}(3.4n - 17.3).$$\begin{align*}
a_{12} &amp;= (-1)^{12-1}(3.4 \cdot 12 - 17.3) \\
&amp;= (-1)^{11}(40.8 - 17.3) \\
&amp;= (-1)^{11}(23.5) \\
&amp;= -23.5
\end{align…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15 and 16, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 15 and 16, Exercise 4.1

Solutions of Question 15 and 16 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}=4 n^{2}(11 n+31) ; a_{22}$$$a_n = 4n^2(11n + 31).$$\begin{align*}
a_{22} &amp;= 4 \cdot 22^2 \cdot (11 \cdot 22 + 31) \\
&amp;= 4 \cdot 484 \cdot (242 + 31) \\
&amp;= 4 \cdot 484 \cdot 273 \\
&amp;= 4 \cdot 132132 \\
&amp;= 528528
\end{align*}$a_{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p9?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 17 and 18, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 17 and 18, Exercise 4.1

Solutions of Question 17 and 18 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}=\log 10^{n} ; a_{43}$$$a_n = \log 10^n.$$\begin{align*}
a_{43} &amp;= \log 10^{43} \\
&amp;= 43 \cdot \log 10 \\
&amp;= 43 \cdot 1 \\
&amp;= 43
\end{align*}$a_{43}= 43$$a_{n}=\ln e^{n} ; a_{67}$$$a_n = \ln e^n.$$\begin{align*}
a_{67} &amp;= \ln e^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19 and 20, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 19 and 20, Exercise 4.1

Solutions of Question 19 and 20 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}$$1,3,5,7,9, \ldots$$$1, 3, 5, 7, 9, \ldots$$$a_1=1$$d=3-1=2$$$a_n = a_1 + (n - 1) d$$\begin{align*}
\implies a_n &amp;= 1 + (n - 1) \cdot 2\\
 &amp;= 1 + 2n - 2\\
&amp;= 2n - 1 \end{align*}$a_n = 2n - 1$$a_{n}$$3,9,27,81,243, \ldots$\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 4.2

Solutions of Question 2 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $5,9,13, \ldots$$$5, 9, 13, \ldots $$$a_1=5$$d=9-5=4$$$a_n=a_1+(n-1)d.$$\begin{align*}
a_4 &amp;=5+(4-1)(4)=5+12=17\\
a_5 &amp;=5+(5-1)(4)=5+16=21\\
a_6 &amp;=5+(6-1)(4)=5+20=25
\end{align*}$17$$21$$25$$11,14,17, \ldots$$$11, 14, 17, \ldots$$$a_1=11$$d=14-11=3$$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.2

Solutions of Question 3 and 4 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $0.07,0.12,0.7, \ldots$$$0.07,0.12,0.7, \ldots$$$a_1 = 0.07$$d=0.05$$a_{11}=?$\begin{align*}
a_n&amp;=a_1+(n-1)d \\
\implies a_{11}&amp;= 0.07+(11-1)(0.05)\\
&amp;=0.07+(10)(0.05)\\
&amp;=0.57
\end{align*}$a_{11}=0.57.$$a_3 = 14$$a_9 = -1$$$a_n = a_1 + (…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.2

Solutions of Question 5 and 6 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{17}=-40$$a_{28}=-73$$a_{1}$$d$$$a_n=a_1+(n-1)d$$\begin{align*}
&amp; a_{17} = -40 \\
\implies &amp;a_1 + 16d = -40 \quad \cdots (1)
\end{align*}\begin{align*}
&amp;a_{28}=-73\\
\implies &amp;a_1 + 27d = -73 \quad \cdots (2)
\end{align*}\begin{align*}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.2

Solutions of Question 7 and 8 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $-6,-2,2, \ldots$$70$$-6,-2,2, \ldots$$a_1=-6$$d=-2+6=4$$a_n=70$$n=?$$$a_n=a_1+(n-1)d.$$\begin{align*}
&amp;70=-6+(n-1)4\\
\implies &amp;70=-6+4n-4\\
\implies &amp;70=4n-10\\
\implies &amp;4n=80\\
\implies &amp; n=20
\end{align*}$a_{20}=70$$\dfrac{5}{2}, \df…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.2

Solutions of Question 9 and 10 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1}{a}, b, \dfrac{1}{c}$$\dfrac{a-c}{2 a c}$$\dfrac{1}{a}, b, \dfrac{1}{c}$\begin{align*}
d&amp;=b-\frac{1}{a}\cdots (i)\\
\end{align*}\begin{align*}
d&amp;=\frac{1}{c}-b \cdots (ii)
\end{align*}\begin{align*}
b-\frac{1}{a}&amp;=\frac{1}{c}-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.2

Solutions of Question 11 and 12 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $1000$$3000$$2$$5000$$3$$20$$$1000, 3000, 5000, \dots, \text{ upto 20 terms}.$$$a_1 = 1000$$d=3000-1000=2000$$S_20=?$$$S_n =\frac{n}{2}[2a_1+(n-1)d],$$\begin{align*}
S_{20} &amp;= \frac{20}{2}[2(1000)+(20-1)2000]\\
&amp;= 10 [2000+(19)2000] \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 13, Exercise 4.2

Solutions of Question 13 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $7$$17$$a=7$$b=17$\begin{align*}
\text{A.M.} &amp;= \frac{a + b}{2}\\
&amp;= \frac{7 + 17}{2} \\
&amp;= \frac{24}{2} = 12.
\end{align*}$12$$3+3 \sqrt{2}$$7-3 \sqrt{2}$$a=3+3\sqrt{2}$$b=7-3\sqrt{2}$\begin{align*}
\text{A.M.} &amp;= \frac{a + b}{2}\\
&amp;= \frac{(3 + 3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 and 15, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 14 and 15, Exercise 4.2

Solutions of Question 14 and 15 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $b$$10$$b$$20$$a= b$$b=20$\begin{align*}
&amp;\text{A.M.} = \frac{a + b}{2} \\
\implies &amp; 10 = \frac{b + 20}{2} \\
\implies &amp; 20 = b + 20 \\
\implies &amp; b = 20 - 20 \\
\implies &amp; b = 0
\end{align*}$b = 0$$b$$25$$b$$20$$b$$10$$b$$-10$$x$$y$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.3

Solutions of Question 3 and 4 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=5$$a_{n}=100$$n=200$$a_{1}=5$$a_{n}=100$$n=200$$a_{1}=5$$a_{n}=100$$n=200$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[a_1+a_n] \\
\implies S_{200}&amp;=\frac{200}{2}[5+100]\\
&amp;=10500.
\end{align}$S_{200}=10500$$a_{1}=4$$n=15$$d=3$$a_{1}=4$$n=1…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.3

Solutions of Question 5 and 6 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=50$$n=20$$d=-4$$a_{1}=50$$n=20$$d=-4$$a_{1}=50$$n=20$$d=-4$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d] \\
\implies S_{20}&amp;=\frac{20}{2}[2(50)+(20-1)(-4)]\\
&amp;=10\times [100-76]\\
&amp;=240.
\end{align}$S_{20}=240$$-3+(-7)+(-11)+\cd…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.3

Solutions of Question 7 and 8 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $9+11+13+15+\cdots$$n=12$$a_1=9$$d=11-9=2$$n=12$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d] \\
\implies S_{12}&amp;=\frac{12}{2}[2(9)+(12-1)(2)]\\
&amp;=6\times [18+22]\\
&amp;=240.
\end{align}$S_{12}=240$$2$$100$$2$$100$$$2+4+6+...+100 (50 \tex…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.3

Solutions of Question 9 and 10 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $1$$99$$1$$99$$$1+3+5+...+99 (50 \text{ terms}).$$$a_{1}=1$$n=50$$d=3-1=2$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d] \\
\implies S_{50}&amp;=\frac{50}{2}[2(1)+(50-1)(2)]\\
&amp;=25\times [2+98]\\
&amp;=2500.
\end{align}$1$$99$$2500$$14$$523$$…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.3

Solutions of Question 11 and 12 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $S_{\boldsymbol{n}}$$a_{1}=3$$a_{n}=-38$$n=8$$a_{1}=3$$a_{n}=-38$$n=8$\begin{align}
S_n&amp;=\frac{n}{2}[a_1+a_n] \\
\implies S_{8}&amp;=\frac{8}{2}[3-38]\\
&amp;=4\times[-35] \\
&amp;=-140.
\end{align}$S_{8}=-140$$S_n$$a_{1}=85$$n=21$$a_{n}=25$$a_{1…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 and 14, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 13 and 14, Exercise 4.3

Solutions of Question 13 and 14 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $S_s$$a_{1}=34$$n=9$$a_{n}=2$$a_{1}=34$$n=9$$a_{n}=2$\begin{align}
S_n&amp;=\frac{n}{2}[a_1+a_n] \\
\implies S_{9}&amp;=\frac{9}{2}[34+2]\\
&amp;=162.
\end{align}$S_{9}=162$$S_n$$a_{1}=5$$d=\frac{1}{2}$$n=13$$a_{1}=5$$d=\frac{1}{2}$$n=13$\begin{a…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15 and 16, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 15 and 16, Exercise 4.3

Solutions of Question 15 and 16 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $S_n$$a_{1}=91$$d=-4$$a_{n}=15$$a_{1}=91$$d=-4$$a_{n}=15$$n=?$\begin{align} 
&amp; a_n=a_1+(n-1)d \\
\implies &amp; 15=91+(n-1)(-4) \\
\implies &amp; 15=91-4n+4 \\
\implies &amp; 4n=95-15 \\
\implies &amp;  4n = 80\\ \implies &amp; n = 20.
\end{align}\begin{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 17, 18 and 19, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 17, 18 and 19, Exercise 4.3

Solutions of Question 17, 18 and 19 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $6+12+18+\ldots+96$$$6+12+18+\ldots+96.$$$a_{1}=6$$d=12-6=6$$a_{n}=96$$n=?$\begin{align} 
&amp; a_n=a_1+(n-1)d \\
\implies &amp; 96=6+(n-1)(6) \\
\implies &amp; 96=6+6n-6 \\
\implies &amp; 6n=96 \\
\implies &amp;  n = 24.
\end{align}\begin{align}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 20, 21 and 22, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 20, 21 and 22, Exercise 4.3

Solutions of Question 20, 21 and 22 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=7$$a_{n}=139$$S_{n}=876$$a_{1}=7$$a_{n}=139$$S_{n}=876$$n$$d$\begin{align}
&amp;S_n=\frac{n}{2}[a_1+a_n]\\
\implies &amp; 876=\frac{n}{2}[7+139]\\
\implies &amp; 1752=146n\\
\implies &amp; n=\frac{1752}{146}=12.
\end{align}\begin{align…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p11?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 23 and 24, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 23 and 24, Exercise 4.3

Solutions of Question 23 and 24 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$ 14+16+18+...+a_{25}.$$$a_1=14$$d=16-14=2$$n=25$$a_25$$S_25$\begin{align}
a_n&amp;=a_1+(n-1)d\\
\implies a_{25}&amp;= 14+(25-1)(2)\\
&amp;=62.
\end{align}\begin{align}
S_n&amp;=\frac{n}{2}[a_1+a_n]\\
\implies S_{25}&amp; =\frac{25}{2}[14+62]\\
&amp; =25 \t…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.4

Solutions of Question 3 and 4 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{3}{2}, \frac{9}{4}, \frac{27}{8}, \frac{81}{16}, \ldots$\(\frac{3}{2}, \frac{9}{4}, \frac{27}{8}, \frac{81}{16}, \ldots\)\begin{align*}
r_1&amp;=\frac{9/4}{3/2} = \frac{9}{4} \times \frac{2}{3} = \frac{3}{2} \\
r_2&amp;=\frac{27/8}{9/4} = …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, 6 and 7, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 5, 6 and 7, Exercise 4.4

Solutions of Question 5, 6 and 7 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=3, r=-2$$a_{1}=3$$r=-2$$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
&amp; a_{2}=a_{1} r=(3)(-2)= -6 \\
&amp; a_{3}=a_{1} r^{2}=(3)(-2)^{2}=3 (4)= 12 \\
&amp; a_{4}=a_{1} r^{3}=(3)(-2)^{3}=3  (-8) = -24
\end{align*}$a_1=3$$a_2=-6$$a_3=12$$a_4=-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 and 9, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 8 and 9, Exercise 4.4

Solutions of Question 8 and 9 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$90,30,10 \ldots$$$a_1=90$$r=\dfrac{30}{90}=\dfrac{1}{3}$$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
&amp; a_{4}=a_{1} r^3=(90)\left(\dfrac{1}{3} \right)^3=90 \times\dfrac{1}{27}=\dfrac{10}{3}\\
&amp; a_{5}=a_{1} r^3=(90)\left(\dfrac{1}{4} \right)^4=…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 and 11, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 10 and 11, Exercise 4.4

Solutions of Question 10 and 11 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$20,30,45 \ldots$$\(a_1=20\)\(r=\frac{30}{20}=\frac{3}{2}\)$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
&amp; a_{4}=a_{1} r^3=(20)\left(\frac{3}{2}\right)^3=20 \times \frac{27}{8} = \frac{540}{8} = 67.5 \\ 
&amp; a_{5}=a_{1} r^4=(20)\left(\frac{3}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 and 13, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 12 and 13, Exercise 4.4

Solutions of Question 12 and 13 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\frac{1}{27}, \frac{1}{9}, \frac{1}{3}, \ldots$$\(a_1=\frac{1}{27}\)\(r=\frac{\frac{1}{9}}{\frac{1}{27}}=3\)$a_{n}=a_{1} r^{n-1}.$\begin{align*}
&amp; a_{4}=a_{1} r^3=\left(\frac{1}{27}\right)(3)^3=\frac{1}{27} \times 27 = 1 \\ 
&amp; a_{5}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 and 15, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 14 and 15, Exercise 4.4

Solutions of Question 14 and 15 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=4, n=3, r=5$$a_{1}=4, n=3, r=5$$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
a_3&amp;= 4\times 5^2 \\
&amp;=4\times 25 = 100. 
\end{align*}$a_3=100$$a_{1}=2, n=5, r=2$$a_{1}=2$$n=5$$r=2$$a_{n}=a_{1} r^{n-1}.$\begin{align*}
a_5 &amp;= 2 \times 2^{…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 16 and 17, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 16 and 17, Exercise 4.4

Solutions of Question 16 and 17 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=7, n=4, r=2$$a_{1}=7$$n=4$$r=2$$a_{n}=a_{1} r^{n-1}.$\begin{align*}
a_4 &amp;= 7 \times 2^{4-1} \\ 
&amp;= 7 \times 2^3 \\ 
&amp;= 7 \times 8 = 56.
\end{align*}$a_4=56$$a_{1}=243, n=5, r=-\frac{1}{3}$$a_{1}=243$$n=5$$r=-\frac{1}{3}$$a_{n}=…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 18 and 19, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 18 and 19, Exercise 4.4

Solutions of Question 18 and 19 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=32, n=6, r=-\frac{1}{2}$$a_{1}=32$$n=6$$r=-\frac{1}{2}$$a_{n}=a_{1} r^{n-1}.$\begin{align*}
a_6 &amp;= 32 \times \left(-\frac{1}{2}\right)^{6-1} \\ 
&amp;= 32 \times \left(-\frac{1}{2}\right)^{5} \\ 
&amp;= 32 \times \left(-\frac{1}{32}\ri…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 20 and 21, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 20 and 21, Exercise 4.4

Solutions of Question 20 and 21 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$3 , \_\_\_ , \_\_\_ , \_\_\_ , 48$$$a_1=3$$a_5=48$$r$$$
a_n=ar^{n-1}.
$$\begin{align*}
&amp;a_5=a_1 r^4 \\
\implies &amp; 48=3r^4 \\
\implies &amp; r^4 = 16 \\
\implies &amp; r^4 = 2^4 \\
\implies &amp; r = 2.
\end{align*}\begin{align*}
&amp; a_2=a_1 r= (3…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p11?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 22 and 23, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 22 and 23, Exercise 4.4

Solutions of Question 22 and 23 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$8 , \_\_\_, \_\_\_, \_\_\_, \_\_\_, \dfrac{1}{4}$$$a_1=8$$a_6=\frac{1}{4}$$r$$n$$a_n = a_1 r^{n-1}.$\begin{align*}
a_6 &amp;= a_1 r^5 \\
\implies \frac{1}{4} &amp;= 8 \cdot r^5 \\
\implies r^5 &amp;= \frac{1}{4 \cdot 8} \\
\implies r^5 &amp;= \frac…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p12?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 24 and 25, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p12?rev=1737476039&amp;do=diff</link>
        <description>Question 24 and 25, Exercise 4.4

Solutions of Question 24 and 25 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$5 , \_\_\_, \_\_\_, \_\_\_, 80$$$a_1=5$$a_5=80$$r$$n$$$a_n = a_1 r^{n-1}.$$\begin{align*}
a_5 &amp;= a_1 r^4 \\
\implies 80 &amp;= 5 \cdot r^4 \\
\implies r^4 &amp;= \frac{80}{5} \\
\implies r^4 &amp;= 16 \\
\implies r &amp;= 2.
\end{align*}\begin{alig…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p13?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 26 and 27, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p13?rev=1737476039&amp;do=diff</link>
        <description>Question 26 and 27, Exercise 4.4

Solutions of Question 26 and 27 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $16\,\, ft$$6$$16\,\,ft$$a_1$$a_2$$a_3,...$$$a_1 = 16\times \dfrac{1}{4} = 4\,\, ft.$$$r=\dfrac{1}{4}$$a_6$$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
a_{6}&amp;=a_{1} r^5 \\
&amp;=(4)\left(\dfrac{1}{4} \right)^5 \\
&amp; = \dfrac{1}{256}
\end{align*}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p14?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 28 and 29, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p14?rev=1737476039&amp;do=diff</link>
        <description>Question 28 and 29, Exercise 4.4

Solutions of Question 28 and 29 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $=a_1= 1$$= a_2 = 2$$= a_3 = 2(2)=4$$= a_7$$$
1+2+4+...+a_7
$$$a_1=1$$r=2$$n=7$$$
S_n=\frac{a_1\left(1-r^n \right)}{1-r}, \quad r\neq 1.
$$\begin{align*}
S_6&amp;=\frac{(1)\left(1-2^7 \right)}{1-2} \\
&amp;=\frac{1-128}{-2}\\
&amp;=127
\end{align…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.5

Solutions of Question 3 and 4 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=5$$r=3$$n=12$$a_{1}=5$$r=3$$n=12$$n$\[
S_n = \frac{a_1 \left(1 - r^n\right)}{1 - r}, \quad r\neq 1.
\]\begin{align*}
S_{12} &amp;= \frac{5\left(1 - 3^{12}\right)}{1 - 3} \\
&amp;= \frac{5\left(1 - 531441\right)}{-2} \\
&amp;= \frac{5(-531440)}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p3?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.5

Solutions of Question 5 and 6 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=7, r=2, n=14$$a_1 = 7$$r = 2$$n = 14$$n$$$S_n = \frac{a_1 \left(1 - r^n\right)}{1 - r}, \quad r \neq 1.$$\begin{align*}
S_{14} &amp;= \frac{7 \left(1 - 2^{14}\right)}{1 - 2} \\
&amp;= \frac{7 \left(1 - 16384\right)}{-1} \\
&amp;= \frac{7 \time…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.5

Solutions of Question 7 and 8 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=16, r=-\frac{1}{2}, n=10$$a_1 = 16$$r = -\frac{1}{2}$$n = 10$$n$$$S_n = \frac{a_1 \left(1 - r^n\right)}{1 - r}, \quad r \neq 1.$$\begin{align*}
S_{10} &amp;= \frac{16 \left(1 - \left(-\frac{1}{2}\right)^{10}\right)}{1 - \left(-\frac{1}…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.5

Solutions of Question 9 and 10 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=343, a_{4}=-1, r=-\frac{1}{7}$$a_{1}=343$$a_{4}=-1$$r=-\frac{1}{7}$$S_n$$$ S_n =\frac{a_1-a_n r}{1-r}, \quad r\neq 1.$$\begin{align*}
S_4 &amp; =\frac{343-(-1)\left(-\frac{1}{7}\right)}{1+\frac{1}{7}} \\
&amp;=\frac{\frac{2400}{7}}{\frac…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p6?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, 12 and 13, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11, 12 and 13, Exercise 4.5

Solutions of Question 11, 12 and 13 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}$$S_{n}=244, r=-3, n=5$$S_{n}=244$$r=-3$$n=5$$$ S_n =\frac{a_1(1-r^n)}{1-r}, \quad r\neq 1.$$\begin{align*}
&amp; 244=\frac{a_1(1-(-3)^5)}{1-(-3)} \\
\implies &amp; 244=\frac{a_1(1+243)}{4} \\
\implies &amp; 976=244a_1\\
\implies &amp; …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p7?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 14, Exercise 4.5

Solutions of Question 14 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $0.444...$$$0.444... = 0.4+0.04+0.004+...$$$a_1=0.4$$r=\frac{0.04}{0.4}=0.1$$|r|=0.1 &lt; 1$\begin{align*}
S-\infty &amp; = \frac{a_1}{1-r} \\
&amp; = \frac{0.4}{1.0.1} = \frac{0.4}{0.9} \\
&amp; = \frac{4}{9}.
\end{align*}$S_{\infty} =\dfrac{4}{9}$$9.99999 ...$$…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 15, Exercise 4.5

Solutions of Question 15 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $30 ft$$\frac{2}{5}$$= 30 ft$$= 30 \times \frac{2}{5} = 12 ft$$= 12 \times \frac{2}{5} = \frac{24}{5} ft$$= \frac{24}{5} \times \frac{2}{5} = \frac{48}{25} ft$$D$$$D=30+2\left(12+\frac{24}{5}+\frac{24}{5}+... \right)$$$$
12+\frac{24}{5}+\frac{24}{5…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 4.6

Solutions of Question 3 &amp; 4 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{18}, \frac{1}{13}, \frac{1}{8}, \ldots \quad 20$\begin{align*}
&amp;\frac{1}{18}, \frac{1}{13}, \frac{1}{8}, \ldots \quad \text{ is in H.P.} \\
&amp;18, 13, 8, \ldots \quad \text{ is in A.P.}
\end{align*}$a_1 = 18$$d = 13 - 18 = -5$$a_{20}.…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 &amp; 6, Exercise 4.6

Solutions of Question 5 &amp; 6 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1}{27}, \dfrac{1}{20}, \dfrac{1}{13}, \ldots \quad$\begin{align*}
&amp;\frac{1}{27}, \frac{1}{20}, \frac{1}{13}, \ldots \quad \text{ is in H.P.} \\
&amp;27, 20, 13, \ldots \quad \text{ is in A.P.}
\end{align*}$a_1 = 27$$d = 20 - 27 = -7$$a_n=…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p4?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 &amp; 8, Exercise 4.6

Solutions of Question 7 &amp; 8 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{4}, \frac{1}{7}, \frac{1}{10}, \frac{1}{13}, \ldots$$ \frac{1}{4}, \frac{1}{7}, \frac{1}{10}, \frac{1}{13}, \ldots $$ a_1 = \frac{1}{4} $$d = \frac{1}{7} - \frac{1}{4} = -\frac{3}{28},$$ n = 14$$$a_n = a_1 + (n-1)d.$$\begin{align*}
…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 4.6

Solutions of Question 9 &amp; 10 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{7}, \frac{1}{6},-1,-\frac{1}{3}, \ldots$$$\frac{1}{7}, \frac{1}{6}, -1, -\frac{1}{3}, \ldots \text{ is in H.P.}$$$$7, 6, -1, -3, \ldots \text{ is in A.P.}$$$a_1 = 7$$d = 6 - 7 = -1$$a_8=?$$$
a_n = a_1 + (n-1)d.
$$\begin{align*}
a_…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p6?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11, Exercise 4.6

Solutions of Question 11 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{2}{3}$$\dfrac{4}{7}$$a=\dfrac{2}{3}$$b=\dfrac{4}{7}$\begin{align*}
\text{H.M.}&amp;=\frac{2ab}{a+b} \\
&amp;=\frac{2\times\frac{2}{3}\times\frac{4}{7}}{\frac{2}{3}+\frac{4}{7}} \\
&amp;=\frac{16/21}{26/21} \\
&amp;=\frac{8}{13} \\
\end{align*}$\dfrac{8}{13…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.7

Solutions of Question 3 and 4 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=0}^{5} 2^{k}$\begin{align*}
\sum_{k=0}^{5} 2^{k} &amp;= 2^0 + 2^1 + 2^2 + 2^3 + 2^4 + 2^5 \\
&amp;= 1 + 2 + 4 + 8 + 16 + 32 \\
&amp;= 63
\end{align*}$\sum_{k=0}^{9} \pi k$\begin{align*}
\sum_{k=0}^{9} \pi k &amp;= \pi(0) + \pi(1) + \pi(2) + \pi(…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.7

Solutions of Question 5 and 6 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=1}^{8} \frac{k}{k+1}$\begin{align*}
\sum_{k=1}^{8} \frac{k}{k+1} &amp;= \frac{1}{2} + \frac{2}{3} + \frac{3}{4} + \frac{4}{5} + \frac{5}{6}\\
&amp;+ \frac{6}{7} + \frac{7}{8} + \frac{8}{9} \\
&amp;= 0.5 + 0.6667 + 0.75 + 0.8 + 0.8333\\
&amp;+ 0.…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.7

Solutions of Question 7 and 8 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=0}^{5}\left(k^{2}-2 k+3\right)$\begin{align*}
\sum_{k=0}^{5} (k^{2} - 2k + 3) &amp;= (0^{2} - 2(0) + 3) + (1^{2} - 2(1) + 3) + (2^{2} - 2 (2) + 3) \\
&amp;+ (3^{2} - 2 (3) + 3) + (4^{2} - 2 (4) + 3) + (5^{2} - 2 (5) + 3) \\
&amp;= (0 - 0 + 3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.7

Solutions of Question 9 and 10 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+\frac{4}{5}+\frac{5}{6}+\dots$$$
\frac{1}{2} + \frac{2}{3} + \frac{3}{4} + \frac{4}{5} + \frac{5}{6} +... = \sum_{k=1}^{\infty}\frac{k}{k+1}
$$$3+6+9+12+15$$$3+6+9+12+15=\sum_{k=1}^{5}3k$$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, 12 and 13, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11, 12 and 13, Exercise 4.7

Solutions of Question 11, 12 and 13 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $-2+4-8+16-32+64$$$
-2 + 4 - 8 + 16 - 32 + 64 = \sum_{k=1}^{6} (-1)^k 2^k
$$$\frac{1}{1 \cdot 2}+\frac{1}{2 \cdot 3}+\frac{1}{3 \cdot 4}+\frac{1}{4 \cdot 5}+$$$
\frac{1}{1 \cdot 2} + \frac{1}{2 \cdot 3} + \frac{1}{3 \cdot 4} +…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14, 15 and 16, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 14, 15 and 16, Exercise 4.7

Solutions of Question 14, 15 and 16 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$n$$n+1$$T_n$$n$$$
T_{n} = n+1.
$$\begin{align*}\sum_{n=1}^{\infty} T_{n} &amp;= \sum_{n=1}^{\infty} (n+1)\\
&amp; = \sum_{n=1}^{\infty} n + \sum_{n=1}^{\infty} 1 \\
&amp; = \frac{n(n+1)}{2} + n \\
&amp; = \frac{n(n+1)}{2} + \frac{2n}{2} \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p8?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 17 and 18, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 17 and 18, Exercise 4.7

Solutions of Question 17 and 18 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$2^{2}+5^{2}+8^{2}+\ldots$$2+5+8+\ldots$$a_k=2+(k-1)(3)=2+3k-3=3k-1$$T_k$$k$\begin{align*}T_k&amp;=(3k-1)^2 \\
&amp;=9k^2-6k+1. \end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (9k^{2} - 6k + 1)\\
&amp; = 9\sum_{k=1}^{n} k^{2} …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p9?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19 and 20, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 19 and 20, Exercise 4.7

Solutions of Question 19 and 20 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1^{3}+3^{3}+5^{3}+$$1+3+5+\ldots$$a_k=1+(k-1)(2)=1+2k-2=2k-1$$T_k$$k$\begin{align*}T_k&amp;=(2k-1)^3 \\
&amp;=(2k)^3+3(2k)^2(-1)+3(2k)(-1)^2+(-1)^3 \\
&amp;=8k^3-12k^2+6k+1
\end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (8k^…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p10?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19 and 20, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 19 and 20, Exercise 4.7

Solutions of Question 19 and 20 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1^{3}+3^{3}+5^{3}+$$1+3+5+\ldots$$a_k=1+(k-1)(2)=1+2k-2=2k-1$$T_k$$k$\begin{align*}T_k&amp;=(2k-1) \\
&amp;=9k^2-6k+1. \end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (2k - 1)\\
&amp; = 2 \sum_{k=1}^{n} k - \sum_{k=1}^{n} 1 \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p11?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 21 and 22, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p11?rev=1737476040&amp;do=diff</link>
        <description>Question 21 and 22, Exercise 4.7

Solutions of Question 21 and 22 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1 \times 4+2 \times 7+3 \times 10+\cdots$$4+7+10+\ldots$$a_k=4+(k-1)(3)=4+3k-3=3k+1$$1+2+3+...$$k$$k(3k+1)$$T_k$$k$\begin{align*}T_k&amp;=k(3k+1) \\
&amp;=3k^2+k. \end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (3k^2 +k)\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p12?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 23 and 24, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p12?rev=1737476040&amp;do=diff</link>
        <description>Question 23 and 24, Exercise 4.7

Solutions of Question 23 and 24 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$$1+2 \times 2+3 \times 2^{2}+4 \times 2^{3}+\ldots.$$$$1+2 \times 2+3 \times 2^{2}+4 \times 2^{3}+\ldots$$$$
1\times 1+2 \times 2+3 \times 2^{2}+4 \times 2^{3}+\ldots
$$$1,2,3,4,\ldots$$a=1$$d=1$$1, 2, 2^2, 2^3, \ldots$$r=\frac{2}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p13?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 25 and 26, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p13?rev=1737476040&amp;do=diff</link>
        <description>Question 25 and 26, Exercise 4.7

Solutions of Question 25 and 26 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1+\frac{4}{7}+\frac{7}{7^{2}}+\frac{10}{7^{3}}+\ldots$\[
1 + \frac{4}{7} + \frac{7}{7^2} + \frac{10}{7^3} + \ldots
\]\(1, 4, 7, 10, \ldots\)\(a = 1\)\(d = 3\)\(1, \frac{1}{7}, \frac{1}{7^2}, \frac{1}{7^3}, \ldots\)\(1\)\(r = \frac…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 27 and 28, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p14?rev=1737476040&amp;do=diff</link>
        <description>Question 27 and 28, Exercise 4.7

Solutions of Question 27 and 28 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$5+\frac{7}{3}+\frac{9}{9}+\frac{11}{27}+\ldots$$$$5+\frac{7}{3}+\frac{9}{9}+\frac{11}{27}+\ldots$$$$
5\times 1+7\times\frac{1}{3}+9\times\frac{1}{9}+11\times\frac{1}{27}+\ldots
$$$5,7,9,11,4,\ldots$$a=5$$d=7-5=2$$1, \dfrac{1}{3}, \d…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.8

Solutions of Question 3 and 4 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $1+4+13+40+121+ \ldots$$n$$$ S_{n}=1+4+13+40+121+\ldots +T_{n} $$$$ S_{n}=1+4+13+40+\ldots +T_{n-1}+T_{n}. $$\begin{align*}
	S_{n}-S_{n}&amp; =1+4+13+40+121+\ldots +T_{n}  \\
	&amp; -\left(1+4+13+40+\ldots +T_{n-1}+T_{n}\right)
\end{align*}\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.8

Solutions of Question 5 and 6 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3+4+6+10+18+34+66+\dots$$n$$$ S_{n}=3+4+6+10+18+\ldots +T_{n} $$$$ S_{n}=3+4+6+10+\ldots +T_{n-1}+T_{n}. $$\begin{align*}
S_{n}-S_{n}&amp; =3+4+6+10+18+\ldots +T_{n}  \\
&amp; -\left(3+4+6+10+\ldots +T_{n-1}+T_{n}\right)
\end{align*}\begin{align…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.8

Solutions of Question 7 and 8 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$$\frac{1}{1 \times 4}+\frac{1}{4 \times 7}+\frac{1}{7 \times 10}+\ldots$$$$\frac{1}{1 \times 4}+\frac{1}{4 \times 7}+\frac{1}{7 \times 10}+\dots$$$T_k$\begin{align*}
T_k &amp;=\frac{1}{(3k-2)(3k+1)}.
\end{align*}\begin{align*}
\frac{1}{(3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.8

Solutions of Question 9 and 10 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\frac{1}{1 \cdot 3}+\frac{1}{2 \cdot 5}+\frac{1}{3 \cdot 7}+\ldots \ldots \text{ up to } \infty$$$\sum_{k=3}^{n} \dfrac{1}{(k+1)(k+2)}$\begin{align*}
T_k &amp;= \frac{1}{(k+1)(k+2)}.
\end{align*}\begin{align*}
\frac{1}{(k+1)(k+2)} = \frac…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p6?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.8

Solutions of Question 11 and 12 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=1}^{n} \frac{1}{k(k+2)}$$T_k$$k$\begin{align*}
T_k &amp;= \frac{1}{k(k+2)}.
\end{align*}\begin{align*}
\frac{1}{k(k+2)} = \frac{A}{k} + \frac{B}{k+2} \ldots (1)
\end{align*}$k(k+2)$\begin{align*}
	1 = A(k+2) + Bk \ldots (2)
\end{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p2?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2 and 3, Exercise 5.1

Solutions of Question 2 and 3 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $x-3$$x^{3}-2 x^{2}-5 x+6$$p(x)=x^{3}-2 x^{2}-5 x+6$$x-c=x-3$$\implies c=3$$x-3$$p(x)$$p(3)=0$\begin{align*}
p(3)&amp;=3^3-2(3)^2-5(3)+6 \\
&amp; = 27-18-15+6 \\
&amp; = 0.
\end{align*}$x-3$$p(x)$$x-3$$x^{3}-2 x^{2}-5 x+1$$p(x)=x^{3}-2 x^{2}-5 x+1$$x-c=x-3$$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p3?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 and 5, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 4 and 5, Exercise 5.1

Solutions of Question 4 and 5 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $4 y^{3}-4 y^{2}+10+2 y$$4 y^{2}-8 y+10$$q$$x^{3}+q x^{2}-7 x+6$$(x+1)$$p(x)=x^{3}+q x^{2}-7 x+6$$x-c=x+1$$\implies c=-1$$x+1$$p(x)$$p(-1)=0$\begin{align*}
&amp;(-1)^3+q(-1)^2-7(-1)+6=0 \\
-&amp;1+q+7+6=0\\
&amp;q+12=0\\
&amp;q=-12
\end{align*}</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 and 7, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 6 and 7, Exercise 5.1

Solutions of Question 6 and 7 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $m$$2 x^{3}+3 x^{2}-3 x-m$$x-2$$p(x)=2 x^{3}+3 x^{2}-3 x-m$$x-c=x-2$$\implies c=2$\begin{align*}
\text{Remainder} &amp; = p(c) = p(2) \\
&amp; = 2(2)^{3} + 3(2)^{2} - 3(2) - m \\
&amp; = 2(8) + 3(4) - 3(2) - m \\
&amp; = 16 + 12 - 6 - m \\
&amp; = 22 - m.
\end{align…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 and 9, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 8 and 9, Exercise 5.1

Solutions of Question 8 and 9 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x^{3}+3 x^{2}-11 x-6$$p(x)=2x^3+3x^2-11x-6$\begin{align}
p(2) &amp;= 2(2)^3+3(2)^2-11(2)-6 \\
&amp;=16+12-22-6 = 0 \end{align}$p(x)$\begin{align}
\begin{array}{r|rrrr}
2 &amp; 2 &amp; 3 &amp; -11 &amp; -6 \\
&amp; \downarrow  &amp;  4 &amp; 14 &amp; 6 \\
\hline
&amp; 2 &amp; 7 &amp; 3 &amp;  0 \\
\…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-2-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 5.2

Solutions of Question 3 and 4 of Exercise 5.2 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x^{3}+5 x^{2}-9 x-18$\( f(x) = 2x^{3} + 5x^{2} - 9x - 18 \)\begin{align*}
f(-2) &amp;= 2(-2)^{3} + 5(-2)^{2} - 9(-2) - 18 \\
&amp;= 2(-8) + 5(4) + 18 - 18 \\
&amp;= -16 + 20 + 18 - 18 = 0.
\end{align*}\( x + 2 \)\( f(x) \)\[
\begin{array}{r|rrrr}
-2 &amp; 2 &amp;…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-2-p3?rev=1737476040&amp;do=diff</link>
        <description>;

Question 5 and 6, Exercise 5.2

Solutions of Question 5 and 6 of Exercise 5.2 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $t^{3}+t^{2}+3 t-5$\( f(t) = t^{3} + t^{2} + 3t - 5 \)\begin{align*}
f(1) &amp;= (1)^{3} + (1)^{2} + 3(1) - 5 \\
&amp;= 1 + 1 + 3 - 5 \\
&amp;= 0.
\end{align*}\( t - 1 \)\( f(t) \)\begin{align}
\begin{array}{r|rrrr}
1 &amp; 1 &amp; 1 &amp; 3 &amp; -5 \\
&amp;   &amp; 1 &amp; 2 &amp; 5 \…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Exercise 5.3

Solutions of Question 2 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2
$t(x)=x^{3}-12 x^{2}+48 x+74$$x$$$t(x)=x^{3}-12 x^{2}+48 x+74.$$$t=12$\begin{align*}
t(12)&amp;=(12)^3-12(12)^2+48(12)+74 \\
&amp;=650.
\end{align*}</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 3, Exercise 5.3

Solutions of Question 3 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3
$x$$2x$$2x+2$\begin{align*}
&amp; x(2x)(2x+2) = 144 \\
\implies &amp; 4x^2(x+1)=144 \\
\implies &amp; x^2(x+1)=36 \\
\implies &amp; x^3+x^2-36=0
\end{align*}$$p(x)=x^3+x^2-36.$$\begin{align*}
p(3)&amp;=3^3+3^2-36 \\
&amp;=27+9-36 = 0
\end{align*}$x=3$$p(x)$$2(3)$$2(3)+…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Exercise 5.3

Solutions of Question 4 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 4
$x$$2x+3$$x-2$\begin{align*}
&amp; x(2x+3)(x-2) = 2475 \\
\implies &amp; x(2x^2+3x-4x-6)=2475 \\
\implies &amp; x(2x^2-x-6)-2475=0 \\
\implies &amp; 2x^3-x^2-6x-2475=0
\end{align*}$$p(x)=2x^3-x^2-6x-2475.$$\begin{align*}
p(11)&amp;=2(11)^3-11^2-6(11)-2475 \\
&amp;=2662…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 5, Exercise 5.3

Solutions of Question 5 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 5
$6 x^{2}+38 x+56$$2 x+8$$ACED$$ABFG$$ACED$$6 x^{2}+38 x+56$$2 x+8$\begin{align*}
&amp; 6 x^{2}+38 x+56 \\
= &amp; 2(3x^2+19x+28) \\
= &amp; 2(3x^2+12x+7x+28) \\
= &amp; 2(3x(x+4)+7(x+4)) \\
=&amp; 2(x+4)(3x+7) \\
=&amp; (2x+8)(3x+7)
\end{align*}\begin{align*}
&amp; Length …</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-4-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Review Exercise

Solutions of Question 2 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Go to</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2 &amp; 3, Review Exercise

Solutions of Question 2 &amp; 3 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left(64 y^{3}-8\right) \div(4 y-2) \quad$\begin{align*}
\frac{(64 y^{3}-8)}{(4 y-2)}&amp;= \frac{(4y - 2)(16y^{2} + 8y + 4)}{4y - 2}\\
&amp; = 16y^{2} + 8y + 4 .\end{align*}$\left(125 y^{3}-8\right) \div(5 y-2)$\begin{align*}
\frac{(125 y^{3}-8)}{(5 …</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise

Solutions of Question 4 &amp; 5 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3 y-2$$6 y^{3}-y^{2}-5 y+2$\begin{align*}3y-2&amp;=0\\
3y&amp;=2\\
y&amp;=\frac{2}{3}\end{align*}\begin{align*}
f(y) &amp;= 6y^{3} - y^{2} - 5y + 2\\
f\left(\frac{2}{3}\right) &amp;= 6\left(\frac{2}{3}\right)^{3} - \left(\frac{2}{3}\right)^{2} - 5\left(\frac{2}{3…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 6 &amp; 7, Review Exercise

Solutions of Question 6 &amp; 7 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $k$$\left(x^{2}+8 x+k\right)$$(x-4)$\( p(x) = x^{2} + 8x + k \)\( p(x) \)\( (x - 4) \)\( p(4) \)\( p(4) = 0 \)\begin{align*}
p(4) &amp;= (4)^2 + 8(4) + k \\
&amp;= 16 + 32 + k \\
&amp;= 48 + k.
\end{align*}\[
48 + k = 0.
\]\[
k = -48.
\]$3 x^{2}-x+32-\frac…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 6, Review Exercise

Solutions of Question 6 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 6
$k$$\left(x^{2}+8 x+k\right)$$(x-4)$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 7, Review Exercise

Solutions of Question 7 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 7
$3 x^{2}-x+32-\frac{121}{x+4}$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Exercise 8.1

Solutions of Question 2 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos 15^{\circ}$$\cos \left(45^{\circ}-30^{\circ}\right)$\begin{align*}
\cos 15^{\circ} &amp; = \cos \left(45^{\circ}-30^{\circ}\right)\\
&amp;= \cos 45 \cos 30 + \sin 45 \sin 30 \\
&amp;= \dfrac{1}{\sqrt{2}}\cdot \dfrac{\sqrt{3}}{2} + \dfrac{1}{\sqrt{2…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 3, Exercise 8.1

Solutions of Question 3 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos 120^{\circ}$$\cos \left(180^{\circ}-60^{\circ}\right)$$\cos \left(90^{\circ}+30^{\circ}\right)$\begin{align*}
\cos 120^{\circ} &amp; = \cos \left(180^{\circ}-60^{\circ}\right) \\
&amp;= - \cos 60 ^{\circ}\\
&amp;= -\dfrac{1}{2}.
\end{align*}\begin{…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Exercise 8.1

Solutions of Question 4 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos 6 \theta \cos 3 \theta-\sin 6 \theta \sin 3 \theta$\begin{align*}
&amp; \cos 6 \theta \cos 3 \theta-\sin 6 \theta \sin 3 \theta \\
&amp; = \cos (6\theta +3\theta) \\
&amp; = \cos 9\theta .
\end{align*}$\cos 7 \theta \cos 2 \theta+\sin 7 \theta \sin…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 8.1

Solutions of Question 5 and 6 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \alpha=\dfrac{4}{5}, \tan \beta=-\dfrac{5}{12}$$\cos (\alpha+\beta)$$\cos (\alpha-\beta)$$\sin \alpha=\dfrac{4}{5}$$\alpha$$\tan \beta=-\dfrac{5}{12}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$$\alpha$$\cos$\begin{alig…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 7, Exercise 8.1

Solutions of Question 7 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\alpha$$\beta$$\sin \alpha=\dfrac{12}{13}$$\tan \beta=\dfrac{4}{3}$$\sin(\alpha+\beta)$$\cos(\alpha+\beta)$$\tan(\alpha+\beta)$$\sin \alpha=\dfrac{12}{13}$$\alpha$$\tan \beta=\dfrac{4}{3}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$\(\a…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 8, Exercise 8.1

Solutions of Question 8 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \alpha=\dfrac{3}{5}$$0&lt;\alpha&lt;\dfrac{\pi}{2}$$\cos \beta=\dfrac{12}{13}$$\dfrac{3 \pi}{2}&lt;\beta&lt;2 \pi$$\csc (\alpha+\beta)$$\sec (\alpha+\beta)$$\cot (\alpha+\beta)$$\sin \alpha=\dfrac{3}{5}$$0&lt;\alpha&lt;\dfrac{\pi}{2}$$\alpha$\begin{align…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 9, Exercise 8.1

Solutions of Question 9 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\alpha$$\beta$$\sin \alpha=\dfrac{1}{\sqrt{2}}$$\cos \beta=-\dfrac{3}{5}$$\sin (\alpha \pm \beta)$$\sin \alpha=\dfrac{1}{\sqrt{2}}$$\alpha$$\cos \beta=-\dfrac{3}{5}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$$\alpha$$\cos$\begin{align*…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 10, Exercise 8.1

Solutions of Question 10 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \left(\dfrac{\pi}{2}-\alpha\right)=\cos \alpha$\begin{align*}
L.H.S &amp; = \sin \left(\frac{\pi}{2}-\alpha\right) \\
&amp; =\sin\frac{\pi}{2} \cos \alpha - \cos \frac{\pi}{2} \sin\alpha \\
&amp; = 1\times \cos \alpha - 0 \times \sin\alpha \\
&amp; =…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p10?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 11, Exercise 8.1

Solutions of Question 11 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{\sin \left(180^{\circ}+\lambda\right) \cos \left(270^{\circ}+\lambda\right)}{\sin \left(180^{\circ}-\lambda\right) \cos \left(270^{\circ}-\lambda\right)}=1$\begin{align*}
L.H.S &amp; = \dfrac{\sin \left(180^{\circ}+\lambda\right) \cos \…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p11?rev=1737476040&amp;do=diff</link>
        <description>Question 12, Exercise 8.1

Solutions of Question 12 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\alpha+\beta+\gamma=180^{\circ}$$\tan \alpha+\tan \beta+\tan \gamma=\tan \alpha \tan \beta \tan \gamma$$$\alpha+\beta+\gamma=180^{\circ}$$\begin{align*}
&amp; \alpha+\beta=180^{\circ}-\gamma \\
\implies &amp; \tan(\alpha+\beta) = \tan(180^{\circ}-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p12?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p12?rev=1737476040&amp;do=diff</link>
        <description>Question 13, Exercise 8.1

Solutions of Question 13 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $r \sin (\theta+\phi)$$12 \sin \theta-5 \cos \theta$$12=r\cos \varphi $$-5=r\sin \varphi$\begin{align*}
&amp; (12)^2+(-5)^2=r^2 \cos^2\varphi+r^2 \sin^2 \varphi \\
\implies &amp; 144+25={{r}^{2}}\left( {{\cos }^{2}}\varphi +{{\sin }^{2}}\varphi  \r…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 4 Exercise 8.2

Solutions of Question 4 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin 2 \theta$$\cos 2 \theta$$\tan 2 \theta$$\sin \frac{\theta}{2}$$\cos \frac{\theta}{2}$$\tan \frac{\theta}{2}$$\cos \theta=\frac{3}{5}$$0&lt;\theta&lt;\frac{\pi}{2}$$\cos\theta=\dfrac{3}{5}$$0&lt;\theta&lt;\dfrac{\pi}{2}$$\theta$$$\sin\theta = \pm \sq…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 Exercise 8.2

Solutions of Question 5 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \theta$$\cos \theta$$\tan \theta$$\sin 2 \theta=\frac{24}{25}, 2 \theta$$\sin 2\theta=\dfrac{24}{25}$$2\theta$$$\cos 2\theta = \pm \sqrt{1-\sin^2 2\theta}$$$2\theta$$\cos 2\theta$\begin{align*}\cos 2\theta &amp; = - \sqrt{1-\sin^2 2\theta}\\…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 6 Exercise 8.2

Solutions of Question 6 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin 15^{\circ} \cos 15^{\circ}$$$\sin 2 \theta = 2\sin\theta \cos\theta$$$$\sin\theta \cos\theta = \frac{1}{2}\sin 2\theta$$$\theta = 15^{\circ}$\begin{align*}
\sin 15^{\circ} \cos 15^{\circ} &amp; = \frac{1}{2}\sin 2(15^{\circ}) \\
&amp; \frac{1}{2…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 7 Exercise 8.2

Solutions of Question 7 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\sin ^{2} \alpha \cos ^{2} \alpha$$\begin{align*}
\sin ^{2} \alpha \cos ^{2} \alpha &amp;= \left(\frac{1-\cos 2\alpha}{2} \right)\left(\frac{1+\cos 2\alpha}{2} \right)\\
&amp;= \frac{1}{4}(1-\cos^2 2\alpha) \\
&amp;=\frac{1}{4}\left(1-\frac{1+\cos 4\alp…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(i, ii &amp; iii) Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 8(i, ii &amp; iii) Exercise 8.2

Solutions of Question 8(i, ii &amp; iii) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $(\sin \theta+\cos \theta)^{2}=1+\sin 2 \theta$\begin{align*}
LHS &amp; = (\sin \theta+\cos \theta)^{2} \\
&amp;=\sin^2\theta + \cos^2\theta +2\sin \theta \cos\theta\\
&amp;= 1+2\sin \theta \cos\theta \quad (\because \sin^2\theta…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(iv, v &amp; vi) Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 8(iv, v &amp; vi) Exercise 8.2

Solutions of Question 8(iv, v &amp; vi) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\csc 2 \alpha=\dfrac{\tan \alpha+\cot \alpha}{2}$\begin{align*}
RHS &amp; = \dfrac{\tan \alpha+\cot \alpha}{2} \\
&amp; = \dfrac{1}{2}\left(\frac{\sin\alpha}{\cos\alpha}+\frac{\cos\alpha}{\sin\alpha} \right)\\
\end{align*}$8 \…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(vii, viii &amp; ix) Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 8(vii, viii &amp; ix) Exercise 8.2

Solutions of Question 8(vii, viii &amp; ix) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin 2 \theta=2 \cot \theta \sin ^{2} \theta$\begin{align*}
RHS &amp;= 2 \cot \theta \sin ^{2} \theta\\
&amp;= 2 \frac{\cos \theta }{\sin \theta} \sin ^{2} \theta\\
&amp;= 2 \cos \theta \sin\theta\\
&amp;=  \sin2 \theta\\
&amp;=LH…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(x, xi &amp; xii) Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 8(x, xi &amp; xii) Exercise 8.2

Solutions of Question 8(x, xi &amp; xii) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sec 2 x=\dfrac{\cos x}{\cos x+\sin x}+\dfrac{\sin x}{\cos x-\sin x}$\begin{align*}
RHS &amp;= \dfrac{\cos x}{\cos x+\sin x}+\dfrac{\sin x}{\cos x-\sin x}\\
&amp;=\dfrac{\cos x(\cos x-\sin x)+\sin x(\cos x+\sin x)}{(\cos x+\…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(xiii, xiv &amp; xv)  Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 8(xiii, xiv &amp; xv)  Exercise 8.2

Solutions of Question 8(xiii, xiv &amp; xv) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\csc 2 \alpha-\cot 2 \alpha=\tan \alpha$\begin{align*}
LHS &amp;= \csc 2 \alpha-\cot 2 \alpha\\
&amp;=\frac{1}{\sin 2 \alpha}- \frac{\cos2 \alpha}{\sin 2\alpha }\\
&amp;=\frac{1-\cos2 \alpha}{\sin2 \alpha}\\
&amp;= \frac{2\si…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(xvi, xvii &amp; xviii)  Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p11?rev=1737476040&amp;do=diff</link>
        <description>Question 8(xvi, xvii &amp; xviii)  Exercise 8.2

Solutions of Question 8(xvi, xvii &amp; xviii) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1-\cos ^{2} \beta}{2-2 \cos \beta}=\cos ^{2} \dfrac{\beta}{2}$\begin{align*}
LHS &amp;= \dfrac{1-\cos ^{2} \beta}{2-2 \cos \beta}\\
&amp;= \dfrac{\sin ^{2} \beta}{2-2 \cos \beta}\\
&amp;=\dfrac{4\sin ^{2} \fr…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1(v, vi, vii &amp; viii) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 1(v, vi, vii &amp; viii) Exercise 8.3

Solutions of Question 1(v, vi, vii &amp; viii) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $ \sin(-u) \sin 5u$\begin{align*}
&amp;\sin(-u) \sin 5u \\
=&amp; -\sin u \sin 5u \\
=&amp; -\frac{1}{2}[\cos(u - 5u) - \cos(u + 5u)] \\
= &amp;-\frac{1}{2}[\cos(-4u) - \cos(6u)] \\
=&amp; \frac{1}{2}[\cos(6u) - \cos(4u) ]
\e…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1(ix, x &amp; xi) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 1(ix, x &amp; xi) Exercise 8.3

Solutions of Question 1(ix, x &amp; xi) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 \sin 75{\circ} \sin 15{\circ}$\begin{align*}
&amp;\quad2 \sin 75^{\circ} \sin 15^{\circ} \\
&amp;= \cos(75^{\circ} - 15^{\circ}) - \cos(75^{\circ} + 15^{\circ}) \\
&amp;= \cos 60^{\circ} - \cos 90^{\circ} \\
\end{align*}$4 \sin …</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2(i, ii, iii, iv and v) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 2(i, ii, iii, iv and v) Exercise 8.3

Solutions of Question 2(i, ii, iii, iv and v) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin 70^{\circ} + \sin 30^{\circ}$\begin{align*}
 &amp; \quad \sin 70^{\circ} + \sin 30^{\circ} \\
&amp; = 2 \sin \left(\frac{70+30}{2} \right) \cos \left(\frac{70-30}{2} \right) \\
&amp; = 2 \sin \left(\frac{1…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3(i, ii, iii, iv &amp; v) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 3(i, ii, iii, iv &amp; v) Exercise 8.3

Solutions of Question 3(i, ii, iii, iv &amp; v) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{\cos (\alpha + \beta)}{\cos(\alpha - \beta)}=\dfrac{1- \tan \alpha \tan \beta}{1+ \tan \alpha \tan \beta}$\begin{align*}
RHS &amp; = \dfrac{1- \tan \alpha \tan \beta}{1+ \tan \alpha \tan \beta} \\
&amp; …</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3(vi, vii, viii, ix &amp; x) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 3(vi, vii, viii, ix &amp; x) Exercise 8.3

Solutions of Question 3(vi, vii, viii, ix &amp; x) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2\tan y \cos 3y= \sec y(\sin 4y-\sin 2y)$\begin{align*}
LHS &amp; = 2\tan y \cos 3y \\
&amp; = 2 \cdot \frac{\sin y}{\cos y} \cos 3y \\
&amp; = \sec y (2 \cos 3y \sin y) \\
&amp; = \sec y \left(\sin (3y+y)-\sin (…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3(xi, xii &amp; xiii) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 3(xi, xii &amp; xiii) Exercise 8.3

Solutions of Question 3(xi, xii &amp; xiii) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2\cos2u \cos u-\sin 2u \sin u=2\cos^3 u$\begin{align*}
LHS &amp; = 2\cos 2u \cos u - \sin 2u \sin u \\
&amp; = 2\left(\cos^2 u - \sin^2 u\right) \cos u - 2\sin u \cos u \sin u \\
&amp; = 2\cos^3 u - 2\sin^2 u \cos u \\
&amp; =…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Review Exercise

Solutions of Question 2 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \theta=\dfrac{3}{5}, \sin \phi=\dfrac{5}{13}$$\theta$$\phi$$\sin (\theta-\phi)$$\sin \theta=\dfrac{3}{5}$$\sin \phi=\dfrac{5}{13}$$\theta$$\phi$\begin{align*}
\cos^2 \theta &amp;= 1-\sin^2\theta\\
&amp;= 1-\left(\frac{3}{5}\right)^2\\
&amp; =…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 3, Review Exercise

Solutions of Question 3 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{\sqrt{2}}(\sin \beta+\cos \beta)$\begin{align*}
&amp;\frac{1}{\sqrt{2}}(\sin \beta+\cos \beta)\\
=&amp; \sin \frac{\pi}{4}\sin \beta+\cos \frac{\pi}{4}\cos \beta\\
=&amp; \cos(\beta -\frac{\pi}{4})
\end{align*}$\frac{1}{\sqrt{2}} \sin 75^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Review Exercise

Solutions of Question 4 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1+\tan 15^{\circ}}{1-\tan 15^{\circ}}$\begin{align*}
&amp;\frac{1+\tan 15^{\circ}}{1-\tan 15^{\circ}}\\
=&amp;\frac{1+\tan 15^{\circ}}{1-1 \cdot \tan 15^{\circ}}\\
=&amp;\frac{\tan 45^{\circ} + \tan 15^{\circ}}{1 - \tan 45^{\circ} \tan 15^{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p5?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Review Exercise

Solutions of Question 5 and 6 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\tan \theta$$\tan \left(\theta-45^{\circ}\right)=\frac{1}{3}$\begin{align*}
&amp; \frac{\tan \theta - \tan 45^{\circ}}{1 + \tan \theta \cdot \tan 45^{\circ}} =\frac{1}{3}\\
\implies &amp; \frac{\tan \theta - 1}{1 + \tan \theta}= \f…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 7, Review Exercise

Solutions of Question 7 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{4 \sin ^{2} \theta \cos \theta}{\cos 3 \theta+\cos \theta}=\tan 2 \theta \tan \theta$\begin{align*}
LHS&amp;=\frac{4 \sin^2 \theta \cos \theta}{\cos 3 \theta + \cos \theta}\\
&amp;=\frac{4 \sin \theta\sin \theta \cos \theta}{4\cos^ 3 \t…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 8, Review Exercise

Solutions of Question 8 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\sqrt{\frac{\cos \left(90^{\circ}+x\right) \sec (-x) \tan \left(180^{\circ}-x\right)}{\sec \left(360^{\circ}-x\right) \sin \left(180^{\circ}+x\right) \cot \left(90^{\circ}-x\right)}}=i .$$\begin{align*}
LHS&amp;= \sqrt{\frac{\cos \left(90…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p8?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 9, Review Exercise

Solutions of Question 9 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\sqrt{\frac{\left(1-\tan ^{2} x \cos (-x) \cos \left(360^{\circ}-x\right)\right) \tan 45^{\circ}}{\left\{\sin 90^{\circ}-\sin \left(180^{\circ}+x\right)\right\}\left\{\sin 90^{\circ}-\cos \left(90^{\circ}-x\right)\right\}}}$$\begin{al…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Exercise 9.1

Solutions of Question 2 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=\dfrac{1}{4+3 \operatorname{Sin} \theta}$\begin{align*} -1 \leq \operatorname{Sin} \theta \leq 1 \end{align*}$3$\begin{align*}  -3 \leq 3 \operatorname{Sin} \theta \leq 3 \end{align*}$4$\begin{align*}
 &amp; 1 \leq 4+3 \operatorname{Sin} \theta \l…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 3, Exercise 9.1

Solutions of Question 3 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=7 \cos 4x$\begin{align*} 
&amp; -1\leq \cos 4x \leq 1 \,\, \forall \,\, x\in \mathbb{R} \\
\implies &amp; -7\leq 7 \cos 4x \leq 7 \\
\end{align*}$= ]-\infty, \infty[ = \mathbb{R}$$=[-7,7]$$y=\cos \frac{x}{3}$\begin{align*} 
&amp; -1\leq \cos \frac{x}{3} \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4(i-iv), Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 4(i-iv), Exercise 9.1

Solutions of Question 4(i-iv) of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=\sin x+x \cdot \cos x$$f(x)=\sin x+x \cdot \cos x$\begin{align*} f(-x)  = \sin (-x) + (-x)\cdot \cos (-x) \end{align*}$\sin(-x)=-\sin x$$\cos (-x) = \cos x$\begin{align*}
f(x) &amp; = -\sin x - x \cdot \cos x \\
&amp; = -(\sin x + x \cdot …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4(v-viii), Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 4(v-viii), Exercise 9.1

Solutions of Question 4(v-viii) of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=\dfrac{\sin ^{2} x}{x+\tan x}$\[y = \frac{\sin^2 x}{x + \tan x}\]\begin{align*}
y(-x) &amp;= \frac{\big(-\sin x\big)^2}{-x - \tan x} \\
&amp;= \frac{\sin^2 x}{-x - \tan x}\\
&amp; = \frac{\sin^2 x}{-(x + \tan x)}\\
&amp; = -\frac{\sin^2 x}{x +…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5(i-v), Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 5(i-v), Exercise 9.1

Solutions of Question 5(i-v) of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=2 \operatorname{Sin} x$$y=2 \operatorname{Cos} 3 x$$y=2 \operatorname{Tan} 2 x$$\mathrm{y}=\operatorname{Cos} \frac{\mathrm{x}}{2}$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5(vi-x), Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 5(vi-x), Exercise 9.1

Solutions of Question 5(vi-x) of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=2 \operatorname{Sin} 3 x$$y=3 \operatorname{Cos} x$$y=\operatorname{Cos}^{2} x$$y=\operatorname{Sin}^{2} x$$y=\operatorname{Tan}^{2} x$$y=\operatorname{Sin} \frac{x}{2}$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p8?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 6, Exercise 9.1

Solutions of Question 6 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=6 \sec(2 x-3)$$\sec$$2\pi$\begin{align*}
6 \sec(2 x-3) &amp; = 6 \sec(2 x-3+2\pi) \\
&amp; = 6 \sec(2(x+\pi)-3)
\end{align*}$6 \sec(2 x-3)$$\pi$$y=\cos (5 x+4)$$\cos$$2\pi$\begin{align*}
\cos (5 x+4) &amp; = 6 \cos(5x+4+2\pi) \\
&amp; = \cos\left(5\left(x+\fr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p9?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 7 &amp; 8, Exercise 9.1

Solutions of Question 7 &amp; 8 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=\operatorname{Sin} x$$y=\operatorname{Sin} 2 x$$[0,2 \pi]$$y=\operatorname{Cos} x$$y=\operatorname{Cos} 2 x$$[0,2 \pi]$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p10?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 9, Exercise 9.1

Solutions of Question 9 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin x=\cos x$$\cos x=x$$\sin x=x$$\tan x=x$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-1-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3,Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-1-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2 and 3,Review Exercise

Solutions of Question 2 and 3 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-1-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-1-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Review Exercise

Solutions of Question 4 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2 and 3, Review Exercise

Solutions of Question 2 and 3 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos \theta -\sin \theta=\sqrt{2}\sin \theta,$$\cos \theta+ \sin \theta=\sqrt{2} \cos \theta$$$\cos \theta -\sin \theta=\sqrt{2}\sin \theta$$\begin{align*}
&amp; \cos \theta=\sqrt{2}\sin \theta + \sin \theta \\
\implies &amp; \cos \the…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Review Exercise

Solutions of Question 4 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Review Exercise

Solutions of Question 5 and 6 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 7, Review Exercise

Solutions of Question 7 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 8, Review Exercise

Solutions of Question 8 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 9, Review Exercise

Solutions of Question 9 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p8?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10(i-v), Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 10(i-v), Review Exercise

Solutions of Question 10(i-v) of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10(vi-x), Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 10(vi-x), Review Exercise

Solutions of Question 10(vi-x) of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/number-theory-by-prof-asghar-ali?rev=1737476035&amp;do=diff">
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        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory by Prof. Asghar Ali</title>
        <link>https://beta.mathcity.org/bsc/number-theory-by-prof-asghar-ali?rev=1737476035&amp;do=diff</link>
        <description>Number Theory by Prof. Asghar Ali

[Number Theory by M Asghar Ali]

We are very thankful to Prof. Asghar Ali for send these notes. These notes are very helpful to prepare BSc or ADS mathematics portion of Number Theory. Number theory is a subject in which students learn different concepts created on the set of integers. For example, the concept of divisibilty exists in the set of integer. Let a and b be any two integers suhc that $a\neq 0$</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Definitions: FSc Part 1 (Mathematics): PTB</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb/definitions?rev=1737476037&amp;do=diff</link>
        <description>Definitions: FSc Part 1 (Mathematics): PTB

On this page, all the definitions of “Textbook of Algebra and Trigonometry Class XI, published by Punjab Textbook Board (PTB) Lahore, Pakistan are given. We are very thankful to Muhammad Waqas Sulaiman for his valuable contribution.$\frac{p}{q}$$p,q \in \mathbb{Z}$$q\neq 0$$\frac{p}{q}$$p,q \in \mathbb{Z}$$q\neq 0$$\mathbb{R}$$0.3333....,21.134134$$\pi = 3.1415...$$\divideontimes$$z=x+iy$$x,y \in \mathbb{R}, i = \sqrt{-1}$$x$$y$$z$$2, 3+\sqrt{3}i, \fra…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Definitions: FSc Part 1 (Mathematics): PTB by Aurang Zaib</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb/definitions-aurang-zaib?rev=1737476037&amp;do=diff</link>
        <description>Definitions: FSc Part 1 (Mathematics): PTB by Aurang Zaib

Definitions from Textbook of Algebra and Trigonometry Class XI, published by Punjab Textbook Board (PTB) Lahore, Pakistan. We are very thankful to Aurang Zaib for his valuable contribution.

Chapter 01: Number System
\( \dfrac{p}{q} \)\( p, q \in \mathbb{Z} \)\( q \neq 0 \)\( \dfrac{3}{4} \)\( \dfrac{7}{2} \)\( \sqrt{2} \)\( \pi \)\( \mathbb{R} \)\( 0.25 \)\( 3.75 \)\( 0.3333... \)\( 1.234234... \)\( \pi \)\( 3.1415... \)\( \sqrt{2} \)\(…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Definitions: Mathematics 11: PTB by Muzzammil Subhan</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb/definitions-muzzammil-subhan?rev=1737476037&amp;do=diff</link>
        <description>Definitions: Mathematics 11: PTB by Muzzammil Subhan

Definitions from Textbook of Algebra and Trigonometry Class XI, published by Punjab Textbook Board (PTB) Lahore, Pakistan. We are very thankful to Muzzammil Subhan for his valuable contribution. Download or view PDF for all definitions. Samples is given below$y=2^x$$y=e^x$$f(x)=\log_a x$$f(x)=\log_e x$$y$$x$$y$$y=x^2+3x$$x^2+xy+y^2=4$$f(-x)=f(x)$$f(-x)=-f(x)$</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Solution and Area of Oblique Triangle</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb/solution-and-area-of-oblique-triangle?rev=1737476037&amp;do=diff</link>
        <description>Solution and Area of Oblique Triangle

These are the common formulas used in Chapter 12 of Textbook of Algebra and Trigonometry Class XI, Punjab Textbook Board Lahore. This handout is very helpful to remember the formulas. All these formulas are given for real valued and defined trigonometric functions. A PDF file can be downloaded for high quality printing and a word file is also given if you wish to modify the contents or credit as you need.
&lt;panel title=$a^2=b^2+c^2-2bc\cos \alpha$$b^2=c^2+a^…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Trigonometric Formulas</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb/trigonometric-formulas?rev=1737476037&amp;do=diff</link>
        <description>Trigonometric Formulas

These are the common formulas used in Chapter 9 to 14 of Textbook of Algebra and Trigonometry Class XI, Punjab Textbook Board Lahore. This handout is very helpful to remember the formulas. All these formulas are given for real valued and defined trigonometric functions. A PDF file can be downloaded for high quality printing and a word file is also given if you wish to modify the contents or credit as you need.
&lt;panel&gt;
${{\sin }^{2}}\theta +{{\cos }^{2}}\theta =1$$1+{{\tan…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Definitions: FSc Part 2 (Mathematics): PTB</title>
        <link>https://beta.mathcity.org/fsc-part2-ptb/definitions?rev=1737476037&amp;do=diff</link>
        <description>Definitions: FSc Part 2 (Mathematics): PTB

On this page, all the definitions of “Calculus and Analytic Geometry, MATHEMATICS 12” (Mathematics FSc Part 2 or HSSC-II), Punjab Textbook Board (PTB) Lahore, Pakistan are given. We are very thankful to $A=x^2$$f:X\to Y$$X$$f:X\to Y$$y$$Y$$y=ax+b$$x$$y$$f(x)=2x-6$$p(x) = {a_n}{x^n} + {a_{n - 1}}{x^{n - 1}} + {a_{n - 2}}{x^{n - 2}} + ... + {a_1}x + {a_0}$${a_0},\,{a_1},\,{a_2},...,{a_n}$$f(x)=ax+b$$X$$I:X\to X$$X$$Y$$C:X \rightarrow Y$$C(x)=a$$x \in X$$…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part2-ptb/definitions-muzzammil-subhan?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Definitions: Mathematics 12: PTB by Muzzammil Subhan</title>
        <link>https://beta.mathcity.org/fsc-part2-ptb/definitions-muzzammil-subhan?rev=1737476037&amp;do=diff</link>
        <description>Definitions: Mathematics 12: PTB by Muzzammil Subhan

Definitions from Calculus and Analytic Geometry, MATHEMATICS 12, published by Punjab Textbook Board (PTB) Lahore, Pakistan. We are very thankful to Muzzammil Subhan for his valuable contribution. Download or view PDF for all definitions. Samples is given below$P(x)=a_0 x^0+a_1 x^1+a_2 x^2+\ldots . .+a_{n-1} x^{n-1}+a_n x^n$$n \in W$$a_0, a_1, a_2, \ldots, a_n \in R$$f(x)=a x+b$$a, b \in R$$a \neq 0$$f(x)=x$$f(x)=c$$c \in R$$\frac{P(x)}{Q(x)}$…</description>
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        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Solution &amp; Area of Oblique Triangle</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solution_area_of_oblique_triangle?rev=1737476035&amp;do=diff</link>
        <description>Solution &amp; Area of Oblique Triangle

Here is the list of all the formulas used in Chapter 12 of FSc Part 1. If there is difficulty to remember these formulas then take a print of this page and see formula from this page while solving the question. After a while you will learn all formulas by heart. To download the PDF of this page see below.
&lt;PHP&gt;
$pre_file=$location/$$location/dn.php?file=$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/advanced-analysis-handwritten-notes?rev=1737476041&amp;do=diff">
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Advanced Analysis: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/advanced-analysis-handwritten-notes?rev=1737476041&amp;do=diff</link>
        <description>Advanced Analysis: Handwritten Notes

[Advanced Analysis: Handwritten Notes]
These notes are provided by Mr. Anwar Khan. We are really very thankful to Mr. Anwar Khan for providing these notes and appreciates his effort to publish these notes on MathCity.org

It covers the complete syllabus of Advanced Analysis paper of MSc Mathematics. See the contents of the notes given below to see the topics covered by these notes.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/advanced-analysis-iqra-liaqat?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Advance Analysis by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/notes/advanced-analysis-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Advance Analysis by Ms. Iqra Liaqat

[Advance Analysis by Ms. Iqra Liaqat]

These notes are send by Ms. Iqra Liaqat. We are really very thankful to her for providing these notes and appreciates her effort to publish these notes on MathCity.org
 Name  Advance Analysis   Sender  Ms. Iqra Liaqat   Author  $\sigma$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/affine-and-euclidean-geometry-shahzad-idress?rev=1737476041&amp;do=diff">
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Affine and Euclidean Geometry by Shahzad Idress</title>
        <link>https://beta.mathcity.org/notes/affine-and-euclidean-geometry-shahzad-idress?rev=1737476041&amp;do=diff</link>
        <description>Affine and Euclidean Geometry by Shahzad Idress

[Affine and Euclidean Geometry by Shahzad Idress]

These notes are sent by shahzad-idress. We acknowledged his efforts to published these notes on MathCity.org.

These are short notes containing topics related to Affine and Euclidean Geometry. The main sections includes $R^n$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/algebra-ii-by-syed-sheraz-asghar?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Algebra II by Syed Sheraz Asghar</title>
        <link>https://beta.mathcity.org/notes/algebra-ii-by-syed-sheraz-asghar?rev=1737476041&amp;do=diff</link>
        <description>Algebra II by Syed Sheraz Asghar

[Algebra II by Syed Sheraz Asghar]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org

	*  Name: Algebra II
	*  Provider: Mr. Muzammil Tanveer</description>
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    <item rdf:about="https://beta.mathcity.org/notes/algebraic-number-theory-notes-anwar-khan?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Algebraic Number Theory Notes by Anwar Khan</title>
        <link>https://beta.mathcity.org/notes/algebraic-number-theory-notes-anwar-khan?rev=1737476041&amp;do=diff</link>
        <description>Algebraic Number Theory Notes by Anwar Khan

[Algebraic Number Theory Notes by Anwar Khan]
Algebraic number theory is a subfield of number theory that studies integers, rational numbers, and their generalisations using abstract algebra techniques. It covers Galois theory, ideals and units in rings of integers, unique factorization, and algebraic number fields and related rings of integers. It is a complex and in-depth subject with numerous linkages to other branches of mathematics.$\mathbb{R}$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/classical-mechanics-muhammad-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Classical Mechanics by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/classical-mechanics-muhammad-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Classical Mechanics by Muhammad Usman Hamid

[Classical Mechanics by Muhammad Usman Hamid]

Objectives of the course:

To provide solid understanding of classical mechanics and enable the students to use this understanding while studying courses on quantum mechanics, statistical mechanics, electromagnetism, fluid dynamics, space-flight dynamics, astrodynamics and continuum mechanics.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/complex-analysis-iqra-liaqat?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Complex Analysis (Notes) by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/notes/complex-analysis-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Complex Analysis (Notes) by Ms. Iqra Liaqat

[Notes of Complex Analysis by Ms. Iqra Liaqat]

These notes are send by Ms. Iqra Liaqat. We are really very thankful to her for providing these notes and appreciates her effort to publish these notes on MathCity.org

Complex analysis is the study of functions of complex numbers. It is useful in a variety of mathematical fields, such as algebraic geometry, number theory, analytic combinatorics, and applied mathematics, as well as in physics fields like…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/complex-analysis-m-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Complex Analysis by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/complex-analysis-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Complex Analysis by M Usman Hamid

[Complex Analysis by M Usman Hamid]
We are really very thankful to Muhammad Usman Hamid for providing these notes and appreciates his effort to publish these notes on MathCity.org

It covers the one part of the syllabus of Complex Analysis paper of MSc Mathematics. See the contents of the notes given below to see the topics covered by these notes.$$
x^2+4=0, x^2+x+1=0 \text{ and } x^2-2x+3=0
$$$i=\sqrt{-1}$$i^2=-1$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Complex Analysis (Quick Review)</title>
        <link>https://beta.mathcity.org/notes/complex-analysis-quick-review?rev=1737476041&amp;do=diff</link>
        <description>Complex Analysis (Quick Review)

[Complex Analysis: Quick Review]
These notes are made and shared by Mr. Akhtar Abbas. We are really very thankful to him for providing these notes and appreciates his efforts to publish these notes on MathCity.org. Important definitions and important results are the part of these notes, these might be helpful to prepare interviews or any other written test after graduation like PPSC, FPSC or etc.$z_1, z_2 \in S$$S$$v(x,y)$$u(x,y)$$f(z)=u(x,y)+iv(x,y)$$f$$D$$C$$D$…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/computing-tools-for-mathematics-asif-arshad?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Computing Tools for Mathematics by Asif Arshad</title>
        <link>https://beta.mathcity.org/notes/computing-tools-for-mathematics-asif-arshad?rev=1737476041&amp;do=diff</link>
        <description>Computing Tools for Mathematics by Asif Arshad

[omputing Tools for Mathematics by Asif Arshad]
Computing tools for mathematics are algorithms that use computers to solve mathematical issues. They are employed in a number of scientific, technical, industrial, and technological domains where computer is crucial and central. They may assist in creating precise and effective numerical techniques, for instance, to solve physical or biological models.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/differential_geometry_notes?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Differential Geometry: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/differential_geometry_notes?rev=1737476041&amp;do=diff</link>
        <description>Differential Geometry: Handwritten Notes

[Differential Geometry: Handwritten Notes]

Differential geometry is a discipline of mathematics that investigates the geometry of smooth objects and spaces, sometimes known as smooth manifolds. It investigates the geometric properties of curves and surfaces using the methods of differential and integral calculus, linear algebra, and multilinear algebra. Mathematical analysis and differential geometry are related concepts. These are the lecture notes of …</description>
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    <item rdf:about="https://beta.mathcity.org/notes/differential-geometry-kaushef_salamat?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Differential Geometry (Notes) by Ms. Kaushef Salamat</title>
        <link>https://beta.mathcity.org/notes/differential-geometry-kaushef_salamat?rev=1737476041&amp;do=diff</link>
        <description>Differential Geometry (Notes) by Ms. Kaushef Salamat

[Differential Geometry by Ms. Kaushef Salamat]
Differential Geometry is an important field in the mathematical sciences. Usually, this is a compulsory or core subject for BS mathematics students.

These notes are send by Ms. Kaushef Salamat. We are really very thankful to her for providing these notes and appreciates her effort to publish these notes on MathCity.org</description>
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    <item rdf:about="https://beta.mathcity.org/notes/differential-geometry-m-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Differential Geometry by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/differential-geometry-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Differential Geometry by M Usman Hamid

[Differential Geometry by M Usman Hamid]
These notes are initially provided by Mr. Anwar Khan. Later send by many persons. We are really very thankful to all for providing these notes and appreciates their effort to publish these notes on MathCity.org</description>
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    <item rdf:about="https://beta.mathcity.org/notes/differential-geometry-syed-hassan-waqas?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Differential Geometry by Syed Hassan Waqas</title>
        <link>https://beta.mathcity.org/notes/differential-geometry-syed-hassan-waqas?rev=1737476041&amp;do=diff</link>
        <description>Differential Geometry by Syed Hassan Waqas

[Differential Geometry by Syed Hassan Waqas]
In the field of mathematics known as differential geometry, smooth manifolds—also known as smooth shapes and spaces—and their geometry are studied. Investigating the geometric characteristics of curves and surfaces involves the use of the tools of differential and integral calculus, linear algebra, and multilinear algebra. Differential calculus and mathematical analysis are related to differential geometry.…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/elementary-linear-algebra-m-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Elementary Linear Algebra by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/elementary-linear-algebra-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Elementary Linear Algebra by Muhammad Usman Hamid

[Elementary Linear Algebra by Muhammad Usman Hamid]

Linear Algebra is the study of vectors and linear transformations. The main objective of this course is to help students learn in rigorous manner, the tools and methods essential for studying the solution spaces of problems in mathematics, engineering, the natural sciences and social sciences and develop mathematical skills needed to apply these to the problems arising within their field of st…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fluid Dynamics I by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/fluid-dynamics-i-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Fluid Dynamics I by Muhammad Usman Hamid

[Fluid Dynamics I by Muhammad Usman Hamid]

These notes are send by Mr. Anwar Khan, PhD. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes are written by Muhammad Usman Hamid.

	*  Name: Fluid Dynamics I</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fluid Mechanics by Ali Raza</title>
        <link>https://beta.mathcity.org/notes/fluid-mechanics-ali-raza?rev=1737476041&amp;do=diff</link>
        <description>Fluid Mechanics by Ali Raza

[Fluid Mechanics by Ali Raza]

Fluid mechanics is the branch of physics that studies how fluids (liquids, gases, and plasmas) behave and interact with forces and energy. Fluid mechanics has many applications in engineering, geophysics, biology, and other fields.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/notes/fluid-mechanics-i-muzammil-tanveer?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fluid Mechanics I by Dr Rao Muzamal Hussain</title>
        <link>https://beta.mathcity.org/notes/fluid-mechanics-i-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Fluid Mechanics I by Dr Rao Muzamal Hussain

[Fluid Mechanics I by Muzammil Tanveer]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes are based on  lectures delivered by Mr. Muzammil Hussain at GC University Faisalabad.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/fluid-mechanics-ii-muzammil-tanveer?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fluid Mechanics II by Dr Rao Muzamal Hussain</title>
        <link>https://beta.mathcity.org/notes/fluid-mechanics-ii-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Fluid Mechanics II by Dr Rao Muzamal Hussain

[Fluid Mechanics I by Muzammil Tanveer]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes are based on  lectures delivered by Mr. Muzammil Hussain at GC University Faisalabad.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/notes/functional-analysis-by-prof-mumtaz-ahmad?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Functional Analysis by Prof Mumtaz Ahmad</title>
        <link>https://beta.mathcity.org/notes/functional-analysis-by-prof-mumtaz-ahmad?rev=1737476041&amp;do=diff</link>
        <description>Functional Analysis by Prof Mumtaz Ahmad

[Functional Analysis by Prof Mumtaz Ahmad]

Functional analysis is a subfield of mathematics that deals with vector space theory and linear algebra. It entails researching the connections between roles, things, incidents, actions, and outcomes. The word $l^\infty$$l^\infty$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/functional-analysis-by-tahir-hussain-jaffery?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Functional Analysis by Mr. Tahir Hussain Jaffery</title>
        <link>https://beta.mathcity.org/notes/functional-analysis-by-tahir-hussain-jaffery?rev=1737476041&amp;do=diff</link>
        <description>Functional Analysis by Mr. Tahir Hussain Jaffery

[Functional Analysis by Prof Mumtaz Ahmad]

Functional analysis is a branch of mathematics concerned with vector space theory and linear algebra. It requires looking into the relationships between various roles, objects, incidents, actions, and results. The term $M$$M+N$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/functional-analysis-m-usman-hamid-and-zeeshan-ahmad?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Functional Analysis by M Usman Hamid and Zeeshan Ahmad</title>
        <link>https://beta.mathcity.org/notes/functional-analysis-m-usman-hamid-and-zeeshan-ahmad?rev=1737476041&amp;do=diff</link>
        <description>Functional Analysis by M Usman Hamid and Zeeshan Ahmad

[Functional Analysis by M Usman Hamid and Zeeshan Ahmad]

These notes are send by Muhammad Usman Hamid and written by Muhammad Usman Hamid and Zeeshan Ahmad. We are really very thankful to him for providing these notes and appreciate his effort to publish these notes on MathCity.org. Usman is dedicated and committed mathematician, who is working very hard for better understanding of mathematics to it readers.</description>
    </item>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fuzzy Sets Theory by Umar Saeed Bunarai</title>
        <link>https://beta.mathcity.org/notes/fuzzy-sets-theory-umar-saeed-bunarai?rev=1737476041&amp;do=diff</link>
        <description>Fuzzy Sets Theory by Umar Saeed Bunarai

[Fuzzy Sets Theory by Umar Saeed Bunarai]
In the field of mathematics known as fuzzy set theory, sets having varying degrees of membership are studied. This implies that an element can be a member of a set only partially or not at all. In several disciplines, including logic, control, data analysis, and decision-making, fuzzy set theory is used to model uncertainty, vagueness, and imprecision.</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>General Topology by Raheel Ahmad</title>
        <link>https://beta.mathcity.org/notes/general-topolgy-raheel-ahmad?rev=1737476041&amp;do=diff</link>
        <description>General Topology by Raheel Ahmad

A handwritten notes of Topology by Mr. Raheel Ahmad. We are very thankful to him for sending these notes.
 Name  General Topology   Author  Mr. Raheel Ahmad   Pages  87 pages   Format  Mobile Scanned PDF   Size  8.0 MB  
What is in the notes?</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>General Topology by Azhar Hussain</title>
        <link>https://beta.mathcity.org/notes/general-topology-azhar-hussain?rev=1737476041&amp;do=diff</link>
        <description>General Topology by Azhar Hussain

[Topology Notes by Azhar Hussain]
The area of topology known as general topology (also known as point set topology) is concerned with the fundamental concepts and constructs of set theory utilised in topology. Most other fields of topology, such as differential topology, geometric topology, and algebraic topology, are built upon it.
The three key ideas of point-set topology are connectedness, compactness, and continuity. Continuous functions move points from on…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Group Theory: Important Definitions and Results</title>
        <link>https://beta.mathcity.org/notes/group-theory-important-definitions-and-results?rev=1737476041&amp;do=diff</link>
        <description>Group Theory: Important Definitions and Results

[Group Theory: Important Definitions and Results]
These notes are made and shared by Mr. Akhtar Abbas. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes contains important definitions with examples and related theorem, which might be helpful to prepare interviews or any other written test after graduation like PPSC, FPSC or etc.$G$$a\in G$$\exists$$e\in G$$a\…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Groups (Handwritten Notes) by Atiq ur Rehman</title>
        <link>https://beta.mathcity.org/notes/groups-handwritten-notes?rev=1737476041&amp;do=diff</link>
        <description>Groups (Handwritten Notes) by Atiq ur Rehman

Groups are a basic idea in algebra, introduced in high school. It&#039;s a very interesting topic in math.

[Cube root of unity group]

	*  Name:  Groups (Handwritten notes)- Lecture Notes 
	*  Author: Atiq ur Rehman 
	*  Pages: 82 pages</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Group Theory by Mr. Muhammad Iftikhar</title>
        <link>https://beta.mathcity.org/notes/groups-theory-m-iftikhar?rev=1737476041&amp;do=diff</link>
        <description>Group Theory by Mr. Muhammad Iftikhar

[Group Theory by Mr. Muhammad Iftikhar]

These notes are send by Mr. Muhammad Iftikhar. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org.
 Name  Lecture Notes on Group Theory   Author  Mr. Muhammad Iftikhar</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>History of Mathematics by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/history-of-mathematics-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>History of Mathematics by Muhammad Usman Hamid

[History of Mathematics by Muhammad Usman Hamid]

Mathematics is a unique aspect of human thought, and its history differs in essence from all other histories. These notes are written by Muhammad Usman Hamid. We are very thankful to him for sharing these notes on our website.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/linear-algebra-important-definitions-and-results?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Linear Algebra: Important Definitions and Results</title>
        <link>https://beta.mathcity.org/notes/linear-algebra-important-definitions-and-results?rev=1737476041&amp;do=diff</link>
        <description>Linear Algebra: Important Definitions and Results

[Linear Algebra: Important Definitions and Results]
These notes are made and shared by Mr. Akhtar Abbas. We are really very thankful to him for providing these notes and appreciates his efforts to publish these notes on MathCity.org. These notes contains important definitions with examples and related theorem, which might be helpful to prepare interviews or any other written test after graduation like PPSC, FPSC or etc.$V$$n$$n$$V$$W$$V$$A$$A$$A…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/notes/mathematical-method-muzammil-tanveer?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Method by Sir Muhammad Awais Aun</title>
        <link>https://beta.mathcity.org/notes/mathematical-method-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Method by Sir Muhammad Awais Aun

[Mathematical Method by Muzammil Tanveer]

Mathematical methods are the approaches employed by mathematicians to address issues in mathematics and science. Algebra, functions, relations and associated graphs, calculus, and statistics are examples of mathematical techniques. Through their usage in resolving practical issues, they are applied to modelling.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/mathematical-method-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Method by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/mathematical-method-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Method by Muhammad Usman Hamid

[Mathematical Method by Muhammad Usman Hamid]

These notes are send by Muhammad Usman Hamid. We acknowledged his efforts to published these notes on MathCity.org.

The main objective of this course is to provide the students with a range of mathematical methods that are essential to the solution of advanced problems encountered in the fields of applied physics and engineering. In addition this course is intended to prepare the students with mathematic…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Statistics I by Muzammil Tanveer</title>
        <link>https://beta.mathcity.org/notes/mathematical-statistics-i-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Statistics I by Muzammil Tanveer

[Mathematical Statistics I]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org 
 Name  Mathematical Statistics</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Statistics II by Sir Haidar Ali</title>
        <link>https://beta.mathcity.org/notes/mathematical-statistics-ii-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Statistics II by Sir Haidar Ali

[Mathematical Statistics II]

A subfield of mathematics called mathematical statistics is concerned with using mathematical techniques to solve statistical problems. It involves using mathematical analysis and probability theory to the study of statistical issues like estimate, hypothesis testing, and confidence intervals. Financial, engineering, and scientific fields all benefit from the use of mathematical statistics, which is a significant area of…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Statistics by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/notes/mathematical-statistics-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Statistics by Ms. Iqra Liaqat

[Mathematical Statistics by Ms. Iqra Liaqat]

These notes are send by Ms. Iqra Liaqat. We are really very thankful to her for providing these notes and appreciates her effort to publish these notes on MathCity.org
 Name  Mathematical Statistics   Provided by</description>
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    <item rdf:about="https://beta.mathcity.org/notes/measure-theory-by-anwar-khan?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Measure Theory Notes by Anwar Khan</title>
        <link>https://beta.mathcity.org/notes/measure-theory-by-anwar-khan?rev=1737476041&amp;do=diff</link>
        <description>Measure Theory Notes by Anwar Khan

[Measure Theory Notes by Anwar Khan]

Measure theory is a branch of mathematics concerned with the concept of “measure,” which is a method of assigning a numerical value to specific sets. The concepts of length, area, and volume are generalised via measurements to more abstract environments, such as infinite-dimensional spaces and areas that cannot be seen.$X$$\sigma-$$X$$\sigma-$$\sigma-$$\lim\limits_{k\to \infty} \sup A_k$$\lim\limits_{k\to \infty} \inf A_k$…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Measure Theory Handwritten Notes by Asim Marwat</title>
        <link>https://beta.mathcity.org/notes/measure-theory-notes-asim-marwat?rev=1737476041&amp;do=diff</link>
        <description>Measure Theory Handwritten Notes by Asim Marwat

[Measure Theory Notes by Asim Marwat]
These notes are made and shared by Mr. Asim Marwat. He has our sincere gratitude for supplying these notes, and we value his effort in having them published on MathCity.org. Measure Theory is an important subject in BS Mathematics. These notes contain topic from base level, like equivalence set, to advance level, like convergent in measure.$L_p$$L_p$$L^\infty$$L_p$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Measure Theory by M Usman Hamid &amp; Saima Akram</title>
        <link>https://beta.mathcity.org/notes/measure-thoery-muhsa?rev=1737476041&amp;do=diff</link>
        <description>Measure Theory by M Usman Hamid &amp; Saima Akram

[Measure Theory by M Usman Hamid &amp; Saima Akram]

The study of measures on sets is the focus of the mathematical field known as measure theory. A measure is a function that gives specific subsets of a given set a non-negative real integer, indicating their size inferentially. The concept of measure is a formalisation and generalisation of common concepts like mass and event probability as well as geometrical measurements (length, area, and volume).</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mechanics (Easy Notes of Mechanics)</title>
        <link>https://beta.mathcity.org/notes/mechanics-by-dr-amir-mahmood?rev=1737476041&amp;do=diff</link>
        <description>Mechanics (Easy Notes of Mechanics)

[Easy Notes of Mechanics]
These notes are provided and prepared by Dr. Amir Mahmood. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org

If there is error or mistake in the notes, then please directly contact to Dr. Amir Mahmood for correction. He can be accessed via his email address at</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mechanics by Sir Nouman Siddique</title>
        <link>https://beta.mathcity.org/notes/mechanics-by-sir-nouman-siddique?rev=1737476041&amp;do=diff</link>
        <description>Mechanics by Sir Nouman Siddique

These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org

	*  Name: Mechanics
	*  Provider: Mr. Muzammil Tanveer</description>
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    <item rdf:about="https://beta.mathcity.org/notes/mechanics-i-statics-dr-babar-ahmad?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mechanics I (Statics) by Dr Babar Ahmad</title>
        <link>https://beta.mathcity.org/notes/mechanics-i-statics-dr-babar-ahmad?rev=1737476041&amp;do=diff</link>
        <description>Mechanics I (Statics) by Dr Babar Ahmad

[Mechanics I (Statics) by Dr Babar Ahmad]

We are very thankful to Dr Babar Ahmad for sharing his book on MathCity.org. This book is very helpful for undergraduate students of Science and Engineering Programs. 

This book is shared by the permission of the author and he keeps the copyright of the book.</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Method of Mathematical Physics by Mr. Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/method-of-mathematical-physics-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Method of Mathematical Physics by Mr. Muhammad Usman Hamid

[Method of Mathematical Physics by Mr. Muhammad Usman Hamid]

Method of Mathematical Physics is an area of mathematics concerned with the application of mathematical methods to physics problems. Mathematical techniques for statistical mechanics, quantum mechanics, and classical mechanics are all included in this large field.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/metric-spaces-notes?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Metric Spaces (Notes)</title>
        <link>https://beta.mathcity.org/notes/metric-spaces-notes?rev=1737476041&amp;do=diff</link>
        <description>Metric Spaces (Notes)

[Metric Spaces (Notes)]
These are updated version of previous notes. Many mistakes and errors have been removed. These notes are collected, composed and corrected by Atiq ur Rehman, PhD. These are actually based on the lectures delivered by Prof. Muhammad Ashfaq (Ex HoD, Department of Mathematics, Government College Sargodha). $(X,d)$$x,y\in X$$$\left| {\,d(x,\,A)\, - \,d(y,\,A)\,} \right|\,\, \le \,\,d(x,\,y).$$$A^c$$A\subset X$$x \in X$$B(x;r)$$A \subset X$$f:(X,d)\to (Y…</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Multiple Choice Questions (BSc/BS/PPSC) by Akhtar Abbas</title>
        <link>https://beta.mathcity.org/notes/multiple-choice-questions-_bsc-bs-ppsc_-akhtar-abbas?rev=1737476041&amp;do=diff</link>
        <description>Multiple Choice Questions (BSc/BS/PPSC) by Akhtar Abbas

[Multiple Choice Questions (BSc/BS/PPSC)]
These notes are made and shared by Mr. Akhtar Abbas. We are really very thankful to him for providing these notes and appreciates his efforts to publish these notes on MathCity.org. Multiple Choice Questions (MCQs) are given in these notes, which might be helpful in BSc, BS or Punjab Public Service Commission (PPSC) exams.$a$$b$$n$$na &gt; b$$(p − 1)! \equiv −1(mod p)$$p$$p$$p$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Multivariable Calculus by Sheikh Muhammad Saleem Shahzad</title>
        <link>https://beta.mathcity.org/notes/multivariable-calculus-sheikh-muhammad-saleem-shahzad?rev=1737476041&amp;do=diff</link>
        <description>Multivariable Calculus by Sheikh Muhammad Saleem Shahzad

[Multivariable Calculus by Sheikh Muhammad Saleem Shahzad]

	*  Have you ever wondered how we can understand the speed of a moving object at any instant of time?
	*  Did you know that Calculus can help us predict future trends by analyzing patterns in data?</description>
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    <item rdf:about="https://beta.mathcity.org/notes/note-for-numerical-methods-m-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Notes for Numerical Methods by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/note-for-numerical-methods-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Notes for Numerical Methods by M Usman Hamid

[Notes for Numerical Methods by M Usman Hamid]
These notes are initially provided by Mr. Anwar Khan. Later the updated version is send by Muhammad Tahir. We are really very thankful to Mr. Anwar Khan and Muhammad Tahir for providing these notes and appreciates their effort to publish these notes on MathCity.org$\left(\frac{1}{3}\right)$$\left(\frac{3}{8}\right)$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/number-theory-handwritten-notes?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/number-theory-handwritten-notes?rev=1737476041&amp;do=diff</link>
        <description>Number Theory: Handwritten Notes

[Number Theory: Handwritten Notes]
The study of the characteristics of the positive integers (1, 2, 3,...) is called number theory. It is significant because it has numerous uses in coding theory, combinatorics, cryptography, and other branches of mathematics and computer science. Some mathematicians also refer to number theory as the</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory Notes by Anwar Khan</title>
        <link>https://beta.mathcity.org/notes/number-theory-notes-anwar-khan?rev=1737476041&amp;do=diff</link>
        <description>Number Theory Notes by Anwar Khan

[Number Theory Notes by Anwar Khan]
Mathematicians who specialize in number theory examine the characteristics and connections between integers. “Higher arithmetic” and “the queen of mathematics” are some names for it.  Because it examines the characteristics and connections between integers and arithmetic functions, number theory is interesting. It has numerous uses in coding theory, combinatorics, cryptography, and other branches of mathematics. Like the ones…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/number-theory-umer-shuaib?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory by Dr Muhammad Umer Shuaib</title>
        <link>https://beta.mathcity.org/notes/number-theory-umer-shuaib?rev=1737476041&amp;do=diff</link>
        <description>Number Theory by Dr Muhammad Umer Shuaib

[Number Theory Notes]
A subfield of mathematics called number theory studies the characteristics of positive integers. Higher arithmetic is another name for it. The study of the relationships between various types of numbers, including prime numbers, rational numbers, and algebraic integers, is done using number theory, one of the oldest fields of mathematics.$\phi$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/numerical-analysis-by-m-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Numerical Analysis by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/numerical-analysis-by-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Numerical Analysis by M Usman Hamid

These notes are initially provided by Mr. Anwar Khan. Later the updated version is send by Muhammad Tahir. We are really very thankful to Mr. Anwar Khan and Muhammad Tahir for providing these notes and appreciates their effort to publish these notes on MathCity.org</description>
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    <item rdf:about="https://beta.mathcity.org/notes/numerical-analysis-ii?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Numerical Analysis II</title>
        <link>https://beta.mathcity.org/notes/numerical-analysis-ii?rev=1737476041&amp;do=diff</link>
        <description>Numerical Analysis II

[Numerical Analysis by Muzammil Tanveer]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org.
 Name    Numerical Analysis II    Compiled by  Muzammil Tanveer</description>
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    <item rdf:about="https://beta.mathcity.org/notes/operation-research-haidar-ali?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Operation Research by Sir Haidar Ali</title>
        <link>https://beta.mathcity.org/notes/operation-research-haidar-ali?rev=1737476041&amp;do=diff</link>
        <description>Operation Research by Sir Haidar Ali

[Notes of Operation Research by Sir Haidar Ali]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These are based on lectures delivered by Sir Haidar Ali at GC University Faisalabad.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/operation-research-handwritten-notes?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Operation Research: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/operation-research-handwritten-notes?rev=1737476041&amp;do=diff</link>
        <description>Operation Research: Handwritten Notes

[Operation Research: Handwritten Notes]
Operation research (OR) is a scientific field that enhances organisational decision-making and problem-solving via the application of mathematical and analytical techniques. The management and administration of many processes, including military, governmental, economic, and industrial ones, include the use of scientific principles. OR is carried out by a group of professionals from various linked fields, depending on …</description>
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    <item rdf:about="https://beta.mathcity.org/notes/partial-differential-equations-m-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Partial Differential Equations by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/partial-differential-equations-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Partial Differential Equations by M Usman Hamid

The course provides a foundation to solve PDE’s with special emphasis on wave, heat and Laplace equations, formulation and some theory of these equations are also intended.
We are really very thankful to Prof. Muhammad Usman Hamid for providing these notes and appreciates his effort to publish these notes on MathCity.org</description>
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    <item rdf:about="https://beta.mathcity.org/notes/partial-differential-equations-muzammil-tanveer?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Partial Differential Equations by Muzammil Tanveer</title>
        <link>https://beta.mathcity.org/notes/partial-differential-equations-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Partial Differential Equations by Muzammil Tanveer

[Partial Differential Equations]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org 
 Name  Partial Differential Equations or PDEs</description>
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    <item rdf:about="https://beta.mathcity.org/notes/real-analysis-hand-written-kaushef?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Real Analysis Handwritten Notes by Kaushef Salamat</title>
        <link>https://beta.mathcity.org/notes/real-analysis-hand-written-kaushef?rev=1737476041&amp;do=diff</link>
        <description>Real Analysis Handwritten Notes by Kaushef Salamat

[Real Analysis Handwritten Notes by Kaushef Salamat]

We are very thankful to Ms. Kaushef Salamat for providing these notes. Real Analysis is a core subject in BS or MSc Mathematics. Without a fundamental grasp of Real Analysis, one cannot claim to be a mathematician. These notes are very comprehensive containing almost all the notions of Real Analysis. For providing these notes, Ms. $\infty$</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Real Analysis Notes by Prof Syed Gul Shah</title>
        <link>https://beta.mathcity.org/notes/real-analysis-notes-by-prof-syed-gul-shah?rev=1737476041&amp;do=diff</link>
        <description>Real Analysis Notes by Prof Syed Gul Shah

[Real Analysis Notes by Prof Syed Gul Shah]

Real analysis, a discipline that explores the complexities of mathematical functions, limits, and sequences, can often be a difficult topic for students. Prof. Syed Gul Shah, as a true analyst, not only excelled in the subject but also gained fame for his extraordinary qualities as a human being.$s_n&lt;u_n&lt;t_n$$n\ge n_0$$\{s_n\}$$\{t_n\}$$\{u_n\}$$\{s_n\}$$\exists$$\left| {\,{s_n}}\right|&gt;\frac{1}{2}s$$\{s_n\}$…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/ring_notes?rev=1737476041&amp;do=diff">
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Ring (Notes) by Prof. M. Dabeer Mughal</title>
        <link>https://beta.mathcity.org/notes/ring_notes?rev=1737476041&amp;do=diff</link>
        <description>Ring (Notes) by Prof. M. Dabeer Mughal

[Ring (Notes) by Prof. M. Dabeer Mughal]
A handwritten notes on Ring (Algebra) by Prof. M. Dabeer Mughal (Federal Directorate of Education, Islamabad, Pakistan). It is best to prepare a “Rings and Vector Spaces” section of your algebra paper or Algebra II for BS or MS Mathematics.$\phi$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/rings_handwritten_notes?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Rings (Handwritten notes) by Atiq ur Rehman</title>
        <link>https://beta.mathcity.org/notes/rings_handwritten_notes?rev=1737476042&amp;do=diff</link>
        <description>Rings (Handwritten notes) by Atiq ur Rehman

[Rings (Handwritten notes) by Atiq ur Rehman]
Ring is a two-operation mathematical structure. It is an abelian group with one operation and a semi-group with another operation, and the distributive law is true for the first operation relative to the second operation. This mathematical idea is fundamentally pure. These notes offer a very simple method for learning the concept of rings and other ideas that are closely related to rings. These are lecture…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/rings-and-modules-iqra-liaqat?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Rings &amp; Modules by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/notes/rings-and-modules-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Rings &amp; Modules by Ms. Iqra Liaqat

Ring is a mathematical structure with two operations. With one operation it is abelian group and with other operation it is semi-group with distributive law holds with first operation w.r.t the other operation. This concept is of pure in nature in mathematics. These advanced level notes are typically taken as an elective in a mathematics undergraduate degree.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/special-functions-muzammil-tanveer?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Special Functions by Dr. Muhey-U-Din</title>
        <link>https://beta.mathcity.org/notes/special-functions-muzammil-tanveer?rev=1737476042&amp;do=diff</link>
        <description>Special Functions by Dr. Muhey-U-Din

These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. Thease notes are based on the lectures by Dr. Muhey-U-Din.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/special-theory-of-relativity-usman-hameed-and-zeeshan-ahmad?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Special Theory of Relativity by M Usman Hamid and M Zeeshan Ahmad</title>
        <link>https://beta.mathcity.org/notes/special-theory-of-relativity-usman-hameed-and-zeeshan-ahmad?rev=1737476042&amp;do=diff</link>
        <description>Special Theory of Relativity by M Usman Hamid and M Zeeshan Ahmad

[Special Theory of Relativity by M Usman Hamid and M Zeeshan Ahmad]
Special theory of relativity developed by Einstein in 1905, after the failure of Newton‘s laws, when he was dealing with the relative motion in space. The theory of relativity deals with relations which exist between physical quantities (such as mass of a particle, length of a rod, electric field at a point etc.) as they appear to different observers in relative …</description>
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    <item rdf:about="https://beta.mathcity.org/notes/theory-of-optimization-muzammil-tanveer?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Theory of Optimization by Ma&#039;am Iqra Razzaq</title>
        <link>https://beta.mathcity.org/notes/theory-of-optimization-muzammil-tanveer?rev=1737476042&amp;do=diff</link>
        <description>Theory of Optimization by Ma&#039;am Iqra Razzaq

[Special Theory of Optimization by Ma&#039;am Iqra Razzaq]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes are based on the lectures by Ma&#039;am Iqra Razzaq.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/theory-of-relativity-and-analytic-dynamics?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Theory of Relativity &amp; Analytic Dynamics: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/theory-of-relativity-and-analytic-dynamics?rev=1737476042&amp;do=diff</link>
        <description>Theory of Relativity &amp; Analytic Dynamics: Handwritten Notes

[Theory of Relativity &amp; Analytic Dynamics: Handwritten Notes]

Theory of Relativity and Analytic Dynamics is a subject that encompasses two distinct topics: relativity theory and analytic dynamics. Albert Einstein&#039;s theory of relativity defines the fundamental principles that control how moving objects behave in relation to one another and to the observer. The motion of objects as a result of forces and torques is the subject of analyt…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/topology-and-functional-analysis-solved-pu?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Topology and Functional Analysis Solved Paper by Noman Khalid</title>
        <link>https://beta.mathcity.org/notes/topology-and-functional-analysis-solved-pu?rev=1737476042&amp;do=diff</link>
        <description>Topology and Functional Analysis Solved Paper by Noman Khalid

These solved papers are written and provided by Mr. noman-khalid. We are very thankful to him for providing these notes to publish on MathCity.org.

Topology and Functional Analysis is considered as one the tough subject in BS/MSc Mathematics in different universities. Here solved paper for the said subject is given for the University of the Punjab (PU), Lahore.</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Topology: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/topology-handwritten-notes?rev=1737476042&amp;do=diff</link>
        <description>Topology: Handwritten Notes

[House of Tau]
A topological space is a collection of points with a topology-a structure that describes how close two points are to one another. It is a generalisation of Euclidean spaces that makes it possible to investigate boundaries, continuity, and connectivity. A topology is a group of open sets, or subsets, that adhere to certain principles.$T_0$$T_1$$T_2$$\varepsilon-$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Vector Spaces (Handwritten notes)</title>
        <link>https://beta.mathcity.org/notes/vector_spaces_handwritten_notes?rev=1737476042&amp;do=diff</link>
        <description>Vector Spaces (Handwritten notes)

[Vector Spaces (Handwritten notes) by Atiq ur Rehman]
Vector space is a fundamental subject in mathematics. At the undergraduate and upper secondary levels, the concept of vector space is regarded as basic and fundamental. These are lecture notes of Prof. Dr. Muhammad Khalid of University of Sargodha, Sargodha written by Atiq ur Rehman.</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Vector &amp; Tensor Analysis by Prof Fazal Abbas</title>
        <link>https://beta.mathcity.org/notes/vector-and-tensor-analysis-by-prof-fazal-abbas?rev=1737476042&amp;do=diff</link>
        <description>Vector &amp; Tensor Analysis by Prof Fazal Abbas

[Vector &amp; Tensor Analysis by Prof Fazal Abbas]

Solution of Chapter 6: Curvilinear Coordinates of the book Vector &amp; Tensor Analysis by Prof. Dr. Nawazish Ali Shah written by Prof. Fazal Abbas Sajid. Here solutions of chapter 6 are provided by the author of the book, for the solutions of all the chapters of the book, please buy the solution manual from the market.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/vector-spaces-review-by-rashad-wattu?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Vector Space (Review) by Rashad Wattu</title>
        <link>https://beta.mathcity.org/notes/vector-spaces-review-by-rashad-wattu?rev=1737476042&amp;do=diff</link>
        <description>Vector Space (Review) by Rashad Wattu

Mathematical vector space is a crucial and fundamental idea. It depends on the concept of field. These notes were primarily written to help maths students understand vector space, which is a concept that they all need to be familiar with.</description>
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    <item rdf:about="https://beta.mathcity.org/ppsc/ppsc-maths-2011?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>PPSC Paper 2011 (Lecturer in Mathematics)</title>
        <link>https://beta.mathcity.org/ppsc/ppsc-maths-2011?rev=1737476042&amp;do=diff</link>
        <description>PPSC Paper 2011 (Lecturer in Mathematics)

[PPSC Paper 2011 (Lecturer in Mathematics)]

On this page, we have given question from old (past) paper of Lecturer in Mathematics conducted in year 2011. This is a MCQs paper and answers are given at the end of the paper. At the end of the PDF is also given to download. This paper is provided by Ms. $R$$x\in R$$x^2=x$$x^2=-x$$x^2=0$$x^2=1$$6$$8$$10$$4$$G$$H$$H$$G$$2$$4$$nZ$$Z$$n$$G$$24$$a$$a^{10}$$2$$12$$10$$V$$n$$V$$n+1$$n$$n-1$$v_1,v_2,v_3,....,v_r$$…</description>
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        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>PPSC Paper 2015 (Lecturer in Mathematics)</title>
        <link>https://beta.mathcity.org/ppsc/ppsc-maths-2015?rev=1737476042&amp;do=diff</link>
        <description>PPSC Paper 2015 (Lecturer in Mathematics)

[PPSC Paper 2011 (Lecturer in Mathematics)]

On this page, we have given question from old (past) paper of Lecturer in Mathematics conducted in year 2011. This is a MCQs paper and answers are given at the end of the paper. At the end of the PDF is also given to download. This paper is provided by Kaushef Salamat. We are very thankful to her for providing this paper.\(\displaystyle \int_{-4}^{0}\frac{tdt}{\sqrt{16-t62}}\)$0$$-4$$4$\(A\cos wt+B\sin wt\)$\…</description>
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    <item rdf:about="https://beta.mathcity.org/ppsc/ppsc-maths-2021?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>PPSC Paper 2021 (Lecturer in Mathematics)</title>
        <link>https://beta.mathcity.org/ppsc/ppsc-maths-2021?rev=1737476042&amp;do=diff</link>
        <description>PPSC Paper 2021 (Lecturer in Mathematics)

[PPSC Paper 2011 (Lecturer in Mathematics)]

On this page, we have given question from old (past) paper of Lecturer in Mathematics conducted in year 2021. This is a MCQs paper and answers are given at the end of the paper. At the end of the PDF is also given to download. This paper is provided by Ms. \(2018\)$4$\(6\)$8$$10$\(X\)\(Y\)\(X\times Y\)\(\parallel (x,y) \parallel=\parallel x\parallel+\parallel y\parallel, \,\forall \, (x,y)\in X \times Y\)\(f(…</description>
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    <item rdf:about="https://beta.mathcity.org/ppsc/ppsc-mock-interview-mathematics?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>PPSC Mock Interview Lecturer Mathematics</title>
        <link>https://beta.mathcity.org/ppsc/ppsc-mock-interview-mathematics?rev=1737476042&amp;do=diff</link>
        <description>PPSC Mock Interview Lecturer Mathematics

[PPSC Mock Interview Lecturer Mathematics]
This handout is shared by Mr. Rashad Wattu and written by Sawaira Sikandar. We are really very thankful to him for providing this handout and appreciates his efforts to publish it on MathCity.org. 
This handout contains the questions collected from the different interviews of the Lecturer in Mathematics conducted by Public Service Commission (PSC). This is help full to prepare interview of all types of jobs whic…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc/fsc_part_1_mcqs/mcqs_with_answers?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>MCQs with Answers (FSc/ICS Part 1)</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_mcqs/mcqs_with_answers?rev=1737476035&amp;do=diff</link>
        <description>MCQs with Answers (FSc/ICS Part 1)

[MCQs Choice]
In this one PDF, MCQs of all chapters of FSc/ICS Part1 are given. There are seven chapters. Answers of MCQs is starting from page 71.

SAMPLE MCQs




	*  $i^{13}=$.............
		*  (A) $i$
		*  (B) 1
		*  (C) -1
		*  (D) 2
$S$$1, \omega, \omega^2$$-1, \omega, \omega^2$$-1, -\omega, -\omega^2$$1, -1, 2$$ax^2+bx+c=0$$a=0, b\neq 0$$a\neq 0$$a=b=0$$b=$$ax^2+bx+c=0$$a=0, b\neq 0$$a\neq 0$$a=b=0$$b=$$n!=n(n-1)(n-2)...3\cdot 2\cdot 1$$n$</description>
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    <item rdf:about="https://beta.mathcity.org/fsc/fsc_part_1_mcqs/mcqs-short_questions_by_mr._parvez_khan?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>MCQs-Short Questions by Mr Parvez Khan</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_mcqs/mcqs-short_questions_by_mr._parvez_khan?rev=1737476035&amp;do=diff</link>
        <description>MCQs-Short Questions by Mr Parvez Khan

	*  MCQs and Short Question written by Mr. Parvez Khan, composed by Mr. Momin Ali from Text Book of Algebra and Trigonometry Class XI (Punjab Textbook Board, Lahore)
	*  &lt;wrap hi&gt;Key to the MCQs is given at page 57.&lt;/wrap&gt;&lt;div&gt;
&lt;div align=&quot;center&quot;&gt;
&lt;iframe src=&quot;http://docs.google.com/viewer?url=http%3A%2F%2Fwww.mathcity.org%2Ffiles%2Ffsc%2Ffsc_part1%2FMCQs-Short_Questions_Math_FSc_Part1.pdf&amp;embedded=true&quot; style=&#039;width: 100%; height: 550px; border: none;&#039;&gt;&lt;…</description>
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    <item rdf:about="https://beta.mathcity.org/msc/notes/mathematical-method-by-khalid-latif-mir?rev=1737476041&amp;do=diff">
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Method by Khalid Latif Mir (Solutions)</title>
        <link>https://beta.mathcity.org/msc/notes/mathematical-method-by-khalid-latif-mir?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Method by Khalid Latif Mir (Solutions)

[Mathematical Method by Khalid Latif Mir (Solutions)]

We are very thankful to Prof. Fazal Abbas Sajid for sharing these solutions. Problems &amp; Methods Mathematical Method by Khalid Latif Mir is a famous book taught in different universities of the Pakistan at BS and Master level. On this page, we have added the solutions of the exercises of the book. The solutions of Chapter 06: The Laplace Transform and its Applications is written by Marrium …</description>
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    <item rdf:about="https://beta.mathcity.org/msc/notes/number-theory-iqra-liaqat?rev=1737476041&amp;do=diff">
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/msc/notes/number-theory-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Number Theory by Ms. Iqra Liaqat

[Number Theory by Ms. Iqra Liaqat]

Notes of number theory provided Ms. Iqra Liaqat is a very good addition in the MSc notes section. We are actually quite grateful to her for giving these notes and likes her encouragement to distribute these notes on MathCity.org
 Name</description>
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    <item rdf:about="https://beta.mathcity.org/msc/notes/theoretical-mechanics-by-khalid-latif-mir?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Theoretical Mechanics by Khalid Latif Mir (Solutions)</title>
        <link>https://beta.mathcity.org/msc/notes/theoretical-mechanics-by-khalid-latif-mir?rev=1737476041&amp;do=diff</link>
        <description>Theoretical Mechanics by Khalid Latif Mir (Solutions)

[Theoretical Mechanics by Khalid Latif Mir (Solutions)]

We are very thankful to Prof. Fazal Abbas Sajid for sharing these solutions. An Intermediate Course in Theoretical Mechanics By Khalid Latif Mir is a famous book taught in different universities of the Pakistan. On this page, we have added the solutions of the exercises of the book.</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 1.1

Solutions of Question 1 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
${{i}^{9}}+{{i}^{19}}$\begin{align}{{i}^{9}}+{{i}^{19}}&amp;=i\cdot{{i}^{8}}+i\cdot{{i}^{18}}\\
&amp;=i\cdot{{\left( {{i}^{2}} \right)}^{4}}+i\cdot{{\left( {{i}^{2}} \right)}^{9}}\\
&amp;=i\cdot{{\left( -1 \right)}^{4}}+i\cdot{{\left( -1 \right)}^{9}}\\
&amp;=i\cdo…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p9?rev=1737476036&amp;do=diff</link>
        <description>Question 11, Exercise 1.1

Solutions of Question 11 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11(i)
${{z}_{1}}=2-i$${{z}_{2}}=-2+i$${\rm Re}\left( \dfrac{{{z}_{1}}{{z}_{2}}}{\overline{{{z}_{1}}}} \right)$$z_1=2-i$$z_2=-2+i$$\overline{z_1}=2+i$\begin{align}
z_1 z_2&amp;=(2-i)(-2+i)\\ 
&amp;=-4+1+2i+2i\\
&amp;=-3+4i
\end{align}\begin{align}
\dfrac{z_1 z_2}{\…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 1.2

Solutions of Question 1 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

If ${{z}_{1}}=2+i$${{z}_{2}}=1-i$${{z}_{1}}=2+i$${{z}_{2}}=1-i$$$z_1+z_2=z_2+z_1.$$\begin{align}z_1+z_2&amp;=(2+i)+(1-i)\\ 
&amp;=3 \ldots (i) \end{align}\begin{align} 
z_2+z_1&amp;=(1-i)+(2+i)\\
&amp;=3 \ldots (ii)\end{align}$$z_1 z_2=z_2 z_1.$$\begin{align}z_1 z_2 …</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p8?rev=1737476036&amp;do=diff</link>
        <description>Question 9, Exercise 1.2

Solutions of Question 9 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)
$z=3+2i,$$-|z|\leq \operatorname{Re}\left( z \right)\leq |z|$$z=3+2i$$|z|=\sqrt{9+4}=\sqrt{13}$${\rm Re}z=3=\sqrt{9}$\begin{align} &amp;-\sqrt{13} \leq \sqrt{9} \leq \sqrt{13}\\
\implies &amp;-|z|\leq \operatorname{Re}\left( z \right)\leq |z|\end{align}$z=3…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 1.3

Solutions of Question 1 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
\begin{align}&amp;z-4w=3i\\ 
&amp;2z+3w=11-5i\end{align}\begin{align}z-4w&amp;=3i		…(i)\\
2z+3w&amp;=11-5i	…(ii)\end{align}$2$\begin{align}2z-8w&amp;=6i		…(iii)\end{align}\[\begin{array}{cccc}
2z&amp;-8w&amp;=6i  \\  
\mathop+\limits_{-}2z&amp;\mathop+\limits_{-}3w&amp;=\mathop-\limit…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p5?rev=1737476036&amp;do=diff</link>
        <description>Question 6, Exercise 1.3

Solutions of Question 6 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
${{z}^{4}}+{{z}^{2}}+1=0$\begin{align}{{z}^{4}}+{{z}^{2}}+1&amp;=0\\
{{z}^{4}}+2\left( \dfrac{1}{2} \right){{z}^{2}}+\dfrac{1}{4}-\dfrac{1}{4}+1&amp;=0\\
{{\left( {{z}^{2}}+\dfrac{1}{2} \right)}^{2}}+\dfrac{4-1}{4}&amp;=0\\
{{\left( {{z}^{2}}+\dfrac{1}{2} \righ…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p4?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, 7 &amp; 8, Review Exercise 1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p4?rev=1737476036&amp;do=diff</link>
        <description>Question 6, 7 &amp; 8, Review Exercise 1

Solutions of Question 6, 7 &amp; 8 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{1}{3+4i}$\begin{align}\dfrac{1}{3+4i}&amp;=\dfrac{1}{3+4i}\times \dfrac{3-4i}{3-4i}\\
&amp;=\dfrac{3-4i}{9+16}\\
&amp;=\dfrac{3-4i}{25}\\
&amp;=\dfrac{3}{25}-\dfrac{4i}{25}\end{align}$\dfrac{3i+2}{3-2i}$\begin{align}\dfrac{3i+2}{3-2i}\\
\dfrac{3i+2}…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p1?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$\sin {{37}^{\circ }}\cos {{22}^{\circ }}+\cos {{37}^{\circ }}\sin {{22}^{\circ }}$\begin{align} \sin (\alpha +\beta )=\sin \alpha \cos \beta +\cos \alpha \sin \beta, \end{align}\begin{a…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p11?rev=1737476036&amp;do=diff</link>
        <description>Question 13, Exercise 10.1

Solutions of Question 13 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$r\,\,\sin \left( \theta +\phi  \right)$$\theta$$\phi$$4\sin \theta +3\cos \theta .$$4\sin \theta +3\cos \theta$$r\sin(\theta + \varphi)$$$4\sin \theta +3\cos \theta=r\cos\varphi\sin\theta+r\sin\varphi\cos\theta --- (1)$…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 10.2

Solutions of Question 1 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$\sin 2\theta ,\,\,\cos 2\theta$$\tan 2\theta$$\tan \theta =-\dfrac{1}{5}$$\theta$$\sin \theta =\dfrac{1}{\sqrt{26}}$$\cos \theta =\dfrac{-5}{\sqrt{26}}$\begin{align}\sin 2\theta &amp;=2\sin…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 and 9, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p7?rev=1737476036&amp;do=diff</link>
        <description>Question 8 and 9, Exercise 10.2

Solutions of Question 8 and 9 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\cos }^{4}}\theta $\begin{align}{{\cos}^{4}}\theta &amp;={{\left( {{\cos }^{2}}\theta  \right)}^{2}}\\
&amp;={{\left( \dfrac{1+\cos 2\theta }{2} \right)}^{2}}\\ 
&amp;=\dfrac{1+2\cos 2\theta +{{\cos }^{2}}2\theta }{4}\\…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 10.3

Solutions of Question 1 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$2\sin 6x\sin x$$$-2\sin \alpha \sin \beta =\cos (\alpha +\beta )-\cos (\alpha -\beta ).$$$\alpha =6x$$\beta =x$\begin{align}-\,2\sin 6x\sin x&amp;=\cos (6x+x)-\cos (6x-x)\\
&amp;=\cos 7x-\cos x…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 10.3

Solutions of Question 5 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{20}^{\circ }}\cos {{40}^{\circ }}\cos {{60}^{\circ }}\cos {{80}^{\circ }}=\dfrac{1}{16}$$2\cos \alpha \cos \beta =\cos \left( \alpha +\beta  \right)+\cos \left( \alpha -\beta  \right)$\begin{align}L.H.S.&amp;=\cos {{20…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 &amp; 9, Review Exercise 10</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 8 &amp; 9, Review Exercise 10

Solutions of Question 8 &amp; 9 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \left( \dfrac{\pi }{4}-\theta  \right)\sin \left( \dfrac{\pi }{4}+\theta  \right)=\dfrac{1}{2}\cos 2\theta $$2\sin \alpha \sin \beta =\cos \left( \alpha -\beta  \right)-\cos \left( \alpha +\beta  \r…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 1.1

Solutions of Question 1 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
${{i}^{9}}+{{i}^{19}}$\begin{align}{{i}^{9}}+{{i}^{19}}&amp;=i\cdot{{i}^{8}}+i\cdot{{i}^{18}}\\
&amp;=i\cdot{{\left( {{i}^{2}} \right)}^{4}}+i\cdot{{\left( {{i}^{2}} \right)}^{9}}\\
&amp;=i\cdot{{\left( -1 \right)}^{4}}+i\cdot{{\left( -1 \right)}^{9}}\\
&amp;=i\cdo…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p9?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p9?rev=1737476037&amp;do=diff</link>
        <description>Question 11, Exercise 1.1

Solutions of Question 11 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11(i)
${{z}_{1}}=2-i$${{z}_{2}}=-2+i$${\rm Re}\left( \dfrac{{{z}_{1}}{{z}_{2}}}{\overline{{{z}_{1}}}} \right)$$z_1=2-i$$z_2=-2+i$$\overline{z_1}=2+i$\begin{align}
z_1 z_2&amp;=(2-i)(-2+i)\\ 
&amp;=-4+1+2i+2i\\
&amp;=-3+4i
\end{align}\begin{align}
\dfrac{z_1 z_2}{\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 1.2

Solutions of Question 1 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

If ${{z}_{1}}=2+i$${{z}_{2}}=1-i$${{z}_{1}}=2+i$${{z}_{2}}=1-i$$$z_1+z_2=z_2+z_1.$$\begin{align}z_1+z_2&amp;=(2+i)+(1-i)\\ 
&amp;=3 \ldots (i) \end{align}\begin{align} 
z_2+z_1&amp;=(1-i)+(2+i)\\
&amp;=3 \ldots (ii)\end{align}$$z_1 z_2=z_2 z_1.$$\begin{align}z_1 z_2 …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 9, Exercise 1.2

Solutions of Question 9 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)
$z=3+2i,$$-|z|\leq \operatorname{Re}\left( z \right)\leq |z|$$z=3+2i$$|z|=\sqrt{9+4}=\sqrt{13}$${\rm Re}z=3=\sqrt{9}$\begin{align} &amp;-\sqrt{13} \leq \sqrt{9} \leq \sqrt{13}\\
\implies &amp;-|z|\leq \operatorname{Re}\left( z \right)\leq |z|\end{align}$z=3…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 1.3

Solutions of Question 1 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
\begin{align}&amp;z-4w=3i\\ 
&amp;2z+3w=11-5i\end{align}\begin{align}z-4w&amp;=3i		…(i)\\
2z+3w&amp;=11-5i	…(ii)\end{align}$2$\begin{align}2z-8w&amp;=6i		…(iii)\end{align}\[\begin{array}{cccc}
2z&amp;-8w&amp;=6i  \\  
\mathop+\limits_{-}2z&amp;\mathop+\limits_{-}3w&amp;=\mathop-\limit…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 6, Exercise 1.3

Solutions of Question 6 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
${{z}^{4}}+{{z}^{2}}+1=0$$$z^4+z^2+1=0$$$$z^4+2z^2+1-z^2=0$$$$( z^2+1 )^2-z^2=0$$$$( z^2+1+z)( z^2+1-z )=0$$$$( z^2+z+1 )( z^2-z+1 )=0$$$$(z^2+z+1 )=0$$$$z=\dfrac{-1\pm \sqrt{1-4}}{2}$$$$z=\dfrac{-1\pm \sqrt{3}i}{2}$$$$(z^2-z+1 )=0$$$$z=\dfrac{1\pm …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, 7 &amp; 8, Review Exercise 1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 6, 7 &amp; 8, Review Exercise 1

Solutions of Question 6, 7 &amp; 8 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{1}{3+4i}$$$z=\dfrac{1}{3+4i}.$$\begin{align}z&amp;=\dfrac{1}{3+4i}\times \dfrac{3-4i}{3-4i}\\
&amp;=\dfrac{3-4i}{9+16}\\
&amp;=\dfrac{3-4i}{25}\\
&amp;=\dfrac{3}{25}-\dfrac{4}{25}i\end{align}$$\bar{z}=\dfrac{3}{25}+\dfrac{4}{25}i.$$$\dfrac{3i+2}{3-2…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 2.1

Solutions of Question 1 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$$\left[ \begin{matrix}
1 &amp; 2 &amp; 4  \\
\end{matrix} \right]
\left[ \begin{matrix}
1 &amp; 0 &amp; 2  \\
2 &amp; 0 &amp; 1  \\
0 &amp; 1 &amp; 2  \\
\end{matrix} \right]
\left[ \begin{matrix}
2  \\
4  \\
6  \\
\end{matrix} \right]$$\begin{align}&amp;\left[ \begin{matri…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p12?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p12?rev=1737476037&amp;do=diff</link>
        <description>Question 13, Exercise 2.1

Solutions of Question 13 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 13(i)
$A$$3$$A+A^t$$$A=\left[ \begin{matrix}
   a_{11} &amp; a_{12} &amp; a_{13}  \\
   a_{21} &amp; a_{22} &amp; a_{23}  \\
   a_{31} &amp; a_{32} &amp; a_{33}  \\
\end{matrix} \right]$$$$A^t=\left[ \begin{matrix}
   a_{11} &amp; a_{21} &amp; a_{31}  \\
   a_{12} &amp; a_{22} …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 2.2

Solutions of Question 1 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1
$A=\begin{bmatrix}1 &amp; 3 &amp; 1  \\-1 &amp; 2 &amp; 0  \\2 &amp; 0 &amp; -2 \end{bmatrix}$$A_{11},A_{21},A_{23},A_{31},A_{32},A_{33}.$$|A|.$$$A=\left[ \begin{matrix}
   1 &amp; 3 &amp; 1  \\
   -1 &amp; 2 &amp; 0  \\
   2 &amp; 0 &amp; -2  \\
\end{matrix} \right]$$$${{A}_{11}}={{\left(…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p15?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p15?rev=1737476037&amp;do=diff</link>
        <description>Question 19, Exercise 2.2

Solutions of Question 19 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 19
$A=\begin{bmatrix}2 &amp; 3  \\-1 &amp; 1\end{bmatrix}$$( A^{-1})^t=( A^t)^{-1}$$$A=\left[ \begin{matrix}
   2 &amp; 3  \\
   -1 &amp; 1  \\
\end{matrix} \right]$$$$A^t=\left[ \begin{matrix}
   2 &amp; -1  \\
   3 &amp; 1  \\
\end{matrix} \right]$$$$|A^t|=5$$$$Ad…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 2.3

Solutions of Question 1 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$\begin{bmatrix}1 &amp; 3 &amp; -1  \\2 &amp; 1 &amp; 4  \\3 &amp; 4 &amp; -5\end{bmatrix}$\begin{align}&amp;\begin{bmatrix}
1 &amp; 3 &amp; -1  \\
2 &amp; 1 &amp; 4  \\
3 &amp; 4 &amp; -5 \end{bmatrix}\\
\underset{\sim}{R}&amp;\begin{bmatrix}
1 &amp; 3 &amp; -1  \\
0 &amp; -5 &amp; 6  \\
0 &amp; -5 &amp; -2 \end{bmat…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 4, Exercise 2.3

Solutions of Question 4 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\begin{bmatrix}2 &amp; 3 &amp; 4 &amp; 5  \\3 &amp; 4 &amp; 5 &amp; 6  \\4 &amp; 5 &amp; 6 &amp; 7  \\9 &amp; 10 &amp; 11 &amp; 12\end{bmatrix}$\begin{align}&amp;\begin{bmatrix}
2 &amp; 3 &amp; 4 &amp; 5  \\
3 &amp; 4 &amp; 5 &amp; 6  \\
4 &amp; 5 &amp; 6 &amp; 7  \\
9 &amp; 10 &amp; 11 &amp; 12 \end{bmatrix}\\
\underset{\sim}{R}&amp;\begin{bm…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 3.2

Solutions of Question 1 of Exercise 3.2 of Unit 03: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question.1(i)
$\vec{a}=3\hat{i}-5\hat{j}$$\vec{b}=-2\hat{i}+3\hat{j}$$\vec{a}+2\vec{b}$\begin{align}\vec{a}+2\vec{b}&amp;=3\hat{i}-5\hat{j}+2(-2\hat{i}+3\hat{j})\\
&amp;=3\hat{i}-5\hat{j}-4\hat{i}+6\hat{j}\\
&amp;=-\hat{i}+\hat{j}\end{align}$\vec{a}=3\hat{i}-5\hat{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p9?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, 13 &amp; 14, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p9?rev=1737476037&amp;do=diff</link>
        <description>Question 12, 13 &amp; 14, Exercise 3.2

Solutions of Question 12, 13 &amp; 14 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 12
$\alpha ,$$|\alpha \hat{i}+(\alpha +1)\hat{j}+2\hat{k}|=3$\begin{align}|\alpha \hat{i}+(\alpha +1)\hat{j}+2\hat{k}|&amp;=3.\end{align}\begin{align}\sqrt{(\alpha )^2+(\alpha +1)^2+(2)^2}&amp;=3.\end{align}\begin{align}&amp;{\alpha ^2+(\alpha +1)^2}+4=9…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 3.3

Solutions of Question 1 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)

If $\vec{a}=3 \hat{i}+4 \hat{j}-\hat{k}$, $\vec{b}=\hat{i}-\hat{j}+3 \hat{k}$ and $\vec{c}=2\hat{i}+\hat{j}-5 \hat{k}$$\vec{a}\cdot \vec{b}$\begin{align}\vec{a} \cdot \vec{b}&amp;=(3 \hat{i}+4 \hat{j}-\hat{k}) \cdot(\hat{i}-\hat{j}+3 \hat{k})\\
\Rightarrow &amp;=(…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 &amp; 13, Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 12 &amp; 13, Exercise 3.3

Solutions of Question 12 &amp; 13 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 12
$\overrightarrow{B A} \cdot \overrightarrow{A C}=0$$|\vec{a}|=\vec{b}|=| \vec{c} \mid=$$\vec{b}=-\vec{c}$$\triangle A B O$\begin{align}\overrightarrow{O B}+\overrightarrow{A B}&amp;=\overrightarrow{O A}\\
\Rightarrow \overrightarrow{B A}&amp;=\overrightar…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1 Exercise 3.4

Solutions of Question 1 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)

Find the cross product $\hat{j} \times(2 \hat{j}+3 \hat{k})$\begin{align}\vec{a}=\hat{j}&amp;=0 \hat{i}+\hat{j}+0 \hat{k}\\
\vec{b}&amp;=0 \hat{i}+2 \hat{j}-3 \hat{k}\\
 \vec{a} \times \vec{b}&amp;=\hat{j} \times(2 \hat{j}+3 \hat{k})\\
&amp;=\left|\begin{array}{lll}\hat{i}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 3.4

Solutions of Question 9 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)

Find the area of parallelogram whose diagonals are $\vec{a}=4 \hat{i}+\hat{j}-2 \hat{k}\quad$$\quad\vec{b}=-2 \hat{i}+3 \hat{j}+4 \hat{k}$$\vec{c}$$\vec{d}$$E$$E$\begin{align}\overrightarrow{A E}&amp;=\overrightarrow{E C}\\
&amp;=\dfrac{1}{2} \vec{a}\\
&amp;=2 \hat{i}+…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 &amp; 2 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 &amp; 2 Exercise 3.5

Solutions of Question 1 &amp; 2 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

Find $\vec{a} \cdot \vec{b} \times \vec{c}$$\vec{a}=2 \hat{i}+\hat{j}+3 \hat{k}$$\vec{b}=-\hat{i}+2 \hat{j}+\hat{k} \quad \text { and }\quad \vec{c}=3 \hat{i}+\hat{j}+2 \hat{k} \text {. }$\begin{align}V&amp;=\vec{a} \cdot \vec{b} \times \vec{c}\\
&amp;=\left|\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 3.5

Solutions of Question 9 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9 (i)

Write the value of $(\hat{i} \times \hat{j}). \hat{k}+\hat{i}. \hat{j}$\begin{align}
(\hat{i} \times \hat{j}) \cdot \hat{k}&amp;=\left|\begin{array}{ccc}
1 &amp; 0 &amp; 0 \\
0 &amp; 1 &amp; 0 \\
0 &amp; 0 &amp; 1
\end{array}\right|&amp;=1 ....(1)\\
\text { and } \hat{i} \cdot \hat{j}&amp;=0…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p6?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Review Exercise 3

Solutions of Question 10 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 10(i)
$A B C$$|\vec{a}|^2=|\vec{b}|^2+|\vec{c}|^2 -2|\vec{b}|| \vec{c}| \cos A$$A B C$$\vec{a}, \vec{b}$$\vec{c}$\begin{align}
\vec{b}&amp;=\vec{a}+\vec{c} \\
\Rightarrow \vec{a}&amp;=\vec{b}-\vec{c} \\
\Rightarrow \vec{a} \cdot \vec{a}&amp;=(\vec{b}-\vec{c}) \cd…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-1-p1?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-1-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 4.1

Solutions of Question 1 and 2 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2,4,6,8, \ldots ,50$$50 $$1,0,1,0,1, \ldots$$0$$1$$...,-4,0,4,8, \ldots, 60$$1,-\dfrac{1}{3}, \dfrac{1}{9},-\dfrac{1}{27}, \ldots,-\dfrac{1}{2187}$$a_n=\dfrac{n(n+1)}{2}$$$a_n=\dfrac{n(n+1)}{2}$$$n=1,$$$a_1=\dfrac{1(1+1)}{2}=1$$$n=2$$$a_2=\dfrac{2(2…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-1-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 4.1

Solutions of Question 6 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Note

The general recursive definition formula defined for Pascal sequences is
$$P_0=1, P_{r+1}=\dfrac{n-r}{r+1} P_r, \text{ where } r=0,1,2,3,\ldots.$$$n=5$$n=5$$$P_0=1, P_{r+1}=\dfrac{5-r}{r+1} P_r, \text{ where } r=0,1,2,3,\ldots.$$$r=0$\begin{align}&amp;P_{0+1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p1?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 4.2

Solutions of Question 1 and 2 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$15$$2,5,8, \ldots$$a_1=2$$d=5-2=3$$n=15$$$a_n=a_1+(n-1) d$$\begin{align}a_{15}&amp;=2+(15-1) 3 \\
&amp;=2+42=44 \end{align}$44$$a_1=8$$a_{21}=108$$$a_n=a_1+(n-1) d.$$\begin{align}
&amp;a_{21}=8+(21-1) d \\
\implies &amp;108=8+20 d\\
\implies &amp;20 d=108-8=100 \\
\imp…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p13?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 17 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p13?rev=1737476038&amp;do=diff</link>
        <description>Question 17 Exercise 4.2

Solutions of Question 17 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 17
$n$$7: 13$$n$$A_1, A_2, A_3, \ldots, A_n$$n$$5, A_1, A_2, A_3, \ldots, A_n, 32$$$a_1=5 \text{ and } a_{n+2}=32.$$$a_n=a_1+(n-1) d$$n$$n+2$\begin{align}a_{n+2}&amp;=a_1+(n+2-1) d \\
	&amp; =a_1+(n+1) d \\
	\implies 32&amp;=5+(n+1)d \\
	\implies (n+1)d&amp;=32-5\\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p1?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 4.3

Solutions of Question 1 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$9,7,5,3, \ldots$$a_1$$d$\begin{align}&amp;a_1=9 \\ 
&amp;d=7-9=-2 \\
&amp;n=20.
\end{align}\begin{align}&amp;a_n=a_1+(n-1)d \\
\implies &amp;a_20=9+(20-1)(-2)=-29.
\end{align}$S_n$$n$\begin{align}
S_n&amp;=\dfrac{n}{2}[a_1+a_n], \\
\implies S_{20}&amp;=\dfrac{20}{2}[9-29] …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 &amp; 14 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 13 &amp; 14 Exercise 4.3

Solutions of Question 13 &amp; 14 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.\begin{align}\text{Total number of rows}&amp; n=40,\\
\text{Seats in a first row} a_1&amp;=20\\
\text{Seat in a second row} a_2&amp;=23\\
\text{Seats in third row} a_3&amp;=26\end{align}$20,23,26, \ldots$$S_{40}$$$S_n=\dfrac{n}{2} [{2} a_1+(n-1) d] \text {.}$$\begin…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 4.4

Solutions of Question 1 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question(i)
$a_1=5, \quad r=3$$a_1, a_1 r, a_1 r^2, a_1 r^3, a_1 r^4, \ldots$$a_1=5 ; r=3$\begin{align}&amp;5,5.3,5.3^2, 5.3^3, 5.3^4, \ldots\\
\Rightarrow &amp;5,15,45,135,405, \ldots\end{align}$a_1=8, \quad r=-\dfrac{1}{2}$$a_1, a_1 r, a_1 r^2, a_1 r^3, a_1 r^4, \ld…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p9?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p9?rev=1737476038&amp;do=diff</link>
        <description>Question 12 Exercise 4.4

Solutions of Question 12 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 12
$n, . \dfrac{a^{n+1}+b^{n+1}}{a^n+b^n}$$a$$b$$a$$b$$\dfrac{a^{n+1}+b^{n-1}}{a^n+b^n}$$a$$b$\begin{align}\dfrac{a^{n+1}+b^{n+1}}{a^n+b^n}&amp;=\sqrt{a b}\quad \because G \cdot M=\sqrt{a b} \\
\Rightarrow \dfrac{a^{n+1}+b^{n+1}}{a^n+b^n}&amp;=a^{\dfrac{1}{…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 4.5

Solutions of Question 1 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$3+6+12+\ldots+3.2^9$$a_1=3, \quad r=\dfrac{6}{3}=2$$a_n=3.2^9$$n$$$a_n=a_1 r^{n-1}$$\begin{align}3.2^9&amp;=3(2)^{n-1} \text { or }(2)^{n-1}=\dfrac{3.2^9}{3} \\
\Rightarrow(2)^{n-1}&amp;=2^9 \\
\Rightarrow n-1&amp;=9 \text { or } n=10  \\
\text {. Now }\qua…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15 &amp; 16 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p10?rev=1737476038&amp;do=diff</link>
        <description>Question 15 &amp; 16 Exercise 4.5

Solutions of Question 15 &amp; 16 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2$$4$$15^{\text {th }}$$a_1=R s .1$$a_2=R s .2$$a_3=R s .4$$1,2,4,8, \ldots$$a_1=1 . \quad r=2 . \quad n=15$$a_n=a_1 r^{n-1}$$15^{1 / 2}$$$a_{15}=a_1 r^{14} $$$$a_{15}=1 .(2)^{1 4}=R s .16384 $$$$S_{30}=\dfrac{a_1(r^{30}-1)}{r-1} $$$r-2$$a_1=1$\begi…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 5.1

Solutions of Question 1 of Exercise 5.1 of Unit 05: Mascellaneous series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$1^2+3^2+5^2+7^2+\ldots$$n$$1+3+5+\ldots$$n^{\text {th }}$$2 n-1$$n^{t h}$$$T_j=(2 j-1)^2$$\begin{align}&amp; \sum_{j=1}^n T_j=\sum_{j=1}^n(2 j-1)^2 \\
&amp; =\sum_{j=1}^n(4 j^2-4 j+1)\\
&amp; =4 \sum_{j=1}^n j^2-4 \sum_{j=1}^n j+\sum_{j=1}^n 1 \\
&amp; =4 \dfr…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 5.1

Solutions of Question 9 of Exercise 5.1 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)
$n$$n$$n$\begin{align}
&amp; T_n=n^2(2 n+3)=2 n^3+3 n^2 \\
&amp; \Rightarrow T_j=2 j^3+3 j^2\end{align}\begin{align}
&amp; \sum_{j=1}^n T_j=2 \sum_{j=1}^n j^3+3 \sum_{j=1}^n j^2 \\
&amp; =2(\dfrac{n(n+1)}{2})^2+3 \dfrac{n(n+1)(2 n+1)}{6} \\
&amp; =\dfrac{n(n+1)}{2}…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-2-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 5.2

Solutions of Question 1 of Exercise 5.2 of Unit 05: Mascellaneous series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$n$$1.2+2.2^2+3.2^3+4.2^4+\ldots$\begin{align}
&amp; S_n=1.2+2.2^2+3 \cdot 2^3+4 \cdot 2^4+\ldots +n \cdot 2^n....(i) \\
&amp; 2 S_n=1.2^2+2.2^3+3.2^4+4.2^5+\ldots +n \cdot 2^n....(ii)\end{align}\begin{align} (1-2) S_n&amp;=1 \cdot 2+(2-1) 2^2+(3-2) 2^2+(4-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-2-p3?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5 Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-2-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 &amp; 5 Exercise 5.2

Solutions of Question 4 &amp; 5 of Exercise 5.2 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$5+\dfrac{7}{3}+\dfrac{9}{3^2}+\dfrac{11}{3^3}+\ldots$\begin{align}
&amp; S_{\infty}=5+\dfrac{7}{3}+\dfrac{9}{3^2}+\dfrac{11}{3^3}+\ldots.(i) \\
&amp; \dfrac{1}{3} S_{\infty}=\dfrac{5}{3}+\dfrac{7}{3^2}+\dfrac{9}{3^2}+\dfrac{11}{3^3}+\ldots.(ii)
\e…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 5.3

Solutions of Question 1 of Exercise 5.3 of Unit 05: Mascellaneous series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1
$n$$n$$4+13+28+49+76+\ldots$\begin{align}
&amp; a_2-a_1=13-4=9 \\
&amp; a_3-a_2=28-13=15 \\
&amp; a_4-a_3=49-28=21 \\
&amp; \cdots \quad \cdots \quad \cdots \\
&amp; \cdots \quad \cdots \quad \cdots \\
&amp; a_n-a_{n-1}=(n-1)th \quad\text{term of sequence}\quad 9,15,21,..…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p6?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 5.3

Solutions of Question 6 of Exercise 5.3 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6
$n$$n$$28+32+52+152+652+\ldots$\begin{align}
&amp; a_2-a_1=32-28=4 \\
&amp; a_3-a_2=52-32=20 \\
&amp; a_4-a_3=152-52=100 \\
&amp; \ldots \quad \cdots \quad \cdots \\
&amp; \cdots \quad \cdots \quad \cdots \\
&amp; a_n-a_{n-1}=(\mathrm{n}-1) \text { term ofthe sequence } 4…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 5.3

Solutions of Question 1 of Exercise 5.4 of Unit 05: Mascellaneous series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\ldots$$n$$$T_n=\dfrac{1}{n(n+1)}$$$T_n$$$\dfrac{1}{n(n+1)}=\dfrac{A}{n}+\dfrac{B}{(n+1)}$$$n(n+1)$$$1=A(n+1)+B n=(A+B) n+A$$$n$$$A+B=0 \text{and} A=1$$$A=1$\begin{align}1+B&amp;=0\\
B&amp;=-1\end{align}\beg…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 5.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 5.4

Solutions of Question 4 of Exercise 5.4 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\sum_{k=1}^n \dfrac{1}{k^2+7 k+12}$\begin{align}S_n &amp;=\sum_{k=1}^n \dfrac{1}{k^2+7 k+12} \\
&amp; =\sum_{k=1}^n \dfrac{1}{(k+3)(k+4)}\end{align}$n^{\text {th }}$$$u_n=\dfrac{1}{(n+3)(n+4)}$$$$\dfrac{1}{(n+3)(n+4)}=\dfrac{A}{n+3}+\dfrac{B}{n+4}$$$A$$B$…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Review Exercise

Solutions of Question 10 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 10
$n^{\text {th }}$$n$$1+(1+\dfrac{1}{2})+(1+\dfrac{1}{2}+\dfrac{1}{4})+(1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8})+\ldots$\begin{align}
a_n&amp;=1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\cdots+\dfrac{1}{2^{n-1}} \\
a_n&amp;=\dfrac{1[1-(\dfrac{1}{2})…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p1?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 6.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 6.1

Solutions of Question 1 and 2 of Exercise 6.1 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{10 !}{3 ! .3 ! \cdot 4 !}$\begin{align}\dfrac{10 !}{3 ! \cdot 3 ! \cdot 4 !}&amp;=\dfrac{10.9 .8 \cdot 7 \cdot 6 \cdot 5.4 !}{3 ! \cdot 3 ! \cdot 4 !}\\
&amp;=\dfrac{10.9 .8 .7 .5}{3.2 .1}\\
&amp;=4200 \end{align}$\dfrac{3 !+4 !}{5 !-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p3?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 6.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 6.1

Solutions of Question 5 of Exercise 6.1 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{(2 n) !}{n !}=2^n(1.3 .5 \ldots(2 n-1))$\begin{align}\dfrac{(2 n) !}{n !}&amp;=\dfrac{1}{n !}[(2 n)(2 n-1)(2 n-2) \\
&amp;=(2 n-3)(2 n-4)(2 n-5) \ldots(2 n-(2 n-4))\\
&amp;(2 n-(2 n-3))(2 n-(2 n-2))(2 n-(2 n-1))]\end{align}$2 n$\begin{align}\dfra…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 6.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 6.1

Solutions of Question 5 of Exercise 6.1 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 6.2

Solutions of Question 1 and 2 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$^6 P_6$\begin{align}^6 P_6&amp;=\dfrac{6 !}{(6-6) !}\\
&amp;=6 !=720\end{align}$^{20} P_2$\begin{align}^{20} P_2&amp;=\dfrac{20 !}{(20-2) !}\\
&amp;=\dfrac{20.19 .18 !}{18 !}\\
&amp;=20 \times 19=380\end{align}$^{16} P_3$\begin{align}^{16} P_3&amp;=\dfr…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 and 15 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p10?rev=1737476038&amp;do=diff</link>
        <description>Question 14 and 15 Exercise 6.2

Solutions of Question 14 and 15 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\dfrac{(n-1) !}{2}=\dfrac{(5-1) !}{2}=\dfrac{24}{2}=12 $$$7$$7$$6 !$$6$$5!$$2 !=2$$7$$$2 \times 5 !=240$$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 6.3

Solutions of Question 1 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$^n C_2=36$$n$\begin{align}&amp;^n C_2=36\\
&amp; \Rightarrow \dfrac{n !}{(n-2) ! 2 !}=36 \\
&amp; \Rightarrow \dfrac{n(n-1)(n-2) !}{(n-2) ! \cdot 2}=36 \\
&amp; \Rightarrow n(n-1)=72 \\
&amp; \Rightarrow n^2-n-72=0 \\
&amp; \Rightarrow n^2-9 n+8 n-72=0\\
&amp; \Rightar…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 6.3

Solutions of Question 9 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$8$$6$$7$$7$$6.$$=7+6=13$${ }^7 C_4$${ }^6 C_4$\begin{align}{ }^7 C_4 \cdot{ }^6 C_4&amp;=\dfrac{7 !}{(7-4) ! 4 !} \cdot \dfrac{6 !}{(6-4)}\\\
&amp;= 525\end{align}$8$$6$$7$$7$$6$$=7+6=13$$3,4,5,6$$6$\begin{align}{ }^7 C_2 \cdot{ }^6 C_6&amp;=\dfrac{7 !}…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 6.3

Solutions of Question 9 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 6.4

Solutions of Question 1 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$S=\{1,2,3,4,5,6\}$$5$$5$\begin{align}A&amp;=\{5\}\\
P(A)&amp;=\dfrac{n(A)}{n(S)}\\
&amp;=\dfrac{1}{6} \end{align}$S=\{1,2,3,4,5,6\}$$1$$1$\begin{align}B&amp;=\{\}\\
&amp;=\phi \text{then}\\
P(B)&amp;=\dfrac{n(B)}{n(S)}\\
&amp;=\dfrac{0}{6}\\
&amp;=0\end{align}$S=\{1,2,3,4,…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 6.4

Solutions of Question 7 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.\begin{align}S&amp;=\{(i, j) ; i, j=1,2,3,4,5,6\}\\
&amp;=\left[\begin{array}{llllll}
(1,1) &amp; (1,2) &amp; (1,3) &amp; (1,4) &amp; (1,5) &amp; (1,6) \\
(2,1) &amp; (2,2) &amp; (2,3) &amp; (2,4) &amp; (2,5) &amp; (2,6) \\
(3,1) &amp; (3,2) &amp; (3,3) &amp; (3,4) &amp; (3,5) &amp; (3,6) \\
(4,1) &amp; (4,2) &amp; (…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 6.5

Solutions of Question 1 and 2 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$A$$B$$P(A)=\dfrac{2}{5}, P(B)=\dfrac{2}{5}$$P(A \cup B)=\dfrac{1}{2}$$P(A \cap B)$\begin{align}
 P(A \cup B)&amp;=P(A)+P(B)-P(A \cap B) \\
 \Rightarrow P(A \cap B)&amp;=P(A)+P(B)-P(A \cup B)
\end{align}$P(A), P(B)$$P(A \cup B)$$$P(A \cap…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 6.5

Solutions of Question 10 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$20$$10$$5$$3$$2$$=20$$=10$$=5$$=3$$=15$$=5$$=10$$=3$$=22$$E$$a A$$B$$2$\begin{align}n(S)&amp;={ }^{30} C_2\\
&amp;=435\\
P(A)&amp;=\dfrac{^{20} C_2}{^{30} C_2}\\
&amp;=\dfrac{190}{435}=\dfrac{38}{87}\\
P(B)&amp;=\dfrac{^{22} C_2}{^{30} C_2}\\
&amp;=\dfrac{231}{43…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Review Exercise 6

Solutions of Question 11 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$n(S)=4$$$\dfrac{1}{4}$$$\quad P( orange )=\dfrac{1}{4}$$$\dfrac{1}{4}$$\dfrac{1}{4}$\begin{align}P(\operatorname{Red})&amp;=\dfrac{1}{4}\\
P( Green )&amp;=\dfrac{1}{4}\end{align}$P(R \cap G)=\phi$$R$$G$\begin{align}\boldsymbol{P}( Red o…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 7.1

Solutions of Question 1 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2+4+6+\cdots+2 n=n(n+1)$$n=1$$$2=1(1+1)=2 $$$n=1$$n=k$$$2+4+6+\cdots+2 k=k(k+1)....(i)$$$n=k+1$$(k+1)^{t h}$$$a_{k+1}=\mathbf{2}(k+1)=2 k+2 $$$k+1$\begin{align}2+4+6+\cdots+2 k+2(k+1)&amp; =k(k+1)+2(k+1) \\
&amp; =(k+1)[k+2] \\
&amp; =(k+1)(k+1+1)\end{a…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p15?rev=1737476038&amp;do=diff</link>
        <description>Question 15 Exercise 7.1

Solutions of Question 15 of Exercise 7.1 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$a+b$$a^n-b^n$$n$$n$$n=2 n, \quad m \in \mathbb{Z}^{+}$$m=1$$$a^{2 n}-b^{2 m}=a^2-b^2=(a+b)(a-b)$$$\Rightarrow(a+b)$$a^2-b^2$$m=1$$n=2$$m=k$$$a^{2 k}-b^{2 k}=Q(a+b)$$$Q$$m=k+1$\begin{align}a^{2(k+1)}-b^{2(k-1)} &amp; =a^{2 k+2}-b^{2 k+2} \\
&amp; =…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 7.2

Solutions of Question 1 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(x^2-\dfrac{1}{y})^4$\begin{align}(x^2-\dfrac{1}{y})^4&amp;=(x^2)^4+{ }^4 C_1(x^2)^3(-\dfrac{1}{y})+ \\
&amp; { }^4 C_2(x^2)^2(-\dfrac{1}{y})^2+{ }^4 C_3(x^2)(-\dfrac{1}{y})^3 + { }^4 C_4(-\dfrac{1}{y})^4 \\
&amp; =x^8- \dfrac{4x^6}{y}+\dfrac{6x^4}{y^2}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p11?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p11?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Exercise 7.2

Solutions of Question 11 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(1+x)^n$$\left(\begin{array}{l}n \\ r\end{array}\right)=\mathrm{C}_r$$\mathrm{C}_1+2 \mathrm{C}_2 x+3 \mathrm{C}_3 x^2+\ldots \ldots . .+\mathrm{nC}_{\mathrm{n}} x^{\mathrm{n}-1}=\mathrm{n}(1+x)^{\mathrm{n}-1}$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 Exercise 7.3

Solutions of Question 1 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\frac{1}{2}$$$
\begin{aligned}
&amp; (1-x)^{\frac{1}{2}}=1+\frac{1}{2} x+ \\
&amp; \frac{\frac{1}{2}\left(-\frac{1}{2}-1\right)}{2 !}(-x)^2
\end{aligned}
$$$$
\begin{aligned}
&amp; +\frac{-\frac{1}{2}\left(-\frac{1}{2}-1\right)\left(-\frac{1}{2}-2\right…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p12?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p12?rev=1737476039&amp;do=diff</link>
        <description>Question 14 Exercise 7.3

Solutions of Question 14 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x$$p x^p-q x^q=(p-q) x^{p+q}$$x$$x=1+h$$h \longrightarrow 0$$$
p x^p-q x^q=p(1+h)^p-q(1+h)^q
$$$$
\begin{aligned}
&amp; p x^p-q x^q \\
&amp; =p(1+p h+\text { higher powers h) } \\
&amp; -q(1+q h+\text { higher powcrs } h) \\
&amp; \Rightarrow p x^p-q x^q=…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p5?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 7 &amp; 8 Review Exercise 7

Solutions of Question 7 &amp; 8 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$7^n-3^n$$n=1$$7^k-3^k=7-4=4$$n=1$$n=k&gt;1$$7^n-3^n=4 Q$$Q$$n=k+1$$$
\begin{aligned}
&amp; 7^{k+1}-3^{k+1}=7.7^k-3.3^k \\
&amp; =(4+3) \cdot 7^k-3.3^k \\
&amp; =4.7^k+3.7^k-3.3^k
\end{aligned}
$$$$
\begin{aligned}
&amp; =4.7^k+3\left[7^k-3^k\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p7?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 11 Review Exercise 7

Solutions of Question 11 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$\sin {{37}^{\circ }}\cos {{22}^{\circ }}+\cos {{37}^{\circ }}\sin {{22}^{\circ }}$\begin{align} \sin (\alpha +\beta )=\sin \alpha \cos \beta +\cos \alpha \sin \beta, \end{align}\begin{a…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p11?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 13, Exercise 10.1

Solutions of Question 13 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$r\,\,\sin \left( \theta +\phi  \right)$$\theta$$\phi$$4\sin \theta +3\cos \theta .$$4\sin \theta +3\cos \theta$$r\sin(\theta + \varphi)$$$4\sin \theta +3\cos \theta=r\cos\varphi\sin\theta+r\sin\varphi\cos\theta --- (1)$…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 10.2

Solutions of Question 1 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$\sin 2\theta ,\,\,\cos 2\theta$$\tan 2\theta$$\tan \theta =-\dfrac{1}{5}$$\theta$$\sin \theta =\dfrac{1}{\sqrt{26}}$$\cos \theta =\dfrac{-5}{\sqrt{26}}$\begin{align}\sin 2\theta &amp;=2\sin…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 and 9, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 8 and 9, Exercise 10.2

Solutions of Question 8 and 9 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\cos }^{4}}\theta $\begin{align}{{\cos}^{4}}\theta &amp;={{\left( {{\cos }^{2}}\theta  \right)}^{2}}\\
&amp;={{\left( \dfrac{1+\cos 2\theta }{2} \right)}^{2}}\\ 
&amp;=\dfrac{1+2\cos 2\theta +{{\cos }^{2}}2\theta }{4}\\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 10.3

Solutions of Question 1 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$2\sin 6x\sin x$$$-2\sin \alpha \sin \beta =\cos (\alpha +\beta )-\cos (\alpha -\beta ).$$$\alpha =6x$$\beta =x$\begin{align}-\,2\sin 6x\sin x&amp;=\cos (6x+x)-\cos (6x-x)\\
&amp;=\cos 7x-\cos x…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 10.3

Solutions of Question 5 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{20}^{\circ }}\cos {{40}^{\circ }}\cos {{60}^{\circ }}\cos {{80}^{\circ }}=\dfrac{1}{16}$$2\cos \alpha \cos \beta =\cos \left( \alpha +\beta  \right)+\cos \left( \alpha -\beta  \right)$\begin{align}L.H.S.&amp;=\cos {{20…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 &amp; 9, Review Exercise 10</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 8 &amp; 9, Review Exercise 10

Solutions of Question 8 &amp; 9 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \left( \dfrac{\pi }{4}-\theta  \right)\sin \left( \dfrac{\pi }{4}+\theta  \right)=\dfrac{1}{2}\cos 2\theta $$2\sin \alpha \sin \beta =\cos \left( \alpha -\beta  \right)-\cos \left( \alpha +\beta  \r…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 1.1

Solutions of Question 1 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
${{i}^{31}}$\begin{align}{{i}^{31}}&amp;=i\cdot{{i}^{30}}\\
&amp;=i\cdot{{\left( {{i}^{2}} \right)}^{15}}\\
&amp;=i\cdot{{\left( -1 \right)}^{15}} \quad \because i^2=-1\\
&amp;=i\cdot(-1)\\
&amp;=-i.\end{align}${{\left( -i \right)}^{6}}$\begin{align}
{{\left…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 1.1

Solutions of Question 7 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 7(i)
$11+12 i$$$z=11+12i$$\begin{align}|z|&amp;= \sqrt{(11)^2+(12)^2}\\
&amp;=\sqrt{265}\end{align}$|11+12 i|=\sqrt{265}$$(2+3 i)-(2+6 i)$$z=(2+3i)−(2+6i)$\begin{align}z&amp;=2+3i−2−6i\\
&amp;=-3i \end{align}\begin{align}
|z| &amp;= \sqrt{0^2+(-3)^2} \\
&amp;= \sqrt{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p1?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 1.2

Solutions of Question 1 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
$\operatorname{Re}(i z)=-\operatorname{Im}(z)$$$z=x+iy$$\begin{align}
iz&amp;=i(x+iy)\\
&amp;=ix-y\end{align}\begin{align}Re(iz)&amp;=-y\\
\implies Re(iz)&amp;=-Im(z)\end{align}$\operatorname{Im}(i z)=\operatorname{Re}(z)$$$z=x+iy$$\begin{align}iz&amp;=i(x+i…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p10?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 10, Exercise 1.2

Solutions of Question 10 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 10(i)
$z_{1}=-3+2 i$$$\left|z_{1}\right|=\left|-z_{1}\right|=\left|\overline{z_{!}}\right|=\left|-\overline{z_{!}}\right|.$$\begin{align}
|z_1| &amp;= \sqrt{(-3)^2 + (2)^2} \\ 
&amp;= \sqrt{9 + 4} = \sqrt{13} \,\, -- (1)
\end{align}\begin{align}
-z_…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 1.3

Solutions of Question 1 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
$z^{2}+169$\begin{align} 
&amp; z^{2} + 169 \\
= &amp; z^{2} - (13i)^2 \\
= &amp;(z + 13i)(z - 13i).
\end{align}$2 z^{2}+18$\begin{align}
&amp; 2z^2 + 18 \\
= &amp;2(z^2 - (3i)^2)\\ 
= &amp;2(z + 3i)(z - 3i)
\end{align}$3 z^{2}+363$\begin{align}
&amp; 3z^2 + 363 \\ …</description>
    </item>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 1.3

Solutions of Question 4 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 4(i)
$(1-i) z+(1+i) \omega=3 ; 2 z-(2+5 i) \omega=2+3 i$\begin{align}
&amp;(1-i) z+(1+i) \omega=3 \quad \cdots(1)\\
&amp;2 z-(2+5 i) \omega=2+3i \quad\cdots(2)
\end{align}$2$\begin{align}
&amp;(2-2i)z+(2+2i) \omega=6  \quad \cdots (3)
\end{align}$(1-i)$\b…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p1?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 1.4

Solutions of Question 1 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
$2+i 2 \sqrt{3}$$z=x+iy=2 + i 2 \sqrt{3}$\begin{align} 
r &amp; = \sqrt{x^2 + y^2} = \sqrt{2^2 + (2\sqrt{3})^2} \\
 &amp; = \sqrt{4 + 12} = \sqrt{16} = 4.
\end{align}\begin{align}
\alpha &amp; = \tan^{-1}\left|\frac{y}{x}\right| = \tan^{-1}\left|\fra…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p11?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 10, Exercise 1.4

Solutions of Question 10 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 10(i)
$Z$$E=(-50+100 i)$$I=(-6-2 i)$$E=(-50+100 i)$$I=(-6-2 i)$$$ E = I \times Z $$$$(-50+100 i)= (-6-2 i) \times Z $$\begin{align}
\implies Z &amp; = \dfrac{-50+100 i}{-6-2 i} \\
&amp; = \dfrac{(-50+100 i)(-6+2i)}{(-6-2 i)(-6+2i)}\\
&amp; = \dfrac{300-…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 8, Review Exercise

Solutions of Question 8 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sqrt{2}+i \sqrt{2}$$\theta=45^{\circ}$$$x= \sqrt{2} + i \sqrt{2}, \quad \theta=\dfrac{\pi}{4}.$$$x_{\max}$\begin{align}
&amp;x=x_{\max} e^{i\theta} \\
\implies &amp; \sqrt{2} + i \sqrt{2}=x_{\max} e^{i\dfrac{\pi}{4}} \\
\implies &amp; x_{\max} \left(\cos\dfr…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.1

Solutions of Question 1 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{lll}1 &amp; 3 &amp; 0 \\ 2 &amp; 0 &amp; 1\end{array}\right]$\begin{align}\text{Order of A}&amp;= 2\times 3\end{align}$B=\left[\begin{array}{ll}1 &amp; 2 \\ 2 &amp; 3 \\ 3 &amp; 4\end{array}\right]$\begin{align}\text{Order of B}&amp;= 3\times 2\end{align}$C…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 2.1

Solutions of Question 4 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$
A=\left[\begin{array}{ccc}
2 &amp; 0 \\
\sqrt{5} &amp; 6 \\
1 &amp; 9
\end{array}\right]$$$$
A^t=\begin{bmatrix}
2 &amp; \sqrt{5} &amp; 1 \\
0 &amp; 6 &amp; 9
\end{bmatrix}$$$$B=\left[\begin{array}{cccc}
1 &amp; 6 &amp; 2 &amp; 0
\end{array}\right] $$$$B^t=\left[\begin{array}{c}
1…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.2

Solutions of Question 1 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[a_{i j}\right]$$2 \times 2$$a_{i j}=\dfrac{i+3 j}{2}$\( a_{ij} = \dfrac{i + 3j}{2} \)\( i = 1, j = 1 \)\[
a_{11} = \dfrac{1 + 3 \cdot 1}{2} = \dfrac{1 + 3}{2} = \dfrac{4}{2} = 2
\]\( i = 1, j = 2 \)\[
a_{12} = \dfrac{1 + 3 \cdot 2}{2} …</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p13?rev=1737476039&amp;do=diff</link>
        <description>Question 13, Exercise 2.2

Solutions of Question 13 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $X$$Y$$2 X-Y=\left[\begin{array}{ccc}1 &amp; 6 &amp; -3 \\ 2 &amp; 1 &amp; 7\end{array}\right]$$X+3 Y=\left[\begin{array}{ccc}4 &amp; 3 &amp; 2 \\ 1 &amp; -3 &amp; 0\end{array}\right]$\begin{align*}
2X - Y = \begin{pmatrix} 1 &amp; 6 &amp; -3 \\ 2 &amp; 1 &amp; 7 \end{pmatrix} \cdots (i)\\…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.3

Solutions of Question 1 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}2 &amp; 3 &amp; 1 \\ 1 &amp; -1 &amp; 2 \\ 4 &amp; 1 &amp; 2\end{array}\right]$\begin{align*}
A &amp;= \left[\begin{array}{ccc}2 &amp; 3 &amp; 1 \\ 1 &amp; -1 &amp; 2 \\ 4 &amp; 1 &amp; 2\end{array}\right]\\
|A|&amp;=2(-2-2)-3(2-8)+1(1+4)\\
\implies |A|&amp;=-8+18+5\\
\implies |…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 2.3

Solutions of Question 7 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $(A B)^{-1}=B^{-1} A^{-1}$$A=\left[\begin{array}{ll}2 &amp; 1 \\ 8 &amp; 6\end{array}\right]$$B=\left[\begin{array}{ll}3 &amp; 2 \\ 0 &amp; 2\end{array}\right]$\begin{align*}
A &amp;= \left[\begin{array}{ll}2 &amp; 1 \\ 8 &amp; 6\end{array}\right] \\	
|A|&amp; = 12 - 8 = 4\\	…</description>
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        <title>Question 1, Exercise 2.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-5-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.5

Solutions of Question 1 of Exercise 2.5 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}1 &amp; 3 &amp; 5 \\ -6 &amp; 8 &amp; 3 \\ -4 &amp; 6 &amp; 5\end{array}\right]$\begin{align*}
&amp; \quad \left[\begin{array}{ccc}1 &amp; 3 &amp; 5 \\ -6 &amp; 8 &amp; 3 \\ -4 &amp; 6 &amp; 5\end{array}\right]\\
\sim &amp; \text{R}
\left[\begin{array}{ccc}
1 &amp; 3 &amp; 5 \\
0 &amp; …</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-5-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.5

Solutions of Question 3 of Exercise 2.5 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}0 &amp; -1 &amp; -1 \\ -1 &amp; 3 &amp; 0 \\ 1 &amp; -1 &amp; 4\end{array}\right]$$A A^{-1}=A^{-1} A=I$\begin{align*}
A&amp;=\left[ \begin{array}{ccc}
0 &amp; -1 &amp; -1  \\ 
-1 &amp; 3 &amp; 0  \\ 
1 &amp; -1 &amp; 4 
\end{array} \right]\\
|A|&amp;=0+1(-4)-1(1-3)\\
&amp;=-4+3\…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.6

Solutions of Question 1 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $ 2 x_{1}-3 x_{2}+4 x_{3}=0$$x_{1}-2 x_{2}+3 x_{3}=0$$4 x_{1}+x_{2}-6 x_{3}=0$\begin{align*}
&amp;2 x_{1}-3 x_{2}+4 x_{3}=0\cdots (i)\\
&amp;x_{1}-2 x_{2}+3 x_{3}=0\cdots (ii)\\
&amp;4 x_{1}+x_{2}-6 x_{3}=0\cdots (iii)\\
\end{align*}\begin{align*}
A &amp;= \le…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 2.6

Solutions of Question 9 and 10 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x-y+3 z=\alpha ; 3 x+y-5 z=\beta ;-5 x-5 y+21 z=\gamma$$\gamma \neq 2 \alpha-3 \beta$$2$$2$$3$$3$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 and 5, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/re-ex-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 4 and 5, Review Exercise

Solutions of Question 4 and 5 of Review Exercise of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left|\begin{array}{ccc}a+1 &amp; l &amp; l \\ l &amp; a+1 &amp; l \\ l &amp; l &amp; a+1\end{array}\right|=(a+1+2 l)(a+1-l)^{2}$\begin{align*}
L.H.S &amp;= \left|\begin{array}{ccc}a+1 &amp; l &amp; l \\ l &amp; a+1 &amp; l \\ l &amp; l &amp; a+1\end{array}\right|\\
&amp;=\left|\b…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.1

Solutions of Question 1 and 2 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{15}$$$a_{n}=3 n+1$$$$a_{n}=3 n+1$$\begin{align*}
a_1 &amp;= 3(1) + 1 = 3 + 1 = 4\\
a_2 &amp;= 3(2) + 1 = 6 + 1 = 7\\
a_3 &amp;= 3(3) + 1 = 9 + 1 = 10\\
a_4 &amp;= 3(4) + 1 = 12 + 1 = 13\\
\end{align*}\begin{align*}
a_{10} &amp;= 3(10) + 1 = 30…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 21 and 22, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 21 and 22, Exercise 4.1

Solutions of Question 21 and 22 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}$$\sqrt{2}, \sqrt{4}, \sqrt{6}, \sqrt{8}, \sqrt{10}, \ldots$$$\sqrt{2}, \sqrt{4}, \sqrt{6}, \sqrt{8}, \sqrt{10}, \ldots$$\begin{align*}
&amp;a_1=\sqrt{2 \cdot 1}, \\
&amp;a_2=\sqrt{4}=\sqrt{2 \cdot 2} \\
&amp;a_3=\sqrt{6}=\sqrt{2 \cdot 3}\\…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 4.2

Solutions of Question 1 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=4, d=3$$a_1= 4$$d=3$$$a_n = a_1 + (n - 1)d.$$\begin{align*}
a_2&amp;=4+(2-1)3=4+3=7\\
a_3 &amp;= 4+ (3-1) 3 = 4 + 6 = 10\\
a_4&amp;=4+(4-1)3=4+9=13
\end{align*}$a_1=4$$a_2=7$$a_3=10$$a_4=13$$a_1=7$$d=5$$a_1= 7$$d=5$$$a_n = a_1 + (n - 1)d.$$\begin{align*}
…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 16 and 17, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 16 and 17, Exercise 4.2

Solutions of Question 16 and 17 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $5$$17$$A_1$$A_2$$5$$17$$5$$A_1$$A_2$$17$$a_1=5$$a_4=17$$$a_n=a_1+(n-1)d.$$\begin{align*}
&amp;a_4 = a_1 + 3d \\
\implies &amp; 17=5+3d\\
\implies &amp; 3d=12\\
\implies &amp; \boxed{d=4}.\end{align*}\begin{align*}
A_1 &amp;= a_2= a_1+d \\
&amp;=5+4=9 \end{a…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.3

Solutions of Question 1 and 2 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $4+7+10+13+16+19+22+25$$4+7+10+13+16+19+22+25$$a_1=4$$d=7-4=3$$n=8$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d]\\
\implies S_8&amp;=\frac{8}{2}[2(4)+(8-1)(3)]\\
&amp;=4[8+7\times 3] = 116
\end{align}$a_{1}=2$$a_{n}=200$$n=100$$a_{1}=2$$a_{n}=200$$…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 25 and 26, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p12?rev=1737476039&amp;do=diff</link>
        <description>Question 25 and 26, Exercise 4.3

Solutions of Question 25 and 26 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$ 6000+70,000+...+a_{20}.$$$a_1=6,000$$d=70,000-6,000=64,000$$n=20$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d]\\
\implies S_{20}&amp; =\frac{20}{2}[2(6,000)+(20-1)(64,000)]\\
&amp; =10 \times [12,000+1,216,000]\\
&amp; =12,280,000.
\end{ali…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.4

Solutions of Question 1 and 2 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $5,20,100,500, \ldots$$5, 20, 100, 500, \ldots $\begin{align*}
\frac{20}{5} = 4\neq \frac{100}{20} = 5.\end{align*}$5, 20, 100, 500, \ldots $\begin{align*}
r_1&amp; =\frac{20}{5} = 4\\
r_2&amp;=\frac{100}{20} = 5\\
r_3&amp;=\frac{500}{100} = 5.
\end{…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 30, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p15?rev=1737476039&amp;do=diff</link>
        <description>Question 30, Exercise 4.4

Solutions of Question 30 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $=a_1= 1$$=a_2= 3$$=a_3=3\times 3 = 9$$=a_4=3\times 9 = 27$$=a_5=3\times 27 = 81$$81$$a_1=1$$r=3$$a_5=?$$$a_n=a_1 r^{n-1}.$$\begin{align*}
a_5&amp;=a_1 r^4 \\
&amp;=(1)(3)^4 = 81
\end{align*}$$S_n=a_1+a_2+a_3+a_4+a_5.$$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.5

Solutions of Question 1 and 2 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $16+16+16+\ldots$$a_1=16$$r=\dfrac{16}{16}=1$$r\neq 1$\begin{align*}
&amp;16+16+16+\ldots \text{ to 11 terms}\\
=&amp;11(16) \\
=&amp; 176
\end{align*}$75+15+3+...$$75+15+3+...$$a_1= 75$$r = \frac{15}{75} = \frac{1}{5}$$n = 10$$n$$$ S_n = \frac{a_1 \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p9?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 16, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 16, Exercise 4.5

Solutions of Question 16 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $80 ft$$90\%$$a_1$$a_1 r$$a_1 r^2$$=a_1= 80 ft$$r=90% = \frac{90}{100} =0.9$$A$\begin{align}
A &amp;= a_1+a_1r+a_1r^2+... \\
&amp; = \frac{a_1}{1-r} \\
&amp; = \frac{80}{1-0.9}\\
&amp;= 800
\end{align}$800 ft$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p1?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.6

Solutions of Question 1 and 2 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{9}, \frac{1}{12}, \frac{1}{15}, \cdots \quad 7$$$\frac{1}{9}, \frac{1}{12}, \frac{1}{15}, \cdots \text{ is in H.P.}$$$$9, 12, 15, ... \text{ is in A.P.}$$$a_1=9$$d=12-9=3$$a_7=?$$$
a_n=a_1+(n-1)d.
$$\begin{align*}
a_7&amp;=9+(6)(3) …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 12, Exercise 4.6

Solutions of Question 12 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1}{3}$$\dfrac{1}{11}$$H_1, H_2, H_3, H_4$$H.Ms$$\dfrac{1}{3}$$\dfrac{1}{11}$$$\dfrac{1}{3},H_1, H_2, H_3, H_4, \dfrac{1}{11} \text{ are in H.P.}$$$$\quad 3,\dfrac{1}{H_1},\dfrac{1}{H_2}, \dfrac{1}{H_3}, \dfrac{1}{H_4},11 \text{ are in A.P.}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p1?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.7

Solutions of Question 1 and 2 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=1}^{5} \frac{1}{2 k}$\begin{align*}
\sum_{k=1}^{5} \frac{1}{2k} &amp;= \frac{1}{2(1)} + \frac{1}{2(2)} + \frac{1}{2(3)} + \frac{1}{2(4)} + \frac{1}{2(5)}\\
&amp;= \frac{1}{2} + \frac{1}{4} + \frac{1}{6} + \frac{1}{8} + \frac{1}{10}\\
&amp;= …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p15?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 29 and 30, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p15?rev=1737476040&amp;do=diff</link>
        <description>Question 29 and 30, Exercise 4.7

Solutions of Question 29 and 30 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$1+4 x+7 x^{2}+10 x^{3}+\ldots$$\[
1 + 4x + 7x^2 + 10x^3 + \ldots
\]\[
1 \times 1 + 4 \times x + 7 \times x^2 + 10 \times x^3 + \ldots
\]\(1, 4, 7, 10, \ldots\)\(a = 1\)\(d = 4 - 1 = 3\)\(1, x, x^2, x^3, \ldots\)\(1\)\(r = x\)\[
S_{\…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.8

Solutions of Question 1 and 2 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3+7+13+21+\ldots$$n$$$ S_{n}=3+7+13+21+31+\ldots +T_{n} $$$$ S_{n}=3+7+13+21+\ldots +T_{n-1}+T_{n}.$$\begin{align*}
S_{n}-S_{n}&amp; =3+7+13+21+31+\ldots +T_{n}  \\
&amp; -\left(3+7+13+21+\ldots +T_{n-1}+T_{n}\right)
\end{align*}\begin{align*}
\…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, 14 and 15, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 13, 14 and 15, Exercise 4.8

Solutions of Question 13, 14 and 15 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{5 \cdot 11}+\frac{1}{7 \cdot 13}+\frac{1}{9 \cdot 15}+\ldots \ldots$$n$$T_k$$k$\begin{align*}
T_k &amp;= \frac{1}{(2k+3)(2k+9)}.
\end{align*}\begin{align*}
\frac{1}{(2k+3)(2k+9)} = \frac{A}{2k+3} + \frac{B}{2k+9} \ldots …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p1?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Exercise 5.1

Solutions of Question 1 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
$2 x^{3}+3 x^{2}-4 x+1$$x+2$$p(x)=2 x^{3}+3 x^{2}-4 x+1$$x-c=x+2 \implies c=-2$\begin{align*}
\text{Remainder} &amp; = p(c) = p(-2) \\
&amp; = 2(-2)^{3}+3 (-2)^{2}-4 (-2)+1 \\
&amp; = -16+12+8+1 \\
&amp;= 5.
\end{align*}$x^{4}+2 x^{3}-x^{2}+2 x+3$$x-2$\( p(x…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 10, Exercise 5.1

Solutions of Question 10 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 10
$\left(x^{3}+11 x^{2}+34 x+24\right)$$(x+1)$$p(x)=x^{3}+11 x^{2}+34 x+24$\begin{align}
\begin{array}{r|rrrr}
-1 &amp; 1 &amp; 11 &amp; 34 &amp; 24 \\
&amp; \downarrow  &amp;  -1 &amp; -10 &amp; -24 \\
\hline
&amp; 1 &amp; 10 &amp; 24 &amp;  0 \\
\end{array}\end{align}$$ p(x) = (x+1)(x^2+10…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-2-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 5.2

Solutions of Question 1 and 2 of Exercise 5.2 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y^{3}-7 y-6$$f(y)=y^{3}-7 y-6$\begin{align*}
f(-1)&amp;=(-1)^{3}-7 (-1)-6 \\
&amp;= -1+7-6 =0.
\end{align*}$y+1$$f(y)$\begin{align}
\begin{array}{r|rrrr}
-1 &amp; 1 &amp; 0 &amp; -7 &amp; -6 \\
&amp; \downarrow  &amp;  -1 &amp; 1 &amp; 6 \\
\hline
&amp; 1 &amp; -1 &amp; -6 &amp;  0 \\
\end{array}\end…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-2-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 5.2

Solutions of Question 7 and 8 of Exercise 5.2 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x^{3}-15 x^{2}+27 x-10$$\dfrac{1}{2}$\( f(x) \)\( x - \frac{1}{2} \)\begin{align}
\begin{array}{r|rrrr}
\frac{1}{2} &amp; 2 &amp; -15 &amp; 27 &amp; -10 \\
&amp;   &amp; 1   &amp; -7 &amp; 10 \\
\hline
&amp; 2 &amp; -14 &amp; 20 &amp; 0 \\
\end{array}
\end{align}\begin{align*}
f(x) &amp;= \left…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Exercise 5.3

Solutions of Question 1 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1
$x$$x+3$$x+3+7=x+10$$120 cm^3$\begin{align*}
&amp; x(x+3)(x+10)=120 \\
\implies  &amp; x(x^2+3x+10x+30)-120=0\\
\implies &amp; x^3+13x^2+30x-120=0.
\end{align*}$$p(x)=x^3+13x^2+30x-120$$\begin{align*}
p(2)&amp;=2^3+13(2)^2+30(2)-120 \\
&amp;=8+52+60-120 =0
\end{ali…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 6, Exercise 5.3

Solutions of Question 6 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 6
$y^3-2y^2-y+2$$y-2$$=p(y)=y^3-2y^2-y+2$$y-2$$y-2$$p(y)$$2$$p(y)$\[
\begin{array}{r|rrrr}
2 &amp; 1 &amp; -2 &amp; -1 &amp; 2 \\
&amp; \downarrow   &amp; 2 &amp; 0 &amp; -2 \\
\hline
&amp; 1  &amp; 0  &amp; -1 &amp; 0 \\
\end{array}
\]\begin{align*}
p(y) &amp; = (y-2)(y^2-1) \\
&amp; = (y-2)(y+1)(y-1)…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 8, Review Exercise

Solutions of Question 8 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 8
$y^{3}+6 y^{2}-y-30$$(y-2)$$(y+3)$$p(y)=y^{3}+6 y^{2}-y-30$$(y-2)$$(y+3)$$p(y)$$2$$-3$$p(y)$\[
\begin{array}{r|rrrr}
2 &amp; 1 &amp; 6 &amp; -1 &amp; -30 \\
 &amp; \downarrow   &amp; 2  &amp; 16 &amp; 30  \\
\hline
-3 &amp; 1  &amp; 8  &amp; 15 &amp; 0 \\
 &amp; \downarrow   &amp; -3  &amp; -15 &amp;  …</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 8, Review Exercise

Solutions of Question 8 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 8
$y^{3}+6 y^{2}-y-30$$(y-2)$$(y+3)$</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Exercise 8.1

Solutions of Question 1 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos (\alpha \pm \beta), \sin (\alpha \pm \beta)$$\tan (\alpha \pm \beta)$$\alpha=180^{\circ}, \beta=60^{\circ}$$\alpha=180^{\circ}$$\beta=60^{\circ}$\begin{align*}
 \cos (\alpha + \beta) &amp; = \cos \alpha \cos \beta - \sin \alpha \sin \beta \…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p13?rev=1737476040&amp;do=diff</link>
        <description>Question 14, Exercise 8.1

Solutions of Question 14 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\theta$$\sin \theta$$\cos \theta$$\alpha$\begin{align*}
&amp;\tan\alpha = \frac{\overline{BC}}{\overline{AB}} \\
\implies &amp;\tan\alpha = \frac{3}{3} = 1 \\
\implies &amp;\alpha = \tan^{-1}(1) = 45^\circ
\end{align*}$45^\circ$$\theta$\begin{align*}
…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p1?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, 2 and 3 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, 2 and 3 Exercise 8.2

Solutions of Question 1, 2 and 3 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $P(-3,4)$$\theta$$\theta$$\cos 2 \theta$$\sin 2 \theta$$2 \theta$$x=-3$$y=4$\begin{align*}
r&amp;= \sqrt{(-3)^2+4^2} \\
&amp;=\sqrt{25} = 5.
\end{align*}$$\sin\theta = \frac{4}{5} \text{ and } \cos\theta = -\frac{3}{5}.$$\begin{align…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p12?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(xix, xx, xxi &amp; xxii)  Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p12?rev=1737476040&amp;do=diff</link>
        <description>Question 8(xix, xx, xxi &amp; xxii)  Exercise 8.2

Solutions of Question 8(xix, xx, xxi &amp; xxii) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\frac{\sin 2 \alpha}{\sin \alpha}-\frac{\cos 2 \alpha}{\cos \alpha}=\sec \alpha$$\begin{align*}
LHS &amp;= \dfrac{\sin 2 \alpha}{\sin \alpha}-\frac{\cos 2 \alpha}{\cos \alpha}\\
&amp;= \dfrac{\sin 2 \alpha …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p1?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1(i, ii, iii &amp; iv)  Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1(i, ii, iii &amp; iv)  Exercise 8.3

Solutions of Question 1(i, ii, iii &amp; iv) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$4 \sin 16x \cos 10x $$\begin{align*}
&amp;4 \sin 16x \cos 10x \\
&amp; = 2 (2\sin 16x \cos 10x) \\
&amp;= 2[\sin(16x+10x)+\sin(16x-10x)]\\
&amp;= 2[\sin (26x)+\sin(6x)]
\end{align*}$10 \cos 10y \cos 6y$\begin{align*}
&amp;10 \…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 4 Exercise 8.3

Solutions of Question 4 of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos 80^{\circ} \cos 60^{\circ} \cos 40^{\circ} \cos 20^{\circ}=\dfrac{1}{16}$\begin{align*}
LHS &amp;= \cos 80^\circ \cos 60^\circ \cos 40^\circ \cos 20^\circ \\
&amp;= \cos 80^\circ \left(\frac{1}{2}\right) \cos 40^\circ \cos 20^\circ \\
&amp;= \frac{1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p9?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 10, Review Exercise

Solutions of Question 10 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin (16 x)=16 \sin (x) \cos (x) \cos (2 x) \cos (4 x) \cos (8 x)$\begin{align*}
RHS&amp;=16 \sin (x) \cos (x) \cos (2 x) \cos (4 x) \cos (8 x) \\
&amp;= 8(2 \sin (x) \cos (x) )\cos (2 x) \cos (4 x) \cos (8 x) \\
&amp;=  8 \sin2 (x) \cos (2 x) \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p1?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Exercise 9.1

Solutions of Question 1 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=2-2 \operatorname{Cos} \theta$\begin{align*} -1 \leq \operatorname{Cos} \theta \leq 1 \end{align*}$-2$\begin{align*} &amp; 2 \geq -2 \operatorname{Cos} \theta \geq -2 \end{align*}$2$\begin{align*}
 &amp; 4 \geq 2-2 \operatorname{Cos} \theta \geq 0 \\
…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p11?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p11?rev=1737476040&amp;do=diff</link>
        <description>Question 10, Exercise 9.1

Solutions of Question 10 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $ V(t)=a \operatorname{Sin}(k(t-d))+c$$56 \mathrm{~Hz} A C$$k$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p10?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10(xi-xv), Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 10(xi-xv), Review Exercise

Solutions of Question 10(xi-xv) of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
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