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    <image rdf:about="https://beta.mathcity.org/_media/logo.png">
        <title>MathCity.org Beta</title>
        <link>https://beta.mathcity.org/</link>
        <url>https://beta.mathcity.org/_media/logo.png</url>
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    <item rdf:about="https://beta.mathcity.org/fsc/kpk_fsc_part_1?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc Part 1 (KPK Boards)</title>
        <link>https://beta.mathcity.org/fsc/kpk_fsc_part_1?rev=1737476036&amp;do=diff</link>
        <description>FSc Part 1 (KPK Boards)

AVAILABLE HERE

[FSc Part 2 KPTP]
Notes of FSc Part 1 of “A Textbook of Mathematics For Class XI” published by Khyber Pakhtunkhwa Textbook Board, Peshawar. We are posting the notes chapter-wise. These notes are shared as open educational resources. This page will be continuously updated.$P(z)$$(\sum)$$\sum n$$\sum n^2$$\sum n^3$$n$$n$$$\frac{a}{a(a+d)}+\frac{a}{(a+d)(a+2d)}+...$$$^nP_r$$^nC_r=\left(\begin{smallmatrix}n\\ r\end{smallmatrix} \right)=\frac{n!}{r!(n-r)!}$$P(…</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc Part 2 (KPK Boards)</title>
        <link>https://beta.mathcity.org/fsc/kpk_fsc_part_2?rev=1737476036&amp;do=diff</link>
        <description>FSc Part 2 (KPK Boards)

[A Textbook of Mathematics For Class XII]
Notes of FSc Part 2 of “A Textbook of Mathematics For Class XII” published by Khyber Pakhtunkhwa Textbook Board, Peshawar. We are posting the notes chapter-wise. These notes are shared as open educational resources. This page will be continuously updated.$y=x^n$$y=(ax+b)^n$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 04: Quadratic Equations</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch04?rev=1737476035&amp;do=diff</link>
        <description>Chapter 04: Quadratic Equations

[Chapter 04: Quadratic Equations]
Notes (Solutions) of Chapter 04: Quadratic Equations, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Textbook Board, Lahore.

Contents &amp; summary

	*  Introduction
		*  Solutions of Quadratic Equations</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 03: General Theorem, Intermediate Forms</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch03_general_theorem_intermediate_forms?rev=1737476035&amp;do=diff</link>
        <description>Chapter 03: General Theorem, Intermediate Forms

[BSc Calculus 3rd Chapter]

What is in the this chapter?

	*  Rolle&#039;s theorem
	*  Geometrical interpretation of Rolle&#039;s theorem
	*  The mean value theorems
	*  Another form of mean value theorem
	*  Increasing and decreasing functions$\frac{0}{0}$$\frac{\infty}{\infty}$$0\times \infty$$\infty \times 0$$\infty-\infty$$0^\infty, 1^\infty, \infty^0$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 11: The Laplace Transform</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch11_the_laplace_transform?rev=1737476035&amp;do=diff</link>
        <description>Chapter 11: The Laplace Transform

Notes of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin. This book is published by Ilmi Kitab Khana, Lahore - PAKISTAN. Solutions of Chapter 11: The Laplace Transform are given here in pdf form.  $f$$[0,\infty)$$f$$\mathcal{L}(f)$$F$$
provided the above improper integral converges. We have $</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 03: Matrices and Determinants</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch03?rev=1737476035&amp;do=diff</link>
        <description>Chapter 03: Matrices and Determinants

[Chapter 03: Matrices and Determinants]

Notes (Solutions) of Chapter 03: Matrices and Determinants, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

Contents &amp; summary

	*  Introduction$2\times2$$2\times2$$2\times2$$n\geq 3$$n\geq 3$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch06?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 06: Sequences and Series</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch06?rev=1737476035&amp;do=diff</link>
        <description>Chapter 06: Sequences and Series

[Chapter 06: Sequences and Series]
Notes (Solutions) of Chapter 06: Sequences and Series, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

Contents &amp; summary

	*  Introduction
	*  Types of Sequences$l,m,n$$p$$q$$r$$$l(q-r)+m(r-p)+n(p-q)=0$$$a_1$$d$$$\begin{align}l=a_1+(p-1)d,\\ m=a_1+(q-1)d,\\ n=a_1+(r-1)d.\end{align}$$
Now $$\begin{align}L.H.S &amp;=  l(q-r)+m(r-p)+n(p-q)\\
&amp;= lq-lr+mr-mp+np-nq\\
&amp;=…</description>
    </item>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 09: Fundamentals of Trigonometry</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch09?rev=1737476036&amp;do=diff</link>
        <description>Chapter 09: Fundamentals of Trigonometry

[Chapter 09: Fundamentals of Trigonometry]
Notes (Solutions) of Chapter 09: Fundamentals of Trigonometry, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore. This chapter has four exercise and solutions of those exercises are given below which can be downloaded in PDF format or can be viewed online.$D^\circ M&#039;S&#039;&#039;$$45^\circ , 30^\circ , 60^\circ$$0^\circ , 90^\circ , 180^\circ , 270^\circ , 36…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Unit 01: Functions and Limits</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch01?rev=1737476036&amp;do=diff</link>
        <description>Unit 01: Functions and Limits

[Unit 01: Functions and Limits]
Notes (Solutions) of Unit 01: Functions and Limits, Calculus and Analytic Geometry, MATHEMATICS 12 (Mathematics FSc Part 2 or HSSC-II), Punjab Text Book Board Lahore. There are five exercises in this chapter. You can view online or download PDF. To view PDF, you must have PDF Reader installed on your system and it can be downloaded from $\lim_{x\to a}\frac{x^n-a^n}{x-a} = na^{n-1}$$\lim_{x\to0}\frac{\sqrt{x+a} - \sqrt{a}}{x} = \frac{…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Unit 03: Integration</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch03?rev=1737476036&amp;do=diff</link>
        <description>Unit 03: Integration

[Unit 03: Integration]
Notes (Solutions) of Unit 03: Integration, Calculus and Analytic Geometry, MATHEMATICS 12 (Mathematics FSc Part 2 or HSSC-II), Punjab Text Book Board Lahore. You can view online or download PDF. To view PDF, you must have PDF Reader installed on your system and it can be downloaded from Software section.$dy$$\delta{y}$$[f(x)]^n f&#039;(x)$$[f(x)]^{-1}f&#039;(x)$</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk?rev=1737476042&amp;do=diff">
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        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc Part 1 (Mathematics): KPK</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk?rev=1737476042&amp;do=diff</link>
        <description>FSc Part 1 (Mathematics): KPK

[A Textbook of Mathematics for Class XI]
&lt;lead&gt;A Textbook of Mathematics for Class XI is published by Khybar Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. The book has total of twelve (12) chapters. &lt;/lead&gt; 
&lt;callout type=“info” icon=“true</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Complex Analysis by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/complex-analysis-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Complex Analysis by M Usman Hamid

[Complex Analysis by M Usman Hamid]
We are really very thankful to Muhammad Usman Hamid for providing these notes and appreciates his effort to publish these notes on MathCity.org

It covers the one part of the syllabus of Complex Analysis paper of MSc Mathematics. See the contents of the notes given below to see the topics covered by these notes.$$
x^2+4=0, x^2+x+1=0 \text{ and } x^2-2x+3=0
$$$i=\sqrt{-1}$$i^2=-1$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 01: Real Numbers, Limits and Continuity</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch01_real_numbers_limits_and_continuity?rev=1737476035&amp;do=diff</link>
        <description>Chapter 01: Real Numbers, Limits and Continuity

[Chapter 01 of Calculus with Analytic Geometry]
Notes of the book Calculus with Analytic Geometry written by Dr. S. M. Yusuf and Prof. Muhammad Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN. 

The notes of this chapter is written by Prof. $\mathbb{R}$$\mathbb{R}$$\mathbb{R}$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 02: The Derivative</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch02_derivatives?rev=1737476035&amp;do=diff</link>
        <description>Chapter 02: The Derivative

[Chapter 02: The Derivative BSc Calculus]
Notes of the book Calculus with Analytic Geometry written by Dr. S. M. Yusuf and Prof. Muhammad Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN. 

Here are few online resource, which are very helpful to find derivative.</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 07: Plane Curves II</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch07_plane_curves_ii?rev=1737476035&amp;do=diff</link>
        <description>Chapter 07: Plane Curves II

Notes of the book Calculus with Analytic Geometry written by Dr. S. M. Yusuf and Prof. Muhammad Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN. 
[Asymptote]

Contents and summary

	*  Asymptotes: A straight line $l$ is called an asymptote for a curve $C$$l$$C$$l$$l$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 08: Analytic Geometry of Three Dimensions</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch08_analytic_geometry_of_three_dimensions?rev=1737476035&amp;do=diff</link>
        <description>Chapter 08: Analytic Geometry of Three Dimensions

Notes of the book Calculus with Analytic Geometry written by Dr. S. M. Yusuf and Prof. Muhammad Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN.

Contents &amp; Summary

	*  Distance between two points$\mathbb{R}^3$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 01: Complex Numbers</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch01_complex_numbers?rev=1737476035&amp;do=diff</link>
        <description>Chapter 01: Complex Numbers

[Chapter 01 Complex Numbers Methods]
Notes of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN. 

A complex number is an element $(x,y)$ of the set
$$
\mathbb{R}^2=\{(x,y): x,y \in \mathbb{R}\}
$$
obeying the following rules of addition and multiplication.$z_1=(x_1,y_1)$$z_2=(x_2,y_2)$$z_1+z_2= (x_1+x_2, y_1+y_2)$$z_1 z_2 = (x_1 x_2 - y_1 y_2, x_1 y_2+y_1 x_2)$$\mathbb{R}^2$$\mathbb{C}$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 02: Groups</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch02_groups?rev=1737476035&amp;do=diff</link>
        <description>Chapter 02: Groups

[Chapter 02: Groups]
Notes of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN.

Contents and summary

	*  Definition (axioms of group)
	*  Definition ( commutative group )
	*</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 10: Higher Order Linear Differential Equations</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch10_higher_order_linear_differential_equations?rev=1737476035&amp;do=diff</link>
        <description>Chapter 10: Higher Order Linear Differential Equations

Notes of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN.

Contents and summary

	*  Higher order linear differential equations</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 01: Number System</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch01?rev=1737476035&amp;do=diff</link>
        <description>Chapter 01: Number System

[Chapter 01: Number System]
Notes (Solutions) of Chapter 01: Number System, Textbook of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

Contents &amp; summary

	*  Rational numbers and irrational numbers$\mathbb{C}$$(x+iy)^n$$\left(\frac{x_1+iy_1}{x_2+iy_2}\right)^n, x_2+iy_2\neq 0$$\sqrt{-1}=i$$\sqrt{-1}$$i$$-i$$i$$-i$$-1$$i^2=-1$$\sqrt{-1}=i$$\sqrt{-1}$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 02: Sets, Functions and Groups</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch02?rev=1737476035&amp;do=diff</link>
        <description>Chapter 02: Sets, Functions and Groups

Notes (Solutions) of Chapter 02: Sets, Functions and Groups, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

[Chapter 02: Sets, Functions and Groups]

Contents &amp; summary

	*  Introduction$p\leftrightarrow q$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 05: Partial Fractions</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch05?rev=1737476035&amp;do=diff</link>
        <description>Chapter 05: Partial Fractions

[Chapter 05: Partial Fractions]
Notes (Solutions) of Chapter 05: Partial Fractions, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

Contents &amp; summary

	*  Introduction
	*  Rational Fraction$\frac {P(x)}{Q(x)}$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 07: Permutation, Combination and Probability</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch07?rev=1737476035&amp;do=diff</link>
        <description>Chapter 07: Permutation, Combination and Probability

[Chapter 07: Permutation , Combination and Probability]
Notes (Solutions) of Chapter 07: Permutation , Combination and Probability, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

Contents &amp; summary</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 08: Mathematical Induction and Binomial Theorem</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch08?rev=1737476036&amp;do=diff</link>
        <description>Chapter 08: Mathematical Induction and Binomial Theorem

[Chapter 08 Mathematical Induction and Binomial Theorem]
Notes (Solutions) of Chapter 08: Mathematical Induction and Binomial Theorem, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.$(a+x)^n$$(a+x)^n$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 10: Trigonometric Identities</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch10?rev=1737476036&amp;do=diff</link>
        <description>Chapter 10: Trigonometric Identities

[Chapter 10: Trigonometric Identities]
Notes (Solutions) of Chapter 10: Trigonometric Identities, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore. There are four exercise in this chapter.</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 11: Trigonometric Functions and their Graphs</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch11?rev=1737476036&amp;do=diff</link>
        <description>Chapter 11: Trigonometric Functions and their Graphs

[Chapter 11: Trigonometric Functions and their Graphs]
Notes (Solutions) of Chapter 11: Trigonometric Functions and their Graphs, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

Contents &amp; summary
$ y = \sin x$$-2\pi \hbox{ to } 2\pi$$ y = \cos x$$-2\pi \hbox{ to } 2\pi$$ y = \tan x$$-\pi \hbox{ to } \pi$$ y = \cot x$$-2\pi \hbox{ to } \pi$$ y = \sec x$$-2\pi \hbox{ to } 2\pi…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 12: Application of Trigonometry</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch12?rev=1737476036&amp;do=diff</link>
        <description>Chapter 12: Application of Trigonometry

[Chapter 12: Application of Trigonometry]
Notes (Solutions) of Chapter 12: Application of Trigonometry, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

Contents &amp; summary

	*  Introduction</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 13: Inverse Trigonometric Functions</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch13?rev=1737476036&amp;do=diff</link>
        <description>Chapter 13: Inverse Trigonometric Functions

[Chapter 13: Inverse Trigonometric Functions]
Notes (Solutions) of Chapter 13: Inverse Trigonometric Functions, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

Contents &amp; summary

	* ${\sin ^{ - 1}}A + {\sin ^{ - 1}}B = {\sin ^{ - 1}}\left( {A\sqrt {1 - {B^2}}  + B\sqrt {1 - {A^2}} } \right)$${\sin ^{ - 1}}A - {\sin ^{ - 1}}B = {\sin ^{ - 1}}\left( {A\sqrt {1 - {B^2}}  - B\sqrt {1 - {…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 14: Solutions of Trigonometric Equation</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_solutions/ch14?rev=1737476036&amp;do=diff</link>
        <description>Chapter 14: Solutions of Trigonometric Equation

[Chapter 14: Solutions of Trigonometric Equation]
Notes (Solutions) of Chapter 14: Solutions of Trigonometric Equation, Text Book of Algebra and Trigonometry Class XI (Mathematics FSc Part 1 or HSSC-I), Punjab Text Book Board, Lahore.

Contents &amp; summary
${\sin ^{ - 1}}A + {\sin ^{ - 1}}B = {\sin ^{ - 1}}\left( {A\sqrt {1 - {B^2}}  + B\sqrt {1 - {A^2}} } \right)$${\sin ^{ - 1}}A - {\sin ^{ - 1}}B = {\sin ^{ - 1}}\left( {A\sqrt {1 - {B^2}}  - B\sqr…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Unit 02: Differentiation</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch02?rev=1737476036&amp;do=diff</link>
        <description>Unit 02: Differentiation

[Unit 02: Differentiation]
Notes (Solutions) of Unit 02: Differentiation, Calculus and Analytic Geometry, MATHEMATICS 12 (Mathematics FSc Part 2 or HSSC-II), Punjab Text Book Board Lahore. You can view online or download PDF. To view PDF, you must have PDF Reader installed on your system and it can be downloaded from Software section.$f&#039;(x)$$x^n$$n \in \mathbb{Z}$$\frac{x+1}{x-1}$$x$$$
\begin{aligned}
\frac{d}{dx}\left(\frac{x+1}{x-1}\right) &amp;= \frac{(x-1)\frac{d}{dx}(x…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Unit 07: Vectors</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch07?rev=1737476036&amp;do=diff</link>
        <description>Unit 07: Vectors

[Unit 07: Vectors]

Notes (Solutions) of Unit 07: Vectors, Calculus and Analytic Geometry, MATHEMATICS 12 (Mathematics FSc Part 2 or HSSC-II), Punjab Text Book Board Lahore. You can view online or download PDF. To view PDF, you must have PDF Reader installed on your system and it can be downloaded from Software section.$u\cdot v$$u\times v$$u\cdot(v\times w)$</description>
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        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc/ICS Part 1 (Mathematics): PTB</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb?rev=1737476042&amp;do=diff</link>
        <description>FSc/ICS Part 1 (Mathematics): PTB

[Textbook of Algebra and Trigonometry Class XI]
&lt;lead&gt;Textbook of Algebra and Trigonometry Class XI is published by Punjab Textbook Board (PTB) Lahore, Pakistan. The book has total of 14 chapters.&lt;/lead&gt; 
One this page, we have posted Notes (Solutions), MCQs, short question, sample papers and old papers related to this subject. This book has wide scope and it is part of syllabus of Mathematics in FSc/ICS from all board (Board of Intermediate and Secondary Educa…</description>
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        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc/ICS Part 2 (Mathematics): PTB</title>
        <link>https://beta.mathcity.org/fsc-part2-ptb?rev=1737476042&amp;do=diff</link>
        <description>FSc/ICS Part 2 (Mathematics): PTB

[Calculus and Analytic Geometry, MATHEMATICS 12]
&lt;lead&gt;Calculus and Analytic Geometry, MATHEMATICS 12 (Mathematics FSc/ICS Part 2 or HSSC-II), Punjab Textbook Board (PTB) Lahore, Pakistan. There are total seven (7) units in this book.&lt;/lead&gt; 
One this page we have posted Notes (Solutions), MCQs, short question, sample papers and old papers related to this subject. This book has wide scope and it is part of syllabus of Mathematics in FSc/ICS from all board (Boar…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>FSc/ICS Part 1 (Mathematics): KPK</title>
        <link>https://beta.mathcity.org/math-11-kpk?rev=1737476042&amp;do=diff</link>
        <description>FSc/ICS Part 1 (Mathematics): KPK

[A Textbook of Mathematics for Class XI]
&lt;lead&gt;A Textbook of Mathematics for Class XI is published by Khybar Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. The book has total of twelve (12) chapters. &lt;/lead&gt; 
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematics 1 for FSc ICS (NBF)</title>
        <link>https://beta.mathcity.org/math-11-nbf?rev=1737476042&amp;do=diff</link>
        <description>Mathematics 1 for FSc ICS (NBF)

[A Textbook of Mathematics for Class XI]
&lt;lead&gt;Model Textbook of Mathematics for Class XI is published by National Book Foundation (NBF), Islamabad, Pakistan. NBF can be considered as Federal Textbook Board Islamabad. The book has total of nine (9) chapters. &lt;/lead&gt; 
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Matric</title>
        <link>https://beta.mathcity.org/matric?rev=1737476042&amp;do=diff</link>
        <description>Matric

&lt;callout type=“success” icon=“fa fa-info”&gt;
This is a new section. We need to do lot of work to complete this section. We will add notes of mathematics for 9th and 10th classes (general and science).
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Mathematics (Science Group)</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>PPSC General Information, Syllabus, Paper Pattern</title>
        <link>https://beta.mathcity.org/ppsc?rev=1737476042&amp;do=diff</link>
        <description>~~DISCUSSION~~

PPSC General Information, Syllabus, Paper Pattern

[PPSC]
Our aim is to give general information, syllabus and paper pattern of paper couducted by Punjab Public Service Commission (PPSC) for the post of Lecturer in Mathematics. This page might be helpful for other jobs as subject specialist or for public service commission of other provinces.</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Notes of Metric Spaces</title>
        <link>https://beta.mathcity.org/bsc/notes_of_metric_spaces?rev=1737476035&amp;do=diff</link>
        <description>Notes of Metric Spaces

These notes are related to Section IV of B Course of Mathematics, paper B. We are very thankful to Mr. Tahir Aziz for sending these notes.


   Name   Notes of Metric Space     Author  Prof. Shahzad Ahmad Khan       Send by  Tahir Aziz</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Notes of Vector Analysis</title>
        <link>https://beta.mathcity.org/bsc/notes_of_vector_analysis?rev=1737476035&amp;do=diff</link>
        <description>Notes of Vector Analysis

[Vector Ananlysis]
Notes of the vector analysis are given on this page. These notes are helpful for BSc or equivalent classes. These notes are written by Amir Taimur Mohmand of University of Peshawar.
&lt;wrap help&gt;The books of these notes is not known. If you know about the book, please inform us.&lt;/wrap&gt;$f$$P$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Notes of Fourier Series</title>
        <link>https://beta.mathcity.org/bsc/notes-fouries-series?rev=1737476035&amp;do=diff</link>
        <description>Notes of Fourier Series

These notes are provided  by Mr. Muhammad Ashfaq. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org
 Name  Notes of Fluid Mechanics   Author  Qayyum Ullah Khan</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Notes of Metric Spaces by Umer Asghar</title>
        <link>https://beta.mathcity.org/bsc/notes-of-metric-spaces-umer-asghar?rev=1737476035&amp;do=diff</link>
        <description>Notes of Metric Spaces by Umer Asghar

These notes are related to Section IV of B Course of Mathematics, paper B. We are very thankful to Mr. Umer Asghar for sending these notes.


   Name   Notes of Metric Space     Author  Mr. Umer Asghar       Pages   19 pages</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Notes of Number Theory by Umer Asghar</title>
        <link>https://beta.mathcity.org/bsc/notes-of-number-theory-by-umer-asghar?rev=1737476035&amp;do=diff</link>
        <description>Notes of Number Theory by Umer Asghar


These notes are very helpful to prepare one of the sections paper of mathematics for BSc. 
 Author:   Umer Asghar   Type:  Composed   Format:  PDF (1.14 mB)    Pages:   24  
Contents and Summary

	*  Divisibility</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory by Prof. Asghar Ali</title>
        <link>https://beta.mathcity.org/bsc/number-theory-by-prof-asghar-ali?rev=1737476035&amp;do=diff</link>
        <description>Number Theory by Prof. Asghar Ali

[Number Theory by M Asghar Ali]

We are very thankful to Prof. Asghar Ali for send these notes. These notes are very helpful to prepare BSc or ADS mathematics portion of Number Theory. Number theory is a subject in which students learn different concepts created on the set of integers. For example, the concept of divisibilty exists in the set of integer. Let a and b be any two integers suhc that $a\neq 0$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory by Prof. M. Tanveer</title>
        <link>https://beta.mathcity.org/bsc/number-theory-by-prof-m-tanveer?rev=1737476035&amp;do=diff</link>
        <description>Number Theory by Prof. M. Tanveer

[Number Theory by Prof. M. Tanveer]
These notes are very helpful to prepare one of the sections of mathematics for BSc. Also these notes can be used for other classes. 
 Author:   Prof. M. Tanveer   Type:  Handwritten   Format:  PDF (972 kB)    Pages:  $a,b, \in \mathbb{Z}$$a \neq 0$$a$$b$$c\in \mathbb{Z}$$b=ac$$a,b, \in \mathbb{Z}$$c \in \mathbb{Z}$$a$$b$$c | a$$c | b$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Vector Analysis by Hameed Ullah: Notes</title>
        <link>https://beta.mathcity.org/bsc/vector_analysis_by_hameed_ullah?rev=1737476035&amp;do=diff</link>
        <description>Vector Analysis by Hameed Ullah: Notes

[right triangle in semi circle]
Note of vector analysis by Hammed Ullah. These notes are send by Umer Asghar, we are very thankful to him for providing these notes. These notes are for helpful for undergraduate level (BSc or BS).
&lt;div&gt;
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 Name  Notes of vector analysis  &lt;div&gt;
&lt;/center&gt;
&lt;/div&gt;</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Definitions: FSc Part 1 (Mathematics): PTB by Aurang Zaib</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb/definitions-aurang-zaib?rev=1737476037&amp;do=diff</link>
        <description>Definitions: FSc Part 1 (Mathematics): PTB by Aurang Zaib

Definitions from Textbook of Algebra and Trigonometry Class XI, published by Punjab Textbook Board (PTB) Lahore, Pakistan. We are very thankful to Aurang Zaib for his valuable contribution.

Chapter 01: Number System
\( \dfrac{p}{q} \)\( p, q \in \mathbb{Z} \)\( q \neq 0 \)\( \dfrac{3}{4} \)\( \dfrac{7}{2} \)\( \sqrt{2} \)\( \pi \)\( \mathbb{R} \)\( 0.25 \)\( 3.75 \)\( 0.3333... \)\( 1.234234... \)\( \pi \)\( 3.1415... \)\( \sqrt{2} \)\(…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Definitions: Mathematics 11: PTB by Muzzammil Subhan</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb/definitions-muzzammil-subhan?rev=1737476037&amp;do=diff</link>
        <description>Definitions: Mathematics 11: PTB by Muzzammil Subhan

Definitions from Textbook of Algebra and Trigonometry Class XI, published by Punjab Textbook Board (PTB) Lahore, Pakistan. We are very thankful to Muzzammil Subhan for his valuable contribution. Download or view PDF for all definitions. Samples is given below$y=2^x$$y=e^x$$f(x)=\log_a x$$f(x)=\log_e x$$y$$x$$y$$y=x^2+3x$$x^2+xy+y^2=4$$f(-x)=f(x)$$f(-x)=-f(x)$</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Solution and Area of Oblique Triangle</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb/solution-and-area-of-oblique-triangle?rev=1737476037&amp;do=diff</link>
        <description>Solution and Area of Oblique Triangle

These are the common formulas used in Chapter 12 of Textbook of Algebra and Trigonometry Class XI, Punjab Textbook Board Lahore. This handout is very helpful to remember the formulas. All these formulas are given for real valued and defined trigonometric functions. A PDF file can be downloaded for high quality printing and a word file is also given if you wish to modify the contents or credit as you need.
&lt;panel title=$a^2=b^2+c^2-2bc\cos \alpha$$b^2=c^2+a^…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Trigonometric Formulas</title>
        <link>https://beta.mathcity.org/fsc-part1-ptb/trigonometric-formulas?rev=1737476037&amp;do=diff</link>
        <description>Trigonometric Formulas

These are the common formulas used in Chapter 9 to 14 of Textbook of Algebra and Trigonometry Class XI, Punjab Textbook Board Lahore. This handout is very helpful to remember the formulas. All these formulas are given for real valued and defined trigonometric functions. A PDF file can be downloaded for high quality printing and a word file is also given if you wish to modify the contents or credit as you need.
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${{\sin }^{2}}\theta +{{\cos }^{2}}\theta =1$$1+{{\tan…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Definitions: Mathematics 12: PTB by Muzzammil Subhan</title>
        <link>https://beta.mathcity.org/fsc-part2-ptb/definitions-muzzammil-subhan?rev=1737476037&amp;do=diff</link>
        <description>Definitions: Mathematics 12: PTB by Muzzammil Subhan

Definitions from Calculus and Analytic Geometry, MATHEMATICS 12, published by Punjab Textbook Board (PTB) Lahore, Pakistan. We are very thankful to Muzzammil Subhan for his valuable contribution. Download or view PDF for all definitions. Samples is given below$P(x)=a_0 x^0+a_1 x^1+a_2 x^2+\ldots . .+a_{n-1} x^{n-1}+a_n x^n$$n \in W$$a_0, a_1, a_2, \ldots, a_n \in R$$f(x)=a x+b$$a, b \in R$$a \neq 0$$f(x)=x$$f(x)=c$$c \in R$$\frac{P(x)}{Q(x)}$…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Advanced Analysis: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/advanced-analysis-handwritten-notes?rev=1737476041&amp;do=diff</link>
        <description>Advanced Analysis: Handwritten Notes

[Advanced Analysis: Handwritten Notes]
These notes are provided by Mr. Anwar Khan. We are really very thankful to Mr. Anwar Khan for providing these notes and appreciates his effort to publish these notes on MathCity.org

It covers the complete syllabus of Advanced Analysis paper of MSc Mathematics. See the contents of the notes given below to see the topics covered by these notes.</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Advance Analysis by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/notes/advanced-analysis-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Advance Analysis by Ms. Iqra Liaqat

[Advance Analysis by Ms. Iqra Liaqat]

These notes are send by Ms. Iqra Liaqat. We are really very thankful to her for providing these notes and appreciates her effort to publish these notes on MathCity.org
 Name  Advance Analysis   Sender  Ms. Iqra Liaqat   Author  $\sigma$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Affine and Euclidean Geometry by Shahzad Idress</title>
        <link>https://beta.mathcity.org/notes/affine-and-euclidean-geometry-shahzad-idress?rev=1737476041&amp;do=diff</link>
        <description>Affine and Euclidean Geometry by Shahzad Idress

[Affine and Euclidean Geometry by Shahzad Idress]

These notes are sent by shahzad-idress. We acknowledged his efforts to published these notes on MathCity.org.

These are short notes containing topics related to Affine and Euclidean Geometry. The main sections includes $R^n$</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Algebra II by Syed Sheraz Asghar</title>
        <link>https://beta.mathcity.org/notes/algebra-ii-by-syed-sheraz-asghar?rev=1737476041&amp;do=diff</link>
        <description>Algebra II by Syed Sheraz Asghar

[Algebra II by Syed Sheraz Asghar]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org

	*  Name: Algebra II
	*  Provider: Mr. Muzammil Tanveer</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Algebraic Number Theory Notes by Anwar Khan</title>
        <link>https://beta.mathcity.org/notes/algebraic-number-theory-notes-anwar-khan?rev=1737476041&amp;do=diff</link>
        <description>Algebraic Number Theory Notes by Anwar Khan

[Algebraic Number Theory Notes by Anwar Khan]
Algebraic number theory is a subfield of number theory that studies integers, rational numbers, and their generalisations using abstract algebra techniques. It covers Galois theory, ideals and units in rings of integers, unique factorization, and algebraic number fields and related rings of integers. It is a complex and in-depth subject with numerous linkages to other branches of mathematics.$\mathbb{R}$</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Classical Mechanics by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/classical-mechanics-muhammad-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Classical Mechanics by Muhammad Usman Hamid

[Classical Mechanics by Muhammad Usman Hamid]

Objectives of the course:

To provide solid understanding of classical mechanics and enable the students to use this understanding while studying courses on quantum mechanics, statistical mechanics, electromagnetism, fluid dynamics, space-flight dynamics, astrodynamics and continuum mechanics.</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Complex Analysis (Easy Notes of Complex Analysis)</title>
        <link>https://beta.mathcity.org/notes/complex-analysis-dr-amir-mahmood?rev=1737476041&amp;do=diff</link>
        <description>Complex Analysis (Easy Notes of Complex Analysis)

[Complex Analysis (Easy Notes of Complex Analysis) ]
The study of complex numbers, together with their manipulation, derivatives, and other characteristics, is known as complex integration. Contour integration is a technique for analysing specific integrals along pathways in the complex plane in the field of complex analysis mathematics. The complex analytic technique known as the calculus of residues and contour integration are closely linked.</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Complex Analysis (Notes) by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/notes/complex-analysis-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Complex Analysis (Notes) by Ms. Iqra Liaqat

[Notes of Complex Analysis by Ms. Iqra Liaqat]

These notes are send by Ms. Iqra Liaqat. We are really very thankful to her for providing these notes and appreciates her effort to publish these notes on MathCity.org

Complex analysis is the study of functions of complex numbers. It is useful in a variety of mathematical fields, such as algebraic geometry, number theory, analytic combinatorics, and applied mathematics, as well as in physics fields like…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Complex Analysis (Quick Review)</title>
        <link>https://beta.mathcity.org/notes/complex-analysis-quick-review?rev=1737476041&amp;do=diff</link>
        <description>Complex Analysis (Quick Review)

[Complex Analysis: Quick Review]
These notes are made and shared by Mr. Akhtar Abbas. We are really very thankful to him for providing these notes and appreciates his efforts to publish these notes on MathCity.org. Important definitions and important results are the part of these notes, these might be helpful to prepare interviews or any other written test after graduation like PPSC, FPSC or etc.$z_1, z_2 \in S$$S$$v(x,y)$$u(x,y)$$f(z)=u(x,y)+iv(x,y)$$f$$D$$C$$D$…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Computing Tools for Mathematics by Asif Arshad</title>
        <link>https://beta.mathcity.org/notes/computing-tools-for-mathematics-asif-arshad?rev=1737476041&amp;do=diff</link>
        <description>Computing Tools for Mathematics by Asif Arshad

[omputing Tools for Mathematics by Asif Arshad]
Computing tools for mathematics are algorithms that use computers to solve mathematical issues. They are employed in a number of scientific, technical, industrial, and technological domains where computer is crucial and central. They may assist in creating precise and effective numerical techniques, for instance, to solve physical or biological models.</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Differential Geometry: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/differential_geometry_notes?rev=1737476041&amp;do=diff</link>
        <description>Differential Geometry: Handwritten Notes

[Differential Geometry: Handwritten Notes]

Differential geometry is a discipline of mathematics that investigates the geometry of smooth objects and spaces, sometimes known as smooth manifolds. It investigates the geometric properties of curves and surfaces using the methods of differential and integral calculus, linear algebra, and multilinear algebra. Mathematical analysis and differential geometry are related concepts. These are the lecture notes of …</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Differential Geometry (Notes) by Ms. Kaushef Salamat</title>
        <link>https://beta.mathcity.org/notes/differential-geometry-kaushef_salamat?rev=1737476041&amp;do=diff</link>
        <description>Differential Geometry (Notes) by Ms. Kaushef Salamat

[Differential Geometry by Ms. Kaushef Salamat]
Differential Geometry is an important field in the mathematical sciences. Usually, this is a compulsory or core subject for BS mathematics students.

These notes are send by Ms. Kaushef Salamat. We are really very thankful to her for providing these notes and appreciates her effort to publish these notes on MathCity.org</description>
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    <item rdf:about="https://beta.mathcity.org/notes/differential-geometry-m-usman-hamid?rev=1737476041&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Differential Geometry by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/differential-geometry-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Differential Geometry by M Usman Hamid

[Differential Geometry by M Usman Hamid]
These notes are initially provided by Mr. Anwar Khan. Later send by many persons. We are really very thankful to all for providing these notes and appreciates their effort to publish these notes on MathCity.org</description>
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    <item rdf:about="https://beta.mathcity.org/notes/differential-geometry-syed-hassan-waqas?rev=1737476041&amp;do=diff">
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Differential Geometry by Syed Hassan Waqas</title>
        <link>https://beta.mathcity.org/notes/differential-geometry-syed-hassan-waqas?rev=1737476041&amp;do=diff</link>
        <description>Differential Geometry by Syed Hassan Waqas

[Differential Geometry by Syed Hassan Waqas]
In the field of mathematics known as differential geometry, smooth manifolds—also known as smooth shapes and spaces—and their geometry are studied. Investigating the geometric characteristics of curves and surfaces involves the use of the tools of differential and integral calculus, linear algebra, and multilinear algebra. Differential calculus and mathematical analysis are related to differential geometry.…</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Elementary Linear Algebra by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/elementary-linear-algebra-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Elementary Linear Algebra by Muhammad Usman Hamid

[Elementary Linear Algebra by Muhammad Usman Hamid]

Linear Algebra is the study of vectors and linear transformations. The main objective of this course is to help students learn in rigorous manner, the tools and methods essential for studying the solution spaces of problems in mathematics, engineering, the natural sciences and social sciences and develop mathematical skills needed to apply these to the problems arising within their field of st…</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fluid Dynamics I by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/fluid-dynamics-i-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Fluid Dynamics I by Muhammad Usman Hamid

[Fluid Dynamics I by Muhammad Usman Hamid]

These notes are send by Mr. Anwar Khan, PhD. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes are written by Muhammad Usman Hamid.

	*  Name: Fluid Dynamics I</description>
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    <item rdf:about="https://beta.mathcity.org/notes/fluid-mechanics-ali-raza?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fluid Mechanics by Ali Raza</title>
        <link>https://beta.mathcity.org/notes/fluid-mechanics-ali-raza?rev=1737476041&amp;do=diff</link>
        <description>Fluid Mechanics by Ali Raza

[Fluid Mechanics by Ali Raza]

Fluid mechanics is the branch of physics that studies how fluids (liquids, gases, and plasmas) behave and interact with forces and energy. Fluid mechanics has many applications in engineering, geophysics, biology, and other fields.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/fluid-mechanics-i-muzammil-tanveer?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fluid Mechanics I by Dr Rao Muzamal Hussain</title>
        <link>https://beta.mathcity.org/notes/fluid-mechanics-i-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Fluid Mechanics I by Dr Rao Muzamal Hussain

[Fluid Mechanics I by Muzammil Tanveer]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes are based on  lectures delivered by Mr. Muzammil Hussain at GC University Faisalabad.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/fluid-mechanics-ii-muzammil-tanveer?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fluid Mechanics II by Dr Rao Muzamal Hussain</title>
        <link>https://beta.mathcity.org/notes/fluid-mechanics-ii-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Fluid Mechanics II by Dr Rao Muzamal Hussain

[Fluid Mechanics I by Muzammil Tanveer]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes are based on  lectures delivered by Mr. Muzammil Hussain at GC University Faisalabad.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/functional-analysis-by-prof-mumtaz-ahmad?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Functional Analysis by Prof Mumtaz Ahmad</title>
        <link>https://beta.mathcity.org/notes/functional-analysis-by-prof-mumtaz-ahmad?rev=1737476041&amp;do=diff</link>
        <description>Functional Analysis by Prof Mumtaz Ahmad

[Functional Analysis by Prof Mumtaz Ahmad]

Functional analysis is a subfield of mathematics that deals with vector space theory and linear algebra. It entails researching the connections between roles, things, incidents, actions, and outcomes. The word $l^\infty$$l^\infty$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/functional-analysis-by-tahir-hussain-jaffery?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Functional Analysis by Mr. Tahir Hussain Jaffery</title>
        <link>https://beta.mathcity.org/notes/functional-analysis-by-tahir-hussain-jaffery?rev=1737476041&amp;do=diff</link>
        <description>Functional Analysis by Mr. Tahir Hussain Jaffery

[Functional Analysis by Prof Mumtaz Ahmad]

Functional analysis is a branch of mathematics concerned with vector space theory and linear algebra. It requires looking into the relationships between various roles, objects, incidents, actions, and results. The term $M$$M+N$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Functional Analysis by M Usman Hamid and Zeeshan Ahmad</title>
        <link>https://beta.mathcity.org/notes/functional-analysis-m-usman-hamid-and-zeeshan-ahmad?rev=1737476041&amp;do=diff</link>
        <description>Functional Analysis by M Usman Hamid and Zeeshan Ahmad

[Functional Analysis by M Usman Hamid and Zeeshan Ahmad]

These notes are send by Muhammad Usman Hamid and written by Muhammad Usman Hamid and Zeeshan Ahmad. We are really very thankful to him for providing these notes and appreciate his effort to publish these notes on MathCity.org. Usman is dedicated and committed mathematician, who is working very hard for better understanding of mathematics to it readers.</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fundamental of Complex Analysis (Solutions of Some Exercises)</title>
        <link>https://beta.mathcity.org/notes/fundamental-of-complex-analysis-prof-m-saleem?rev=1737476041&amp;do=diff</link>
        <description>Fundamental of Complex Analysis (Solutions of Some Exercises)

[Fundamental of Complex Analysis, Solutions of Some Exercises]

Complex analysis is the study of functions that exist in the complex plane, that is, functions with complex arguments and complex outputs. With roots in the 18th century and the years just before, it is one of the classical branches of mathematics. In the 20th century, significant figures in mathematics who are connected to complex numbers include Euler, Gauss, Riemann, …</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Fuzzy Sets Theory by Umar Saeed Bunarai</title>
        <link>https://beta.mathcity.org/notes/fuzzy-sets-theory-umar-saeed-bunarai?rev=1737476041&amp;do=diff</link>
        <description>Fuzzy Sets Theory by Umar Saeed Bunarai

[Fuzzy Sets Theory by Umar Saeed Bunarai]
In the field of mathematics known as fuzzy set theory, sets having varying degrees of membership are studied. This implies that an element can be a member of a set only partially or not at all. In several disciplines, including logic, control, data analysis, and decision-making, fuzzy set theory is used to model uncertainty, vagueness, and imprecision.</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>General Topology by Raheel Ahmad</title>
        <link>https://beta.mathcity.org/notes/general-topolgy-raheel-ahmad?rev=1737476041&amp;do=diff</link>
        <description>General Topology by Raheel Ahmad

A handwritten notes of Topology by Mr. Raheel Ahmad. We are very thankful to him for sending these notes.
 Name  General Topology   Author  Mr. Raheel Ahmad   Pages  87 pages   Format  Mobile Scanned PDF   Size  8.0 MB  
What is in the notes?</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>General Topology by Azhar Hussain</title>
        <link>https://beta.mathcity.org/notes/general-topology-azhar-hussain?rev=1737476041&amp;do=diff</link>
        <description>General Topology by Azhar Hussain

[Topology Notes by Azhar Hussain]
The area of topology known as general topology (also known as point set topology) is concerned with the fundamental concepts and constructs of set theory utilised in topology. Most other fields of topology, such as differential topology, geometric topology, and algebraic topology, are built upon it.
The three key ideas of point-set topology are connectedness, compactness, and continuity. Continuous functions move points from on…</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Group Theory: Important Definitions and Results</title>
        <link>https://beta.mathcity.org/notes/group-theory-important-definitions-and-results?rev=1737476041&amp;do=diff</link>
        <description>Group Theory: Important Definitions and Results

[Group Theory: Important Definitions and Results]
These notes are made and shared by Mr. Akhtar Abbas. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes contains important definitions with examples and related theorem, which might be helpful to prepare interviews or any other written test after graduation like PPSC, FPSC or etc.$G$$a\in G$$\exists$$e\in G$$a\…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Group Theory by Mr. Muhammad Iftikhar</title>
        <link>https://beta.mathcity.org/notes/groups-theory-m-iftikhar?rev=1737476041&amp;do=diff</link>
        <description>Group Theory by Mr. Muhammad Iftikhar

[Group Theory by Mr. Muhammad Iftikhar]

These notes are send by Mr. Muhammad Iftikhar. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org.
 Name  Lecture Notes on Group Theory   Author  Mr. Muhammad Iftikhar</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Handwritten Notes of Real Analysis by Asim Marwat</title>
        <link>https://beta.mathcity.org/notes/handwritten-notes-real-analysis-asim-marwat?rev=1737476041&amp;do=diff</link>
        <description>Handwritten Notes of Real Analysis by Asim Marwat

[Handwritten Notes of Real Analysis by Asim Marwat]

Real analysis is a branch of mathematics that analyses how real numbers, sequences and series, and real functions behave. It focuses on real numbers and frequently extends the real line by including positive and negative infinity. Real analysis investigates a number of the properties of real-valued sequences and functions, including convergence, limits, continuity, smoothness, differentiabilit…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>History of Mathematics by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/history-of-mathematics-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>History of Mathematics by Muhammad Usman Hamid

[History of Mathematics by Muhammad Usman Hamid]

Mathematics is a unique aspect of human thought, and its history differs in essence from all other histories. These notes are written by Muhammad Usman Hamid. We are very thankful to him for sharing these notes on our website.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/linear-algebra-important-definitions-and-results?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Linear Algebra: Important Definitions and Results</title>
        <link>https://beta.mathcity.org/notes/linear-algebra-important-definitions-and-results?rev=1737476041&amp;do=diff</link>
        <description>Linear Algebra: Important Definitions and Results

[Linear Algebra: Important Definitions and Results]
These notes are made and shared by Mr. Akhtar Abbas. We are really very thankful to him for providing these notes and appreciates his efforts to publish these notes on MathCity.org. These notes contains important definitions with examples and related theorem, which might be helpful to prepare interviews or any other written test after graduation like PPSC, FPSC or etc.$V$$n$$n$$V$$W$$V$$A$$A$$A…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/notes/mathematical-method-muzammil-tanveer?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Method by Sir Muhammad Awais Aun</title>
        <link>https://beta.mathcity.org/notes/mathematical-method-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Method by Sir Muhammad Awais Aun

[Mathematical Method by Muzammil Tanveer]

Mathematical methods are the approaches employed by mathematicians to address issues in mathematics and science. Algebra, functions, relations and associated graphs, calculus, and statistics are examples of mathematical techniques. Through their usage in resolving practical issues, they are applied to modelling.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/mathematical-method-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Method by Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/mathematical-method-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Method by Muhammad Usman Hamid

[Mathematical Method by Muhammad Usman Hamid]

These notes are send by Muhammad Usman Hamid. We acknowledged his efforts to published these notes on MathCity.org.

The main objective of this course is to provide the students with a range of mathematical methods that are essential to the solution of advanced problems encountered in the fields of applied physics and engineering. In addition this course is intended to prepare the students with mathematic…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/mathematical-statistics-i-muzammil-tanveer?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Statistics I by Muzammil Tanveer</title>
        <link>https://beta.mathcity.org/notes/mathematical-statistics-i-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Statistics I by Muzammil Tanveer

[Mathematical Statistics I]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org 
 Name  Mathematical Statistics</description>
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    <item rdf:about="https://beta.mathcity.org/notes/mathematical-statistics-ii-muzammil-tanveer?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Statistics II by Sir Haidar Ali</title>
        <link>https://beta.mathcity.org/notes/mathematical-statistics-ii-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Statistics II by Sir Haidar Ali

[Mathematical Statistics II]

A subfield of mathematics called mathematical statistics is concerned with using mathematical techniques to solve statistical problems. It involves using mathematical analysis and probability theory to the study of statistical issues like estimate, hypothesis testing, and confidence intervals. Financial, engineering, and scientific fields all benefit from the use of mathematical statistics, which is a significant area of…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/mathematical-statistics-iqra-liaqat?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Statistics by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/notes/mathematical-statistics-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Statistics by Ms. Iqra Liaqat

[Mathematical Statistics by Ms. Iqra Liaqat]

These notes are send by Ms. Iqra Liaqat. We are really very thankful to her for providing these notes and appreciates her effort to publish these notes on MathCity.org
 Name  Mathematical Statistics   Provided by</description>
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    <item rdf:about="https://beta.mathcity.org/notes/measure-theory-by-anwar-khan?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Measure Theory Notes by Anwar Khan</title>
        <link>https://beta.mathcity.org/notes/measure-theory-by-anwar-khan?rev=1737476041&amp;do=diff</link>
        <description>Measure Theory Notes by Anwar Khan

[Measure Theory Notes by Anwar Khan]

Measure theory is a branch of mathematics concerned with the concept of “measure,” which is a method of assigning a numerical value to specific sets. The concepts of length, area, and volume are generalised via measurements to more abstract environments, such as infinite-dimensional spaces and areas that cannot be seen.$X$$\sigma-$$X$$\sigma-$$\sigma-$$\lim\limits_{k\to \infty} \sup A_k$$\lim\limits_{k\to \infty} \inf A_k$…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/measure-theory-notes-asim-marwat?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Measure Theory Handwritten Notes by Asim Marwat</title>
        <link>https://beta.mathcity.org/notes/measure-theory-notes-asim-marwat?rev=1737476041&amp;do=diff</link>
        <description>Measure Theory Handwritten Notes by Asim Marwat

[Measure Theory Notes by Asim Marwat]
These notes are made and shared by Mr. Asim Marwat. He has our sincere gratitude for supplying these notes, and we value his effort in having them published on MathCity.org. Measure Theory is an important subject in BS Mathematics. These notes contain topic from base level, like equivalence set, to advance level, like convergent in measure.$L_p$$L_p$$L^\infty$$L_p$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/measure-thoery-muhsa?rev=1737476041&amp;do=diff">
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Measure Theory by M Usman Hamid &amp; Saima Akram</title>
        <link>https://beta.mathcity.org/notes/measure-thoery-muhsa?rev=1737476041&amp;do=diff</link>
        <description>Measure Theory by M Usman Hamid &amp; Saima Akram

[Measure Theory by M Usman Hamid &amp; Saima Akram]

The study of measures on sets is the focus of the mathematical field known as measure theory. A measure is a function that gives specific subsets of a given set a non-negative real integer, indicating their size inferentially. The concept of measure is a formalisation and generalisation of common concepts like mass and event probability as well as geometrical measurements (length, area, and volume).</description>
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    <item rdf:about="https://beta.mathcity.org/notes/mechanics-by-dr-amir-mahmood?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mechanics (Easy Notes of Mechanics)</title>
        <link>https://beta.mathcity.org/notes/mechanics-by-dr-amir-mahmood?rev=1737476041&amp;do=diff</link>
        <description>Mechanics (Easy Notes of Mechanics)

[Easy Notes of Mechanics]
These notes are provided and prepared by Dr. Amir Mahmood. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org

If there is error or mistake in the notes, then please directly contact to Dr. Amir Mahmood for correction. He can be accessed via his email address at</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mechanics by Sir Nouman Siddique</title>
        <link>https://beta.mathcity.org/notes/mechanics-by-sir-nouman-siddique?rev=1737476041&amp;do=diff</link>
        <description>Mechanics by Sir Nouman Siddique

These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org

	*  Name: Mechanics
	*  Provider: Mr. Muzammil Tanveer</description>
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    <item rdf:about="https://beta.mathcity.org/notes/mechanics-i-statics-dr-babar-ahmad?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mechanics I (Statics) by Dr Babar Ahmad</title>
        <link>https://beta.mathcity.org/notes/mechanics-i-statics-dr-babar-ahmad?rev=1737476041&amp;do=diff</link>
        <description>Mechanics I (Statics) by Dr Babar Ahmad

[Mechanics I (Statics) by Dr Babar Ahmad]

We are very thankful to Dr Babar Ahmad for sharing his book on MathCity.org. This book is very helpful for undergraduate students of Science and Engineering Programs. 

This book is shared by the permission of the author and he keeps the copyright of the book.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/method-of-mathematical-physics-m-usman-hamid?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Method of Mathematical Physics by Mr. Muhammad Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/method-of-mathematical-physics-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Method of Mathematical Physics by Mr. Muhammad Usman Hamid

[Method of Mathematical Physics by Mr. Muhammad Usman Hamid]

Method of Mathematical Physics is an area of mathematics concerned with the application of mathematical methods to physics problems. Mathematical techniques for statistical mechanics, quantum mechanics, and classical mechanics are all included in this large field.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/metric-spaces-notes?rev=1737476041&amp;do=diff">
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Metric Spaces (Notes)</title>
        <link>https://beta.mathcity.org/notes/metric-spaces-notes?rev=1737476041&amp;do=diff</link>
        <description>Metric Spaces (Notes)

[Metric Spaces (Notes)]
These are updated version of previous notes. Many mistakes and errors have been removed. These notes are collected, composed and corrected by Atiq ur Rehman, PhD. These are actually based on the lectures delivered by Prof. Muhammad Ashfaq (Ex HoD, Department of Mathematics, Government College Sargodha). $(X,d)$$x,y\in X$$$\left| {\,d(x,\,A)\, - \,d(y,\,A)\,} \right|\,\, \le \,\,d(x,\,y).$$$A^c$$A\subset X$$x \in X$$B(x;r)$$A \subset X$$f:(X,d)\to (Y…</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Multiple Choice Questions (BSc/BS/PPSC) by Akhtar Abbas</title>
        <link>https://beta.mathcity.org/notes/multiple-choice-questions-_bsc-bs-ppsc_-akhtar-abbas?rev=1737476041&amp;do=diff</link>
        <description>Multiple Choice Questions (BSc/BS/PPSC) by Akhtar Abbas

[Multiple Choice Questions (BSc/BS/PPSC)]
These notes are made and shared by Mr. Akhtar Abbas. We are really very thankful to him for providing these notes and appreciates his efforts to publish these notes on MathCity.org. Multiple Choice Questions (MCQs) are given in these notes, which might be helpful in BSc, BS or Punjab Public Service Commission (PPSC) exams.$a$$b$$n$$na &gt; b$$(p − 1)! \equiv −1(mod p)$$p$$p$$p$</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Multivariable Calculus by Sheikh Muhammad Saleem Shahzad</title>
        <link>https://beta.mathcity.org/notes/multivariable-calculus-sheikh-muhammad-saleem-shahzad?rev=1737476041&amp;do=diff</link>
        <description>Multivariable Calculus by Sheikh Muhammad Saleem Shahzad

[Multivariable Calculus by Sheikh Muhammad Saleem Shahzad]

	*  Have you ever wondered how we can understand the speed of a moving object at any instant of time?
	*  Did you know that Calculus can help us predict future trends by analyzing patterns in data?</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Notes for Numerical Methods by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/note-for-numerical-methods-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Notes for Numerical Methods by M Usman Hamid

[Notes for Numerical Methods by M Usman Hamid]
These notes are initially provided by Mr. Anwar Khan. Later the updated version is send by Muhammad Tahir. We are really very thankful to Mr. Anwar Khan and Muhammad Tahir for providing these notes and appreciates their effort to publish these notes on MathCity.org$\left(\frac{1}{3}\right)$$\left(\frac{3}{8}\right)$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/number-theory-handwritten-notes?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/number-theory-handwritten-notes?rev=1737476041&amp;do=diff</link>
        <description>Number Theory: Handwritten Notes

[Number Theory: Handwritten Notes]
The study of the characteristics of the positive integers (1, 2, 3,...) is called number theory. It is significant because it has numerous uses in coding theory, combinatorics, cryptography, and other branches of mathematics and computer science. Some mathematicians also refer to number theory as the</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory Notes by Anwar Khan</title>
        <link>https://beta.mathcity.org/notes/number-theory-notes-anwar-khan?rev=1737476041&amp;do=diff</link>
        <description>Number Theory Notes by Anwar Khan

[Number Theory Notes by Anwar Khan]
Mathematicians who specialize in number theory examine the characteristics and connections between integers. “Higher arithmetic” and “the queen of mathematics” are some names for it.  Because it examines the characteristics and connections between integers and arithmetic functions, number theory is interesting. It has numerous uses in coding theory, combinatorics, cryptography, and other branches of mathematics. Like the ones…</description>
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    <item rdf:about="https://beta.mathcity.org/notes/number-theory-umer-shuaib?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory by Dr Muhammad Umer Shuaib</title>
        <link>https://beta.mathcity.org/notes/number-theory-umer-shuaib?rev=1737476041&amp;do=diff</link>
        <description>Number Theory by Dr Muhammad Umer Shuaib

[Number Theory Notes]
A subfield of mathematics called number theory studies the characteristics of positive integers. Higher arithmetic is another name for it. The study of the relationships between various types of numbers, including prime numbers, rational numbers, and algebraic integers, is done using number theory, one of the oldest fields of mathematics.$\phi$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Numerical Analysis by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/numerical-analysis-by-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Numerical Analysis by M Usman Hamid

These notes are initially provided by Mr. Anwar Khan. Later the updated version is send by Muhammad Tahir. We are really very thankful to Mr. Anwar Khan and Muhammad Tahir for providing these notes and appreciates their effort to publish these notes on MathCity.org</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Numerical Analysis II</title>
        <link>https://beta.mathcity.org/notes/numerical-analysis-ii?rev=1737476041&amp;do=diff</link>
        <description>Numerical Analysis II

[Numerical Analysis by Muzammil Tanveer]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org.
 Name    Numerical Analysis II    Compiled by  Muzammil Tanveer</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Operation Research by Sir Haidar Ali</title>
        <link>https://beta.mathcity.org/notes/operation-research-haidar-ali?rev=1737476041&amp;do=diff</link>
        <description>Operation Research by Sir Haidar Ali

[Notes of Operation Research by Sir Haidar Ali]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These are based on lectures delivered by Sir Haidar Ali at GC University Faisalabad.</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Operation Research: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/operation-research-handwritten-notes?rev=1737476041&amp;do=diff</link>
        <description>Operation Research: Handwritten Notes

[Operation Research: Handwritten Notes]
Operation research (OR) is a scientific field that enhances organisational decision-making and problem-solving via the application of mathematical and analytical techniques. The management and administration of many processes, including military, governmental, economic, and industrial ones, include the use of scientific principles. OR is carried out by a group of professionals from various linked fields, depending on …</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Partial Differential Equations by M Usman Hamid</title>
        <link>https://beta.mathcity.org/notes/partial-differential-equations-m-usman-hamid?rev=1737476041&amp;do=diff</link>
        <description>Partial Differential Equations by M Usman Hamid

The course provides a foundation to solve PDE’s with special emphasis on wave, heat and Laplace equations, formulation and some theory of these equations are also intended.
We are really very thankful to Prof. Muhammad Usman Hamid for providing these notes and appreciates his effort to publish these notes on MathCity.org</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Partial Differential Equations by Muzammil Tanveer</title>
        <link>https://beta.mathcity.org/notes/partial-differential-equations-muzammil-tanveer?rev=1737476041&amp;do=diff</link>
        <description>Partial Differential Equations by Muzammil Tanveer

[Partial Differential Equations]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org 
 Name  Partial Differential Equations or PDEs</description>
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    <item rdf:about="https://beta.mathcity.org/notes/real-analysis-hand-written-kaushef?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Real Analysis Handwritten Notes by Kaushef Salamat</title>
        <link>https://beta.mathcity.org/notes/real-analysis-hand-written-kaushef?rev=1737476041&amp;do=diff</link>
        <description>Real Analysis Handwritten Notes by Kaushef Salamat

[Real Analysis Handwritten Notes by Kaushef Salamat]

We are very thankful to Ms. Kaushef Salamat for providing these notes. Real Analysis is a core subject in BS or MSc Mathematics. Without a fundamental grasp of Real Analysis, one cannot claim to be a mathematician. These notes are very comprehensive containing almost all the notions of Real Analysis. For providing these notes, Ms. $\infty$</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Real Analysis Notes by Prof Syed Gul Shah</title>
        <link>https://beta.mathcity.org/notes/real-analysis-notes-by-prof-syed-gul-shah?rev=1737476041&amp;do=diff</link>
        <description>Real Analysis Notes by Prof Syed Gul Shah

[Real Analysis Notes by Prof Syed Gul Shah]

Real analysis, a discipline that explores the complexities of mathematical functions, limits, and sequences, can often be a difficult topic for students. Prof. Syed Gul Shah, as a true analyst, not only excelled in the subject but also gained fame for his extraordinary qualities as a human being.$s_n&lt;u_n&lt;t_n$$n\ge n_0$$\{s_n\}$$\{t_n\}$$\{u_n\}$$\{s_n\}$$\exists$$\left| {\,{s_n}}\right|&gt;\frac{1}{2}s$$\{s_n\}$…</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Ring (Notes) by Prof. M. Dabeer Mughal</title>
        <link>https://beta.mathcity.org/notes/ring_notes?rev=1737476041&amp;do=diff</link>
        <description>Ring (Notes) by Prof. M. Dabeer Mughal

[Ring (Notes) by Prof. M. Dabeer Mughal]
A handwritten notes on Ring (Algebra) by Prof. M. Dabeer Mughal (Federal Directorate of Education, Islamabad, Pakistan). It is best to prepare a “Rings and Vector Spaces” section of your algebra paper or Algebra II for BS or MS Mathematics.$\phi$</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Rings (Handwritten notes) by Atiq ur Rehman</title>
        <link>https://beta.mathcity.org/notes/rings_handwritten_notes?rev=1737476042&amp;do=diff</link>
        <description>Rings (Handwritten notes) by Atiq ur Rehman

[Rings (Handwritten notes) by Atiq ur Rehman]
Ring is a two-operation mathematical structure. It is an abelian group with one operation and a semi-group with another operation, and the distributive law is true for the first operation relative to the second operation. This mathematical idea is fundamentally pure. These notes offer a very simple method for learning the concept of rings and other ideas that are closely related to rings. These are lecture…</description>
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Rings &amp; Modules by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/notes/rings-and-modules-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Rings &amp; Modules by Ms. Iqra Liaqat

Ring is a mathematical structure with two operations. With one operation it is abelian group and with other operation it is semi-group with distributive law holds with first operation w.r.t the other operation. This concept is of pure in nature in mathematics. These advanced level notes are typically taken as an elective in a mathematics undergraduate degree.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/special-functions-muzammil-tanveer?rev=1737476042&amp;do=diff">
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        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Special Functions by Dr. Muhey-U-Din</title>
        <link>https://beta.mathcity.org/notes/special-functions-muzammil-tanveer?rev=1737476042&amp;do=diff</link>
        <description>Special Functions by Dr. Muhey-U-Din

These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. Thease notes are based on the lectures by Dr. Muhey-U-Din.</description>
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        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Special Theory of Relativity by M Usman Hamid and M Zeeshan Ahmad</title>
        <link>https://beta.mathcity.org/notes/special-theory-of-relativity-usman-hameed-and-zeeshan-ahmad?rev=1737476042&amp;do=diff</link>
        <description>Special Theory of Relativity by M Usman Hamid and M Zeeshan Ahmad

[Special Theory of Relativity by M Usman Hamid and M Zeeshan Ahmad]
Special theory of relativity developed by Einstein in 1905, after the failure of Newton‘s laws, when he was dealing with the relative motion in space. The theory of relativity deals with relations which exist between physical quantities (such as mass of a particle, length of a rod, electric field at a point etc.) as they appear to different observers in relative …</description>
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    <item rdf:about="https://beta.mathcity.org/notes/theory-of-optimization-muzammil-tanveer?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Theory of Optimization by Ma&#039;am Iqra Razzaq</title>
        <link>https://beta.mathcity.org/notes/theory-of-optimization-muzammil-tanveer?rev=1737476042&amp;do=diff</link>
        <description>Theory of Optimization by Ma&#039;am Iqra Razzaq

[Special Theory of Optimization by Ma&#039;am Iqra Razzaq]
These notes are provided and composed by Mr. Muzammil Tanveer. We are really very thankful to him for providing these notes and appreciates his effort to publish these notes on MathCity.org. These notes are based on the lectures by Ma&#039;am Iqra Razzaq.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/notes/theory-of-relativity-and-analytic-dynamics?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Theory of Relativity &amp; Analytic Dynamics: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/theory-of-relativity-and-analytic-dynamics?rev=1737476042&amp;do=diff</link>
        <description>Theory of Relativity &amp; Analytic Dynamics: Handwritten Notes

[Theory of Relativity &amp; Analytic Dynamics: Handwritten Notes]

Theory of Relativity and Analytic Dynamics is a subject that encompasses two distinct topics: relativity theory and analytic dynamics. Albert Einstein&#039;s theory of relativity defines the fundamental principles that control how moving objects behave in relation to one another and to the observer. The motion of objects as a result of forces and torques is the subject of analyt…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/notes/topology-and-functional-analysis-solved-pu?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Topology and Functional Analysis Solved Paper by Noman Khalid</title>
        <link>https://beta.mathcity.org/notes/topology-and-functional-analysis-solved-pu?rev=1737476042&amp;do=diff</link>
        <description>Topology and Functional Analysis Solved Paper by Noman Khalid

These solved papers are written and provided by Mr. noman-khalid. We are very thankful to him for providing these notes to publish on MathCity.org.

Topology and Functional Analysis is considered as one the tough subject in BS/MSc Mathematics in different universities. Here solved paper for the said subject is given for the University of the Punjab (PU), Lahore.</description>
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    <item rdf:about="https://beta.mathcity.org/notes/topology-handwritten-notes?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Topology: Handwritten Notes</title>
        <link>https://beta.mathcity.org/notes/topology-handwritten-notes?rev=1737476042&amp;do=diff</link>
        <description>Topology: Handwritten Notes

[House of Tau]
A topological space is a collection of points with a topology-a structure that describes how close two points are to one another. It is a generalisation of Euclidean spaces that makes it possible to investigate boundaries, continuity, and connectivity. A topology is a group of open sets, or subsets, that adhere to certain principles.$T_0$$T_1$$T_2$$\varepsilon-$</description>
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    <item rdf:about="https://beta.mathcity.org/notes/vector_spaces_handwritten_notes?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Vector Spaces (Handwritten notes)</title>
        <link>https://beta.mathcity.org/notes/vector_spaces_handwritten_notes?rev=1737476042&amp;do=diff</link>
        <description>Vector Spaces (Handwritten notes)

[Vector Spaces (Handwritten notes) by Atiq ur Rehman]
Vector space is a fundamental subject in mathematics. At the undergraduate and upper secondary levels, the concept of vector space is regarded as basic and fundamental. These are lecture notes of Prof. Dr. Muhammad Khalid of University of Sargodha, Sargodha written by Atiq ur Rehman.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/notes/vector-and-tensor-analysis-by-dr-nawazish?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Vector &amp; Tensor Analysis by Dr Nawazish Ali (Solutions)</title>
        <link>https://beta.mathcity.org/notes/vector-and-tensor-analysis-by-dr-nawazish?rev=1737476042&amp;do=diff</link>
        <description>Vector &amp; Tensor Analysis by Dr Nawazish Ali (Solutions)

[Vector &amp; Tensor Analysis by Dr Nawazish Ali (Solutions)]

We are very thankful to Prof. Fazal Abbas Sajid for sharing these solutions. Vector &amp; Tensor Analysis for Scientists and Engineers,
by Prof. Dr. Nawazish Ali Shah is a famous book taught in different universities of the Pakistan. On this page, we have added the solutions of the exercises of the book. Solutions of Chapter 5 is written by</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/notes/vector-and-tensor-analysis-by-prof-fazal-abbas?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Vector &amp; Tensor Analysis by Prof Fazal Abbas</title>
        <link>https://beta.mathcity.org/notes/vector-and-tensor-analysis-by-prof-fazal-abbas?rev=1737476042&amp;do=diff</link>
        <description>Vector &amp; Tensor Analysis by Prof Fazal Abbas

[Vector &amp; Tensor Analysis by Prof Fazal Abbas]

Solution of Chapter 6: Curvilinear Coordinates of the book Vector &amp; Tensor Analysis by Prof. Dr. Nawazish Ali Shah written by Prof. Fazal Abbas Sajid. Here solutions of chapter 6 are provided by the author of the book, for the solutions of all the chapters of the book, please buy the solution manual from the market.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/notes/vector-spaces-review-by-rashad-wattu?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Vector Space (Review) by Rashad Wattu</title>
        <link>https://beta.mathcity.org/notes/vector-spaces-review-by-rashad-wattu?rev=1737476042&amp;do=diff</link>
        <description>Vector Space (Review) by Rashad Wattu

Mathematical vector space is a crucial and fundamental idea. It depends on the concept of field. These notes were primarily written to help maths students understand vector space, which is a concept that they all need to be familiar with.</description>
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    <item rdf:about="https://beta.mathcity.org/ppsc/ppsc-maths-2011?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>PPSC Paper 2011 (Lecturer in Mathematics)</title>
        <link>https://beta.mathcity.org/ppsc/ppsc-maths-2011?rev=1737476042&amp;do=diff</link>
        <description>PPSC Paper 2011 (Lecturer in Mathematics)

[PPSC Paper 2011 (Lecturer in Mathematics)]

On this page, we have given question from old (past) paper of Lecturer in Mathematics conducted in year 2011. This is a MCQs paper and answers are given at the end of the paper. At the end of the PDF is also given to download. This paper is provided by Ms. $R$$x\in R$$x^2=x$$x^2=-x$$x^2=0$$x^2=1$$6$$8$$10$$4$$G$$H$$H$$G$$2$$4$$nZ$$Z$$n$$G$$24$$a$$a^{10}$$2$$12$$10$$V$$n$$V$$n+1$$n$$n-1$$v_1,v_2,v_3,....,v_r$$…</description>
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    <item rdf:about="https://beta.mathcity.org/ppsc/ppsc-maths-2015?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>PPSC Paper 2015 (Lecturer in Mathematics)</title>
        <link>https://beta.mathcity.org/ppsc/ppsc-maths-2015?rev=1737476042&amp;do=diff</link>
        <description>PPSC Paper 2015 (Lecturer in Mathematics)

[PPSC Paper 2011 (Lecturer in Mathematics)]

On this page, we have given question from old (past) paper of Lecturer in Mathematics conducted in year 2011. This is a MCQs paper and answers are given at the end of the paper. At the end of the PDF is also given to download. This paper is provided by Kaushef Salamat. We are very thankful to her for providing this paper.\(\displaystyle \int_{-4}^{0}\frac{tdt}{\sqrt{16-t62}}\)$0$$-4$$4$\(A\cos wt+B\sin wt\)$\…</description>
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    <item rdf:about="https://beta.mathcity.org/ppsc/ppsc-maths-2021?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>PPSC Paper 2021 (Lecturer in Mathematics)</title>
        <link>https://beta.mathcity.org/ppsc/ppsc-maths-2021?rev=1737476042&amp;do=diff</link>
        <description>PPSC Paper 2021 (Lecturer in Mathematics)

[PPSC Paper 2011 (Lecturer in Mathematics)]

On this page, we have given question from old (past) paper of Lecturer in Mathematics conducted in year 2021. This is a MCQs paper and answers are given at the end of the paper. At the end of the PDF is also given to download. This paper is provided by Ms. \(2018\)$4$\(6\)$8$$10$\(X\)\(Y\)\(X\times Y\)\(\parallel (x,y) \parallel=\parallel x\parallel+\parallel y\parallel, \,\forall \, (x,y)\in X \times Y\)\(f(…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/ppsc/ppsc-mock-interview-mathematics?rev=1737476042&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:02+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>PPSC Mock Interview Lecturer Mathematics</title>
        <link>https://beta.mathcity.org/ppsc/ppsc-mock-interview-mathematics?rev=1737476042&amp;do=diff</link>
        <description>PPSC Mock Interview Lecturer Mathematics

[PPSC Mock Interview Lecturer Mathematics]
This handout is shared by Mr. Rashad Wattu and written by Sawaira Sikandar. We are really very thankful to him for providing this handout and appreciates his efforts to publish it on MathCity.org. 
This handout contains the questions collected from the different interviews of the Lecturer in Mathematics conducted by Public Service Commission (PSC). This is help full to prepare interview of all types of jobs whic…</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch04_techniques_of_integration?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 04: Techniques of Integration</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch04_techniques_of_integration?rev=1737476035&amp;do=diff</link>
        <description>Chapter 04: Techniques of Integration

These notes are written by Mr. Aqeel Nawaz. We are very thankful to him for providing these notes.

	*  Anti-derivative
	*  Table of integrals
	*  Integration by substitution
	*  Integration by parts
	*  Column (or tabular) integration</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch04_techniques_of_integration_farooq?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 04: Techniques of Integration</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch04_techniques_of_integration_farooq?rev=1737476035&amp;do=diff</link>
        <description>Chapter 04: Techniques of Integration

&lt;div&gt;&lt;img src=&quot;https://dl.dropbox.com/u/64787761/integration.jpg&quot; title=&quot;Integral of the one variable function&quot; class=&quot;mediaright&quot; alt=&quot;Integral of the one variable function&quot; /&gt;&lt;/div&gt;
These notes are written by Prof. Muhammad Farooq. We are very thankful to him for providing these notes.

	*  Anti-derivative
	*  Table of integrals
	*  Integration by substitution
	*  Integration by parts
	*  Column (or tabular) integration</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch05_the_definite_integral?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 05: The Definite Integral</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch05_the_definite_integral?rev=1737476035&amp;do=diff</link>
        <description>Chapter 05: The Definite Integral

These notes are written by Mr. Abrar Mustafa. We are very thankful to him for providing these notes.

	*  The definite integral as limit of a sum
	*  Evaluation of limit of a sum
	*  Evaluation of definite integral</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch06_plane_curves_i?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 06: Plane Curves I</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch06_plane_curves_i?rev=1737476035&amp;do=diff</link>
        <description>Chapter 06: Plane Curves I

Notes of the book Calculus with Analytic Geometry written by Dr. S. M. Yusuf and Prof. Muhammad Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN.
[Conic section]

Contents and summary

	*  Conic sections
	*  The parabola
	*  The ellipse</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch09_functions_of_several_variables?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 09: Functions of Several Variables</title>
        <link>https://beta.mathcity.org/bsc/notes_of_calculus_with_analytic_geometry/ch09_functions_of_several_variables?rev=1737476035&amp;do=diff</link>
        <description>Chapter 09: Functions of Several Variables

	*  Homogeneous Functions
	*  Differentials
	*  Change of variables, the chain rule
	*  Implicit functions
	*  Directional derivative
	*  Tangent planes and normal lines
	*  Extrema of functions of two variables</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch03_matrices?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 03: Matrices</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch03_matrices?rev=1737476035&amp;do=diff</link>
        <description>Chapter 03: Matrices

Notes of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN.

The difficulty level of this chapter is very low. Most of the questions involve calculations. This chapter is wide range of applications in Linear Algebra. In many universities teachers include this chapter in the syllabus of Linear Algebra for BS students of mathematics and other subjects.</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch04_system_of_linear_equations?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 04: System of Linear Equations</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch04_system_of_linear_equations?rev=1737476035&amp;do=diff</link>
        <description>Chapter 04: System of Linear Equations

Notes of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN.

The difficulty level of this chapter is low. Most of the questions involve calculations. This chapter is wide range of applications in Linear Algebra and Operations Research. In many universities teachers include this chapter in the syllabus of Linear Algebra and Operations Research for BS students of mathematics and other …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch05_determinants?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 05: Determinants</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch05_determinants?rev=1737476035&amp;do=diff</link>
        <description>Chapter 05: Determinants

	*  Determinant of a square matrix
	*  Axiomatic definition of a determinant
	*  Determinant as sum of products of elements
	*  Determinant of the transpose
	*  An algorithm to evaluate Det A
	*  Determinants and inverse of matrices</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch06_vector_spaces?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 06: Vector Spaces</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch06_vector_spaces?rev=1737476035&amp;do=diff</link>
        <description>Chapter 06: Vector Spaces

Notes of  Chapter 06 Vector Spaces of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN.

Contents and summary

	*  Subspaces
	*  Linear combinations and spanning sets</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch07_inner_product_spaces?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 07: Inner Product Spaces</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch07_inner_product_spaces?rev=1737476035&amp;do=diff</link>
        <description>Chapter 07: Inner Product Spaces

Notes of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN.

Inner product spaces form and important topic of Functional Analysis. These are simply vector space over the field of real or complex numbers and with an inner product defined on them.</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch08_infinite_series?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 08: Infinite Series</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch08_infinite_series?rev=1737476035&amp;do=diff</link>
        <description>Chapter 08: Infinite Series

&lt;div&gt;&lt;img src=&quot;http://mathcity.org/images/series.gif&quot; title=&quot;Geometric series&quot; class=&quot;mediaright&quot; alt=&quot;Geometric series&quot; /&gt;&lt;/div&gt;
Notes of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN. 

Infinite series are of great importance in both pure and applied mathematics. They play a significant role in Physics and engineering. In fact many functions can be represented by infinite series. The theo…</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch09_first_order_differential_equations?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 09: First Order Differential Equations</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mathematical_method/ch09_first_order_differential_equations?rev=1737476035&amp;do=diff</link>
        <description>Chapter 09: First Order Differential Equations

Notes of the book Mathematical Method written by S.M. Yusuf, A. Majeed and M. Amin, published by Ilmi Kitab Khana, Lahore - PAKISTAN.

Contents and summary

	*  D.E and their classification
	*  Formation of differential equation</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc/fsc_part_1_mcqs/mcqs_with_answers?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>MCQs with Answers (FSc/ICS Part 1)</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_1_mcqs/mcqs_with_answers?rev=1737476035&amp;do=diff</link>
        <description>MCQs with Answers (FSc/ICS Part 1)

[MCQs Choice]
In this one PDF, MCQs of all chapters of FSc/ICS Part1 are given. There are seven chapters. Answers of MCQs is starting from page 71.

SAMPLE MCQs




	*  $i^{13}=$.............
		*  (A) $i$
		*  (B) 1
		*  (C) -1
		*  (D) 2
$S$$1, \omega, \omega^2$$-1, \omega, \omega^2$$-1, -\omega, -\omega^2$$1, -1, 2$$ax^2+bx+c=0$$a=0, b\neq 0$$a\neq 0$$a=b=0$$b=$$ax^2+bx+c=0$$a=0, b\neq 0$$a\neq 0$$a=b=0$$b=$$n!=n(n-1)(n-2)...3\cdot 2\cdot 1$$n$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc/fsc_part_2_mcqs/short_questions_by_mr._akhtar_abbas?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Short Questions by Mr. Akhtar Abbas</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_2_mcqs/short_questions_by_mr._akhtar_abbas?rev=1737476036&amp;do=diff</link>
        <description>Short Questions by Mr. Akhtar Abbas

	*  We are very thankful to Mr. Akhtar Abbas for sharing these short questions.
	*  These short questions are selected from previous 5 years papers of different boards. Solve these at your own to perform well in annual exams.$\sqrt{x^2-4}$$f(x)=\frac{2x}{x-2}$$x=2$$x^{100}$</description>
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    <item rdf:about="https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch04?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Unit 04: Introduction to Analytic Geometry</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch04?rev=1737476036&amp;do=diff</link>
        <description>Unit 04: Introduction to Analytic Geometry

[Unit 01: Functions and Limits]
Notes (Solutions) of Unit 04: Introduction to Analytic Geometry, Calculus and Analytic Geometry, MATHEMATICS 12 (Mathematics FSc Part 2 or HSSC-II), Punjab Text Book Board Lahore. You can view online or download PDF. To view PDF, you must have PDF Reader installed on your system and it can be downloaded from Software section.$ax^2+ 2hxy+by^2=0$</description>
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    <item rdf:about="https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch05?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Unit 05: Linear Inequalities and Linear Programming</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch05?rev=1737476036&amp;do=diff</link>
        <description>Unit 05: Linear Inequalities and Linear Programming

[Unit 05: Linear Inequalities and Linear Programming]
Notes (Solutions) of Unit 05: Linear Inequalities and Linear Programming, Calculus and Analytic Geometry, MATHEMATICS 12 (Mathematics FSc Part 2 or HSSC-II), Punjab Text Book Board Lahore. You can view online or download PDF. To view PDF, you must have PDF Reader installed on your system and it can be downloaded from Software section.</description>
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    <item rdf:about="https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch06?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Unit 06: Conic Section</title>
        <link>https://beta.mathcity.org/fsc/fsc_part_2_solutions/ch06?rev=1737476036&amp;do=diff</link>
        <description>Unit 06: Conic Section

[Unit 06: Conic Section]

Notes (Solutions) of Unit 06: Conic Section, Calculus and Analytic Geometry, MATHEMATICS 12 (Mathematics FSc Part 2 or HSSC-II), Punjab Text Book Board Lahore. You can view online or download PDF. To view PDF, you must have PDF Reader installed on your system and it can be downloaded from Software section.</description>
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    <item rdf:about="https://beta.mathcity.org/matric/9th_science/unit08?rev=1737476041&amp;do=diff">
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        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Unit 08: Linear Graph and their Application</title>
        <link>https://beta.mathcity.org/matric/9th_science/unit08?rev=1737476041&amp;do=diff</link>
        <description>Unit 08: Linear Graph and their Application

On this page notes of Unit 08 of Mathematics 9 written by Dr. Karamat H. Dar and Prof. Irfan-ul-Haq are given.
[Unit 08: Linear Graph and their Application]
After studying this unit the students will be able to:

	*  Identity pair of real numbers as an ordered pair.$O$$\left( O \right)$$\left( a,b \right)$$a\,$$b$$y=c.$$x=a.$$y=mx.$$y=mx+c.$</description>
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    <item rdf:about="https://beta.mathcity.org/matric/9th_science/unit11?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Unit 11: Parallelograms and Triangles</title>
        <link>https://beta.mathcity.org/matric/9th_science/unit11?rev=1737476041&amp;do=diff</link>
        <description>Unit 11: Parallelograms and Triangles

On this page notes of Unit 11 of Mathematics 9 written by Dr. Karamat H. Dar and Prof. Irfan-ul-Haq are given.
[Unit 08: Linear Graph and their Application]
After studying this unit, the students will be able to:

	*  prove that in a parallelogram
		*  the opposite sides are congruent,</description>
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    <item rdf:about="https://beta.mathcity.org/msc/notes/mathematical-method-by-khalid-latif-mir?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Mathematical Method by Khalid Latif Mir (Solutions)</title>
        <link>https://beta.mathcity.org/msc/notes/mathematical-method-by-khalid-latif-mir?rev=1737476041&amp;do=diff</link>
        <description>Mathematical Method by Khalid Latif Mir (Solutions)

[Mathematical Method by Khalid Latif Mir (Solutions)]

We are very thankful to Prof. Fazal Abbas Sajid for sharing these solutions. Problems &amp; Methods Mathematical Method by Khalid Latif Mir is a famous book taught in different universities of the Pakistan at BS and Master level. On this page, we have added the solutions of the exercises of the book. The solutions of Chapter 06: The Laplace Transform and its Applications is written by Marrium …</description>
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    <item rdf:about="https://beta.mathcity.org/msc/notes/number-theory-iqra-liaqat?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Number Theory by Ms. Iqra Liaqat</title>
        <link>https://beta.mathcity.org/msc/notes/number-theory-iqra-liaqat?rev=1737476041&amp;do=diff</link>
        <description>Number Theory by Ms. Iqra Liaqat

[Number Theory by Ms. Iqra Liaqat]

Notes of number theory provided Ms. Iqra Liaqat is a very good addition in the MSc notes section. We are actually quite grateful to her for giving these notes and likes her encouragement to distribute these notes on MathCity.org
 Name</description>
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    <item rdf:about="https://beta.mathcity.org/msc/notes/theoretical-mechanics-by-khalid-latif-mir?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Theoretical Mechanics by Khalid Latif Mir (Solutions)</title>
        <link>https://beta.mathcity.org/msc/notes/theoretical-mechanics-by-khalid-latif-mir?rev=1737476041&amp;do=diff</link>
        <description>Theoretical Mechanics by Khalid Latif Mir (Solutions)

[Theoretical Mechanics by Khalid Latif Mir (Solutions)]

We are very thankful to Prof. Fazal Abbas Sajid for sharing these solutions. An Intermediate Course in Theoretical Mechanics By Khalid Latif Mir is a famous book taught in different universities of the Pakistan. On this page, we have added the solutions of the exercises of the book.</description>
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    <item rdf:about="https://beta.mathcity.org/msc/syllabus/pu?rev=1737476041&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:01+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Syllabus for PU</title>
        <link>https://beta.mathcity.org/msc/syllabus/pu?rev=1737476041&amp;do=diff</link>
        <description>Syllabus for PU

&lt;img src=http://www.mathcity.org/images/logopu.gif alt=&quot;University of the Punjab Logo&quot; class=mediaright /&gt;

Syllabus and scheme of studies for Regular/Private students doing MSc Mathematics from University of the Punjab, Lahore. 

2 years M.Sc Mathematics programme consists of two parts namely Part-I and Part II. The regulation, Syllabi and Courses of Reading for the M.Sc. (Mathematics) Part-I and Part-II (Regular Scheme) are given below.</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch02-composition-of-forces?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 02: Composition of Forces</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch02-composition-of-forces?rev=1737476035&amp;do=diff</link>
        <description>Chapter 02: Composition of Forces

Notes of Chapter 02: Composition of Forces: Introduction to Mechanics by Q. K. Ghori published by West Pak Publishing Company (Pvt) Ltd. Notes of this chapter is send by Mr. Tahir Aziz. We are very thankful for his such effort.$(\lambda,\mu)$</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch04-centres-of-mass-and-gravity?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 04: Centres of Mass and Gravity</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch04-centres-of-mass-and-gravity?rev=1737476035&amp;do=diff</link>
        <description>Chapter 04: Centres of Mass and Gravity

Notes of Introduction to Mechanics by Q. K. Ghori published by West Pak Publishing Company (Pvt) Ltd. These notes are written by Prof. Muhammad Tanveer. Following are the main topics of this chapter.

	*  Linear Moment</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 05: Friction</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch05-friction?rev=1737476035&amp;do=diff</link>
        <description>Chapter 05: Friction

Notes of Introduction to Mechanics by Q. K. Ghori published by West Pak Publishing Company (Pvt) Ltd. These notes are written by Prof. Muhammad Tanveer. Following are the main topics of this chapter.

	*  Friction
	*  Laws of friction</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch06-virtual-work?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 06: Virtual Work</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch06-virtual-work?rev=1737476035&amp;do=diff</link>
        <description>Chapter 06: Virtual Work

Notes of Chapter 06: Virtual Work: Introduction to Mechanics by Q. K. Ghori published by West Pak Publishing Company (Pvt) Ltd. Notes of this chapter is provide by *Prof. M. Tanveer*. We are very thankful to him for such a kind effort.</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch07-kinematics?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 07: Kinematics</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch07-kinematics?rev=1737476035&amp;do=diff</link>
        <description>Chapter 07: Kinematics

Notes of Chapter 07: Kinematics: Introduction to Mechanics by Q. K. Ghori published by West Pak Publishing Company (Pvt) Ltd. Notes of this chapter is send by Mr. Tahir Aziz and Mr. Umair Sabi Ullah. We are very thankful to them for such a kind effort.</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch08-rectilinear-motion?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 08: Rectilinear Motion</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch08-rectilinear-motion?rev=1737476035&amp;do=diff</link>
        <description>Chapter 08: Rectilinear Motion

Notes of Chapter 08: Rectilinear Motion: Introduction to Mechanics by Q. K. Ghori published by West Pak Publishing Company (Pvt) Ltd. Thanks to Mr. Tahir Aziz and Atiq ur Rehman for sending these notes.

	*  Motion with constant acceleration</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 10: Motion of a Projectile</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch10-motion-of-a-projectile?rev=1737476035&amp;do=diff</link>
        <description>Chapter 10: Motion of a Projectile

Notes of Chapter 10:  Motion of a Projectile: Introduction to Mechanics by Q. K. Ghori published by West Pak Publishing Company (Pvt) Ltd. These notes are written by Prof. Shariq Mehtab Syed

	*  Trajectory of a Projectile</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch12-orbital-motion?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Chapter 12: Orbital Motion</title>
        <link>https://beta.mathcity.org/bsc/notes_of_mechanics/introduction_to_mechanics/ch12-orbital-motion?rev=1737476035&amp;do=diff</link>
        <description>Chapter 12: Orbital Motion

Notes of Chapter 12: Orbital Motion: Introduction to Mechanics by Q. K. Ghori published by West Pak Publishing Company (Pvt) Ltd. 

	*  Motion under the Central 
	*  Elliptic Orbit under a  central Force 
	*  Polar form of the Orbit</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/paper_pattern/punjab_university/b.sc._paper_pattern_for_general_mathematics?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Paper Pattern for General Mathematics</title>
        <link>https://beta.mathcity.org/bsc/paper_pattern/punjab_university/b.sc._paper_pattern_for_general_mathematics?rev=1737476035&amp;do=diff</link>
        <description>Paper Pattern for General Mathematics

Paper pattern for General Mathematics chapter-wise for University of the Punjab, Lahore is given on this page. This pattern is extracted from syllabus and old papers, so use at your own risk. This pattern is made by Prof. Muhammad Farooq.
&lt;img src=&quot;../../../files/bsc/BSC_maths_paper_pattern_general_farooq.gif&quot; alt=&quot;BSc Mathematics Paper Pattern&quot; class=&quot;mediacenter img-responsive&quot; /&gt;</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/paper_pattern/punjab_university/b.sc._paper_pattern_for_general_mathematics_split_program?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Syllabus &amp; Paper Pattern for General Mathematics (Split Program)</title>
        <link>https://beta.mathcity.org/bsc/paper_pattern/punjab_university/b.sc._paper_pattern_for_general_mathematics_split_program?rev=1737476035&amp;do=diff</link>
        <description>Syllabus &amp; Paper Pattern for General Mathematics (Split Program)

There was one examination after two years for BA/BSc Program from University of Punjab (PU), Lahore but from this year (2016), PU has made changes in its examination policies for the said program. The BA/BSc Program has been split into two parts. Syllabus is break into two part year wise. After the each year of the program candidate has to appeared in examination instead of appearing after two year. In this regards syllabus of Gen…</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/paper_pattern/punjab_university/b.sc._paper_pattern_for_mathematics_a_course?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Paper Pattern for A-Course of Mathematics</title>
        <link>https://beta.mathcity.org/bsc/paper_pattern/punjab_university/b.sc._paper_pattern_for_mathematics_a_course?rev=1737476035&amp;do=diff</link>
        <description>Paper Pattern for A-Course of Mathematics

Paper pattern for A-Course of Mathematics, chapter-wise for University of the Punjab, Lahore is given on this page. This pattern is extracted from syllabus and old papers, so use at your own risk.


&lt;img src=&quot;../../../files/bsc/BSC_maths_paper_pattern_farooq_a.gif&quot; alt=&quot;BSc Mathematics Paper Pattern&quot; class=&quot;mediacenter img-responsive&quot; /&gt;


&lt;callout type=</description>
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    <item rdf:about="https://beta.mathcity.org/bsc/paper_pattern/punjab_university/b.sc._paper_pattern_for_mathematics_b_course?rev=1737476035&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:55+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Paper Pattern for B-Course of Mathematics</title>
        <link>https://beta.mathcity.org/bsc/paper_pattern/punjab_university/b.sc._paper_pattern_for_mathematics_b_course?rev=1737476035&amp;do=diff</link>
        <description>Paper Pattern for B-Course of Mathematics

Paper pattern for B-Course of Mathematics chapter-wise for University of the Punjab, Lahore is given on this page. This pattern is extracted from syllabus and old papers, so use at your own risk. This pattern is made by Prof. Muhammad Farooq.
&lt;img src=&quot;../../../files/bsc/BSC_maths_paper_pattern_farooq_b.gif&quot; alt=&quot;BSc Mathematics Paper Pattern Paper A&quot; 
 class=&quot;mediacenter img-responsive&quot; /&gt;</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p1?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 1.1

Solutions of Question 1 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
${{i}^{9}}+{{i}^{19}}$\begin{align}{{i}^{9}}+{{i}^{19}}&amp;=i\cdot{{i}^{8}}+i\cdot{{i}^{18}}\\
&amp;=i\cdot{{\left( {{i}^{2}} \right)}^{4}}+i\cdot{{\left( {{i}^{2}} \right)}^{9}}\\
&amp;=i\cdot{{\left( -1 \right)}^{4}}+i\cdot{{\left( -1 \right)}^{9}}\\
&amp;=i\cdo…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2 &amp; 3, Exercise 1.1

Solutions of Question 2 &amp; 3 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
${{i}^{107}}+{{i}^{112}}+{{i}^{122}}+{{i}^{153}}=0$\begin{align}L.H.S.&amp;={{i}^{107}}+{{i}^{112}}+{{i}^{122}}+{{i}^{153}}\\
&amp;=i\cdot i^{106}+i^{112}+i^{122}+i\cdot i^{152}\\
&amp;=i.{{\left( {{i}^{2}} \right)}^{53}}+{{\left( {{i}^{2}} \right)}^{56}}+…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 4, Exercise 1.1

Solutions of Question 4 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)
$\left( a,0 \right)\left( 2,-b \right)$\begin{align}&amp;\left( a,0 \right)-\left( 2,-b \right)\\
&amp;=\left( a+0i \right)-\left( 2-bi \right)\\
&amp;=\left( a-2 \right)+\left( 0+b \right)i\\
&amp;=\left( a-2 \right)+bi\end{align}$\left( -3,\dfrac{1}{2} \right)\le…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p4?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p4?rev=1737476036&amp;do=diff</link>
        <description>Question 5, Exercise 1.1

Solutions of Question 5 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$8i+11,-7+5i$\begin{align}&amp;(8i+11)\times (-7+5i)\\
&amp;=\left( 11+8i \right)\times \left( -7+5i \right)\\
&amp;=\left( -77+40{{i}^{2}} \right)+\left( 55-56 \right)i\\
&amp;=\left( -77+40\left( -1 \right) \right)+\left( 55-56 \right)i\\
&amp;=\left( -77-40 \right)+…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p5?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p5?rev=1737476036&amp;do=diff</link>
        <description>Question 6, Exercise 1.1

Solutions of Question 6 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
$\dfrac{4+i}{3+5i}$$a+ib$\begin{align}\dfrac{4+i}{3+5i}&amp;=\dfrac{4+i}{3+5i}\times \dfrac{3-5i}{3-5i}\\
&amp;=\dfrac{\left( 12+5 \right)+\left( 3-20 \right)i}{9-25{{i}^{2}}}\\
&amp;=\dfrac{17-17i}{9+25}\\
&amp;=\dfrac{17}{34}-\dfrac{17}{34}i\\
&amp;=\dfrac{1}{2}-\dfr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p6?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p6?rev=1737476036&amp;do=diff</link>
        <description>Question 7, Exercise 1.1

Solutions of Question 7 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
${{z}_{1}}=1+2i$${{z}_{2}}=2+3i$$|{{z}_{1}}+{{z}_{2}}|$$z_1=1+2i$$z_2=2+3i$\begin{align}
{{z}_{1}}+{{z}_{2}}&amp;=1+2i+2+3i\\
&amp;=1+2+2i+3i\\
&amp;=3+5i
\end{align}\begin{align}
|z_1+z_2|&amp;=\sqrt{3^2+5^2}\\
&amp;=\sqrt{9+25}\\ 
&amp;=\sqrt{34}\end{align}${{z}_{1}}=1+2…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p7?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p7?rev=1737476036&amp;do=diff</link>
        <description>Question 8, Exercise 1.1

Solutions of Question 8 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$\dfrac{1-2i}{2+i}+\dfrac{4-i}{3+2i}$$a+ib.$\begin{align}&amp;\dfrac{1-2i}{2+i}+\dfrac{4-i}{3+2i}\\
&amp;=\dfrac{\left( 3+2i \right)\left( 1-2i \right)+\left( 2+i \right)\left( 4-i \right)}{\left( 2+i \right)\left( 3+2i \right)}\\
&amp;=\dfrac{\left( 3+4+2i-6i …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p8?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 1.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-1-p8?rev=1737476036&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 1.1

Solutions of Question 9 &amp; 10 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$\dfrac{\left( 3-2i \right)\left( 2+3i \right)}{\left( 1+2i \right)\left( 2-i \right)}$\begin{align}z&amp;=\dfrac{\left( 3-2i \right)\left( 2+3i \right)}{\left( 1+2i \right)\left( 2-i \right)}\\
&amp;=\dfrac{6+6+9i-4i}{2+2+4i-i}\\
&amp;=\dfrac{12+5i}{4+3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p1?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 1.2

Solutions of Question 1 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

If ${{z}_{1}}=2+i$${{z}_{2}}=1-i$${{z}_{1}}=2+i$${{z}_{2}}=1-i$$$z_1+z_2=z_2+z_1.$$\begin{align}z_1+z_2&amp;=(2+i)+(1-i)\\ 
&amp;=3 \ldots (i) \end{align}\begin{align} 
z_2+z_1&amp;=(1-i)+(2+i)\\
&amp;=3 \ldots (ii)\end{align}$$z_1 z_2=z_2 z_1.$$\begin{align}z_1 z_2 …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p2?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 1.2

Solutions of Question 2 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2

$z_1=-1+i$, $z_2=3-2i$${{z}_{3}}=2-2i$${{z}_{1}}=-1+i$${{z}_{2}}=3-2i$${{z}_{3}}=2-2i$$$(z_1+z_2)+z_3=z_1+(z_2+z_3).$$\begin{align} 
{{z}_{1}}+{{z}_{2}}&amp;=\left( -1+i \right)+\left( 3-2i \right)\\
&amp;=2-i\end{align}\begin{align}
\left( {{z}_{1}}+{{z}_{2}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p3?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 1.2

Solutions of Question 3 &amp; 4 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
${{z}_{1}}=\sqrt{3}+\sqrt{2}i$${{z}_{2}}=\sqrt{2}-\sqrt{3}i$${{z}_{3}}=2+3i$${{z}_{1}}=\sqrt{3}+\sqrt{2}i$${{z}_{2}}=\sqrt{2}-\sqrt{3}i$${{z}_{3}}=2+3i$\begin{align}{{z}_{1}}\left( {{z}_{2}}+{{z}_{3}} \right)&amp;={{z}_{1}}{{z}_{2}}+{{z}_{1}}{{z}_{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p4?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p4?rev=1737476036&amp;do=diff</link>
        <description>Question 5, Exercise 1.2

Solutions of Question 5 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
${{z}_{1}}=2+4i$${{z}_{2}}=1-3i$$\overline{{{z}_{1}}+{{z}_{2}}}=\overline{{{z}_{1}}}+\overline{{{z}_{2}}}$${{z}_{1}}=2+4i$${{z}_{2}}=1-3i$$\overline{{{z}_{1}}}=2-4i$$\overline{{{z}_{2}}}=1+3i$\begin{align}z_1+z_2&amp;=2+4i+1-3i\\
&amp;=3+i \end{align}\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p5?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p5?rev=1737476036&amp;do=diff</link>
        <description>Question 6, Exercise 1.2

Solutions of Question 6 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
${{z}_{1}}$${{z}_{2}}$$|{{z}_{1}}{{z}_{2}}|=|{{z}_{1}}||{{z}_{2}}|$${{z}_{1}}=a+bi$${{z}_{2}}=c+di$$|z_1=\sqrt{a^2+b^2}|$$|z_2=\sqrt{c^2+d^2}|$\begin{align}
L.H.S.&amp;=|{{z}_{1}}{{z}_{2}}|\\
&amp;=|(a+bi)(c+di)|\\ 
&amp;=|ac-bd+(ad+bc)i|\\
&amp;=\sqrt{{{(ac-bd)}^{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p6?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p6?rev=1737476036&amp;do=diff</link>
        <description>Question 7, Exercise 1.2

Solutions of Question 7 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$\dfrac{2+3i}{5-2i}$\begin{align}&amp;\dfrac{2+3i}{5-2i} \\
=&amp;\dfrac{2+3i}{5-2i}\times \dfrac{5+2i}{5+2i} \quad \text{by rationalizing} \\
=&amp;\dfrac{10-6+15i+4i}{25+4}\\
=&amp;\dfrac{4+19i}{29}\\
=&amp;\dfrac{4}{29}+\dfrac{19}{29}i \end{align}$=\dfrac{4}{29}$$=\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p7?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-2-p7?rev=1737476036&amp;do=diff</link>
        <description>Question 8, Exercise 1.2

Solutions of Question 8 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$z+\overline{z}=2\operatorname{Re}\left( z \right)$$z=a+ib$$\overline{z}=a-ib$\begin{align}z+\overline{z}&amp;=\left( a+ib \right)+\left( a-ib \right)\\
&amp;=a+ib+a-ib\\
&amp;=2a\\
z+\overline{z}&amp;=2\operatorname{Re}\left( z \right)\end{align}$z-\overline{z}=2i…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p1?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 1.3

Solutions of Question 1 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
\begin{align}&amp;z-4w=3i\\ 
&amp;2z+3w=11-5i\end{align}\begin{align}z-4w&amp;=3i		…(i)\\
2z+3w&amp;=11-5i	…(ii)\end{align}$2$\begin{align}2z-8w&amp;=6i		…(iii)\end{align}\[\begin{array}{cccc}
2z&amp;-8w&amp;=6i  \\  
\mathop+\limits_{-}2z&amp;\mathop+\limits_{-}3w&amp;=\mathop-\limit…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p2?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 1.3

Solutions of Question 2 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$P(z)$$$P\left( z \right)={{z}^{3}}+6z+20$$$$p\left( z \right)={{z}^{3}}+6z+20$$$(z-a)$$P(z)$$P(a)=0$$z=-2$\begin{align}
P(-2)&amp;=(-2)^3+6(-2)+20\\
&amp;=-8-12+20\\
&amp;=0\end{align}$z+2$${{z}^{3}}+6z+20$$$\begin{array}{c|cccc}
-2 &amp; 1 &amp; 0 &amp; 6 &amp; 20 \\  
 &amp; \d…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p3?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 1.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 1.3

Solutions of Question 3 &amp; 4 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
${{z}_{1}}=-1+i$${{z}_{2}}=-1-i$${{z}^{2}}+2z+2=0$$$z^2+2z_1+2=0\quad \ldots (i)$$$z_1=-1+i$\begin{align}L.H.S &amp;= (-1+i)^2+2(-1+i)+2\\
&amp;=1-2i-1-2+2i+2\\
&amp;=0=R.H.S\end{align}$z_1=-1+i$$z_2=-1-i$\begin{align}
L.H.S&amp;=(-1-i)^2+2(-1-i)+2\\
&amp;=1+2i-1-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p4?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/ex1-3-p4?rev=1737476036&amp;do=diff</link>
        <description>Question 5, Exercise 1.3

Solutions of Question 5 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
${{z}^{2}}+z+3=0$${{z}^{2}}+z+3=0$$a=1,\,\,\,b=1$$c=3$\begin{align}z&amp;=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\\ 
z&amp;=\dfrac{-\left( 1 \right)\pm \sqrt{{{\left( 1 \right)}^{2}}-4\left( 1 \right)\left( 3 \right)}}{2\left( 1 \right)}\\
z&amp;=\dfrac{-1\pm \s…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p1?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise 1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Review Exercise 1

Solutions of Question 1 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1
${{\left( \dfrac{2i}{1+i} \right)}^{2}}$$i$$2i$$1-i$$i+1$$\dfrac{5+2i}{4-3i}$$-\dfrac{7}{25}+\dfrac{26}{25}i$$\dfrac{5}{4}-\dfrac{2}{3}i$$\dfrac{14}{25}+\dfrac{23}{25}i$$\dfrac{26}{7}+\dfrac{23}{7}i$${{i}^{57}}+\frac{1}{{{i}^{25}}}$$0$$2i$$-2…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p2?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3, Review Exercise 1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2 &amp; 3, Review Exercise 1

Solutions of Question 2 &amp; 3 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{i}^{n}}+{{i}^{n+1}}+{{i}^{n+2}}+{{i}^{n+3}}=0$$\forall n\in N$\begin{align}{{i}^{n}}+{{i}^{n+1}}+{{i}^{n+2}}+{{i}^{n+3}}&amp;=0\\
L.H.S.&amp;={{i}^{n}}+{{i}^{n}}\cdot i+{{i}^{n}}\cdot {{i}^{2}}+{{i}^{n}}\cdot {{i}^{3}}\\
&amp;={{i}^{n}}\left( 1+i+{{i}^{2}}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p3?rev=1737476036&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise 1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit01/review-ex-1-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise 1

Solutions of Question 4 &amp; 5 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{z}_{1}}=2-i$${{z}_{2}}=1+i,$$|\dfrac{{{z}_{1}}+{{z}_{2}}+1}{{{z}_{1}}-{{z}_{2}}+1}|$\begin{align}{{z}_{1}}&amp;=2-i,\\
{{z}_{2}}&amp;=1+i,\\
\dfrac{{{z}_{1}}+{{z}_{2}}+1}{{{z}_{1}}-{{z}_{2}}+1}&amp;=\dfrac{\left( 2-i \right)+\left( 1+i \right)+1}{\left( 2-…</description>
    </item>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$\sin {{37}^{\circ }}\cos {{22}^{\circ }}+\cos {{37}^{\circ }}\sin {{22}^{\circ }}$\begin{align} \sin (\alpha +\beta )=\sin \alpha \cos \beta +\cos \alpha \sin \beta, \end{align}\begin{a…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p2?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 10.1

Solutions of Question 2 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \dfrac{\pi }{12}$$\dfrac{\pi }{12}$$\dfrac{\pi }{3}-\dfrac{\pi }{4}$\begin{align}\sin (\alpha -\beta )=\sin \alpha \cos \beta -\cos \alpha \sin.\end{align}\begin{align} \Rightarrow \quad \sin \left( \frac{\pi }{3}-\f…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p3?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3, Exercise 10.1

Solutions of Question 3 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin u=\dfrac{3}{5}$$\sin v=\dfrac{4}{5}$$u$$v$$0$$\dfrac{\pi }{2}$$\cos \left( u+v \right)$$\sin u=\dfrac{3}{5},$$0\le u\le \dfrac{\pi }{2}.$$\sin v=\dfrac{4}{5},$$0\le v\le \dfrac{\pi }{2}.$$\cos u=\pm \sqrt{1-{{\sin }^…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p4?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p4?rev=1737476036&amp;do=diff</link>
        <description>Question, Exercise 10.1

Solutions of Question 4 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \alpha =-\dfrac{4}{5}$$\cos \beta =-\dfrac{12}{13}$$\alpha $$\beta $$\sin \left( \alpha -\beta  \right)$$\sin \alpha=-\dfrac{4}{5}$$\alpha$$\sin \beta=-\dfrac{12}{13}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$$\…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p5?rev=1737476036&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p5?rev=1737476036&amp;do=diff</link>
        <description>Question 5, Exercise 10.1

Solutions of Question 5 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\tan \alpha =\dfrac{3}{4}$$\sec \beta =\dfrac{13}{5}$$\alpha$$\beta$$\sin \left( \alpha +\beta  \right)$$\tan\alpha =\dfrac{3}{4}$$\tan\alpha$$\alpha$\begin{align}{{\sec}^{2}}\alpha &amp;=1+{{\tan}^{2}}\alpha\\
\Rightarrow \q…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p6?rev=1737476036&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p6?rev=1737476036&amp;do=diff</link>
        <description>Question 6, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos \alpha =2{{\cos }^{2}}\dfrac{\alpha }{2}-1=1-2{{\sin }^{2}}\dfrac{\alpha }{2}$\begin{align}L.H.S&amp;=\cos \alpha \\
\cos \alpha &amp;=\cos 2\dfrac{\alpha }{2}\\
&amp;={{\cos }^{2}}\dfrac{\alpha }{2}-{{\sin }^{2}}\dfrac{\alpha }…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p7?rev=1737476036&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p7?rev=1737476036&amp;do=diff</link>
        <description>Question 7, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cot \left( \alpha +\beta  \right)=\dfrac{\cot \alpha \cot \beta -1}{\cot \alpha +\cot \beta }$\begin{align}L.H.S.&amp;=\cot (\alpha +\beta )\\
&amp;=\dfrac{1}{\tan (\alpha +\beta )}\\
&amp;=\dfrac{1}{\,\dfrac{\tan \alpha +\tan \beta…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p8?rev=1737476036&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p8?rev=1737476036&amp;do=diff</link>
        <description>Question 8, Exercise 10.1

Solutions of Question 8 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\tan \left( \dfrac{\pi }{4}+\theta  \right)=\dfrac{\cos \theta +\sin \theta }{\cos \theta -\sin \theta }$\begin{align}L.H.S.&amp;=\tan \left( \dfrac{\pi }{4}+\theta  \right)\\ 
&amp;=\dfrac{\sin \left( \dfrac{\pi }{4}+\theta  \ri…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p9?rev=1737476036&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p9?rev=1737476036&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 10.1

Solutions of Question 9 and 10 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{\sin \theta }{\sec 4\theta }+\dfrac{\cos \theta }{\cos ec4\theta }=\sin 5\theta $\begin{align}L.H.S.&amp;=\dfrac{\sin \theta }{\sec 4\theta }+\dfrac{\cos \theta }{\cos ec4\theta }\\
&amp;=\dfrac{\sin \theta }…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p10?rev=1737476036&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question11 and 12, Exercise 10.1</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-1-p10?rev=1737476036&amp;do=diff</link>
        <description>Question11 and 12, Exercise 10.1

Solutions of Question 11 and 12 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\alpha$$\beta$$\gamma$$ABC$$\cot \dfrac{\alpha }{2}+\cot \dfrac{\beta }{2}+\cot \dfrac{\gamma }{2}=\cot \dfrac{\alpha }{2}\cot \dfrac{\beta }{2}\cot \dfrac{\gamma }{2}$$\alpha$$\beta$$\gamma$\begin{align}&amp;\…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p1?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 10.2

Solutions of Question 1 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$\sin 2\theta ,\,\,\cos 2\theta$$\tan 2\theta$$\tan \theta =-\dfrac{1}{5}$$\theta$$\sin \theta =\dfrac{1}{\sqrt{26}}$$\cos \theta =\dfrac{-5}{\sqrt{26}}$\begin{align}\sin 2\theta &amp;=2\sin…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p2?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 10.2

Solutions of Question 2 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \theta =\dfrac{5}{13}$$\theta $$\sin 2\theta $$\sin \theta =\dfrac{5}{13}$$$\cos \theta =\pm \sqrt{1-{{\sin }^{2}}\theta }.$$$\theta$$\cos$\begin{align}\cos\theta &amp;=-\sqrt{1-{{\sin }^{2}}\theta }\\
&amp;=-\sqrt{1-\left(\…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p3?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3, Exercise 10.2

Solutions of Question 3 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \theta =\dfrac{4}{5}$$\theta$$\sin2\theta$$\sin \theta =\dfrac{4}{5}$$\theta$$\cos \theta =-\dfrac{3}{5}$\begin{align}\sin 2\theta &amp;=2\sin \theta \cos \theta \\
&amp;=2\left( \dfrac{4}{5} \right)\left( -\dfrac{3}{5} \rig…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p4?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 and 5, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p4?rev=1737476036&amp;do=diff</link>
        <description>Question 4 and 5, Exercise 10.2

Solutions of Question 4 and 5 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos \theta =-\dfrac{3}{7}$$\theta $$\sin \dfrac{\theta }{2}$$\cos \theta =-\dfrac{3}{7}$$\theta$\begin{align}&amp;\pi &lt; \theta &lt; \dfrac{3\pi}{2} \\
\implies &amp;\frac{\pi}{2} &lt; \frac{\theta}{2} &lt; \dfrac{3\pi}{4}\end…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p5?rev=1737476036&amp;do=diff</link>
        <description>Question 6, Exercise 10.2

Solutions of Question 6 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{15}^{\circ }}$${{15}^{\circ }}=\dfrac{{{30}^{\circ }}}{2}$$\dfrac{\theta }{2}=\dfrac{{{30}^{\circ }}}{2}$$\cos {{15}^{\circ }}$\begin{align}\cos {{15}^{\circ }}&amp;=\cos \dfrac{{{30}^{\circ }}}{2}=\sqrt{\dfrac{1+\cos …</description>
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 10.2</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-2-p6?rev=1737476036&amp;do=diff</link>
        <description>Question 7, Exercise 10.2

Solutions of Question 7 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\cos }^{4}}\theta -{{\sin }^{4}}\theta =\dfrac{1}{\sec 2\theta }$\begin{align}L.H.S&amp;={{\cos }^{4}}\theta -{{\sin }^{4}}\theta \\ 
&amp;=\left( {{\cos }^{2}}\theta -{{\sin }^{2}}\theta  \right)\left( {{\cos }^{2}}\theta +{{\…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p1?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p1?rev=1737476036&amp;do=diff</link>
        <description>Question 1, Exercise 10.3

Solutions of Question 1 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$2\sin 6x\sin x$$$-2\sin \alpha \sin \beta =\cos (\alpha +\beta )-\cos (\alpha -\beta ).$$$\alpha =6x$$\beta =x$\begin{align}-\,2\sin 6x\sin x&amp;=\cos (6x+x)-\cos (6x-x)\\
&amp;=\cos 7x-\cos x…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p2?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p2?rev=1737476036&amp;do=diff</link>
        <description>Question 2, Exercise 10.3

Solutions of Question 2 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\sin {{37}^{\circ }}+\sin {{43}^{\circ }}.$$$$\sin \alpha +\sin \beta =2\sin \left( \dfrac{\alpha +\beta }{2} \right)\cos \left( \dfrac{\alpha -\beta }{2} \right).$$$\alpha ={{37}^{\circ }}$$\beta ={{43}^{\circ }}$\begin…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p3?rev=1737476036&amp;do=diff">
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        <dc:date>2025-01-21T16:13:56+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p3?rev=1737476036&amp;do=diff</link>
        <description>Question 3, Exercise 10.3

Solutions of Question 3 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\dfrac{\cos {{75}^{\circ }}+\cos {{15}^{\circ }}}{\sin {{75}^{\circ }}-\sin {{15}^{\circ }}}=\sqrt{3}.$$$$\cos \alpha +\cos \beta =2\cos \left( \dfrac{\alpha +\beta }{2} \right)\cos \left( \dfrac{\alpha -\beta }{2} \righ…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p4?rev=1737476037&amp;do=diff">
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.3</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/ex10-3-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 10.3

Solutions of Question 5 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\cos {{20}^{\circ }}\cos {{40}^{\circ }}\cos {{60}^{\circ }}\cos {{80}^{\circ }}=\dfrac{1}{16}.$$$2\cos \alpha \cos \beta =\cos \left( \alpha +\beta  \right)+\cos \left( \alpha -\beta  \right)$\begin{align}L.H.S.&amp;=\cos {…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise 10</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Review Exercise 10

Solutions of Question 1 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{50}^{\circ }}5{0}&#039;\cos {{9}^{\circ }}1{0}&#039;-\sin {{50}^{\circ }}5{0}&#039;\sin {{9}^{\circ }}1{0}&#039;=$$0$$\dfrac{1}{2}$$1$$\dfrac{\sqrt{3}}{2}$$\tan {{15}^{\circ }}=2-\sqrt{3}$${{\cot }^{2}}{{75}^{\circ }}$$7+\sq…</description>
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    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p2?rev=1737476037&amp;do=diff">
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Review Exercise 10</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 and 3, Review Exercise 10

Solutions of Question 2 and 3 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{2\sin \theta \sin 2\theta }{\cos \theta +\cos 3\theta }=\tan 2\theta \tan \theta $\begin{align}L.H.S.&amp;=\dfrac{2\sin \theta \sin 2\theta }{\cos \theta +\cos 3\theta }\\
&amp;=\dfrac{2\sin \theta \s…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise 10</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise 10

Solutions of Question 4 &amp; 5 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\sin }^{2}}\dfrac{\theta }{2}=\dfrac{\sin \theta \tan \dfrac{\theta }{2}}{2}$\begin{align}R.H.S.&amp;=\dfrac{\sin \theta \tan \dfrac{\theta }{2}}{2}\\
&amp;=\dfrac{\sin \theta \sin \dfrac{\theta }{2}}{2\cos \d…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7, Review Exercise 10</title>
        <link>https://beta.mathcity.org/fsc-part1-kpk/sol/unit10/re-ex10-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 6 &amp; 7, Review Exercise 10

Solutions of Question 6 &amp; 7 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos 4\theta =1-8{{\sin }^{2}}\theta {{\cos }^{2}}\theta $\begin{align}L.H.S&amp;=\cos 4\theta \\
&amp;=\cos 2\left( 2\theta  \right)\\
&amp;=1-2si{{n}^{2}}2\theta \\
&amp;=1-2{{\left( 2sin\theta \cos \theta  \right)}^{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 1.1

Solutions of Question 1 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
${{i}^{9}}+{{i}^{19}}$\begin{align}{{i}^{9}}+{{i}^{19}}&amp;=i\cdot{{i}^{8}}+i\cdot{{i}^{18}}\\
&amp;=i\cdot{{\left( {{i}^{2}} \right)}^{4}}+i\cdot{{\left( {{i}^{2}} \right)}^{9}}\\
&amp;=i\cdot{{\left( -1 \right)}^{4}}+i\cdot{{\left( -1 \right)}^{9}}\\
&amp;=i\cdo…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 &amp; 3, Exercise 1.1

Solutions of Question 2 &amp; 3 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
${{i}^{107}}+{{i}^{112}}+{{i}^{122}}+{{i}^{153}}=0$\begin{align}L.H.S.&amp;={{i}^{107}}+{{i}^{112}}+{{i}^{122}}+{{i}^{153}}\\
&amp;=i\cdot i^{106}+i^{112}+i^{122}+i\cdot i^{152}\\
&amp;=i.{{\left( {{i}^{2}} \right)}^{53}}+{{\left( {{i}^{2}} \right)}^{56}}+…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 4, Exercise 1.1

Solutions of Question 4 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)
$\left( a,0 \right)\left( 2,-b \right)$\begin{align}&amp;\left( a,0 \right)-\left( 2,-b \right)\\
&amp;=\left( a+0i \right)-\left( 2-bi \right)\\
&amp;=\left( a-2 \right)+\left( 0+b \right)i\\
&amp;=\left( a-2 \right)+bi\end{align}$\left( -3,\dfrac{1}{2} \right)\le…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 1.1

Solutions of Question 5 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$8i+11,-7+5i$\begin{align}&amp;(8i+11)\times (-7+5i)\\
&amp;=\left( 11+8i \right)\times \left( -7+5i \right)\\
&amp;=\left( -77+40{{i}^{2}} \right)+\left( 55-56 \right)i\\
&amp;=\left( -77+40\left( -1 \right) \right)+\left( 55-56 \right)i\\
&amp;=\left( -77-40 \right)+…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 6, Exercise 1.1

Solutions of Question 6 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
$\dfrac{4+i}{3+5i}$$a+ib$\begin{align}\dfrac{4+i}{3+5i}&amp;=\dfrac{4+i}{3+5i}\times \dfrac{3-5i}{3-5i}\\
&amp;=\dfrac{\left( 12+5 \right)+\left( 3-20 \right)i}{9-25{{i}^{2}}}\\
&amp;=\dfrac{17-17i}{9+25}\\
&amp;=\dfrac{17}{34}-\dfrac{17}{34}i\\
&amp;=\dfrac{1}{2}-\dfr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 1.1

Solutions of Question 7 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
${{z}_{1}}=1+2i$${{z}_{2}}=2+3i$$|{{z}_{1}}+{{z}_{2}}|$$z_1=1+2i$$z_2=2+3i$\begin{align}
{{z}_{1}}+{{z}_{2}}&amp;=1+2i+2+3i\\
&amp;=1+2+2i+3i\\
&amp;=3+5i
\end{align}\begin{align}
|z_1+z_2|&amp;=\sqrt{3^2+5^2}\\
&amp;=\sqrt{9+25}\\ 
&amp;=\sqrt{34}\end{align}${{z}_{1}}=1+2…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 8, Exercise 1.1

Solutions of Question 8 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$\dfrac{1-2i}{2+i}+\dfrac{4-i}{3+2i}$$a+ib.$\begin{align}&amp;\dfrac{1-2i}{2+i}+\dfrac{4-i}{3+2i}\\
&amp;=\dfrac{\left( 3+2i \right)\left( 1-2i \right)+\left( 2+i \right)\left( 4-i \right)}{\left( 2+i \right)\left( 3+2i \right)}\\
&amp;=\dfrac{\left( 3+4+2i-6i …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-1-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 1.1

Solutions of Question 9 &amp; 10 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$\dfrac{\left( 3-2i \right)\left( 2+3i \right)}{\left( 1+2i \right)\left( 2-i \right)}$\begin{align}z&amp;=\dfrac{\left( 3-2i \right)\left( 2+3i \right)}{\left( 1+2i \right)\left( 2-i \right)}\\
&amp;=\dfrac{6+6+9i-4i}{2+2+4i-i}\\
&amp;=\dfrac{12+5i}{4+3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 1.2

Solutions of Question 1 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

If ${{z}_{1}}=2+i$${{z}_{2}}=1-i$${{z}_{1}}=2+i$${{z}_{2}}=1-i$$$z_1+z_2=z_2+z_1.$$\begin{align}z_1+z_2&amp;=(2+i)+(1-i)\\ 
&amp;=3 \ldots (i) \end{align}\begin{align} 
z_2+z_1&amp;=(1-i)+(2+i)\\
&amp;=3 \ldots (ii)\end{align}$$z_1 z_2=z_2 z_1.$$\begin{align}z_1 z_2 …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 1.2

Solutions of Question 2 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2

$z_1=-1+i$, $z_2=3-2i$${{z}_{3}}=2-2i$${{z}_{1}}=-1+i$${{z}_{2}}=3-2i$${{z}_{3}}=2-2i$$$(z_1+z_2)+z_3=z_1+(z_2+z_3).$$\begin{align} 
{{z}_{1}}+{{z}_{2}}&amp;=\left( -1+i \right)+\left( 3-2i \right)\\
&amp;=2-i\end{align}\begin{align}
\left( {{z}_{1}}+{{z}_{2}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 1.2

Solutions of Question 3 &amp; 4 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
${{z}_{1}}=\sqrt{3}+\sqrt{2}i$${{z}_{2}}=\sqrt{2}-\sqrt{3}i$${{z}_{3}}=2+3i$${{z}_{1}}=\sqrt{3}+\sqrt{2}i$${{z}_{2}}=\sqrt{2}-\sqrt{3}i$${{z}_{3}}=2+3i$\begin{align}{{z}_{1}}\left( {{z}_{2}}+{{z}_{3}} \right)&amp;={{z}_{1}}{{z}_{2}}+{{z}_{1}}{{z}_{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 1.2

Solutions of Question 5 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
${{z}_{1}}=2+4i$${{z}_{2}}=1-3i$$\overline{{{z}_{1}}+{{z}_{2}}}=\overline{{{z}_{1}}}+\overline{{{z}_{2}}}$${{z}_{1}}=2+4i$${{z}_{2}}=1-3i$$\overline{{{z}_{1}}}=2-4i$$\overline{{{z}_{2}}}=1+3i$\begin{align}z_1+z_2&amp;=2+4i+1-3i\\
&amp;=3+i \end{align}\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 6, Exercise 1.2

Solutions of Question 6 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)
${{z}_{1}}$${{z}_{2}}$$|{{z}_{1}}{{z}_{2}}|=|{{z}_{1}}||{{z}_{2}}|$${{z}_{1}}=a+bi$${{z}_{2}}=c+di$$|z_1=\sqrt{a^2+b^2}|$$|z_2=\sqrt{c^2+d^2}|$\begin{align}
L.H.S.&amp;=|{{z}_{1}}{{z}_{2}}|\\
&amp;=|(a+bi)(c+di)|\\ 
&amp;=|ac-bd+(ad+bc)i|\\
&amp;=\sqrt{{{(ac-bd)}^{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 1.2

Solutions of Question 7 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$\dfrac{2+3i}{5-2i}$\begin{align}&amp;\dfrac{2+3i}{5-2i} \\
=&amp;\dfrac{2+3i}{5-2i}\times \dfrac{5+2i}{5+2i} \quad \text{by rationalizing} \\
=&amp;\dfrac{10-6+15i+4i}{25+4}\\
=&amp;\dfrac{4+19i}{29}\\
=&amp;\dfrac{4}{29}+\dfrac{19}{29}i \end{align}$=\dfrac{4}{29}$$=\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-2-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 8, Exercise 1.2

Solutions of Question 8 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$z+\overline{z}=2\operatorname{Re}\left( z \right)$$z=a+ib$$\overline{z}=a-ib$\begin{align}z+\overline{z}&amp;=\left( a+ib \right)+\left( a-ib \right)\\
&amp;=a+ib+a-ib\\
&amp;=2a\\
z+\overline{z}&amp;=2\operatorname{Re}\left( z \right)\end{align}$z-\overline{z}=2i…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 1.3

Solutions of Question 1 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
\begin{align}&amp;z-4w=3i\\ 
&amp;2z+3w=11-5i\end{align}\begin{align}z-4w&amp;=3i		…(i)\\
2z+3w&amp;=11-5i	…(ii)\end{align}$2$\begin{align}2z-8w&amp;=6i		…(iii)\end{align}\[\begin{array}{cccc}
2z&amp;-8w&amp;=6i  \\  
\mathop+\limits_{-}2z&amp;\mathop+\limits_{-}3w&amp;=\mathop-\limit…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 1.3

Solutions of Question 2 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$P(z)$$$P\left( z \right)={{z}^{3}}+6z+20$$$$p\left( z \right)={{z}^{3}}+6z+20$$$(z-a)$$P(z)$$P(a)=0$$z=-2$\begin{align}
P(-2)&amp;=(-2)^3+6(-2)+20\\
&amp;=-8-12+20\\
&amp;=0\end{align}$z+2$${{z}^{3}}+6z+20$$$\begin{array}{c|cccc}
-2 &amp; 1 &amp; 0 &amp; 6 &amp; 20 \\  
 &amp; \d…</description>
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        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 1.3

Solutions of Question 3 &amp; 4 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
${{z}_{1}}=-1+i$${{z}_{2}}=-1-i$${{z}^{2}}+2z+2=0$$$z^2+2z_1+2=0\quad \ldots (i)$$$z_1=-1+i$\begin{align}L.H.S &amp;= (-1+i)^2+2(-1+i)+2\\
&amp;=1-2i-1-2+2i+2\\
&amp;=0=R.H.S\end{align}$z_1=-1+i$$z_2=-1-i$\begin{align}
L.H.S&amp;=(-1-i)^2+2(-1-i)+2\\
&amp;=1+2i-1-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/ex1-3-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 1.3

Solutions of Question 5 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
${{z}^{2}}+z+3=0$$${{z}^{2}}+z+3=0.$$$a=1$$b=1$$c=3$\begin{align}z&amp;=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\\ 
&amp;=\dfrac{-1\pm \sqrt{{{\left( 1 \right)}^{2}}-4\left( 1 \right)\left( 3 \right)}}{2\left( 1 \right)}\\
&amp;=\dfrac{-1\pm \sqrt{1-12}}{2}\\
&amp;=\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise 1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Review Exercise 1

Solutions of Question 1 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1
${{\left( \dfrac{2i}{1+i} \right)}^{2}}$$i$$2i$$1-i$$i+1$$\dfrac{5+2i}{4-3i}$$-\dfrac{7}{25}+\dfrac{26}{25}i$$\dfrac{5}{4}-\dfrac{2}{3}i$$\dfrac{14}{25}+\dfrac{23}{25}i$$\dfrac{26}{7}+\dfrac{23}{7}i$${{i}^{57}}+\frac{1}{{{i}^{25}}}$$0$$2i$$-2…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3, Review Exercise 1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 &amp; 3, Review Exercise 1

Solutions of Question 2 &amp; 3 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{i}^{n}}+{{i}^{n+1}}+{{i}^{n+2}}+{{i}^{n+3}}=0$$\forall n\in N$\begin{align}{{i}^{n}}+{{i}^{n+1}}+{{i}^{n+2}}+{{i}^{n+3}}&amp;=0\\
L.H.S.&amp;={{i}^{n}}+{{i}^{n}}\cdot i+{{i}^{n}}\cdot {{i}^{2}}+{{i}^{n}}\cdot {{i}^{3}}\\
&amp;={{i}^{n}}\left( 1+i+{{i}^{2}}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise 1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit01/review-ex-1-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise 1

Solutions of Question 4 &amp; 5 of Review Exercise 1 of Unit 01: Complex Numbers. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{z}_{1}}=2-i$${{z}_{2}}=1+i,$$\left|\dfrac{{{z}_{1}}+{{z}_{2}}+1}{{{z}_{1}}-{{z}_{2}}+1}\right|$$z_1=2-i$$z_2=1+i$\begin{align}
\dfrac{{{z}_{1}}+{{z}_{2}}+1}{{{z}_{1}}-{{z}_{2}}+1}&amp;=\dfrac{\left( 2-i \right)+\left( 1+i \right)+1}{\left( 2-i \rig…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 2.1

Solutions of Question 1 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$$\left[ \begin{matrix}
1 &amp; 2 &amp; 4  \\
\end{matrix} \right]
\left[ \begin{matrix}
1 &amp; 0 &amp; 2  \\
2 &amp; 0 &amp; 1  \\
0 &amp; 1 &amp; 2  \\
\end{matrix} \right]
\left[ \begin{matrix}
2  \\
4  \\
6  \\
\end{matrix} \right]$$\begin{align}&amp;\left[ \begin{matri…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 2.1

Solutions of Question 2 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$A=\begin{bmatrix}2 &amp; -5 &amp; 1\\ 3 &amp; 0 &amp; -4\end{bmatrix}$$B=\begin{bmatrix}1 &amp; -2 &amp; -3 \\ 0 &amp; -1 &amp; 5\end{bmatrix}$$C=\begin{bmatrix}0 &amp; 1 &amp; -2\\0 &amp; -1 &amp; -1\end{bmatrix}$$2A+3B-4C.$$A=\begin{bmatrix}2 &amp; -5 &amp; 1\\ 3 &amp; 0 &amp; -4\end{bmatrix}$$B=\begin…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3, Exercise 2.1

Solutions of Question 3 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3(i)
$A=\begin{bmatrix}x &amp; y &amp; z\end{bmatrix}$$B=\begin{bmatrix}a &amp; h &amp; g\\h &amp; b &amp; f\\g &amp; f &amp; c\end{bmatrix}$$C=\begin{bmatrix}x\\y\\z\end{bmatrix}$$\left( AB \right)C=A\left( BC \right)$$A=\begin{bmatrix}x &amp; y &amp; z\end{bmatrix}$$B=\begin{bmatri…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 4, Exercise 2.1

Solutions of Question 4 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$A= \begin{bmatrix}1 &amp; 4 &amp; 4  \\ 4 &amp; 1 &amp; 4  \\ 4 &amp; 4 &amp; 1 \end{bmatrix}$$\dfrac{1}{3}A^2-2A-9I=0$$A=\begin{bmatrix} 1 &amp; 4 &amp; 4  \\ 4 &amp; 1 &amp; 4  \\ 4 &amp; 4 &amp; 1 \end{bmatrix}$\begin{align}\frac{1}{3}A^2&amp;=\frac{1}{3}\left[ \begin{matrix}
   1 &amp; 4 &amp; 4 …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 5 &amp; 6, Exercise 2.1

Solutions of Question 5 &amp; 6 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$A= \begin{bmatrix} 0 &amp; 2b &amp; -2  \\ 3 &amp; 1 &amp; 3  \\ 3a &amp; 3 &amp; -1 \end{bmatrix}$$a$$b$$A=\begin{bmatrix} 0 &amp; 2b &amp; -2  \\ 3 &amp; 1 &amp; 3  \\ 3a &amp; 3 &amp; -1 \end{bmatrix}$$$A^t=\left[ \begin{matrix}
   0 &amp; 3 &amp; 3a  \\
   2b &amp; 1 &amp; 3  \\
   -2 &amp; 3 &amp; -1  \\
\end{ma…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 2.1

Solutions of Question 7 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$ A=\begin{bmatrix}1 &amp; 0 &amp; -1 &amp; 2  \\3 &amp; 1 &amp; 2 &amp; \quad 5  \\0 &amp; -2 &amp; 1 &amp; 6\end{bmatrix}$$ B=\begin{bmatrix} 2 &amp; -1 &amp; 3 &amp; 1  \\1 &amp; 3 &amp; -1 &amp; 4  \\3 &amp; 1 &amp; 2 &amp; -1 \end{bmatrix}$$( A+B )^t=A^t+B^t$$A=\left[  \begin{matrix}1 &amp; 0 &amp; -1 &amp; 2  \\3 &amp; 1 &amp;…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 8, Exercise 2.1

Solutions of Question 8 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$A=\begin{bmatrix}1 &amp; 2 &amp; 0  \\3 &amp; -1 &amp; 4 \end{bmatrix}$$( A^t )^t=A$$$A=\left[ \begin{matrix}
   1 &amp; 2 &amp; 0  \\
   3 &amp; -1 &amp; 4  \\
\end{matrix}  \right]$$$$A^t=\left[  \begin{matrix}
   1 &amp; 3  \\
   2 &amp; -1  \\
   0 &amp; 4  \\
\end{matrix} \rig…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 9, Exercise 2.1

Solutions of Question 9 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)
$A=\begin{bmatrix}2 &amp; -1 &amp; 3  \\1 &amp; \quad 0 &amp; 1 \end{bmatrix},$$B=\begin{bmatrix}1 &amp; 2  \\2 &amp; 2  \\ 3 &amp; 0 \end{bmatrix}$$( AB )^t=B^tA^t$$$A=\left[  \begin{matrix}
   2 &amp; -1 &amp; 3  \\
   1 &amp; \quad 0 &amp; 1  \\
\end{matrix}  \right],$$$$B=\left[…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p9?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p9?rev=1737476037&amp;do=diff</link>
        <description>Question 10, Exercise 2.1

Solutions of Question 10 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 10
$A=\begin{bmatrix}1 &amp; -3 &amp; 4  \\-3 &amp; 2 &amp; -5  \\4 &amp; -5 &amp; 0 \end{bmatrix}$$B=\begin{bmatrix}5 &amp; 6 &amp; 7 \\6 &amp; -8 &amp; 3  \\7 &amp; 3 &amp; 1 \end{bmatrix}$$A$$B$$A+B$$$A=\left[ \begin{matrix}
   1 &amp; -3 &amp; 4  \\
   -3 &amp; 2 &amp; -5  \\
   4 &amp; -5 &amp; 0  \\
\end{ma…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p10?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p10?rev=1737476037&amp;do=diff</link>
        <description>Question 11, Exercise 2.1

Solutions of Question 11 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11
$A=\begin{bmatrix}0 &amp; 1 &amp; -2  \\-1 &amp; 0 &amp; 3  \\2 &amp; -3 &amp; 0 \end{bmatrix}$$B=\begin{bmatrix}0 &amp; -6 &amp; 11  \\6 &amp; 0 &amp; -7  \\-11 &amp; 7 &amp; 0 \end{bmatrix}$$A+B$$$A=\left[ \begin{matrix}
   0 &amp; 1 &amp; -2  \\
   -1 &amp; 0 &amp; 3  \\
   2 &amp; -3 &amp; 0  \\
\end{matri…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p11?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-1-p11?rev=1737476037&amp;do=diff</link>
        <description>Question 12, Exercise 2.1

Solutions of Question 12 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 12(i)
$A=\begin{bmatrix}3 &amp; 2 &amp; 1  \\4 &amp; 5 &amp; 6  \\-2 &amp; 3 &amp; 4\end{bmatrix}$$A+A^t$$$A=\left[ \begin{matrix}
   3 &amp; 2 &amp; 1  \\
   4 &amp; 5 &amp; 6  \\
   -2 &amp; 3 &amp; 4  \\
\end{matrix} \right]$$$$A^t=\left[ \begin{matrix}
   3 &amp; 4 &amp; -2  \\
   2 &amp; 5 &amp; 3  \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 2.2

Solutions of Question 1 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1
$A=\begin{bmatrix}1 &amp; 3 &amp; 1  \\-1 &amp; 2 &amp; 0  \\2 &amp; 0 &amp; -2 \end{bmatrix}$$A_{11},A_{21},A_{23},A_{31},A_{32},A_{33}.$$|A|.$$$A=\left[ \begin{matrix}
   1 &amp; 3 &amp; 1  \\
   -1 &amp; 2 &amp; 0  \\
   2 &amp; 0 &amp; -2  \\
\end{matrix} \right]$$$${{A}_{11}}={{\left(…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 2.2

Solutions of Question 2 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$$\left| \begin{matrix}
   1 &amp; 2 &amp; 0  \\
   3 &amp; 1 &amp; 0  \\
   -1 &amp; 2 &amp; 0  \\
\end{matrix} \right|=0$$$\left| \begin{matrix}1 &amp; 2 &amp; 3  \\-8 &amp; 4 &amp; -12  \\2 &amp; -1 &amp; 3 \end{matrix} \right|=0$$$\left| \begin{matrix}
   1 &amp; 2 &amp; 3  \\
   -8 &amp; 4 &amp; -…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3, Exercise 2.2

Solutions of Question 3 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
$A$$3,$$|A^t|=|A|$$$A=\begin{bmatrix}
   a_{11} &amp; a_{12} &amp; a_{13}  \\
   a_{21} &amp; a_{22} &amp; a_{23}  \\
   a_{31} &amp; a_{32} &amp; a_{33}  \\
\end{bmatrix}$$\begin{align}|A|&amp;=a_{11} \left( a_{22} a_{33}-a_{23} a_{32} \right)-a_{12}\left( a_{21}a_{33}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 4, Exercise 2.2

Solutions of Question 4 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)
$\left| \begin{matrix}0 &amp; 1 &amp; 3  \\-1 &amp; 2 &amp; 1  \\2 &amp; 1 &amp; 1 \end{matrix} \right|.$\begin{align}&amp;\left| \begin{matrix}
   0 &amp; 1 &amp; 3  \\
   -1 &amp; 2 &amp; 1  \\
   2 &amp; 1 &amp; 1  \\
\end{matrix} \right| \\
=&amp;0\left( 2-1 \right)-1\left( -1-2 \right)+3\l…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 5, Exercise 2.2

Solutions of Question 5 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$\begin{vmatrix}a &amp; b &amp; c\\l &amp; m &amp; n\\x &amp; y &amp; z \end{vmatrix}=\begin{vmatrix}a &amp; l &amp; x\\b &amp; m &amp; y\\c &amp; n &amp; z \end{vmatrix}$\begin{align}L.H.S.&amp;=\begin{vmatrix}
a &amp; b &amp; c  \\
l &amp; m &amp; n  \\
x &amp; y &amp; z
\end{vmatrix}\\
&amp;=\begin{vmatrix}
a &amp; b &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 6, Exercise 2.2

Solutions of Question 6 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Questiopn 6(i)
$\left| \begin{matrix}a-b &amp; b-c &amp; c-a  \\b-c &amp; c-a &amp; a-b  \\c-a &amp; a-b &amp; b-c  \end{matrix} \right|=0$\begin{align} L.H.S&amp;=\left| \begin{matrix}
a-b &amp; b-c &amp; c-a  \\
b-c &amp; c-a &amp; a-b  \\
c-a &amp; a-b &amp; b-c  \\
\end{matrix} \right| \\ 
&amp;=\left| \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 2.2

Solutions of Question 7 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$\left| \begin{matrix}3860 &amp; 3861  \\3862 &amp; 3863 \end{matrix} \right|$$$\left| \begin{matrix}
   3860 &amp; 3861  \\
   3862 &amp; 3863  \\
\end{matrix} \right|=14911180-14911182$$$$=-2$$$\left| \begin{matrix}81 &amp; 82 &amp; 83  \\84 &amp; 85 &amp; 86  \\87 &amp; 8…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8,9 &amp; 10, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 8,9 &amp; 10, Exercise 2.2

Solutions of Questions 8,9 &amp; 10 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\left| \begin{matrix}1+x &amp; y &amp; z  \\x &amp; 1+y &amp; z  \\x &amp; y &amp; 1+z \end{matrix} \right|=1+x+y+z$$$L.H.S.=\left| \begin{matrix}
   1+x &amp; y &amp; z  \\
   x &amp; 1+y &amp; z  \\
   x &amp; y &amp; 1+z  \\
\end{matrix} \right|$$$$=\left| \begin{matrix}
   1 &amp; 0 &amp; -…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p9?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p9?rev=1737476037&amp;do=diff</link>
        <description>Question 11, Exercise 2.2

Solutions of Question 11 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11(i)
$\left[ \begin{matrix}7 &amp; 1 &amp; 3  \\6 &amp; 2 &amp; -2  \\5 &amp; 1 &amp; 1\end{matrix} \right]$$$A=\left[ \begin{matrix}
   7 &amp; 1 &amp; 3  \\
   6 &amp; 2 &amp; -2  \\
   5 &amp; 1 &amp; 1  \\
\end{matrix} \right]$$$$|A|=7(2+2)-1(6+10)+3(6-10)$$$$=28-16-12$$$$|A|=0$$$A$$\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p10?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p10?rev=1737476037&amp;do=diff</link>
        <description>Question 12, Exercise 2.2

Solutions of Question 12 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 12
$\lambda $$A$$A=\begin{bmatrix}-\lambda  &amp; 1 &amp; 0  \\1 &amp; -\lambda  &amp; 1  \\0 &amp; 1 &amp; -\lambda \end{bmatrix}$$$A=\left[ \begin{matrix}
   -\lambda  &amp; 1 &amp; 0  \\
   1 &amp; -\lambda  &amp; 1  \\
   0 &amp; 1 &amp; -\lambda   \\
\end{matrix} \right]$$$$|A|=-\lamb…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p11?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p11?rev=1737476037&amp;do=diff</link>
        <description>Question 13, Exercise 2.2

Solutions of Question 13 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 13(i)
$x,$$\left| \begin{matrix}x &amp; 2 &amp; 3  \\0 &amp; -1 &amp; 1  \\0 &amp; 4 &amp; 5 \end{matrix} \right|=9$$$\left| \begin{matrix}
   x &amp; 2 &amp; 3  \\
   0 &amp; -1 &amp; 1  \\
   0 &amp; 4 &amp; 5  \\
\end{matrix} \right|=9$$$$x(-5-4)-2(0)+3(0)=9$$$$-9x=9$$$$x=-1$$$x,$$\left…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p12?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 &amp; 15, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p12?rev=1737476037&amp;do=diff</link>
        <description>Question 14 &amp; 15, Exercise 2.2

Solutions of Questions 14 &amp; 15 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$A=\begin{bmatrix}0 &amp; 2 &amp; 2  \\-1 &amp; 3 &amp; 2  \\1 &amp; 0 &amp; 5\end{bmatrix}$$A^{-1}$$$A=\left[ \begin{matrix}
   0 &amp; 2 &amp; 2  \\
   -1 &amp; 3 &amp; 2  \\
   1 &amp; 0 &amp; 5  \\
\end{matrix} \right]$$$A^{-1}$$$A^{-1}=\dfrac{Adj\,\,A}{|A|}$$$$Adj\,\,A={{\left[ \begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p13?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 16 &amp; 17, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p13?rev=1737476037&amp;do=diff</link>
        <description>Question 16 &amp; 17, Exercise 2.2

Solutions of Questions 16 &amp; 17 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$A=\begin{bmatrix}3 &amp; -1  \\4 &amp; 2\end{bmatrix}$$|A^{-1}|=\dfrac{1}{|A|}$$$A=\left[ \begin{matrix}
   3 &amp; -1  \\
   4 &amp; 2  \\
\end{matrix} \right]$$$$|A|=6+4$$$$\Rightarrow |A|=10\ldots (1)$$$$A^{-1}=\dfrac{1}{|A|}AdjA$$$$AdjA=\left[ \begin{ma…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p14?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 18, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-2-p14?rev=1737476037&amp;do=diff</link>
        <description>Question 18, Exercise 2.2

Solutions of Question 18 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 18(i)
$A$$B$$( A^{-1})^{-1}=A$$A$$2\times 2$$$A=\left[ \begin{matrix}
   a_{11} &amp; a_{12}  \\
   a_{21} &amp; a_{22}  \\
\end{matrix} \right]$$$$|A|=a_{11}a_{22}-a_{12}a_{21}$$$$AdjA=\left[ \begin{matrix}
   a_{22} &amp; -a_{12}  \\
   -a_{21} &amp; a_{11…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 2.3

Solutions of Question 1 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$\begin{bmatrix}1 &amp; 3 &amp; -1  \\2 &amp; 1 &amp; 4  \\3 &amp; 4 &amp; -5\end{bmatrix}$\begin{align}&amp;\begin{bmatrix}
1 &amp; 3 &amp; -1  \\
2 &amp; 1 &amp; 4  \\
3 &amp; 4 &amp; -5 \end{bmatrix}\\
\underset{\sim}{R}&amp;\begin{bmatrix}
1 &amp; 3 &amp; -1  \\
0 &amp; -5 &amp; 6  \\
0 &amp; -5 &amp; -2 \end{bmat…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 2.3

Solutions of Question 2 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$$\begin{bmatrix}4 &amp; -2 &amp; 5 \\ 2 &amp; 1 &amp; 0  \\ -1 &amp; 2 &amp; 3  \end{bmatrix}$$$$A=\begin{bmatrix}
4 &amp; -2 &amp; 5  \\
2 &amp; 1 &amp; 0  \\
-1 &amp; 2 &amp; 3 \end{bmatrix}.$$\begin{align}|A|&amp;=\begin{vmatrix}4 &amp; -2 &amp; 5  \\ 2 &amp; 1 &amp; 0  \\ -1 &amp; 2 &amp; 3 \end{vmatrix}\\
&amp;=…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit02/ex2-3-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3, Exercise 2.3

Solutions of Question 3 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3(i)
$$\left[ \begin{matrix}
   1 &amp; 0 &amp; -2  \\
   2 &amp; 2 &amp; 1  \\
   -1 &amp; 2 &amp; 3  \\
\end{matrix} \right]$$\begin{align}&amp;\begin{bmatrix}
1 &amp; 0 &amp; -2  \\
2 &amp; 2 &amp; 1  \\
-1 &amp; 2 &amp; 3 \end{bmatrix}\\
\underset{\sim}{R}&amp; \begin{bmatrix}
1 &amp; 0 &amp; -2  \\
0 &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 3.2

Solutions of Question 1 of Exercise 3.2 of Unit 03: Matrices and Determinants. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question.1(i)
$\vec{a}=3\hat{i}-5\hat{j}$$\vec{b}=-2\hat{i}+3\hat{j}$$\vec{a}+2\vec{b}$\begin{align}\vec{a}+2\vec{b}&amp;=3\hat{i}-5\hat{j}+2(-2\hat{i}+3\hat{j})\\
&amp;=3\hat{i}-5\hat{j}-4\hat{i}+6\hat{j}\\
&amp;=-\hat{i}+\hat{j}\end{align}$\vec{a}=3\hat{i}-5\hat{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2, Exercise 3.2

Solutions of Question 2 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)

Find unit vector having the same direction as the vector $3\hat{i}.$$$\overset{\scriptscriptstyle\rightharpoonup}{a}=3\hat{i}$$$$|\overset{\scriptscriptstyle\rightharpoonup}{a}|=\sqrt{{{(3)}^{2}}}=3$$$$\hat{a}=\dfrac{{\overset{\scriptscriptstyle\rightharpo…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 3.2

Solutions of Question 3 &amp; 4 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3

If $\vec{r}=\hat{i}-9\hat{j}$$\vec{a}=\hat{i}+2\hat{j}$$\vec{b}=5\hat{i}-\hat{j}$$p$$q$$\vec{r}=p\vec{a}+q\vec{b}$$$\vec{r}=p\vec{a}+q\vec{b}.$$$\vec{r},\vec{a}$$\vec{b}$$$\hat{i}-9\hat{j}=p(\hat{i}+2\hat{j})+q(5\hat{i}-\hat{j})$$$$\implies \hat{i}-9\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 5 &amp; 6, Exercise 3.2

Solutions of Question 5 &amp; 6 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5

Find the length of the vector $\overrightarrow{AB}$$\vec{A}(-3,5)$$\vec{B}(7,9)$$\overrightarrow{AB}$$\vec{A}$$\vec{B}$$$\overrightarrow{OA}=-3\hat{i}+5\hat{j},$$$$\overrightarrow{OB}=7\hat{i}+9\hat{j}.$$\begin{align}\overrightarrow{AB}&amp;=\overrightarr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 3.2

Solutions of Question 7 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)

Find the components and the magnitude of $\overrightarrow{PQ}$$P(-1,2)$$Q(2,-1)$\begin{align}\overrightarrow{PQ}&amp;=\overrightarrow{OQ}-\overrightarrow{OP}\\ 
&amp;=(2\hat{i}-\hat{j})-(-\hat{i}+2\hat{j})\\ 
&amp;=3\hat{i}-3\hat{j}\end{align}\begin{align}|\overrighta…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 7, Exercise 3.2

Solutions of Question 7 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)

Find the components and the magnitude of $\overrightarrow{PQ}$$P(-1,2)$$Q(2,-1)$\begin{align}\overrightarrow{PQ}&amp;=\overrightarrow{OQ}-\overrightarrow{OP}\\ 
&amp;=(2\hat{i}-\hat{j})-(-\hat{i}+2\hat{j})\\ 
&amp;=3\hat{i}-3\hat{j}\end{align}\begin{align}|\overrighta…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 3.2

Solutions of Question 9 &amp; 10 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$\overrightarrow{a}=\hat{i}+\hat{j}+\hat{k}, $$$ and $$, find a vector of magnitude of $$ unit which is parallel to the vector $\begin{align}2\overrightarrow{a}-\overrightarrow{b}+3\overrightarrow{c}&amp;=2(\hat{i}+\hat{j}+\hat{k})-(4\hat{i}-2\hat{j}+3\h…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p8?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 3.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-2-p8?rev=1737476037&amp;do=diff</link>
        <description>Question 11, Exercise 3.2

Solutions of Question 11 of Exercise 3.2 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11(i)

Find the position vectors of the point of division of the line segments joining point $C$$5\hat{j}$$D$$4\hat{i}+\hat{j}$$2:5$$C$$\overrightarrow{OC}=5\hat{j}$$D$$\overrightarrow{OD}=4\hat{i}+\hat{j}$$H$$\overline{CD}$$2:5$$H$\begin{align}\overrightarrow…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1, Exercise 3.3

Solutions of Question 1 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)

If $\vec{a}=3 \hat{i}+4 \hat{j}-\hat{k}$, $\vec{b}=\hat{i}-\hat{j}+3 \hat{k}$ and $\vec{c}=2\hat{i}+\hat{j}-5 \hat{k}$$\vec{a}\cdot \vec{b}$\begin{align}\vec{a} \cdot \vec{b}&amp;=(3 \hat{i}+4 \hat{j}-\hat{k}) \cdot(\hat{i}-\hat{j}+3 \hat{k})\\
\Rightarrow &amp;=(…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3 Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 and 3 Exercise 3.3

Solutions of Question 2 and 3 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$$\vec{a}=2 \hat{i} + 2 \hat{j}-5 \hat{k}, \quad \vec{b}=2 \hat{i}+\hat{j}-7 \hat{k}$$\begin{align}\vec{a}+\vec{b}&amp;=(2 \hat{i}+2 \hat{j}-5 \hat{k})+(2 \hat{i}+\hat{j}-7 \hat{k}) \\
\Rightarrow &amp;=4 \hat{i}+3 \hat{j}-12 \hat{k}\\
\Rightarrow|\vec{a}+\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 and 5 Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 4 and 5 Exercise 3.3

Solutions of Question 4 and 5 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\hat{i}+7 \hat{j} + 3 \hat{k}$$\hat{i}-\hat{j}+2 \hat{k}$$2 \hat{i}-$$\hat{j}+3 \hat{k}$$\vec{a}=\hat{i}+7 \hat{j}+3 \hat{k}$$\vec{b}=\hat{i}-\hat{j}+2 \hat{k}$$\vec{c} = 2 \hat{i}-\hat{j}-3 \hat{k}$\begin{align}\vec{a} \cdot \vec{b}&amp;=(\hat{i}+7 \h…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 6 Exercise 3.3

Solutions of Question 6 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)

Let $\vec{a}=\hat{i}+3 \hat{j}-4 \hat{k}$ and $\vec{b}=2 \hat{i}-3 \hat{j}-5 \hat{k}$$m$$\vec{a}+m \vec{b}$$\vec{a}$\begin{align}
\vec{a}+m \vec{b}&amp; =\hat{i}+3 \hat{j}-4 \hat{k}+m(2 \hat{i}-3 \hat{j}+5 \hat{k}) \\
&amp; =(1+2 m) \hat{i}+(3-3 m) \hat{j}+(5 m-4) …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 3.3

Solutions of Question 7 &amp; 8 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$\vec{a}$$\vec{b}$$\vec{a}=-\dfrac{3}{2} \hat{j}+\dfrac{4}{5} \hat{k} \cdot \vec{b}=\hat{i}-2 \hat{j}-2 \hat{k}$$\vec{a}$$\vec{b}$$\vec{b}$$\vec{a}$$\vec{a}=-\dfrac{3}{2} \hat{j}+\dfrac{4}{5} \hat{k}\quad$$\vec{b}=\hat{i}-2 \hat{j}-2 \hat{k}$\begin{a…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 3.3

Solutions of Question 9 &amp; 10 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$\vec{k}-2 \hat{i}+3 \hat{j}+\hat{k}$$\vec{S}=2 \hat{i}+\hat{j}-\hat{k}$\begin{align}W &amp;=\vec{F} \cdot s \\
\Rightarrow W &amp;=(2 \hat{i}+3 \hat{j}+\hat{k}) \cdot(2 \hat{i}+\hat{j}-\hat{k}) \\
\Rightarrow W &amp;=2(2) \div 3(1)+1(-1) \\
\Rightarrow W &amp;=4+3 …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 3.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-3-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 11, Exercise 3.3

Solutions of Question 11 of Exercise 3.3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11 (i)

Show that the vectors $3 \hat{i}-2 \hat{j}+$$\hat{k} . \quad \hat{i}-3 \hat{j}-5 \hat{k}$$2 \hat{i}+\hat{j}-4 \hat{k}$$\vec{a}=3 \hat{i}-2 \hat{j}+\hat{k}$$\vec{b}=\hat{i}-3 \hat{j}+5 \hat{k}$$\vec{c}=2 \hat{i}+\hat{j}-4 \hat{k}$\begin{align}|\vec{a}|&amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p1?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p1?rev=1737476037&amp;do=diff</link>
        <description>Question 1 Exercise 3.4

Solutions of Question 1 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)

Find the cross product $\hat{j} \times(2 \hat{j}+3 \hat{k})$\begin{align}\vec{a}=\hat{j}&amp;=0 \hat{i}+\hat{j}+0 \hat{k}\\
\vec{b}&amp;=0 \hat{i}+2 \hat{j}-3 \hat{k}\\
 \vec{a} \times \vec{b}&amp;=\hat{j} \times(2 \hat{j}+3 \hat{k})\\
&amp;=\left|\begin{array}{lll}\hat{i}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p2?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p2?rev=1737476037&amp;do=diff</link>
        <description>Question 2 Exercise 3.4

Solutions of Question 2 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)

Show in two different ways that the vectors $\vec{a}$$\vec{b}$$\vec{a}=-\hat{i}+2 \hat{j}-3 \hat{k}, \quad \vec{b}=2 \hat{i}-4 \hat{j}+$$6 \hat{k}$\begin{align}\vec{a} \times \vec{b}&amp;=\left|\begin{array}{ccc}
\hat{i} &amp; \hat{j} &amp; \hat{k} \\
-1 &amp; 2 &amp; -3 \\
2 …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p3?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p3?rev=1737476037&amp;do=diff</link>
        <description>Question 3 Exercise 3.4

Solutions of Question 3 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3(i)

Find a unit vector that is orthogonal to
the given vector $\vec{a}=\hat{i}- 2 \hat{j}+3 \hat{k}, \quad \vec{b}=2 \hat{i}+\hat{j}-\hat{k}$$\hat{n}$$\vec{a}$$\vec{b}$\begin{align}\hat{n}&amp;=\dfrac{\vec{a} \times \vec{b}}{\mid \vec{a} \times \vec{b}} \\
\text { …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p4?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p4?rev=1737476037&amp;do=diff</link>
        <description>Question 4 Exercise 3.4

Solutions of Question 4 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)

If $\vec{a}=3 \hat{i}-6 \hat{j}+5 \hat{k},\quad\vec{b}=2\hat{i}-\hat{j}+4 \hat{k} \quad$ and $\quad \vec{c}=\hat{i}+\hat{j} \quad \hat{k},\quad$$\vec{a} \times \vec{b}$\begin{align}\vec{a} \times \vec{b}&amp;=\left|\begin{array}{ccc}
\hat{i} &amp; \hat{j} &amp; \hat{k}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p5?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p5?rev=1737476037&amp;do=diff</link>
        <description>Question 5 Exercise 3.4

Solutions of Question 5 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)

Use the vector product to compute the area of the triangle with the given vertices $P(-2,-3), \quad Q(3,2)\quad$$\quad R(-1,-8)$$P Q$$\bar{P} R$\begin{align}\text{Area of triangle}&amp;=\dfrac{1}{2}|\overrightarrow{P Q} \times \overrightarrow{P R}| \\
\text { S…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p6?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p6?rev=1737476037&amp;do=diff</link>
        <description>Question 6 Exercise 3.4

Solutions of Question 6 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6(i)

A force $\vec{F}=3 \hat{i}-2 \hat{j}+5 \hat{k}$$(1,-2,2)$$\vec{r}$$P(1,-2.2)$$O(0,0,0)$\begin{align}\vec{r}&amp;=\overrightarrow{O P}\\
&amp;=(1,-2,2)-(0,0,0) \\
\Rightarrow \vec{r}&amp;=(1,-2,2).\\
\text { Hence } \vec{M}-\vec{r} \times \vec{F}&amp;=\left|\begin{array}{cc…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p7?rev=1737476037&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:57+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 3.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-4-p7?rev=1737476037&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 3.4

Solutions of Question 7 &amp; 8 of Exercise 3.4 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7

If $\vec{A}+\vec{B}+\vec{C}=\vec{O}$$$\vec{A} \times \vec{B}=\vec{B} \times \vec{C}=\vec{C} \times \vec{A}.$$$$\vec{A}+\vec{B}+\vec{C}=\vec{O} \text {. }$$$\vec{A}$$$\vec{A} \times(\vec{A}+\vec{B}+\vec{C})=0$$\begin{align}\Rightarrow \vec{A} \times \ve…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 &amp; 2 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 &amp; 2 Exercise 3.5

Solutions of Question 1 &amp; 2 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

Find $\vec{a} \cdot \vec{b} \times \vec{c}$$\vec{a}=2 \hat{i}+\hat{j}+3 \hat{k}$$\vec{b}=-\hat{i}+2 \hat{j}+\hat{k} \quad \text { and }\quad \vec{c}=3 \hat{i}+\hat{j}+2 \hat{k} \text {. }$\begin{align}V&amp;=\vec{a} \cdot \vec{b} \times \vec{c}\\
&amp;=\left|\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 &amp; 4 Exercise 3.5

Solutions of Question 3 &amp; 4 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3

For the vectors $\vec{a}=3 \hat{i}+2 \hat{k}$$\vec{b}=\hat{i}+2 \hat{j}+\hat{k}\quad$$\quad\vec{c}=-\hat{j}+4 \hat{k}$$\vec{a} \cdot \vec{b} \times \vec{c}=\vec{b} \cdot \vec{c} \times \vec{a}=\vec{c} \cdot \vec{a} \times \vec{b}$$\vec{a} \cdot \vec{b}…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5(i) &amp; 5(ii) Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5(i) &amp; 5(ii) Exercise 3.5

Solutions of Question 5(i) &amp; 5(ii) of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$\vec{a}=a_1 \hat{i}+a_2 \hat{j}+a_3 \hat{k}\quad$$\quad\vec{b}=b_1 \hat{i}+b_2 \hat{j}+b_3 \hat{k}\quad$$\vec{a} \times \vec{b}\quad$$\vec{a} \times \vec{b}$$\vec{a}$$\vec{b}$$\vec{a} \times \vec{b}$$\vec{a}$$\vec{b}$$\vec{a} \times \v…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p4?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5(iii) &amp; 5(iv) Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 5(iii) &amp; 5(iv) Exercise 3.5

Solutions of Question 5(iii) &amp; 5(iv) of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\vec{a}=a_1 \hat{i}+a_2 \hat{j}+a_3 \hat{k}\quad$$\quad\vec{b}=b_1 \hat{i}+b_2 \hat{j}+b_3 \hat{k}\quad$$(\vec{a}. \vec{b})^2,\quad|a|^2,\quad|b|^2$\begin{align}\vec{a} \cdot \vec{b}&amp;=(a_1 \hat{i}+a_2 \hat{j} + a_3 \hat{k}) \cdot(b_1 \hat{i}+b_2 \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p5?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 3.5

Solutions of Question 6 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6

Do the points $(4. 2.1)$$(5,1,6)$$(2.2,-5)$$(3.5 .0)$$A(4,-2,1), B(5,1,6)$$C(2,2,-5)$$D(3,5.0)$$A, \overrightarrow{O A}=4 \hat{i}-2 \hat{j}+\hat{k}$$B, \overrightarrow{O B}=5 \hat{i}+\hat{j}+6 \hat{k}$$C, \overrightarrow{O C}=2 \hat{i}+2 \hat{i}-5 \hat{k}$$D, …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 3.5

Solutions of Question 7 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)

For what value of $c$$\vec{u}=\hat{i}+2 \hat{j}+3 \hat{k}$$\vec{v}=2 \hat{i}-3 \hat{j}+4 \hat{k} \cdot \vec{w}=3 \hat{i}+\hat{j}+c \hat{k}$\begin{align}\vec{u} \cdot \vec{v} \times \vec{w}&amp;=0\\
\vec{u} \cdot \vec{v} \times \vec{w}&amp;=0\\
\Rightarrow\left|\beg…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 3.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/ex3-5-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 3.5

Solutions of Question 8 of Exercise 3.5 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)

Find the volume of tetrahedron with the Vectors as coterminous edges
\begin{align}\vec{a}&amp;=\hat{i}+2 \hat{j}+3 \hat{k},\\ 
\vec{b}&amp;=4 \hat{i}+5 \hat{j}+6 \hat{k}, \\
\vec{c}&amp;=7 \hat{j}+8 \hat{k}\end{align}\begin{align}V&amp;=\dfrac{1}{6}[\vec{u} \cdot \vec{v} \…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Review Exercise 3

Solutions of Question 1 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

$\hat{i} \cdot(\hat{j} \times \hat{k})+\hat{j} \cdot(\hat{i} \times \hat{k})+\hat{k} \cdot(\hat{i} \times \hat{j})$$0$$1$$1$$3$$3 \hat{i}+5 \hat{j}+2 \hat{k}$$2 \hat{i}-3 \hat{j}-5 \hat{k}$$5 \hat{i}+2 \hat{j}-3 \hat{k}$$\hat{i}-2 \hat{i}+\hat{j}+3 \…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Review Exercise 3

Solutions of Question 2 &amp; 3 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$\lambda$$\mu$$$(\hat{i}+3 \hat{j}+9 \hat{k}) \times(3 \hat{i}-\lambda \hat{j}+\mu \hat{k})=\overrightarrow{0} \text {. }$$\begin{align}(\hat{i}+3 \hat{j}+9 \hat{k}) \times(3 \hat{i}-\lambda \hat{j}+\mu \hat{k})&amp;=\vec{O} \\
\Rightarrow\left|\b…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 &amp; 5 Review Exercise 3

Solutions of Question 4 &amp; 5 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\vec{r}=x \hat{i}+y \hat{j}+z \hat{k}$$(\vec{r} \times \hat{i}) \cdot(\bar{r} \times \hat{j})+x y$$$(\vec{r} \times \hat{i}) \cdot(\vec{r} \times \hat{j})+x y $$\begin{align}\text { Now } \vec{r} \times \hat{i}&amp;=\left|\begin{array}{ccc}
\hat{…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 6 &amp; 7 Review Exercise 3

Solutions of Question 6 &amp; 7 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6
$\lambda$$\vec{a}=\hat{i}+3 \hat{j}+\hat{k}$$\bar{b}=2 \hat{i}-\hat{j}-\hat{k}$$\vec{c}=\lambda \hat{j}+3 \hat{k}$\begin{align}\vec{a} \cdot \vec{b} \times \vec{c}&amp;=0 \\
\Rightarrow\left|\begin{array}{ccc}
1 &amp; 3 &amp; 1 \\
2 &amp; -1 &amp; -1 \\
0 &amp; \lamb…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 &amp; 9 Review Exercise 3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit03/review-ex3-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 8 &amp; 9 Review Exercise 3

Solutions of Question 8 &amp; 9 of Review Exercise 3 of Unit 03: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8
$(0,0,2),(-1,3,2),(1,0,4)$$A(0,0,2)$$B(-1,3,2)$$C(1,0,4)$$\vec{a}=\overrightarrow{A B}=(-1,3,2)-(0,0,2)$$\Rightarrow \vec{a}=(-1,3,0)$$\vec{b}=\overrightarrow{B C}=(1,0,4)-(-1,3,2)$$\Rightarrow \vec{b}=(2,-3,2)$$$ \text{Area of triangle} =\dfr…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-1-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 4.1

Solutions of Question 1 and 2 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2,4,6,8, \ldots ,50$$50 $$1,0,1,0,1, \ldots$$0$$1$$...,-4,0,4,8, \ldots, 60$$1,-\dfrac{1}{3}, \dfrac{1}{9},-\dfrac{1}{27}, \ldots,-\dfrac{1}{2187}$$a_n=\dfrac{n(n+1)}{2}$$$a_n=\dfrac{n(n+1)}{2}$$$n=1,$$$a_1=\dfrac{1(1+1)}{2}=1$$$n=2$$$a_2=\dfrac{2(2…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4 Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-1-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 and 4 Exercise 4.1

Solutions of Question 3 and 4 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{1}{2}, \dfrac{2}{3} \dfrac{3}{4}, \dfrac{4}{5}, \ldots$$$\dfrac{1}{1+1}, \dfrac{2}{2+1}, \dfrac{3}{3+1}, \dfrac{4}{4+1},...$$$\dfrac{n}{n+1}$$2,-4,6,-8,10, \ldots$\begin{align}
&amp;(-1)^2 \cdot 2 \cdot 1, (-1)^3 \cdot 2 \cdot 2, (-1)^4 \cdot 2 \…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-1-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 4.1

Solutions of Question 5 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5(i)
$\sum_{j=1}^6(2 j-3)$\begin{align}\sum_{j=1}^6(2 j-3)&amp;=(2.1-3)+(2.2-3)+(2.3-3)+(2.4-3)\\&amp;+(2.5-3)+(2.6-3) \\
\implies \sum_{j=1}^6(2 j-3)&amp;=-1+1+3+5+7+9 .\end{align}$\sum_{k=1}^5(-1)^k 2^{k-1}$\begin{align}\sum_{k=1}^5(-1)^k 2^{k-1}&amp; =(-1)^1 2^{1-…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 4.2

Solutions of Question 1 and 2 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$15$$2,5,8, \ldots$$a_1=2$$d=5-2=3$$n=15$$$a_n=a_1+(n-1) d$$\begin{align}a_{15}&amp;=2+(15-1) 3 \\
&amp;=2+42=44 \end{align}$44$$a_1=8$$a_{21}=108$$$a_n=a_1+(n-1) d.$$\begin{align}
&amp;a_{21}=8+(21-1) d \\
\implies &amp;108=8+20 d\\
\implies &amp;20 d=108-8=100 \\
\imp…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 and 4 Exercise 4.2

Solutions of Question 3 and 4 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$6,9,12, \ldots, 78$$a_1=6$$d=9-6=3$$a_n=78$$$a_n=a_1+(n-1) d$$\begin{align}&amp;78=6+(n-1) 3 \\
\implies &amp;3(n-1)=78-6 \\
\implies &amp;n-1=\dfrac{72}{3} \\
\implies &amp;n=24+1=25.\end{align}$25$$n$$a_n=2n+7$$$a_n=2 n+7. --- (1)$$\begin{align}a_{n+1}=2(n+1)+7=2…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 4.2

Solutions of Question 5 and 6 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\log a, \log (a b), \log \left(a b^2\right), \log \left(a b^3\right), \ldots$$$n$$\log$$a$$b$$b$$$a_n=\log (a b^{n-1}).$$\begin{align}a_n&amp;=\log(a b^{n-1}). \end{align}\begin{align}
d&amp;=a_{n+1}-a_n \\
&amp;=\log (a b^n)-\log (a b^{n-1}) \\
&amp;=\log \left(\…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 4.2

Solutions of Question 7 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$a_6+a_4=6$$a_6-a_4=\dfrac{2}{3}$$a_1$$d$\begin{align} &amp;a_6+a_4=6 \\
\implies &amp; a_1+5d+a_1+3d=6\\
\implies &amp; 2a_1+8d=6\\
\implies &amp; a_1+4d=3 --- (1)
\end{align}\begin{align} &amp;a_6-a_4=\dfrac{2}{3} \\
\implies &amp; a_1+5d-a_1-3d=\dfrac{2}{3}\\
\implies &amp;…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 4.2

Solutions of Question 8 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8
$\dfrac{b+c-a}{a}, \dfrac{c+a-b}{b}, \dfrac{a+b-c}{c}$$\dfrac{1}{a}, \dfrac{1}{b}, \dfrac{1}{c}$$\dfrac{b+c-a}{a}, \dfrac{c+a-b}{b}, \dfrac{a+b-c}{c}$\begin{align}\therefore \dfrac{c+a-b}{b}-\dfrac{b+c-a}{a}&amp;=\dfrac{a+b-c}{c}-\dfrac{c+a-b}{b} \\
\te…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 4.2

Solutions of Question 9 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$24m$$21m$$18m$$$a_1=24,$$$$a_2=21,$$$$a_3=18.$$$$d=21-24=18-21=-3,$$\begin{align} a_8&amp;=a_1+7d\\
&amp;=24+7(-3)=3.
\end{align}$3m$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 4.2

Solutions of Question 10 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 10
$500$$a_1$$$a_1=20135.$$$d=-500$$a_{11}$\begin{align}
a_{11}&amp;=a_1+10d \\
&amp;=20135+10(-500)\\
&amp;=15135. \end{align}$1070$$15135$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Exercise 4.2

Solutions of Question 11 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11
$a_1$$$a_1=1000.$$$= d=100$$a_n=5400$$n$\begin{align}
&amp;a_n=a_1+(n-1)d \\
 \implies &amp;5400=1000+(n-1)100\\
 \implies &amp;5400=900+100n \\
 \implies &amp;100n=5400-900\\
 \implies &amp;100n=4500\\
 \implies &amp;n=45.\end{align}</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p9?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 &amp; 13 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p9?rev=1737476038&amp;do=diff</link>
        <description>Question 12 &amp; 13 Exercise 4.2

Solutions of Question 12 &amp; 13 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$a_1$$$a_1=3500.$$$=d=750$$a_{21}$\begin{align}
a_{21}&amp;=a_1+20d\\
&amp;=3500+20(750) \\
&amp;=18500. \end{align}$12$$18$$a=12, b=18$$A$\begin{align}A&amp;=\dfrac{a+b}{2}\\&amp;=\dfrac{12+18}{2}\\&amp;=\dfrac{30}{2}=15.\end{align}$\dfrac{1}{3}$$\dfrac{1}{4}$$a=\dfrac{1}{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p10?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p10?rev=1737476038&amp;do=diff</link>
        <description>Question 14 Exercise 4.2

Solutions of Question 14 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 14(i)
$A_1, A_2, A_3$$6, A_1, A_2, A_3, 41$$$a_1=6 \text{ and } a_6=41.$$\begin{align}&amp; a_5=11\\
\Rightarrow &amp;a_1+4 d=41 \\
\Rightarrow &amp;6+4 d=41 \\
\Rightarrow &amp;d=\dfrac{41-6}{4}\\
&amp;=\dfrac{35}{4}.\end{align}\begin{align} A_1&amp;=a+d=6+\dfrac{35}{4} \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p11?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p11?rev=1737476038&amp;do=diff</link>
        <description>Question 15 Exercise 4.2

Solutions of Question 15 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 15
$n, \dfrac{a^{n+1}+b^{n+1}}{a^n+b^n}$$a$$b$$a$$b$$A$$a$$b$$$
A=\dfrac{a+b}{2}. --- (1)
$$$$
A=\dfrac{a^{n+1}+b^{n+1}}{a^n+b^n}. --- (2)
$$\begin{align}&amp;\dfrac{a+b}{2}=\dfrac{a^{n+1}+b^{n+1}}{a^n+b^n}, --- (3) \\
	\implies &amp;(a^n+b^n)(a+b)=2(a^{n+1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p12?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 16 Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-2-p12?rev=1737476038&amp;do=diff</link>
        <description>Question 16 Exercise 4.2

Solutions of Question 16 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 16
$5$$8$$5$$8$$A_1, A_2, A_3, A_4, A_5$$5$$8$$5, A_1, A_2, A_3, A_4, A_5, 8$$$a_1=5 \text{ and } a_7=8.$$\begin{align}&amp;a_7=a+6d\\
\implies &amp;8=5+6d\\
\implies &amp;6d=8-5\\
\implies &amp;d=\dfrac{3}{6}=\dfrac{1}{2}.
\end{align}\begin{align}
A_1&amp;=a+d=5+\dfra…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 4.3

Solutions of Question 1 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$9,7,5,3, \ldots$$a_1$$d$\begin{align}&amp;a_1=9 \\ 
&amp;d=7-9=-2 \\
&amp;n=20.
\end{align}\begin{align}&amp;a_n=a_1+(n-1)d \\
\implies &amp;a_20=9+(20-1)(-2)=-29.
\end{align}$S_n$$n$\begin{align}
S_n&amp;=\dfrac{n}{2}[a_1+a_n], \\
\implies S_{20}&amp;=\dfrac{20}{2}[9-29] …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 4.3

Solutions of Question 2 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$a_1, a_n, n, d$$S_n$$a_1=2, n=17, d=3$$a_1=2, n=17, d=3$$a_{17}$$S_{17}$$$a_{n}=a_1+(n-1)d.$$$$a_{17}=2+(17-1)(3)=50.$$$$S_n=\dfrac{n}{2}[a_1+a_n]$$\begin{align}S_{17}&amp;=\dfrac{17}{2}(a_1+a_17) \\
&amp;=\dfrac{17}{2}(2+50)=442.\end{align}$a_{17}=50$$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 &amp; 4 Exercise 4.3

Solutions of Question 3 &amp; 4 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
$5$$25$$350$$5$$25$$350$$$25,30,35, \ldots, 350.$$$a_1=25, d=5$$a_n=350$$n$\begin{align}a_n&amp;=a_1+(n-1) d\end{align}\begin{align}
350&amp;=25+(n-1)(5) \\
\Rightarrow 5 n-5+25&amp;=350 \\
\Rightarrow 5 n&amp;=350-20=330 \\
\Rightarrow n&amp;=66, \text { now f…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 5 &amp; 6 Exercise 4.3

Solutions of Question 5 &amp; 6 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5
$20$$120$$$a-2 d, a-d, a+d, a+2 d,$$$Condition-1$$20$\begin{align}a-3 d+a-d+a+d+a+3 d&amp;=20 \\
\Rightarrow 4 a&amp;=20\\
\Rightarrow a&amp;=5 .\end{align}$Condition-2$$120$\begin{align}(a-3 d)^2+(a-d)^2+(a+d)^2+(a+2 d)^2&amp;=120 \\
\Rightarrow a^2-6 a d+…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 4.3

Solutions of Question 7 &amp; 8 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$1+3-5+7+9-11+13+15-$$17+\ldots$$3 n$\begin{align}&amp;(1+7+13+\ldots)+(3+9+15+\ldots)- \\
&amp; (5+11+17+\ldots) \ldots \ldots \ldots . . .(1)\end{align}$\mathrm{n}$$n$$3 n$$$1+7+13+\ldots$$$$a_1=1, d=7-1=6$$$n$\begin{align}S_n&amp;=\dfrac{n}{2}[2 a_1+…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p6?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 &amp; 10 Exercise 4.3

Solutions of Question 9 &amp; 10 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$$306,315,324,333, \ldots, 693$$$a=306$$$d=(315-306) = 9 \text { and } a_n=693 .$$$n$\begin{align}a_n&amp;=a_1+(n-1) d \text { becomes } \\
\Rightarrow a_1+(n-1) d&amp;=693 \\
\Rightarrow 306+(n-1) \cdot 9&amp;=693 \\
\Rightarrow 9 n&amp;=396 \\
\Rightarr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 &amp; 12 Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-3-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 11 &amp; 12 Exercise 4.3

Solutions of Question 11 &amp; 12 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$16 \mathrm{ft}$$48 \mathrm{ft}$$80 \mathrm{ft}$$a_1=16 \mathrm{ft}$$2^{\text {nd }}$$a_2=48 \mathrm{ft}$$a_3=80 \mathrm{ft}$$16,48,80, \ldots \quad$$d=48-16=32$$S_6$\begin{align}S_n&amp;=\dfrac{n}{2}[2 a_1+(n-1) d] \\
\therefore S_6&amp;=\dfrac{6}{2}(2.16+5…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 4.4

Solutions of Question 1 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question(i)
$a_1=5, \quad r=3$$a_1, a_1 r, a_1 r^2, a_1 r^3, a_1 r^4, \ldots$$a_1=5 ; r=3$\begin{align}&amp;5,5.3,5.3^2, 5.3^3, 5.3^4, \ldots\\
\Rightarrow &amp;5,15,45,135,405, \ldots\end{align}$a_1=8, \quad r=-\dfrac{1}{2}$$a_1, a_1 r, a_1 r^2, a_1 r^3, a_1 r^4, \ld…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Exercise 4.4

Solutions of Question 2 &amp; 3 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$27$$243$$$a_3=27 \quad\text{and}\quad a_5=243$$\begin{align}a_3&amp;=a_1 r^2=27\\
a_5&amp;=a_1 r^4=243.\end{align}\begin{align}\dfrac{a_1 r^4}{a_1 r^2}&amp;=\dfrac{243}{27}=9 \\
\Rightarrow r^2&amp;=9 \text { or } r= \pm 3 .\end{align}$$a_1(9)=27 \quad \te…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 &amp; 5 Exercise 4.4

Solutions of Question 4 &amp; 5 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\dfrac{1}{64}$$r=\dfrac{1}{2}$$a_1=16$$a_n=\dfrac{1}{64}$$r=\dfrac{1}{2}$$n$$$a_n=a_1 r^{n-1} \quad \text{then}$$\begin{align}\dfrac{1}{64}&amp;=16(\dfrac{1}{2})^{n-1} \\
\Rightarrow(\dfrac{1}{2})^{n-1}&amp;=\dfrac{1}{64 \times 16}=\dfrac{1}{1024} …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 6 &amp; 7 Exercise 4.4

Solutions of Question 6 &amp; 7 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6
$a_{10}=l, a_{13}=m$$a_{16}=n;\quad$$\ln =m^2$$a_n=a_1 r^{n-1}$\begin{align}a_{10}&amp;=a_1 r^9=l \\
a_{13}&amp;=a_1 r^{12}=m\\
\text{and} \quad a_{16}&amp;=a_1 e^{\mathbf{A 5}}=n\end{align}\begin{align}a_{10} \cdot a_{16}&amp;=\ln =(a_1 r^9)(a_1 r^{15})\\
…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 4.4

Solutions of Question 8 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$3.14$$2.71$$a=3.14$$b=2.71$$$G= \pm \sqrt{(3.14)(2.71)}= \pm 2.94$$$$G=2.94 \quad \text{or} \quad -2.94$$$-6$$-216$$a=-6$$b=-216$\begin{align}G&amp;= \pm \sqrt{(-6)(-216)}= \pm \sqrt{1296} \\
\Rightarrow G&amp;= \pm 36\end{align}$$G=36 \quad \text{or} \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p6?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 4.4

Solutions of Question 9 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)
$3 \dfrac{5}{9}=\dfrac{32}{9}\quad$$\quad40 \dfrac{1}{2}=\dfrac{81}{2}$$G_1, G_2, G_3, G_4$$G_5$$\dfrac{32}{9}$$\dfrac{81}{2}$$\dfrac{32}{9}, G_1, G_2, G_3, G_4, G_5, \dfrac{81}{2}$$a_7=\dfrac{81}{2}$$a_1=\dfrac{32}{9}$\begin{align}a_1 r^6&amp;=\dfra…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 4.4

Solutions of Question 10 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 10
$48$$18$$a$$b$$1$$48$$$\quad a-b=48....(i)$$$a$$b$$$G=\sqrt{a b}$$$a$$b$$$A=\dfrac{a+b}{2}$$$2$$A \cdot M=G \cdot M+18$$A \cdot M-G \cdot M=18$$$\Rightarrow \dfrac{a+b}{2}-\sqrt{a b}=18$$$$(a+b)-2 \sqrt{a b}=36 \text {. }$$$a=b+48$\begin{align}(b…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-4-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Exercise 4.4

Solutions of Question 11 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 11
$\mathrm{n}$$a$$b$$nth$$G_1, G_2, G_9, \ldots, G_n$$n$$a$$b$$a, G_1, G_2, G_3, \ldots, G_n, b$$n+2$$a_{n+2}=b$$a_n=a_1 r^{n-1}$$n$$n+2$\begin{align}a_{n+2}&amp;=a_1 r^{n i 1}=a r^{n+1}=b \\
\because a_1&amp;=a \\
\Rightarrow \quad r^{n+1}&amp;=\dfrac{b}{a} .…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 4.5

Solutions of Question 1 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$3+6+12+\ldots+3.2^9$$a_1=3, \quad r=\dfrac{6}{3}=2$$a_n=3.2^9$$n$$$a_n=a_1 r^{n-1}$$\begin{align}3.2^9&amp;=3(2)^{n-1} \text { or }(2)^{n-1}=\dfrac{3.2^9}{3} \\
\Rightarrow(2)^{n-1}&amp;=2^9 \\
\Rightarrow n-1&amp;=9 \text { or } n=10  \\
\text {. Now }\qua…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 4.5

Solutions of Question 2 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2(i)
$a_1, a_n, n_2 r$$S_n$$a_1=1, \quad r=-2, \quad a_n=64$$n$$S_n$$a_n=a_1 r^{n-1}$\begin{align}64&amp;=(-2)^{n-1}\\
\Rightarrow(-2)^{n-1}&amp;=(-2)^6 \\
\Rightarrow n-1&amp;=6 \\
\Rightarrow n&amp;=7\\
S_7&amp;=\dfrac{a_1[r^{\prime \prime}-1]}{r-1}\\
\text{then}\\
S_7…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 4.5

Solutions of Question 3 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
$a_2=2$$a_3=1$$a_1$$r$$$a_n=a_1 r^{n-1}$$$$a_2=a_1 r=2....(i)$$$$a_3=a_1 r^2=1...(ii)$$\begin{align}\dfrac{a_1 r^2}{a_1 r}&amp;=\dfrac{1}{2}\\
\Rightarrow r&amp;=\dfrac{1}{2} \text {, }\end{align}\begin{align}\dfrac{a_1}{2}&amp;=2\\
\Rightarrow a_1&amp;=4 \text {. …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 4.5

Solutions of Question 4 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4(i)
$0 . \overline{8}$$$0 . \overline{8}=0.888888 \ldots$$\begin{align}0 . \overline{8}&amp;=0.8+0.08+0.008 \div 0.0008+ \ldots\\
\text { or } 0 . \overline{8}&amp;=0.8+(0.1)(0.8) +(0.1)^2(0.8)+\ldots \ldots \ldots \ldots .(\mathrm{i})\end{align}$$a_1=0.8, \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 &amp; 6 Exercise 4.5

Solutions of Question 5 &amp; 6 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5
$r$$S_{10}=244 S_5$$$S_n=\dfrac{a_1(r^n-1)}{r-1}$$$$S_{10}=\dfrac{a_1(r^{10}-1)}{r-1} \quad \text{and}\quad S_5=\dfrac{a_1(r^5-1)}{r-1}$$$S_{10}$$S_S$\begin{align}\dfrac{a_1(r^{10}-1)}{r-1}&amp;=244 \dfrac{a_1(r^5-1)}{r-1} \\
\Rightarrow r^{10}-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p6?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 4.5

Solutions of Question 7 &amp; 8 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$\operatorname{sum} S_n$$n$$\{(\dfrac{1}{2})^n\}$$$\{(\dfrac{1}{2})^n\}=\dfrac{1}{2}, \dfrac{1}{2^2}, \dfrac{1}{2^3}, \ldots$$$$a_1=\dfrac{1}{2}$$$$r=\dfrac{\dfrac{1}{2^2}}{\dfrac{1}{2}}=\dfrac{1}{2}$$\begin{align}S_n&amp;=\dfrac{a_1(1-r^n)}{1-r…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 9 &amp; 10 Exercise 4.5

Solutions of Question 9 &amp; 10 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9
$9$$n$$r$$a_1$$$S_n=\dfrac{a_1[r^n-1]}{r-1}$$$$S_6=\dfrac{a_1(r^5-1)}{r-1}$$$$S_3=\dfrac{a_1(r^3-1)}{r-1} \text {. }$$$3$$9$$6$\begin{align} \dfrac{a_1(r^6-1)}{r-1}&amp;=9 \dfrac{a_1(r^3-1)}{r-1} \\
\Rightarrow r^6-1-9(r^3-1) \\
\Rightarrow r^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 &amp; 12 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 11 &amp; 12 Exercise 4.5

Solutions of Question 11 &amp; 12 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$p^{t h}, q^{t h}$$r^{t h}$$a, b, c$$a^{q-r} b^{r-p} c^{p-q}=1$$a_n=a_1 r^{n-1}$$a_p=a_1 r^{p-1}=a \quad a_q=a_1 r^{q-1}=b$$a_r=a_1 r^{r-1}$\begin{align}a^{q-r}&amp;=(a_1 r^{p-1})^{q-r} . \\
b^{r-p}&amp;=(a_1 r^{q-1})^{r-p}, \text { and } \\
c^{p-q}&amp;=(a_1 r^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p9?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 &amp; 14 Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit04/ex4-5-p9?rev=1737476038&amp;do=diff</link>
        <description>Question 13 &amp; 14 Exercise 4.5

Solutions of Question 13 &amp; 14 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$y=\dfrac{x}{3}+\dfrac{x^2}{3^2}+\dfrac{x^3}{3^3}+\ldots$$0&lt;x&lt;3$$x=\dfrac{3 y}{1+y}$$$1+y=1+\dfrac{x}{3}+\dfrac{x^2}{3^2}+\dfrac{x^3}{3^3}$$$a_1=1$$r=\dfrac{x}{3}$$|r|=\dfrac{x}{3}&lt;1$$0&lt;x&lt;3$$S_{\infty}=\dfrac{a_1}{1-r}$$a_1, \quad r$$$S_{\infty}=\dfr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 5.1

Solutions of Question 1 of Exercise 5.1 of Unit 05: Mascellaneous series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$1^2+3^2+5^2+7^2+\ldots$$n$$1+3+5+\ldots$$n^{\text {th }}$$2 n-1$$n^{t h}$$$T_j=(2 j-1)^2$$\begin{align}&amp; \sum_{j=1}^n T_j=\sum_{j=1}^n(2 j-1)^2 \\
&amp; =\sum_{j=1}^n(4 j^2-4 j+1)\\
&amp; =4 \sum_{j=1}^n j^2-4 \sum_{j=1}^n j+\sum_{j=1}^n 1 \\
&amp; =4 \dfr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Exercise 5.1

Solutions of Question 2 &amp; 3 of Exercise 5.1 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Q2 Find the sum $1.2+2.3+3.4+\ldots+99.100$$1+2+3+\ldots+99$$2+3+4+\ldots+100$$n^{\text {th }}$$n(n+1)$$n^{\text {th }}$$\quad T_j=j(j+1)=j^2+j$$j=1$$j=99$$$
\begin{aligned}
&amp; \sum_{j=1}^{99} \tau_j=\sum_{j=1}^{99} j^2+\sum_{j=1}^{99} j \\
&amp; =\frac{99…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 &amp; 5 Exercise 5.1

Solutions of Question 4 &amp; 5 of Exercise 5.1 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$2+(2+5)+(2+5+8)+\ldots$$n$\begin{align}&amp; T_j=\dfrac{j}{2}[2(2)+3(j-1)]\\
&amp;=\dfrac{j(3 j+1)}{2} \\
&amp; =\dfrac{1}{2}(3 j^2+j)\end{align}\begin{align}&amp; \sum_{j=1}^n T_i=\dfrac{1}{2}[3 \sum_{j=1}^n j^2+\sum_{j=1}^n j] \\
&amp; =\dfrac{1}{2}[3 \dfra…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 5.1

Solutions of Question 6 of Exercise 5.1 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 6
$1.2 \cdot 3+2 \cdot 3.4+3.4 .5+\ldots$$n$$1+2+3+\ldots, \quad 2+3+4+5+\ldots$$3+4+5+6+7+\ldots$$n^{t h}$$j, j+1$$j+2$$n^{t h}$\begin{align}
&amp; T_j=j(j+1)(j+2)-j(j^2+3 j+2) \\
&amp; =j^3+3 j^2+2 j\end{align}\begin{align}
&amp; \sum_{j=1}^n T_j=\sum_{j=1}^n …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-1-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 7 &amp; 8 Exercise 5.1

Solutions of Question 7 &amp; 8 of Exercise 5.1 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7
$n$$1.5 .9+2.6 .10+3.7 .11+\ldots$$T_j=j(j+4)(j+8)$\begin{align}
&amp; =j(j^2+12 j+32) \\
&amp; =j^3+12 j^2+32 j\end{align}\begin{align}
&amp; \sum_{j=1}^n T_j=\sum_{j=1}^n j^3+12 \sum_{j=1}^n j^2+32 \sum_{j=1}^n j \\
&amp; =(\dfrac{n(n+1)}{2})^2+12 \dfrac…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-2-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-2-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 5.2

Solutions of Question 1 of Exercise 5.2 of Unit 05: Mascellaneous series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$n$$1.2+2.2^2+3.2^3+4.2^4+\ldots$\begin{align}
&amp; S_n=1.2+2.2^2+3 \cdot 2^3+4 \cdot 2^4+\ldots +n \cdot 2^n....(i) \\
&amp; 2 S_n=1.2^2+2.2^3+3.2^4+4.2^5+\ldots +n \cdot 2^n....(ii)\end{align}\begin{align} (1-2) S_n&amp;=1 \cdot 2+(2-1) 2^2+(3-2) 2^2+(4-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-2-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-2-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Exercise 5.2

Solutions of Question 2 &amp; 3 of Exercise 5.2 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$1+3^2 x+5^2 x^2+7^2 x^3+\ldots, x&lt;1$\begin{align}
&amp; S_{\infty}=1+3^2 x+5^2 x^2+7^2 x^3+\ldots ..(1)\\
&amp; x S_{\infty}=x+3^2 x^2+5^2 x^3+7^2 x^4+\ldots..(2)\end{align}\begin{align}&amp; (1-x) S_{\infty}=1^2+(3^2-1^2) x+(5^2-3^2) x^2+(7^2-5^2) x^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 5.3

Solutions of Question 1 of Exercise 5.3 of Unit 05: Mascellaneous series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1
$n$$n$$4+13+28+49+76+\ldots$\begin{align}
&amp; a_2-a_1=13-4=9 \\
&amp; a_3-a_2=28-13=15 \\
&amp; a_4-a_3=49-28=21 \\
&amp; \cdots \quad \cdots \quad \cdots \\
&amp; \cdots \quad \cdots \quad \cdots \\
&amp; a_n-a_{n-1}=(n-1)th \quad\text{term of sequence}\quad 9,15,21,..…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 5.3

Solutions of Question 2 of Exercise 5.3 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$n$$n$$4+14+30+52+80+114+\ldots$\begin{align}
&amp; a_2-a_1=14-4=10 \\
&amp; a_3-a_2=30-14=16 \\
&amp; a_4-a_3=52-30=22 \\
&amp; \cdots \quad \cdots \quad \cdots \\
&amp; \cdots \quad \cdots \quad \cdots \\
&amp; a_n-a_{n-1}=(\mathrm{n}-1)\text{ term of the sequence} 10,1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 5.3

Solutions of Question 3 of Exercise 5.3 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 3
$n$$n$$4+10+18+28+40+\ldots$\begin{align}
&amp; a_2-a_1=10-4=6 \\
&amp; a_3-a_2=18-10=8 \\
&amp; a_4-a_3=28-18=10 \\
&amp; \text {... ... ... } \\
&amp; \text {... ... ... } \\
&amp; a_n-a_{n \quad 1}=(\mathrm{n}-1) \text { term of the sequence } \end{align}$6,10,8, \ldot…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 5.3

Solutions of Question 4 of Exercise 5.3 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$n$$n$$3+5+11+29+83+245+\ldots$\begin{align}
&amp; a_2-a_1=5-3=2 \\
&amp; a_3-a_2=11-5=6 \\
&amp; a_4-a_3=29-11=18 \\
&amp; \text {... ... ... } \\
&amp; \text {... ... ... } \\
&amp; a_n-a_{n-1}=(\mathrm{n}-1) \text { term ofthe sequence }\end{align}$6,10,18, \ldots$\beg…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-3-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 5.3

Solutions of Question 5 of Exercise 5.3 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 5
$n$$n$$3+9+21+45+93+189+\ldots$\begin{align}
&amp; a_2-a_1=9-3=6 \\
&amp; a_3-a_2=21-9=12 \\
&amp; a_4-a_3=45-21=24\\
&amp; \text {... ... ... } \\
&amp; \text {... ... ... } \\
&amp;a_n-a_{n-1}=(\mathrm{n}-1)\quad \text{ term of the sequence}\quad 6,12,24, \ldots\end{ali…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 5.3

Solutions of Question 1 of Exercise 5.4 of Unit 05: Mascellaneous series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1(i)
$\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\ldots$$n$$$T_n=\dfrac{1}{n(n+1)}$$$T_n$$$\dfrac{1}{n(n+1)}=\dfrac{A}{n}+\dfrac{B}{(n+1)}$$$n(n+1)$$$1=A(n+1)+B n=(A+B) n+A$$$n$$$A+B=0 \text{and} A=1$$$A=1$\begin{align}1+B&amp;=0\\
B&amp;=-1\end{align}\beg…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Exercise 5.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/ex5-4-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Exercise 5.4

Solutions of Question 2 &amp; 3 of Exercise 5.4 of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 2
$\sum_{k=1}^n \dfrac{1}{9 k^2+3 k-2}$\begin{align}\text { Let } S_n&amp;=\sum_{k=1}^n \dfrac{1}{9 k^2+3 k-2} \\
S_n&amp;=\sum_{k=1}^n \dfrac{1}{9 k^2+6 k-3 k-2} \\
&amp; =\sum_{k=1}^n \dfrac{1}{3 k(3 k+2)-1(3 k+2)} \\
S_n&amp;=\sum_{k=1}^n \dfrac{1}{(3 k-1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Review Exercise 5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Review Exercise 5

Solutions of Question 1 of Review Exercise 5 of Unit 05: Vectors. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 1

$t_n=6 n+5$$t_{n+1}=$$6 n-1$$6 n+11$$6 n+6$$6 n-5$$1+\dfrac{2}{3}+\dfrac{6}{3^2}+\dfrac{10}{3^3}+\dfrac{14}{3^4}+\ldots$$6$$2$$3$$4$$1+2.2+3.2^2+\cdots+100.2^{\prime \prime}$$99.2^{100}$$100.2^{100}$$99.2^{100}+1$$1000.2^{100}$$n^{t h}$$1.2+2.3+3.4+\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 &amp; 3 Review Exercise

Solutions of Question 2 &amp; 3 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n$$1.2+2.3+3.4+\ldots$$n^{\text {th }}$$$a_n=n(n+1)=n^2+n$$\begin{align}
\sum_{r=1}^n a_r&amp;=\sum_{r=1}^n r^2+\sum_{r=1}^n r \\
&amp; =\dfrac{n(n+1)(2 n+1)}{6}+\dfrac{n(n+1)}{2} \\
&amp; =\dfrac{n(n+1)}{2}[\dfrac{2 n+1}{3}+1] \\
&amp; =\dfrac{n(n+1)}{2} \cdot …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Review Exercise

Solutions of Question 4 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 4
$\dfrac{1}{1.4 .7}+\dfrac{1}{4.7 .10}+\dfrac{1}{7.10 .13}+\ldots$$1,4,7, \ldots$$$a_n=\dfrac{1}{(3 n-2)(3 n+1)(3 n+4)}$$\begin{align}
\dfrac{1}{(3 n-2)(3 n+1)(3 n+4)}&amp;=\dfrac{A}{3 n-2}+\dfrac{B}{3 n+1}+\dfrac{C}{3 n+4}\end{align}$(3 n-2)(3 n+…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 5 &amp; 6 Review Exercise

Solutions of Question 5 &amp; 6 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$5+12 x+19 x^2+26 x^3+\ldots$$n$\begin{align}S_n&amp;=5+12 x+19 x^2+26 x^3+\cdots+(7 n-2) x^{n-1}...(i)\\ 
x S_n&amp;=5 x+12 x^2+19 x^3+\cdots+(7 n-9) x^{n-1}+(7 n-1) x^n....(ii)\end{align}\begin{align}(1-x) S_n&amp;=5+(12-5) x+(19-12) x^2+\cdots\\
&amp;+[7 n-2-(…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Review Exercise

Solutions of Question 7 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 7(i)
$1.2^2+3.3^2+5.4^2+\ldots$$n$$1,3,5, \ldots,(2 n-1)$$2^2, 3^2, 4^2, \ldots,(n+1)^2$\begin{align}
&amp; a_n=(2 n-1)(n+1)^2 \\
&amp; a_n=(2 n-1)(n^2+2 n+1) \\
&amp; a_n=2 n^3+3 n^2-1\end{align}\begin{align}
\sum_{r=1}^n a_r&amp;=2 \sum_{r=1}^n r^3+\sum_{r=1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p6?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Review Exercise

Solutions of Question 8 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 8(i)
$n$$n^{t h}$$n^3+3^n.$$n^h$$$a_n=n^3+3^n$$\begin{align}\sum_{r=1}^n a_r&amp;=\sum_{r=1}^n r^3+\sum_{r=1}^n 3^r \\
&amp; =[\dfrac{n(n+1)}{2}]^2+\dfrac{3(3^n-1)}{3-1} \\
&amp; =\dfrac{n^2(n+1)^2}{4}+\dfrac{3}{2}(3^n-1) \end{align}$n$$$S_n=\dfrac{n^2(n+1…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit05/re-ex5-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Review Exercise

Solutions of Question 9 of Review Exercise of Unit 05: Miscullaneous Series. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.

Question 9(i)
$n$$3+7+13+21+31+\ldots$\begin{align}
&amp; a_2-a_1=7-3=4 \\
&amp; a_3-a_2=13-7=6 \\
&amp; a_4-a_3=21-13=8 \\
&amp; \ldots \quad \ldots \quad \ldots \\
&amp; \ldots \quad \cdots \quad \ldots \\
&amp; a_n-a_{n-1}=(n-1) \text { term of the series } \\
&amp; 4,6,8, \ldo…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 6.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 6.1

Solutions of Question 1 and 2 of Exercise 6.1 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{10 !}{3 ! .3 ! \cdot 4 !}$\begin{align}\dfrac{10 !}{3 ! \cdot 3 ! \cdot 4 !}&amp;=\dfrac{10.9 .8 \cdot 7 \cdot 6 \cdot 5.4 !}{3 ! \cdot 3 ! \cdot 4 !}\\
&amp;=\dfrac{10.9 .8 .7 .5}{3.2 .1}\\
&amp;=4200 \end{align}$\dfrac{3 !+4 !}{5 !-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Exercise 6.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 &amp; 4 Exercise 6.1

Solutions of Question 3 &amp; 4 of Exercise 6.1 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{1}{6 !}+\dfrac{2}{7 !}+\dfrac{3}{8 !}=\dfrac{75}{8 !}$\begin{align}\dfrac{1}{6 !}+\dfrac{2}{7 !}+\dfrac{3}{8 !}&amp;=\dfrac{1}{6 !}+\dfrac{2}{7.6 !}+\dfrac{3}{8.7 .6 !} \\
&amp; =\dfrac{56+16+3}{8 !}\\
&amp;=\dfrac{75}{8 !}\end{align}$\df…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p4?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 6.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-1-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 6.1

Solutions of Question 4 of Exercise 6.1 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 6.2

Solutions of Question 1 and 2 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$^6 P_6$\begin{align}^6 P_6&amp;=\dfrac{6 !}{(6-6) !}\\
&amp;=6 !=720\end{align}$^{20} P_2$\begin{align}^{20} P_2&amp;=\dfrac{20 !}{(20-2) !}\\
&amp;=\dfrac{20.19 .18 !}{18 !}\\
&amp;=20 \times 19=380\end{align}$^{16} P_3$\begin{align}^{16} P_3&amp;=\dfr…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 and 4 Exercise 6.2

Solutions of Question 3 and 4 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$^n P_r=n(^{n-1} P_{r-1})$$$^n P_r=n({ }^{n-1} P_{r-1})$$\begin{align}n(^{n-1} P_{r-1})&amp;=n \dfrac{(n-1) !}{((n-1)-(r-1)) !} \\
&amp; =\dfrac{n(n-1) !}{(n-r) !}\\
&amp;=\dfrac{n !}{(n-r) !}\\
&amp;=^n P_r\end{align}$^n P_r=^{n-1} P_r+r(^{n-1} …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p3?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 6.2

Solutions of Question 5 and 6 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$7.$$7$$7$\begin{align}^7 P_7&amp;=\dfrac{7 !}{(7-7) !}\\
&amp; =7 !\\
&amp;=5,040 \end{align}$2,4,5,7,9$$2,4,5,7,9$$\mathrm{n} . \mathrm{m}$$e$$$=5.4 .3 .2=120\quad \text{or}$$$$^5 P_4=\dfrac{5 !}{5-4} !=120$$$2$$4$$3$$E_1$$m_1=2$$E_2$$m_2=3…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 7 and 8 Exercise 6.2

Solutions of Question 7 and 8 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1,2,3,4$$E_1$$m_1=5$$E_2$$\cdot m_2=5$$E_3$$m_3=5$$$m_1 \cdot m_2 \cdot m_3=5.5 \cdot 5=125$$$1,2,3,4$$E_1$$m_1=5$$E_2$$m_2=4$$E_3$$m_3=3$$$m_1 \cdot m_2 \cdot m_3=5 \cdot 4 \cdot 3=60$$$8$$5$$=4$$=4$$=5$$=3$$4 ! \cdot 5 ! \cdot …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 6.2

Solutions of Question 9 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$=^6 P_1=6$$s=^6 P_2=30$$=^6 P_3=120$$=^6 P_4=360$$=^6 P_5=720$$=^6 P_6=720$$6+30+120+360+720+720=1956$</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 6.2

Solutions of Question 10 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n=8$$r=5$\begin{align}^8 P_5&amp;=\dfrac{8 !}{(8-5) !}\\
&amp;=\dfrac{8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 !}{3 !}\\
&amp;=6720\end{align}\begin{align}^2 P_2 \times^7 P_4&amp;=2 \times \dfrac{7 !}{(7-4) !}\\
&amp;=2 \times\dfrac{7.6 .5 .4 .3 !}{3 !}\\
&amp;=…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p7?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Exercise 6.2

Solutions of Question 11 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$10$$1000$$2.3,4,0,8,9$$10$$1000$$10$$100$$E_1$$m_1=5$$E_2$$m_2=5$$10$$100$$$m_1 \cdot m_2=5.5=25$$$100$$1000$$0$$E_1$$m_1=5$$E_2$$\boldsymbol{m}_2=5$$E_3$$m_3=4$$100$$1000$$$m_1 \cdot m_2 \cdot m_3=5.5 \cdot 4=100$$$10$$1000$$$100 + 25=125…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p8?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 12 Exercise 6.2

Solutions of Question 12 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$8.$$n=8$$\mathrm{O}$$m_1=3$\begin{align}
 \left(\begin{array}{c}
n \\
m 1
\end{array}\right)&amp;=\left(\begin{array}{l}
8 \\
3
\end{array}\right) \\
&amp; =\dfrac{8 !}{3 !}\\
&amp;=\dfrac{8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 !}{3 !}\\
&amp;=6,720 \e…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 Exercise 6.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-2-p9?rev=1737476038&amp;do=diff</link>
        <description>Question 13 Exercise 6.2

Solutions of Question 13 of Exercise 6.2 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\mathrm{E}$$n=10$$m_1=4$$E, m_2=2$$L$$m_3=2$$C$\begin{align}\text{total number of permutations are}
 &amp;=\left(\begin{array}{c}
n \\
m_1, m_2, m_3
\end{array}\right)\\&amp;=\left(\begin{array}{c}
10 \\
4,2,2
\end{array}\right) \\
&amp; =\dfrac{10 !}…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 6.3

Solutions of Question 1 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$^n C_2=36$$n$\begin{align}&amp;^n C_2=36\\
&amp; \Rightarrow \dfrac{n !}{(n-2) ! 2 !}=36 \\
&amp; \Rightarrow \dfrac{n(n-1)(n-2) !}{(n-2) ! \cdot 2}=36 \\
&amp; \Rightarrow n(n-1)=72 \\
&amp; \Rightarrow n^2-n-72=0 \\
&amp; \Rightarrow n^2-9 n+8 n-72=0\\
&amp; \Rightar…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 6.3

Solutions of Question 2 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n$$r$${ }^n P_r=840$${ }^n C_r=35$\begin{align}
&amp;^n P_r=\dfrac{n !}{(n-r) !}=840 ....(i)\\
&amp;^n C_r=\dfrac{n !}{(n-r) ! r !}=35....(ii)\end{align}\begin{align}\dfrac{n !}{(n-r) !} \cdot \dfrac{(n-r) ! r !}{n !}&amp;=\dfrac{840}{35}\\
r!&amp;=24\\
\te…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 6.3

Solutions of Question 3 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n$$^{2 n} C_3:^n C_2=36: 3$\begin{align}
&amp; { }^{2 n} C_3:{ }^n C_2=36: 3 . \\
&amp; \Rightarrow \dfrac{(2 n) !}{(2 n-3) ! 3 !} \times \dfrac{(n-2) ! 2 !}{n !}=12 \\
&amp; \Rightarrow \dfrac{2 n(2 n-1)(2 n-2)(2 n-3) !}{(2 n-3) ! 3 !}\times\dfrac{(n-2…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 6.3

Solutions of Question 4 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${ }^{n-1} C_r+{ }^{n-1} C_{r-1}={ }^n C_r$$${ }^n{ }^1 C_r+{ }^n{ }^1 C_{r-1}={ }^n C_s$$\begin{align}
{ }^{n-1} C_r+{ }^{n-1} C_{r-1}&amp;=\dfrac{(n-1) !}{(n-r-1) ! r !}+\dfrac{(n-1) !}{(n-1-(r-1)) !(r-1) !} \\
&amp; =\dfrac{(n-1) !}{(n-r-1) ! r(r-…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 6.3

Solutions of Question 5 and 6 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$12$$n=12$${ }^{12} C_2=66$$12$$n=12$${ }^{12} C_3=220$$${ }^6 C_2=\dfrac{6 !}{(6-2) ! 2 !}=15 $$$6$$\quad 15-6=9$</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8 Exercise 6.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-3-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 7 and 8 Exercise 6.3

Solutions of Question 7 and 8 of Exercise 6.3 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$20$\begin{align}{ }^{20} C_2&amp;=\dfrac{20 !}{(20-2)2!}!\\
&amp;=\dfrac{20!}{18!\cdot 2!}\\
&amp;=190\end{align}$7$$10$$3$$7$$10$$${ }^{10} C_7=\dfrac{10 !}{(10-7) ! 7 !}=120$$$7$$4.$$4$$${ }^7 C_4=\dfrac{7 !}{(7-4) ! 4 !}=35.$$$35$$10.$</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 6.4

Solutions of Question 1 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$S=\{1,2,3,4,5,6\}$$5$$5$\begin{align}A&amp;=\{5\}\\
P(A)&amp;=\dfrac{n(A)}{n(S)}\\
&amp;=\dfrac{1}{6} \end{align}$S=\{1,2,3,4,5,6\}$$1$$1$\begin{align}B&amp;=\{\}\\
&amp;=\phi \text{then}\\
P(B)&amp;=\dfrac{n(B)}{n(S)}\\
&amp;=\dfrac{0}{6}\\
&amp;=0\end{align}$S=\{1,2,3,4,…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 6.4

Solutions of Question 2 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$4$$5$$6$$3$$4+5+6=15$$${ }^{15} C_3=\dfrac{15 !}{(15-3) ! 3 !}=455 $$$${ }^6 C_4=\dfrac{6 !}{(6-4) ! 4 !}=15$$$$=\dfrac{15}{455}=\dfrac{3}{91}$$$4$$5$$6$$3$$4+5+6=15$$${ }^{15} C_3=\dfrac{15 !}{(15-3) ! 3 !}=455 $$$${ }^4 C_3=\dfrac{4 !}{(4-…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 6.4

Solutions of Question 3 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$8$$8$$2^8$$$n(S)=256$$$$\dfrac{1}{256}$$$8$$$A=\{8\}$$$${ }^8 C_8=\dfrac{8 !}{(8-8) ! 8 !}=1$$$8$$$P(A)=\dfrac{1}{256}$$$7$$8$$2^8$$$n(S)=256$$$$\dfrac{1}{256}$$$7$$$B=\{7\}$$$7$$8$$$n(B)={ }^8 C_7=\dfrac{8 !}{(8-7) ! 7 !}=8$$$7$$8$$$P(B)=\d…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 6.4

Solutions of Question 4 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.\begin{align}S&amp;=(HHII,HHT.HTH.HTT.THII.THT.TTH,TT7),\\
\text{then} n(S)&amp;=2^3=8\end{align}$$A=\{H H H\}$$$$n(A)=1$$$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{1}{8}$\begin{align}S&amp;=(HHII,HHT.HTH.HTT.THII.THT.TTH,TT7),\\ 
\text{then} n(S)&amp;=2^3=8\end{align}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p5?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 6.4

Solutions of Question 5 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$6$$4$$3$$2$$=6+4=10$$5$$10$\begin{align}{ }^{10)} C_5 &amp;=\dfrac{10 !}{(10-5) ! 5 !}\\
&amp;=252\\ 
n(S)&amp;=252\end{align}$3$$2$$3$$2$\begin{align}{ }^6 \mathrm{C}_3\cdot{ }^{4} \mathrm{C}_2&amp;=\dfrac{6 !}{(6-3) ! 3 !} \cdot \dfrac{4 !}{(4-2) ! 2 !}\\…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 6.4</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-4-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 6.4

Solutions of Question 6 of Exercise 6.4 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$52$$$=52$$$=4$$$=\dfrac{4}{52}=\dfrac{1}{13}$$$52$$=52$$13$$13$$$\dfrac{13}{52}+ \dfrac{13}{52}=\dfrac{1}{4}+\dfrac{1}{4}=\dfrac{2}{4}=\dfrac{1}{2}$$$52$$=52$$13.$$$=\dfrac{13}{52}=\dfrac{1}{4}$$$52$$=52$$12.$$$=\dfrac{12}{52}=\dfrac{3}{13}$…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 and 2 Exercise 6.5

Solutions of Question 1 and 2 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$A$$B$$P(A)=\dfrac{2}{5}, P(B)=\dfrac{2}{5}$$P(A \cup B)=\dfrac{1}{2}$$P(A \cap B)$\begin{align}
 P(A \cup B)&amp;=P(A)+P(B)-P(A \cap B) \\
 \Rightarrow P(A \cap B)&amp;=P(A)+P(B)-P(A \cup B)
\end{align}$P(A), P(B)$$P(A \cup B)$$$P(A \cap…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p2?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 3 and 4 Exercise 6.5

Solutions of Question 3 and 4 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$P(A)=0.5$$P(A \cup B)=0.6$$P(B)$$A$$B$$\mathrm{A}$$B$$A \cap B=\emptyset$\begin{align}P(A \cup B)&amp;=P(A)+P(B)\\
\Rightarrow P(B)&amp;=P(A \cup B)-P(A)\\
&amp;=0.6-.0 .5=0.1 \end{align}$30$$1$$30.$\begin{align}S&amp;=\{1,2,3, \ldots, 50\} \tex…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p3?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 6.5

Solutions of Question 5 and 6 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{8}{9}$$$E=\{ event\, passing\, the\, test \}$$$$E^{\prime}=\{ event\, failing\, the\, test \}$$$E$$E^{\prime}$$P(E)=\dfrac{8}{9}$\begin{align}P(E^{\prime})&amp;=1-P(E)=1-\dfrac{8}{9}=\dfrac{1}{9}\end{align}$4$$4$\begin{align}S…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 6.5

Solutions of Question 7 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$52$$52$$26$$26$$13$$13$$13$$13$$13$$10,9,8,7,6,5,4,3$$2.$$$=\dfrac{13}{52}=\dfrac{1}{4}$$$$=\dfrac{4}{52}=\dfrac{1}{13}$$\begin{align}
P(A \cup B)&amp;=P(A)+P(B) \\
&amp; =\dfrac{1}{4}+\dfrac{1}{13}=\dfrac{17}{52} \end{align}$$=1-\dfrac{17}{52}=\dfr…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p5?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 6.5

Solutions of Question 8 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$7$$11.$\begin{align}s&amp;=(i i, j): i, j-1,2,3,4,5,6\}\\
&amp;=\left[\begin{array}{llllll}
(1.1) &amp; (1.2) &amp; (1.3) &amp; (1.4) &amp; (1.5) &amp; (1.6) \\
(2.1) &amp; (2.2) &amp; (2.3) &amp; (2.4) &amp; (2.5) &amp; (2.6) \\
(3.1) &amp; (3.2) &amp; (3.3) &amp; (3.4) &amp; (3.5) &amp; (3.6) \\
(4.1) &amp; (4…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p6?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 6.5</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/ex6-5-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 6.5

Solutions of Question 9 of Exercise 6.5 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2$$\dfrac{1}{7}$$\dfrac{1}{5}$\begin{align}
P(\text { Ajmal scicction })&amp;=\dfrac{1}{7} \\
\Rightarrow P(\text { Ajmal not selected })&amp;=\dfrac{6}{7} \\
P(\text { Bushra selection })&amp;=\dfrac{1}{5} \\
\Rightarrow P(\text { Bushra not selected }…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p1?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Review Exercise 6

Solutions of Question 1 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$O, P, Q, R, S, T, U$$2520$$9040$$5140$$4880$$\{1,2,3,4,5,6,7\}$$14$$42$$28$$21$$\{1,2,3,4,6,7,8\}$$3$$7$$120$$180$$144$$96$$\dfrac{(n+2) !(n-2) !}{(n+1) !(n-1) !}$$(n-3)$$(\dot{n}-1)$$\dfrac{n+1}{n+2}$$\dfrac{n+2}{n-1}$$5$$768$$724…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Review Exercise 6

Solutions of Question 2 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${ }^{2 n} C_r={ }^{2 n} C_{r+2}$$r$\begin{align}
{ }^{2 n} C_r&amp;={ }^{2 n} C_{r+2} \\
\Rightarrow \dfrac{(2 n) !}{(2 n-r) ! r !}&amp;=\dfrac{(2 n) !}{(2 n-(r+2)) !(r+2) !}\end{align}$(2 n)$\begin{align}
\Rightarrow \dfrac{1}{(2 n-r) ! r…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 &amp; 4 Review Exercise 6

Solutions of Question 3 &amp; 4 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${ }^{56} P_{r+6}:{ }^{54} P_{r+3}=30800: 1$$r$\begin{align}
{ }^{56} P_{r+6}:{ }^{54} P_r+3&amp;=30800: 1  \\
\Rightarrow \dfrac{\dfrac{56 !}{[56-(r+6)] !}}{\dfrac{54 !}{[54-(r+3)] !}}&amp;=\dfrac{30800}{1} \\
\Rightarrow \dfrac{56…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p4?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 5 &amp; 6 Review Exercise 6

Solutions of Question 5 &amp; 6 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$n=6$$$$(n-1) !=(6-1) !=5 !=120$$$120-24=96$$n=6$$(n-1) !=(6-1) !=5 !=120$$$(n-1) !=(5-1) !=4 !=24$$$$(n-1) !=(6-1) !=5 !=120$$$$4 ! \cdot 2 !=48$$$(5-1) !$</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 7 &amp; 8 Review Exercise 6

Solutions of Question 7 &amp; 8 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$P(A)=0.8, P(B)=0.5$$P(B / A)=0.4$$P(A \cap B)$\begin{align}
P(B \mid A)&amp;=\dfrac{P(A \cap B)}{P(A)} \\
\Rightarrow P(A \cap B)&amp;=P(B \mid A) \cdot P(A)\\
&amp;=0.4 \times 0.8=0.32\end{align}$P(A)=0.8, P(B)=0.5$$P(B / A)=0.4$$P(A …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10 Review Exercise 6</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit06/re-ex6-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 9 &amp; 10 Review Exercise 6

Solutions of Question 9 &amp; 10 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2,3,0,3,4,2,3$$1$$=100,0000$$$=\dfrac{7 !}{3 ! \cdot 2 !}=420 $$$1$$0$$7$$0$$$=\dfrac{6 !}{2 ! 3 !}=60 $$$1$$420-50=360$$n$$n$$(n-1)$$(n - 1)$$(n-1)$$(n-2) !$$2$$2 !$$n$$$(n-2) ! \cdot 2 !=2(n-2) ! $$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p1?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 7.1

Solutions of Question 1 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2+4+6+\cdots+2 n=n(n+1)$$n=1$$$2=1(1+1)=2 $$$n=1$$n=k$$$2+4+6+\cdots+2 k=k(k+1)....(i)$$$n=k+1$$(k+1)^{t h}$$$a_{k+1}=\mathbf{2}(k+1)=2 k+2 $$$k+1$\begin{align}2+4+6+\cdots+2 k+2(k+1)&amp; =k(k+1)+2(k+1) \\
&amp; =(k+1)[k+2] \\
&amp; =(k+1)(k+1+1)\end{a…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p2?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 7.1

Solutions of Question 2 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1+5+9+\ldots+(4 n-3)=n(2 n-1)$$n=1$$$1=1(2.1-1)=1$$$n=1$$n=k$\begin{align}1+5+9+\ldots+(4 k-3)\\
&amp; =k(2 k-1)....(i) \\
\end{align}$n=k+1$$k+1$$$a_{k-1}=4(k+1)-3=4 k+1 $$$(k+1)^{t h}$\begin{align}1+5+9+\ldots+(4 k-3)+(4 k+1)&amp; =k(2 k-1)+4 k+1 …</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 7.1

Solutions of Question 3 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$3+6+9+\ldots+3 n=\dfrac{3 n(n+1)}{2}$$n=1$$3=\dfrac{3.1(1+1)}{2}=3$$n=1$$n=k$$$3+6+9+\ldots+3 k=\dfrac{3 k(k+1)}{2}....(i)$$$n=k+1$$(k+1)$$a_{k+1}=3(k+1)$$(k+1)^{t h}$\begin{align}3+6+9+\ldots+3 k+3(k+1) &amp; =\dfrac{3 k(k+1)}{2}+3(k+1) \\
&amp; =3…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 7.1

Solutions of Question 4 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$3+7+11+\cdots+(4 n-1)=n(2 n+1)$$n=1$$$3=1(2+1)=3 $$$n=1$$n=k$\begin{align}3+7+11+\cdots+(4 k-1) 
&amp; =k(2 k+1)....(i) \end{align}$n=k+1$$(k+1)$$a_{k+1}=4(k+1)-1$$(k+1)^{t h}$\begin{align}
3+7+11+\cdots+(4 k-1)+[4(k+1)-1] &amp; =k(2 k+1)+4(k+1)-1 \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p5?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 7.1

Solutions of Question 5 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1^3+2^3+3^3+\ldots+n^3=\left[\dfrac{n(n+1)}{2}\right]^2$$n=1$$1^3=1=\left[\dfrac{1(1+1)}{2}\right]^2=1$$n=1$$n=k_1$\begin{align}1^3+2^3+3^3+\ldots+k^3&amp; =[\dfrac{k(k+1)}{2}]^2....(i)\end{aligned}
3. Now $$ the $$ term of the given series on l…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 7.1

Solutions of Question 6 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1(1 !)+2(2 !)+3(3 !)+\ldots+n(n !)= -(n+1) !-1$$n=1$$$1(1 !)=1=(1+1) !-1=2 !-1=1 $$$n=1$$n=k$\begin{align}1(1 !)+2(2 !)+3(3 !)+\ldots+k(k !)&amp; =(k+1) !-1  \ldots . .(i)\end{align}$n=k+1$$(k+1)^{t h}$$a_{k+1}=(k+1)[(k+1) !]$$a_{k-1}$\begin{ali…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p7?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 7.1

Solutions of Question 7 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1.2+2.3+3.4+\ldots+n(n+1)=\dfrac{n(n+1)(n+2)}{3}$$n=1$$$1.2=2=\dfrac{1(1+1)(1+2)}{3}=2 $$$n=1$$n=k$\begin{align}1.2+2.3+3.4+\ldots+k(k+1)&amp; =\dfrac{k(k+1)(k+2)}{3}....(i)\end{align}$n=k+1$$(k-1)^{t h}$$a_{k+1}=(k+1)(k+ 2)$$(k+1)^{\text {th }}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 7.1

Solutions of Question 8 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1+2+2^2+2^3+\ldots+2^n 1=2^n-1$$n=1$$1=2^1-1=1$$n=1$$n-k&gt;1$\begin{align}1+2+2^2+2^3+\ldots+2^{k-1} \\
&amp; =2^k-1 ....(i)\end{align}$n-k-1$$(k+1)^{t h}$$a_{k+1}=2^k$$a_{k+1}$\begin{align}1+2+2^2+2^3+\ldots+2^{k-1}-2^k &amp; =2^k-12^k \\
&amp; =2^k+2^k-…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p9?rev=1737476038&amp;do=diff</link>
        <description>Question 9 Exercise 7.1

Solutions of Question 9 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\ldots+\dfrac{1}{3^n}=\dfrac{1}{2}[1-\dfrac{1}{3^n}]$$n=1$$$\dfrac{1}{3}-\dfrac{1}{2}[1-\dfrac{1}{3}]-\dfrac{1}{2} \dfrac{2}{3}=\dfrac{1}{3} $$$n=1$$n=k$$$\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\ldots…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p10?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p10?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 7.1

Solutions of Question 10 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\left(\begin{array}{1}5 \\5 \end{array}\right)+\left(\begin{array}{l}6 \\ 5\end{array}\right)+\left(\begin{array}{l}7 \\ 5\end{array}\right)+\ldots+\left(\begin{array}{c}n+4 \\ 5\end{array}\right)=\left(\begin{array}{c}n+5 \\ 6\end{array}\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p11?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p11?rev=1737476038&amp;do=diff</link>
        <description>Question 11 Exercise 7.1

Solutions of Question 11 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.\begin{align}
&amp; \left(\begin{array}{l}
2 \\
2
\end{array}\right)+\left(\begin{array}{l}
3 \\
2
\end{array}\right)+\left(\begin{array}{l}
4 \\
2
\end{array}\right)+\ldots+\left(\begin{array}{l}
n \\
2
\end{array}\right)=\left(\begin{array}{c…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p12?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p12?rev=1737476038&amp;do=diff</link>
        <description>Question 12 Exercise 7.1

Solutions of Question 12 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{5^{2 n}-1}{24}$$n=1$$$\dfrac{5^{2 n}-1}{24}=\dfrac{5^{2.1}-1}{24}=\dfrac{24}{24}=1 \in \mathbb{Z}$$$n=1$$n=k&gt;1$$$\dfrac{5^{2 k}-1}{24} \in \mathbb{Z}$$$n=k+1$\begin{align}\dfrac{5^{2(k+1)}-1}{24}&amp;=\dfrac{5^{2 k+2}-1}{24} \\
&amp; =\dfra…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p13?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p13?rev=1737476038&amp;do=diff</link>
        <description>Question 13 Exercise 7.1

Solutions of Question 13 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2^n&gt;n \forall n \in \mathbf{N}$$n=1$$2^n=2^1=2$$n=1$$2&gt;1$$n=1$$n=l&gt;I$$2^k&gt;k\cdots(i)$$n=k+1$\begin{align}
&amp; 2^{k+1}=2^k \cdot 2&gt;k \cdot 2 \quad \text { by (i) } \\
&amp; \Rightarrow 2^{k+1}&gt;2 k=k+k \\
&amp;\Rightarrow 2^{k+1}&gt;k+1 \text {. as } k&gt;1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p14?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 Exercise 7.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-1-p14?rev=1737476038&amp;do=diff</link>
        <description>Question 14 Exercise 7.1

Solutions of Question 14 of Exercise 7.1 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$5$$3^{2 n-1}+2^{2 n-1}$$n$$n=1$$$3^{2 n-1}+2^{2 n-1}=3^{2.1-1}+2^{2.1-1}=5 \text {. }$$$5$$5$$5$$5.$$n=1$$n=k&gt;1$$54$$3^{2 k} 1+2^{2 k} \quad 1$$$3^{2 k-1}+2^{2 k-1}=5 Q$$$Q$$n=k+1$\begin{align}
3^{2(k+1)-1}+2^{2(k+1)-1} &amp; =3^{2 k+2-1}+2^{2…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p1?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p1?rev=1737476038&amp;do=diff</link>
        <description>Question 1 Exercise 7.2

Solutions of Question 1 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(x^2-\dfrac{1}{y})^4$\begin{align}(x^2-\dfrac{1}{y})^4&amp;=(x^2)^4+{ }^4 C_1(x^2)^3(-\dfrac{1}{y})+ \\
&amp; { }^4 C_2(x^2)^2(-\dfrac{1}{y})^2+{ }^4 C_3(x^2)(-\dfrac{1}{y})^3 + { }^4 C_4(-\dfrac{1}{y})^4 \\
&amp; =x^8- \dfrac{4x^6}{y}+\dfrac{6x^4}{y^2}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p2?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p2?rev=1737476038&amp;do=diff</link>
        <description>Question 2 Exercise 7.2

Solutions of Question 2 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$4^{th}$$(2+a)^7$$\ln$$n=7$$a=2$$b=a$$$T_{r+1}=\frac{7 !}{(7-r) ! r !}(2)^{7-r } a^r $$$4^{\text {th }}$$r=3$\begin{align}
&amp; T_{3+1}=\dfrac{7 !}{(7-3) ! 3 !} 2^{7-3} a^3 \\
&amp; \Rightarrow T_4=\dfrac{7 !}{4 ! 3 !} \cdot 2^4 a^3 \\
&amp; \Rightarrow…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p3?rev=1737476038&amp;do=diff</link>
        <description>Question 3 Exercise 7.2

Solutions of Question 3 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x$$(\dfrac{4 x^2}{3}-\dfrac{3}{2 x})$$n=9, \quad a=\dfrac{4 x^2}{3}$$b=-\dfrac{3}{2 x}$$T_{r+1}$$x$$T_{r+1}$\begin{align}T_{r+1}&amp;=\dfrac{9 !}{(9-r) ! r !}(\dfrac{4 x^2}{3})^{9-r}(-\dfrac{3}{2 x})^r \\
&amp; =\dfrac{9 !}{(9-r) ! r !} \cdot \dfrac…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p4?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p4?rev=1737476038&amp;do=diff</link>
        <description>Question 4 Exercise 7.2

Solutions of Question 4 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x^{23}$$(x^2-x)^{20}$$n=20, \quad a=x^2$$b=-x$$T_{r, 1}$$x^{23}$\begin{align}T_{r-1}&amp;=\dfrac{20 !}{(20-r) ! r !}(x^2)^{20 r}(-x)^r \\
&amp; =\dfrac{20 !}{(20-r) ! r !}(-1)^r \cdot x^{40-2 r+r} \\
&amp; =\dfrac{20 !}{(20-r) ! r !}(-1)^r x^{40-r}\end{…</description>
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        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p5?rev=1737476038&amp;do=diff</link>
        <description>Question 5 Exercise 7.2

Solutions of Question 5 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(\dfrac{a}{x}+b x)^8$$a=\dfrac{a}{x}$$b=b x$$n=8$$n-8$$8+1=9$$$(\dfrac{8+2}{2})^{t h}=5^{t h}$$T_{r+1}$$$T_{r+1}=\dfrac{8 !}{(8-r) ! r !}(\dfrac{a}{x})^{8-r}(b x)^r$$$T_5$$r=4$\begin{align}T_5&amp;=\dfrac{8 !}{(8-4) ! 4 !}(\dfrac{a}{x})^{8-4}(b …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p6?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p6?rev=1737476038&amp;do=diff</link>
        <description>Question 6 Exercise 7.2

Solutions of Question 6 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(2 \sqrt{x}-\dfrac{3}{x \sqrt{x}})^{23}$$a=2 \sqrt{x}$$b=-\dfrac{3}{x \sqrt{x}}$$n=23$$x$\begin{align}
T_{r+1}&amp;=\dfrac{23 !}{(23-r) ! r !}(2 \sqrt{x})^{23-r}(-\dfrac{3}{x \sqrt{x}})^r \\
&amp; =\dfrac{23 !}{(23-r) ! r !} \cdot 2^{23-r} \cdot(-3)…</description>
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p7?rev=1737476038&amp;do=diff</link>
        <description>Question 7 Exercise 7.2

Solutions of Question 7 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(2+\sqrt{3})^5+(2-\sqrt{3})^5$\begin{align}(2+\sqrt{3})^5+(2 \cdot \sqrt{3})^5&amp; =[(2)^5+{ }^5 C_1 \cdot 2^4 \cdot \sqrt{3}+{ }^5 C_2 \cdot 2^3 \cdot(\sqrt{3})^2 \\
&amp; +^5 C_3 \cdot 2^2 \cdot(\sqrt{3})^4+{ }^5 C_4 \cdot 2 \cdot(\sqrt{3})^4 \\
…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p8?rev=1737476038&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p8?rev=1737476038&amp;do=diff</link>
        <description>Question 8 Exercise 7.2

Solutions of Question 8 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(3-2 x)^{10}$$x=\frac{3}{4}$$\left(3-2,1^{10}=3^{10}\left(1-\frac{3 x}{2}\right)^{10}\right.$$\left(1-\frac{3 x}{2}\right)^{10}$$p+1$$: 3-\mathbf{2}_1 1^{10}$$T_{5} !=\left(\begin{array}{c}10 \\ 5\end{array}\right) 3^{10} 5-2 \gamma^{15}$$x=…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p9?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 9 Exercise 7.2

Solutions of Question 9 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(x-y)=&quot;$$x=12$$y-4$$x=12$$$
\begin{aligned}
&amp; \left(x \quad y=20(12-y)^{20}\right. \\
&amp; =12^{2 n}\left(\begin{array}{ll}
1 &amp; \frac{y}{12}
\end{array}\right)^{31}
\end{aligned}
$$$\frac{(n+1) \cdot x}{1+|x|}$$\left(\frac{1}{12}\right)^2 \cdot…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p10?rev=1737476038&amp;do=diff">
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        <dc:date>2025-01-21T16:13:58+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 7.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-2-p10?rev=1737476038&amp;do=diff</link>
        <description>Question 10 Exercise 7.2

Solutions of Question 10 of Exercise 7.2 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$n=2 ;$$s=2^{n-1}$$$
\left.(1+x)^n=\left(\begin{array}{l}
n \\
\vdots
\end{array}\right)+\left(\begin{array}{l}
m \\
1
\end{array}\right) x+\left(\begin{array}{l}
n \\
2
\end{array}\right) x^2-\ldots+i_n^*\right) x^n \cdot
$$$x=1$$(1 \div 1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p1?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 Exercise 7.3

Solutions of Question 1 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\frac{1}{2}$$$
\begin{aligned}
&amp; (1-x)^{\frac{1}{2}}=1+\frac{1}{2} x+ \\
&amp; \frac{\frac{1}{2}\left(-\frac{1}{2}-1\right)}{2 !}(-x)^2
\end{aligned}
$$$$
\begin{aligned}
&amp; +\frac{-\frac{1}{2}\left(-\frac{1}{2}-1\right)\left(-\frac{1}{2}-2\right…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p2?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2 Exercise 7.3

Solutions of Question 2 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sqrt{26}$$$
\begin{aligned}
&amp; \sqrt{26}=\sqrt{25+1} \\
&amp; =\sqrt{25} \sqrt{1+\frac{1}{25}}=5\left[1+\frac{1}{25}\right]^{\frac{1}{2}}
\end{aligned}
$$$$
\begin{aligned}
&amp; \sqrt{26}=5\left[1+\frac{1}{25}\right]^{\frac{1}{2}} \\
&amp; =5\left[1+\f…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p3?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3 Exercise 7.3

Solutions of Question 3 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sqrt{\frac{1-x}{1+x}}$$x^3$$\sqrt{\frac{1-x}{1+x}}$$$
=(1-x)^{\frac{1}{2}}(1+x)^{-\frac{1}{2}} \text {. }
$$$$
\begin{aligned}
&amp; (1-x)^{\frac{1}{2}}(1+x)^{\frac{1}{2}} \\
&amp; =\left[1-\frac{x}{2}+\frac{\frac{1}{2}\left(\frac{1}{2}-1\right)}{2…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p4?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4 Exercise 7.3

Solutions of Question 4 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x$$x^2$$x$$$
\sqrt{\frac{1-3 x}{1+4 x}}=1-\frac{7 x}{2}
$$$$
\sqrt{\frac{1-3 x}{1-4 x}}=(1-3 x)^{\frac{1}{2}}(1+4 x)^{-\frac{1}{2}}
$$$x^2$$x$$$
\begin{aligned}
&amp; =\left(1-\frac{3 x}{2}\right) \times\left(1-\frac{4 x}{2}\right) \\
&amp; =\left(1…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5 and 6 Exercise 7.3

Solutions of Question 5 and 6 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x$$x^2$$x$$$
\frac{(8+3 x)^{\frac{2}{3}}}{(2+3 x) \sqrt{4-5 x}}=1-\frac{5 x}{8}
$$$$
\frac{\sqrt[4]{3}-3 x j^{\frac{2}{3}}}{2 \cdot 3 x+4-5 x}
$$$$
\begin{aligned}
&amp; =\frac{8^{\frac{2}{3}}\left(1+\frac{3 x}{8}\right)^{\frac{2}{3}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p6?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8 Exercise 7.3

Solutions of Question 7 and 8 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x^4$$(1-x)^{\frac{1}{4}}+(1-x)^{\frac{1}{4}}=a-b x^2$$a$$b$$$
\begin{aligned}
&amp; (1+x)^{\frac{1}{4}}+(1-x)^{\frac{1}{4}} \\
&amp; =\left[1+\frac{x}{4}+\frac{\frac{1}{4}\left(\frac{1}{4}-1\right)}{2 !} x^2+\right. \\
&amp; \left.\frac{\fra…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p7?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 9 Exercise 7.3

Solutions of Question 9 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x^{\prime \prime}$$\left(\frac{1+x}{1-x}\right)^2$$$
\begin{aligned}
&amp; \left(\frac{1+x}{1-x}\right)^2=(1+x)^2(1-x)^{-2} \\
&amp; =\left(x^2+2 x+1\right)(1-x)^2
\end{aligned}
$$$$
\begin{aligned}
&amp; =\left(x^2+2 x+1\right)[1+2 x+ \\
&amp; \frac{-2(-2-…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p8?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 10 Exercise 7.3

Solutions of Question 10 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$1-\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}+\ldots$$(1+x)^n$$$
\begin{aligned}
&amp; 1+n x+\frac{n(n-1)}{2 !} x^2 \\
&amp; +\frac{n(n-1(n-2))}{3 !} x^3+\ldots
\end{aligned}
$$$n x=-\frac{1}{4}$$\frac{n(n-1)}{2 !} x^2=\frac{1.3}{2 !} \cdot …</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 11 Exercise 7.3

Solutions of Question 11 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$y=\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}+\frac{1 \cdot 3 \cdot 5}{3 !} \cdot \frac{1}{2^6}+\ldots$$y^2+2 y-1=0$$y=\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}+\frac{1.3 \cdot 5}{3 !} \cdot \frac{1}{2^6}+\ldots$$$
S=y+1=1+\f…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 12 Exercise 7.3

Solutions of Question 12 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$2 y=\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}+\frac{1.3 \cdot 5}{3 !} \cdot \frac{1}{2^6}+\ldots$$4 y^2+4 y-1=0$$$
2 y=\frac{1}{2^2}+\frac{1.3}{2 !} \cdot \frac{1}{2^4}-\frac{1.3 \cdot 5}{3 !} \cdot \frac{1}{2^6}+\ldots
$$$S=2 y+1=…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 Exercise 7.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/ex7-3-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 13 Exercise 7.3

Solutions of Question 13 of Exercise 7.3 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$x$$x^3$$x$$n^{\text {th }}$$1+x$$\frac{2 n+(n+1) x}{2 n+(n-1) x}$$$
\begin{aligned}
&amp; (1+x)^{\frac{1}{n}}=\frac{2 n+(n+1) x}{2 n+(n-1) x} \\
&amp; \frac{2 n+(n+1) x}{2 n+(n-1) x} \\
&amp; =1+\frac{1}{n} x+\frac{\frac{1}{n}\left(\frac{1}{n}-1\right…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p1?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 Review Exercise 7

Solutions of Question 1 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.
Chose the correct option.
&lt;panel&gt;$O, P, Q, R, S, T, U$$2520$$9040$$5140$$4880$$\{1,2,3,4,5,6,7\}$$14$$42$$28$$21$$\{1,2,3,4,6,7,8\}$$3$$7$$120$$180$$144$$96$$\dfrac{(n+2) !(n-2) !}{(n+1) !(n-1) !}$$(n-3)$$(\dot{n}-1)$$\dfrac{n+1}{n…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p2?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2 Review Exercise 7

Solutions of Question 2 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\left(2 x^3+3 y\right)^8$$a=2 x^3$$b=3 y$$n=8$$n=8$$\frac{8+2}{2}=5$$$
\begin{aligned}
&amp; T_5=\frac{8 !}{(8-4) ! 4 !}\left(2 x^3\right)^{8-4}(3 y)^4 \\
&amp; T_5=70.2^4 \cdot 3^4 \cdot x^{12} \cdot y^4 \\
&amp; =90720 x^{12} y^4
\end{aligne…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3 &amp; 4 Review Exercise 7

Solutions of Question 3 &amp; 4 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$(2 x-4 y)^7$$n=7, a=2 x$$b=-4 y$$$
\begin{aligned}
&amp; T_{3+1}=\frac{7 !}{(7-3) ! 3 !}(2 x)^{7 \cdot 3}(-4 y)^3 \\
&amp; =\frac{7 !}{(7-3) ! 3 !} \cdot\left(2^4\right) \cdot(-4)^3 \cdot x^4 y^3 \\
&amp; \Rightarrow T_4=-35840 x^4 y^3…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p4?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 5 &amp; 6 Review Exercise 7

Solutions of Question 5 &amp; 6 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\left(\frac{2}{x^2}+\frac{x^2}{2}\right)^{10}$$n=10, a^{\prime}=\frac{2}{x^2}$$b=\frac{x^2}{2}$$T_{r+1}$$x$$$
\begin{aligned}
&amp; T_{r+1}=\frac{10 !}{(10-r) ! r !}\left(\frac{2}{x^2}\right)^{10 r}\left(\frac{x^2}{2}\right)^r …</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10 Review Exercise 7</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit07/re-ex7-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10 Review Exercise 7

Solutions of Question 9 and 10 of Review Exercise 7 of Unit 07: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p1?rev=1737476039&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$\sin {{37}^{\circ }}\cos {{22}^{\circ }}+\cos {{37}^{\circ }}\sin {{22}^{\circ }}$\begin{align} \sin (\alpha +\beta )=\sin \alpha \cos \beta +\cos \alpha \sin \beta, \end{align}\begin{a…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 10.1

Solutions of Question 2 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \dfrac{\pi }{12}$$\dfrac{\pi }{12}$$\dfrac{\pi }{3}-\dfrac{\pi }{4}$\begin{align}\sin (\alpha -\beta )=\sin \alpha \cos \beta -\cos \alpha \sin.\end{align}\begin{align} \Rightarrow \quad \sin \left( \frac{\pi }{3}-\f…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 10.1

Solutions of Question 3 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin u=\dfrac{3}{5}$$\sin v=\dfrac{4}{5}$$u$$v$$0$$\dfrac{\pi }{2}$$\cos \left( u+v \right)$$\sin u=\dfrac{3}{5},$$0\le u\le \dfrac{\pi }{2}.$$\sin v=\dfrac{4}{5},$$0\le v\le \dfrac{\pi }{2}.$$\cos u=\pm \sqrt{1-{{\sin }^…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p4?rev=1737476039&amp;do=diff</link>
        <description>Question, Exercise 10.1

Solutions of Question 4 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \alpha =-\dfrac{4}{5}$$\cos \beta =-\dfrac{12}{13}$$\alpha $$\beta $$\sin \left( \alpha -\beta  \right)$$\sin \alpha=-\dfrac{4}{5}$$\alpha$$\sin \beta=-\dfrac{12}{13}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$$\…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 10.1

Solutions of Question 5 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\tan \alpha =\dfrac{3}{4}$$\sec \beta =\dfrac{13}{5}$$\alpha$$\beta$$\sin \left( \alpha +\beta  \right)$$\tan\alpha =\dfrac{3}{4}$$\tan\alpha$$\alpha$\begin{align}{{\sec}^{2}}\alpha &amp;=1+{{\tan}^{2}}\alpha\\
\Rightarrow \q…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos \alpha =2{{\cos }^{2}}\dfrac{\alpha }{2}-1=1-2{{\sin }^{2}}\dfrac{\alpha }{2}$\begin{align}\cos \alpha &amp;=\cos 2\dfrac{\alpha }{2}\\
&amp;={{\cos }^{2}}\dfrac{\alpha }{2}-{{\sin }^{2}}\dfrac{\alpha }{2}\\ 
&amp;={{\cos }^{2}}…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 10.1

Solutions of Question 1 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cot \left( \alpha +\beta  \right)=\dfrac{\cot \alpha \cot \beta -1}{\cot \alpha +\cot \beta }$\begin{align}L.H.S.&amp;=\cot (\alpha +\beta )\\
&amp;=\dfrac{1}{\tan (\alpha +\beta )}\\
&amp;=\dfrac{1}{\,\dfrac{\tan \alpha +\tan \beta…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 8, Exercise 10.1

Solutions of Question 8 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\tan \left( \dfrac{\pi }{4}+\theta  \right)=\dfrac{\cos \theta +\sin \theta }{\cos \theta -\sin \theta }$\begin{align}L.H.S.&amp;=\tan \left( \dfrac{\pi }{4}+\theta  \right)\\ 
&amp;=\dfrac{\sin \left( \dfrac{\pi }{4}+\theta  \ri…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p9?rev=1737476039&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 10.1

Solutions of Question 9 and 10 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{\sin \theta }{\sec 4\theta }+\dfrac{\cos \theta }{\cos ec4\theta }=\sin 5\theta $\begin{align}L.H.S.&amp;=\dfrac{\sin \theta }{\sec 4\theta }+\dfrac{\cos \theta }{\cos ec4\theta }\\
&amp;=\dfrac{\sin \theta }…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question11 and 12, Exercise 10.1</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-1-p10?rev=1737476039&amp;do=diff</link>
        <description>Question11 and 12, Exercise 10.1

Solutions of Question 11 and 12 of Exercise 10.1 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\alpha$$\beta$$\gamma$$ABC$$\cot \dfrac{\alpha }{2}+\cot \dfrac{\beta }{2}+\cot \dfrac{\gamma }{2}=\cot \dfrac{\alpha }{2}\cot \dfrac{\beta }{2}\cot \dfrac{\gamma }{2}$$\alpha$$\beta$$\gamma$\begin{align}&amp;\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p1?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 10.2

Solutions of Question 1 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$\sin 2\theta ,\,\,\cos 2\theta$$\tan 2\theta$$\tan \theta =-\dfrac{1}{5}$$\theta$$\sin \theta =\dfrac{1}{\sqrt{26}}$$\cos \theta =\dfrac{-5}{\sqrt{26}}$\begin{align}\sin 2\theta &amp;=2\sin…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p2?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 10.2

Solutions of Question 2 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \theta =\dfrac{5}{13}$$\theta $$\sin 2\theta $$\sin \theta =\dfrac{5}{13}$$$\cos \theta =\pm \sqrt{1-{{\sin }^{2}}\theta }.$$$\theta$$\cos$\begin{align}\cos\theta &amp;=-\sqrt{1-{{\sin }^{2}}\theta }\\
&amp;=-\sqrt{1-\left(\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p3?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 10.2

Solutions of Question 3 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\sin \theta =\dfrac{4}{5}$$\theta$$\sin2\theta$$\sin \theta =\dfrac{4}{5}$$\theta$$\cos \theta =-\dfrac{3}{5}$\begin{align}\sin 2\theta &amp;=2\sin \theta \cos \theta \\
&amp;=2\left( \dfrac{4}{5} \right)\left( -\dfrac{3}{5} \rig…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 and 5, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4 and 5, Exercise 10.2

Solutions of Question 4 and 5 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos \theta =-\dfrac{3}{7}$$\theta $$\sin \dfrac{\theta }{2}$$\cos \theta =-\dfrac{3}{7}$$\theta$\begin{align}&amp;\pi &lt; \theta &lt; \dfrac{3\pi}{2} \\
\implies &amp;\frac{\pi}{2} &lt; \frac{\theta}{2} &lt; \dfrac{3\pi}{4}\end…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p5?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 10.2

Solutions of Question 6 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{15}^{\circ }}$${{15}^{\circ }}=\dfrac{{{30}^{\circ }}}{2}$$\dfrac{\theta }{2}=\dfrac{{{30}^{\circ }}}{2}$$\cos {{15}^{\circ }}$\begin{align}\cos {{15}^{\circ }}&amp;=\cos \dfrac{{{30}^{\circ }}}{2}=\sqrt{\dfrac{1+\cos …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p6?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 10.2</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-2-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 10.2

Solutions of Question 7 of Exercise 10.2 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\cos }^{4}}\theta -{{\sin }^{4}}\theta =\dfrac{1}{\sec 2\theta }$\begin{align}L.H.S&amp;={{\cos }^{4}}\theta -{{\sin }^{4}}\theta \\ 
&amp;=\left( {{\cos }^{2}}\theta -{{\sin }^{2}}\theta  \right)\left( {{\cos }^{2}}\theta +{{\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 10.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 10.3

Solutions of Question 1 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan. There are four parts in Question 1.$2\sin 6x\sin x$$$-2\sin \alpha \sin \beta =\cos (\alpha +\beta )-\cos (\alpha -\beta ).$$$\alpha =6x$$\beta =x$\begin{align}-\,2\sin 6x\sin x&amp;=\cos (6x+x)-\cos (6x-x)\\
&amp;=\cos 7x-\cos x…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p2?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 10.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 10.3

Solutions of Question 2 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\sin {{37}^{\circ }}+\sin {{43}^{\circ }}.$$$$\sin \alpha +\sin \beta =2\sin \left( \dfrac{\alpha +\beta }{2} \right)\cos \left( \dfrac{\alpha -\beta }{2} \right).$$$\alpha ={{37}^{\circ }}$$\beta ={{43}^{\circ }}$\begin…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p3?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 10.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 10.3

Solutions of Question 3 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\dfrac{\cos {{75}^{\circ }}+\cos {{15}^{\circ }}}{\sin {{75}^{\circ }}-\sin {{15}^{\circ }}}=\sqrt{3}.$$$$\cos \alpha +\cos \beta =2\cos \left( \dfrac{\alpha +\beta }{2} \right)\cos \left( \dfrac{\alpha -\beta }{2} \righ…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p4?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 10.3</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/ex10-3-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 10.3

Solutions of Question 5 of Exercise 10.3 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$$\cos {{20}^{\circ }}\cos {{40}^{\circ }}\cos {{60}^{\circ }}\cos {{80}^{\circ }}=\dfrac{1}{16}.$$$2\cos \alpha \cos \beta =\cos \left( \alpha +\beta  \right)+\cos \left( \alpha -\beta  \right)$\begin{align}L.H.S.&amp;=\cos {…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise 10</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Review Exercise 10

Solutions of Question 1 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos {{50}^{\circ }}5{0}&#039;\cos {{9}^{\circ }}1{0}&#039;-\sin {{50}^{\circ }}5{0}&#039;\sin {{9}^{\circ }}1{0}&#039;=$$0$$\dfrac{1}{2}$$1$$\dfrac{\sqrt{3}}{2}$$\tan {{15}^{\circ }}=2-\sqrt{3}$${{\cot }^{2}}{{75}^{\circ }}$$7+\sq…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p2?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Review Exercise 10</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2 and 3, Review Exercise 10

Solutions of Question 2 and 3 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\dfrac{2\sin \theta \sin 2\theta }{\cos \theta +\cos 3\theta }=\tan 2\theta \tan \theta $\begin{align}L.H.S.&amp;=\dfrac{2\sin \theta \sin 2\theta }{\cos \theta +\cos 3\theta }\\
&amp;=\dfrac{2\sin \theta \s…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p3?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise 10</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise 10

Solutions of Question 4 &amp; 5 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.${{\sin }^{2}}\dfrac{\theta }{2}=\dfrac{\sin \theta \tan \dfrac{\theta }{2}}{2}$\begin{align}R.H.S.&amp;=\dfrac{\sin \theta \tan \dfrac{\theta }{2}}{2}\\
&amp;=\dfrac{\sin \theta \sin \dfrac{\theta }{2}}{2\cos \d…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p4?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7, Review Exercise 10</title>
        <link>https://beta.mathcity.org/math-11-kpk/sol/unit10/re-ex10-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 6 &amp; 7, Review Exercise 10

Solutions of Question 6 &amp; 7 of Review Exercise 10 of Unit 10: Trigonometric Identities of Sum and Difference of Angles. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.$\cos 4\theta =1-8{{\sin }^{2}}\theta {{\cos }^{2}}\theta $\begin{align}L.H.S&amp;=\cos 4\theta \\
&amp;=\cos 2\left( 2\theta  \right)\\
&amp;=1-2\sin^2 2\theta \\
&amp;=1-2{{\left( 2\sin\theta \cos \theta  \right)}^{2}}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p1?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 1.1

Solutions of Question 1 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
${{i}^{31}}$\begin{align}{{i}^{31}}&amp;=i\cdot{{i}^{30}}\\
&amp;=i\cdot{{\left( {{i}^{2}} \right)}^{15}}\\
&amp;=i\cdot{{\left( -1 \right)}^{15}} \quad \because i^2=-1\\
&amp;=i\cdot(-1)\\
&amp;=-i.\end{align}${{\left( -i \right)}^{6}}$\begin{align}
{{\left…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p2?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 1.1

Solutions of Question 2 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2(i)
$x+iy$$(3+2i)+(2+4i)$\begin{align}&amp;(3+i2)+(2+i4)\\
=&amp;(3+2)+(i2+i4)\\
=&amp;5+i6\end{align}$x+iy$$(4+3i)-(2+5i)$\begin{align}&amp;(4+3i)-(2+5i)\\
=&amp;(4-2)+(3i-5i)\\
=&amp;2-2i\end{align}$x+iy$$(4+7i)+(4-7i)$\begin{align}
&amp;(4+7i)+(4-7i)\\
=&amp;(4+4)+(7i-7i…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p3?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 1.1

Solutions of Question 3 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3(i)
$\dfrac{(2+i)(3-2i)}{1+i}$\begin{align}&amp;\dfrac{(2+i)(3-2i)}{1+i}\\
=&amp;\dfrac{6-2i^2+3i-4i}{1+i}\\
=&amp;\dfrac{8-i}{1+i}\\
=&amp;\dfrac{8-i}{1+i}\times \dfrac{1-i}{1-i}\\
=&amp;\dfrac{8+i^2-8i-i}{1^2-i^2}\\
=&amp;\dfrac{7-9i}{2}\\
=&amp;\dfrac{7}{2}-\dfrac{9}…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 1.1

Solutions of Question 4 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 4(i)
$x$$y$$(2+3i)x+(1+3i)y+2=0$\begin{align}&amp;(2+3i)x+(1+3i)y+2=0\\
\implies &amp;(2x+y+2)+(3x+3y)i=0.\end{align}\begin{align}
2x+y+2&amp;=0 \quad \cdots(1)\\
3x+3y&amp;=0\quad \cdots (2)
\end{align}\begin{align}
&amp;3x=-3y \\
x=-y \quad ... (3) \end{align}$…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 1.1

Solutions of Question 5 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 5
$z$$4z-3\bar{z}=\dfrac{1-18i}{2-i}$$z=x+iy$$\bar{z}=x-iy$\begin{align}&amp;4z-3\bar{z}=\dfrac{1-18i}{2-i}\\
\implies &amp;4(x+iy)-3(x-iy)=\dfrac{1-18i}{2-i}\times \dfrac{2+i}{2+i}\\
\implies &amp;4x+4iy-3x+3iy=\dfrac{(1-18i)(2+i)}{2^2-i^2} \end{align}\b…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p6?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-1-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 1.1

Solutions of Question 6 of Exercise 1.1 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 6(i)
$4-3 i$$z=4-3 i$$\bar{z}=4+3i$$3 i+8$$2+\sqrt{\dfrac{-1}{5}}$\begin{align}z=&amp;2+\sqrt{\dfrac{-1}{5}}\\
=&amp;2+\sqrt{\dfrac{1}{5}}i,\end{align}$$\bar{z}=2-\sqrt{\dfrac{1}{5}}i$$$\dfrac{5 }{2}i-\dfrac{7}{8}$$z=\dfrac{5 }{2}i-\dfrac{7}{8},$$\bar…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 1.2

Solutions of Question 1 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
$\operatorname{Re}(i z)=-\operatorname{Im}(z)$$$z=x+iy$$\begin{align}
iz&amp;=i(x+iy)\\
&amp;=ix-y\end{align}\begin{align}Re(iz)&amp;=-y\\
\implies Re(iz)&amp;=-Im(z)\end{align}$\operatorname{Im}(i z)=\operatorname{Re}(z)$$$z=x+iy$$\begin{align}iz&amp;=i(x+i…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 1.2

Solutions of Question 2 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2
$$
\left(z_{1} z_{2}\right)\left(z_{3} z_{4}\right)=\left(z_{1} z_{3}\right)\left(z_{2} z_{4}\right)=z_{3}\left(z_{1} z_{2}\right) z_{4}
$$\begin{align}
&amp;(z_1 z_2)(z_3 z_4) \\
=&amp;(z_1 z_2)z_5 \quad \text {Let }z_5=z_3 z_4 \\
=&amp;z_1 (z_2 z_5) \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 1.2

Solutions of Question 3 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3(i)
$z \in \mathbb{C}$$z$$z=\bar{z}$$$z=a+ib\quad \text{where}\quad a,b\in \mathbb{R}\, ... (1)$$$z$$\overline{z}=z$$z$$z$$b=0$\begin{align}
&amp;z=a \\
\implies &amp;\bar{z}=a \end{align}$z=\bar{z}$$\overline{z}=z$$z$\begin{align}&amp; z=\bar{z}\\
\Righ…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 1.2

Solutions of Question 4 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 4
$z_{1}=2-3 i$$\left|z_{1} z_{2}\right|=16$$\left|z_{2}\right|$$$z_{1}=2-3i$$\begin{align}|z_1|&amp;=\sqrt{(2)^2+(-3)^2}\\
&amp;=\sqrt{13}\end{align}\begin{align}&amp;|z_{1} z_{2}|=16\\
\Rightarrow \quad &amp;|z_{1}|| z_{2}|=16\\
\Rightarrow \quad &amp; \sqrt{13…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p5?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 1.2

Solutions of Question 5 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 5
$z_1$$z_2$$|z_1+z_2|^2-|z_1-z_2|^2=4Re(z_1)Re(z_2)$\begin{align}z_1&amp;=x_1+iy_1 \text{ and } z_2&amp;=x_2+iy_2\end{align}\begin{align}z_1+z_2&amp;=x_1+iy_1+x_2+iy_2\\
 &amp;=x_1+x_2+i(y_1+y_2)\\
|z_1+z_2|^2&amp;=(x_1+x_2)^2+(y_1+y_2)^2\\
 &amp;=x^2_1+x^2_2+2x_1x_…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 1.2

Solutions of Question 6 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 6
$\lambda$$\left|\dfrac{z_{1}}{z_{2}}+\lambda\right|=\sqrt{\lambda+2}$$z_{1}=3+i$$z_{2}=1+i$\begin{align} &amp;z_{1}=3+i\text{ and } z_{2}=1+i.\end{align}\begin{align}
\dfrac{z_1}{z_2} &amp;= \dfrac{3+i}{1+i}\\
&amp;=\dfrac{(3+i)(1-i)}{(1+i)(1-i)} \\
&amp;=\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 1.2

Solutions of Question 7 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 7
$\sqrt{2}|z| \geq|\operatorname{Re}(z)|+|\operatorname{Im}(z)| \quad$$\left(|x|-|y|)^{2} \geq 0\right)$\begin{align}
&amp;\left(|x|-|y|)^{2} \geq 0\right) \\
\implies &amp; |x|^2+|y|^2-2|x||y| \geq 0 \\
\implies &amp; |x|^2+|y|^2 \geq 2|x||y| \\
\implie…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 8, Exercise 1.2

Solutions of Question 8 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 8(i)
$|2 z-i|=4$$x$$y$$z=x+i y$$$|2z-i|=4.$$$z=x+i y$\begin{align}
&amp; |2(x+iy)-i|=4 \\
\implies &amp; |2x+i(2y-1)|=4 \\
\implies &amp; \sqrt{(2x)^2+(2y-1)^2}=4
\end{align}\begin{align}
&amp; (2x)^2+(2y-1)^2 = 16\\
\implies &amp; 4x^2+4y^2-4y+1-16=0 \\
\implies…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 1.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-2-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 9, Exercise 1.2

Solutions of Question 9 of Exercise 1.2 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 9(i)
$(2+4 i)^{-1}$$z=2+4i$\begin{align}
Re(2+4i)^{-1} &amp; = Re(z^{-1}) = \dfrac{Re(z)}{|z|^2} \\
&amp; =\dfrac{2}{2^2+4^2} = \dfrac{2}{20}\\ 
&amp;= \dfrac{1}{10}.
\end{align}\begin{align}
Im(2+4i)^{-1} &amp; = Im(z^{-1}) = -\dfrac{Im(z)}{|z|^2} \\
&amp; =-\df…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 1.3

Solutions of Question 1 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
$z^{2}+169$\begin{align} 
&amp; z^{2} + 169 \\
= &amp; z^{2} - (13i)^2 \\
= &amp;(z + 13i)(z - 13i).
\end{align}$2 z^{2}+18$\begin{align}
&amp; 2z^2 + 18 \\
= &amp;2(z^2 - (3i)^2)\\ 
= &amp;2(z + 3i)(z - 3i)
\end{align}$3 z^{2}+363$\begin{align}
&amp; 3z^2 + 363 \\ …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 1.3

Solutions of Question 2 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2(i)
$z^{2}-6 z+2=0$\begin{align} &amp; z^2 - 6z + 2 = 0 \\
\implies &amp; z^2 - 2(3)(z)+9-9+2=0 \\
\implies &amp; (z - 3)^2+7= 0 \\
\implies &amp;  (z - 3)^2 = 7.
\end{align}\begin{align} &amp;z - 3 = \pm \sqrt{7} \\
 \implies &amp;z = 3 \pm \sqrt{7}\end{align}$\{3 …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p3?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 1.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 1.3

Solutions of Question 3 of Exercise 1.3 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3(i)
$\dfrac{1}{3} z^{2}+2 z-16=0$\begin{align}&amp;\dfrac{1}{3}z^{2}+2 z-16=0\\
\implies &amp;z^{2} + 6z - 48 = 0 \end{align}$$ z = \dfrac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a},$$$$a = 1,\quad  b = 6,\quad \text{and}\quad  c = -48.$$\begin{align} 
z&amp; = \d…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p1?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 1.4

Solutions of Question 1 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
$2+i 2 \sqrt{3}$$z=x+iy=2 + i 2 \sqrt{3}$\begin{align} 
r &amp; = \sqrt{x^2 + y^2} = \sqrt{2^2 + (2\sqrt{3})^2} \\
 &amp; = \sqrt{4 + 12} = \sqrt{16} = 4.
\end{align}\begin{align}
\alpha &amp; = \tan^{-1}\left|\frac{y}{x}\right| = \tan^{-1}\left|\fra…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p2?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 1.4

Solutions of Question 2 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2(i)
$\left(\cos \dfrac{\pi}{6}+i \sin \dfrac{\pi}{6}\right)\left(\cos \dfrac{\pi}{3}+i \sin \dfrac{\pi}{3}\right)$$z_1=\cos \dfrac{\pi}{6}+i \sin \dfrac{\pi}{6}=e^{i\frac{\pi}{6}}$$z_2=\cos \dfrac{\pi}{3}+i \sin \dfrac{\pi}{3}=e^{i\frac{\pi}{…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 1.4

Solutions of Question 3 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3(i)
$\left(x_{1}+i y_{1}\right)\left(x_{2}+i y_{2}\right)\left(x_{3}+i y_{3}\right) \ldots\left(x_{n}+i y_{n}\right)=a+i b$$\left(x_{1}^{2}+y_{1}^{2}\right)\left(x_{2}^{2}+y_{2}^{2}\right)\left(x_{3}^{2}+y_{3}^{2}\right) \ldots\left(x_{n}^{2}…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 1.4

Solutions of Question 4 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 4
$\dfrac{1+z}{1-z}=\cos 2 \theta+i \sin 2 \theta$$z=i \tan \theta$\begin{align}&amp;\dfrac{1+z}{1-z}=\cos 2 \theta+i \sin 2 \theta\\
\implies &amp;\dfrac{1+z}{1-z}=e^{i2\theta}\\
\implies &amp;(1+z)=(1-z)e^{i2\theta}\\
\implies &amp;z+z e^{i2\theta}=e^{i2\th…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p5?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 1.4

Solutions of Question 5 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 5
$\cos \alpha+\cos \beta+\cos \gamma=\sin \alpha+\sin \beta+\sin \gamma=0$$\cos 3 \alpha+\cos 3 \beta+\cos 3 \gamma=3 \cos (\alpha+\beta+\gamma)$$\sin 3 \alpha+\sin 3 \beta+\sin 3 \gamma=3 \sin (\alpha+\beta+\gamma)$\begin{align}
\cos \alpha …</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6(i-ix), Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6(i-ix), Exercise 1.4

Solutions of Question 6(i-ix) of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sqrt{2}\left(\cos 315^{\circ}+i \sin 315^{\circ}\right)$\begin{align}
&amp;\sqrt{2}\left(\cos 315^{\circ}+i \sin 315^{\circ}\right) \\
=&amp; \sqrt{2} \left(\dfrac{1}{\sqrt{2}}-\dfrac{i}{\sqrt{2}} \right) \\
=&amp; 1-i.
\end{align}$5\left(\cos 210^{\ci…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6(x-xvii), Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 6(x-xvii), Exercise 1.4

Solutions of Question 6(x-xvii) of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $7 \sqrt{2}\left(\cos \dfrac{5 \pi}{4}+i \sin \dfrac{5 \pi}{4}\right)$$10 \sqrt{2}\left(\cos \dfrac{7 \pi}{4}+i \sin \dfrac{7 \pi}{4}\right)$$2\left(\cos\dfrac{5\pi}{2}+i \sin \dfrac{5\pi}{2}\right)$$\dfrac{1}{\sqrt{2}}\left(\cos \dfrac{\…</description>
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 1.4

Solutions of Question 7 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 7(i)
$\arg (z-1)=-\dfrac{\pi}{4}$$z=x+iy$\begin{align*}
&amp;\arg (z-1)=-\dfrac{\pi}{4} \\
\implies &amp; \arg(x+iy-1) = -\dfrac{\pi}{4} \\
\implies &amp; \arg(x-1+iy) = -\dfrac{\pi}{4} \\
\implies &amp; \tan^{-1}\left(\dfrac{y}{x-1}\right) = -\dfrac{\pi}{4} …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 8, Exercise 1.4

Solutions of Question 8 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 8(i)
$0.004 \mathrm{~mm}$$\dfrac{\pi}{4}$$$x_{\max}=0.004, \quad \theta=\dfrac{\pi}{4}.$$\begin{align}
x&amp;=x_{\max} e^{i\theta} \\
&amp;=0.004 e^{i\dfrac{\pi}{4}} \\
&amp;=\frac{4}{1000} \left(\cos\left(\dfrac{\pi}{4}\right) +i \sin\left(\dfrac{\pi}{4}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 1.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/ex1-4-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 9, Exercise 1.4

Solutions of Question 9 of Exercise 1.4 of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 9(i)
$x=2+3 i$$x_{\max }=1+4 i$$\mathrm{t}=0$$$x=2+3i$$$$x_{\max}=1+4 i$$$$\implies x=x_{\max} e^{i\theta}$$$$2+3i=(1+4 i) e^{i\theta}$$\begin{align}
\implies e^{i\theta}&amp;=\dfrac{2+3i}{1+4i} \\
&amp;=\dfrac{(2+3i)(1-4i)}{(1+4i)(1-4i)} \\
&amp;=\dfrac{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Review Exercise

Solutions of Question 1 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\operatorname{part}(\mathrm{s})$$z$$z$$(0,0)$$(1,0)$$(0,1)$$(1,1)$$z$$|z|$$1 / z$$-z$$\bar{z}$$x$$y$$x y$$z_{1}=3+2 i$$z_{2}=5+6 i$$z_{1}&gt;z_{2}$$z_{1}&lt;z_{2}$$\overline{z_{1}}=\overline{z_{2}}$$\overline{z_{1}}=-\overline{z_{2}}$$\mathrm{z}=3+4 i$$…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Review Exercise

Solutions of Question 2 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $i^{2}+i^{4}+i^{6}+\cdots+i^{100}$\begin{align*}
&amp; i^{2}+i^{4}+i^{6}+\ldots+i^{100} \\
=&amp; i^2 + (i^2)^2 + (i^2)^3 + (i^2)^4 + \ldots +(i^2)^{49} +(i^2)^{50} \\
=&amp; -1 + (-1)^2 + (-1)^3 + (-1)^4 + \ldots + (-1)^{49}+(-1)^{50} \\
=&amp; -1+1-1+1- \ldots -…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Review Exercise

Solutions of Question 3 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3 x^{2}+108$\begin{align*}
&amp; 3 x^{2}+108\\
=&amp;3 (x^{2}+36)\\
=&amp;3 (x^{2}-(6i)^2)\\
=&amp;3 (x+6i)(x-6i)
\end{align*}$4 x^{2}+40$\begin{align*}
&amp;4 x^{2}+40\\
=&amp;4 (x^{2}+10)\\
=&amp;4 (x^{2}+(\sqrt{10}i)^2)\\
=&amp;4 (x+\sqrt{10}i)(x-\sqrt{10}i)
\end{align*}</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Review Exercise

Solutions of Question 4 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $z=x+i y$$\left|\dfrac{z+2 i}{z-2 i}\right|=1$$z = x + iy$\begin{align*}
&amp; \left|\dfrac{z + 2i}{z - 2i}\right| = 1\\
\implies &amp; |z + 2i| = |z - 2i|\\
\implies &amp; |x + i(y + 2)| = |x + i(y - 2)|\\
\implies &amp;  \sqrt{x^2 + (y + 2)^2} = \sqrt{x^2 + (y -…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Review Exercise

Solutions of Question 5 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $z$$(z-3 i)(2+5 i)=3-4 i$$z$$(z-3 i)(2+5 i)=3-4 i$\begin{align*}
&amp;(z-3 i)(2+5 i)=3-4 i \\
\implies &amp; z-3 i=\dfrac{3-4 i}{2+5 i} \\
\implies &amp; z-3 i=\dfrac{(3-4 i)(2-5i)}{(2+5 i)(2-5i)}\\
\implies &amp; z-3 i=\dfrac{6-20-15i-8i}{4+25}\\
\implies &amp; z-3 i…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Review Exercise

Solutions of Question 6 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\dfrac{1}{i^{10}}+(2-i)^{2}+\sqrt{-25}\right]^{3}$\begin{align*}
&amp;\left[\dfrac{1}{i^{10}} + (2 - i)^2 + \sqrt{-25}\right]^3\\
=&amp;\left[\dfrac{1}{(i^2)^5} + ( 4 - 4i + i^2) + 5i \right]^3\\
=&amp;\left[\dfrac{1}{(-1)^5} + ( 4 - 4i -1) + 5i \right]…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit01/re-ex-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Review Exercise

Solutions of Question 7 of Review Exercise of Unit 01: Complex Numbers. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 z^{2}-11 z+16=0$\begin{align*}
&amp;2 z^{2}-11 z+16=0\\
\implies&amp;z^2 - \dfrac{11}{2}z + 8 = 0\\
\implies&amp; z^2 - \dfrac{11}{2}z = -8\\
\implies&amp; z^2 - 2z\dfrac{11}{4}z + \dfrac{121}{16} = -8 + \dfrac{121}{16}\\
\implies&amp;\left(z-\dfrac{11}{4}\right)^2…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.1

Solutions of Question 1 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{lll}1 &amp; 3 &amp; 0 \\ 2 &amp; 0 &amp; 1\end{array}\right]$\begin{align}\text{Order of A}&amp;= 2\times 3\end{align}$B=\left[\begin{array}{ll}1 &amp; 2 \\ 2 &amp; 3 \\ 3 &amp; 4\end{array}\right]$\begin{align}\text{Order of B}&amp;= 3\times 2\end{align}$C…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 2.1

Solutions of Question 2 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\quad A=\left[\begin{array}{lll}3 &amp; 6 &amp; 2 \\ 2 &amp; 1 &amp; 9\end{array}\right]$$B=\left[\begin{array}{ll}\frac{1}{3} &amp; 1 \\ 2 &amp; 6\end{array}\right]$$C=\left[\begin{array}{l}3 \\ 2 \\ 8\end{array}\right]$$D=\left[\begin{array}{lll}1 &amp; 6 &amp; 9 \\ 2 &amp; 0 …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-1-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.1

Solutions of Question 3 of Exercise 2.1 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$A=\begin{bmatrix}
3 &amp; 0 &amp; 0 \\
0 &amp; 1 &amp; 0 \\
2 &amp; 6 &amp; 0
\end{bmatrix}$$$$B=\begin{bmatrix}
-6 &amp; 0 &amp; 0 \\
0 &amp; -6 &amp; 0 \\
0 &amp; 0 &amp; -6
\end{bmatrix}$$$$C=\begin{bmatrix}
1 &amp; 0 \\
2 &amp; 0
\end{bmatrix}$$$$D=\begin{bmatrix}
1 &amp; 0 &amp; 0 \\
0 &amp; 1 &amp; 0 \\
0 &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.2

Solutions of Question 1 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[a_{i j}\right]$$2 \times 2$$a_{i j}=\dfrac{i+3 j}{2}$\( a_{ij} = \dfrac{i + 3j}{2} \)\( i = 1, j = 1 \)\[
a_{11} = \dfrac{1 + 3 \cdot 1}{2} = \dfrac{1 + 3}{2} = \dfrac{4}{2} = 2
\]\( i = 1, j = 2 \)\[
a_{12} = \dfrac{1 + 3 \cdot 2}{2} …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.2

Solutions of Question 3 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}3 &amp; -1 &amp; 2 \\ 0 &amp; 6 &amp; 1 \\ -1 &amp; 0 &amp; -3\end{array}\right]$$B=\left[\begin{array}{ccc}2 &amp; 1 &amp; 7 \\ 0 &amp; 2 &amp; -1 \\ -3 &amp; 4 &amp; 2\end{array}\right]$$C$$A+B+C=0$$$A+B+C=0,$$$$C=-A-B.$$\begin{align*}
C&amp;=-\begin{bmatrix}3 &amp; -1 &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.2

Solutions of Question 3 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}3 &amp; -1 &amp; 2 \\ 0 &amp; 6 &amp; 1 \\ -1 &amp; 0 &amp; -3\end{array}\right]$$B=\left[\begin{array}{ccc}2 &amp; 1 &amp; 7 \\ 0 &amp; 2 &amp; -1 \\ -3 &amp; 4 &amp; 2\end{array}\right]$$C$$A+B+C=0$$$A+B+C=0,$$$$C=-A-B.$$\begin{align*}
C&amp;=-\begin{bmatrix}3 &amp; -1 &amp;…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p4?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 2.2

Solutions of Question 4 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$\begin{align}\left[\begin{array}{cc} 2 &amp; 1 \\  3 &amp; 2 \end{array}\right]A\left[\begin{array}{cc} 1 &amp; 3 \\  2 &amp; 4 \end{array}\right]&amp;=\left[\begin{array}{cc} 1 &amp; 0 \\  0 &amp; 1 \end{array}\right]\end{align}$ B = \left[\begin{array}{cc} 2 &amp; 1 \\ 3…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 2.2

Solutions of Question 5 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $X=\left[\begin{array}{lll}1 &amp; 2 &amp; 2 \\ 2 &amp; 1 &amp; 2 \\ 2 &amp; 2 &amp; 1\end{array}\right]$$X^{2}-4 X-5 I=0$\begin{align}L.H.S. &amp; =X^{2}-4 X-5 I \\
&amp;=\begin{bmatrix}
1 &amp; 2 &amp; 2 \\
2 &amp; 1 &amp; 2 \\
2 &amp; 2 &amp; 1
\end{bmatrix}
\begin{bmatrix}
1 &amp; 2 &amp; 2 \\
2 &amp; 1 &amp; 2…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 2.2

Solutions of Question 6 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{cc}2 &amp; 1 \\ 3 &amp; -3\end{array}\right]$$\alpha$$\beta$$A^{2}+\alpha I=\beta A$\begin{align}
&amp; A^{2}+\alpha I=\beta A\\
\implies &amp;\begin{bmatrix}
2 &amp; 1 \\
3 &amp; -3
\end{bmatrix}
\begin{bmatrix}
2 &amp; 1 \\
3 &amp; -3
\end{bmatrix}+\a…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7, Exercise 2.2

Solutions of Question 7 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ll}x &amp; 0 \\ y &amp; 1\end{array}\right]$$n, A^{n}=\left[\begin{array}{cc}x^{n} &amp; 0 \\ \dfrac{y\left(x^{n}-1\right)}{x-1} &amp; 1\end{array}\right]$$$A = \begin{bmatrix} x &amp; 0 \\ y &amp; 1 \end{bmatrix}.$$$n = 1$\begin{align}A^1 =\beg…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 8, Exercise 2.2

Solutions of Question 8 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$B$$2 \times 3$$3 \times 2$$(A B)^{t}=B^{t} A^{t}$\( A \)\( B \)\( 2 \times 3 \)\( 3 \times 2 \)\begin{align*}
	A &amp;= \begin{bmatrix}
	a_{11} &amp; a_{12} &amp; a_{13} \\
	a_{21} &amp; a_{22} &amp; a_{23}
\end{bmatrix}\\
B &amp;= \begin{bmatrix}
	b_{11} &amp; b_{12}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 9, Exercise 2.2

Solutions of Question 9 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$B$$3 \times 3$$(A+B)^{t}=A^{t}+B^{t}$\begin{align*}
A &amp;= \begin{pmatrix} 
a_{11} &amp; a_{12} &amp; a_{13} \\ 
a_{21} &amp; a_{22} &amp; a_{23} \\ 
a_{31} &amp; a_{32} &amp; a_{33} 
\end{pmatrix} \\
B &amp;= \begin{pmatrix} 
b_{11} &amp; b_{12} &amp; b_{13} \\ 
b_{21} &amp; b_{22…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 10, Exercise 2.2

Solutions of Question 10 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$B$$A B=B$$B A=A$$A^{2}+B^{2}$$$AB = B$$$$BA = A$$\begin{align*}
A^2 &amp;= AA\\
&amp; = A(BA)\\
&amp;=(AB)A\\
&amp;=BA\\
&amp;=A
\end{align*}\begin{align*}
B^2&amp;= BB \\
&amp;=B(AB)\\
&amp; = (BA)B\\
&amp;=AB\\
&amp;=B\end{align*}$$A^2 + B^2 = A + B$$$AB = B$$BA = A$$$A^2 + B…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p11?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 11, Exercise 2.2

Solutions of Question 11 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[a_{i j}\right]$$3 \times 3$$a_{i j}=i^{2}-j^{2}$$A$$A=\left[a_{i j}\right]$$a_{ij}=a+{ji}$$a_{ij}=-a_{ji}$$a_{i j}=i^{2}-j^{2}$\begin{align}
a_{ji} &amp; = j^2 -i^2 \\
&amp;= - (i^2 -j^2) \\
&amp;= - a_{ij}
\end{align}$a_{ij}=-a_{ji}$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p12?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, Exercise 2.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-2-p12?rev=1737476039&amp;do=diff</link>
        <description>Question 12, Exercise 2.2

Solutions of Question 12 of Exercise 2.2 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$\left(A^{n}\right)^{t}=\left(A^{t}\right)^{n}$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.3

Solutions of Question 1 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}2 &amp; 3 &amp; 1 \\ 1 &amp; -1 &amp; 2 \\ 4 &amp; 1 &amp; 2\end{array}\right]$\begin{align*}
A &amp;= \left[\begin{array}{ccc}2 &amp; 3 &amp; 1 \\ 1 &amp; -1 &amp; 2 \\ 4 &amp; 1 &amp; 2\end{array}\right]\\
|A|&amp;=2(-2-2)-3(2-8)+1(1+4)\\
\implies |A|&amp;=-8+18+5\\
\implies |…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 2.3

Solutions of Question 2 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{lll}3 &amp; 2 &amp; 3 \\ 4 &amp; 5 &amp; 1 \\ 2 &amp; 1 &amp; 0\end{array}\right]$\(R_1\)\(a_{11} = 3\)\(a_{12} = 2\)\(a_{13} = 3\)\begin{align*}
A &amp;= \left[\begin{array}{ccc} 3 &amp; 2 &amp; 3 \\ 4 &amp; 5 &amp; 1 \\ 2 &amp; 1 &amp; 0 \end{array}\right]\\
&amp; A_{11} = (-1…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.3

Solutions of Question 3 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}3 &amp; 1 &amp; 2 \\ 2 &amp; 3 &amp; 1 \\ -4 &amp; 1 &amp; -3\end{array}\right]$\begin{align*}
A &amp;= \left[\begin{array}{ccc} 3 &amp; 1 &amp; 2 \\ 2 &amp; 3 &amp; 1 \\ -4 &amp; 1 &amp; -3\end{array}\right]\end{align*}\(3 \times 3\)\begin{align*}
|A| &amp;= 3(3 \cdot (-3) …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 2.3

Solutions of Question 4 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\lambda$$\left[\begin{array}{lll}\lambda &amp; 1 &amp; 3 \\ 2 &amp; 1 &amp; 8 \\ 0 &amp; 3 &amp; 1\end{array}\right]$\begin{align*}
A &amp;= \left[\begin{array}{ccc}
\lambda &amp; 1 &amp; 3 \\
2 &amp; 1 &amp; 8 \\
0 &amp; 3 &amp; 1
\end{array}\right]\\
|A| &amp;= \lambda \cdot (-23) - 1 \cdot 2 + 3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 2.3

Solutions of Question 5 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}1 &amp; -1 &amp; 1 \\ 2 &amp; 1 &amp; -1 \\ 1 &amp; -2 &amp; -1\end{array}\right]$\begin{align*}
A &amp;= \left[\begin{array}{ccc}
1 &amp; -1 &amp; 1 \\
2 &amp; 1 &amp; -1 \\
1 &amp; -2 &amp; -1
\end{array}\right]\\
|A|&amp;=  1 [-1 - 2] + 1 [-2 + 1] + 1 [-4 - 1] \\
&amp;= 1 \cd…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 2.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-3-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 2.3

Solutions of Question 6 of Exercise 2.3 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}2 &amp; 1 &amp; -3 \\ 0 &amp; 1 &amp; 0 \\ 2 &amp; 1 &amp; 6\end{array}\right]$$A^{-1}$$A A^{-1}=A^{-1} A=I_{3}$\begin{align*} A &amp;= \begin{bmatrix}
2 &amp; 1 &amp; -3 \\
0 &amp; 1 &amp; 0 \\
2 &amp; 1 &amp; 6
\end{bmatrix} \end{align*}$ A^{-1} $$ A $\begin{align*}
…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-5-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-5-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.5

Solutions of Question 1 of Exercise 2.5 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}1 &amp; 3 &amp; 5 \\ -6 &amp; 8 &amp; 3 \\ -4 &amp; 6 &amp; 5\end{array}\right]$\begin{align*}
&amp; \quad \left[\begin{array}{ccc}1 &amp; 3 &amp; 5 \\ -6 &amp; 8 &amp; 3 \\ -4 &amp; 6 &amp; 5\end{array}\right]\\
\sim &amp; \text{R}
\left[\begin{array}{ccc}
1 &amp; 3 &amp; 5 \\
0 &amp; …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-5-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-5-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 2.5

Solutions of Question 2 of Exercise 2.5 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left[\begin{array}{ccc}5 &amp; 9 &amp; 3 \\ 3 &amp; -5 &amp; 6 \\ 2 &amp; 10 &amp; 6\end{array}\right]$\begin{align*}&amp;\quad\left[ \begin{array}{ccc}
5 &amp; 9 &amp; 3 \\ 
3 &amp; -5 &amp; 6 \\ 
2 &amp; 10 &amp; 6 
\end{array} \right]\\
\sim &amp; \text{R}\left[ \begin{array}{ccc}
1 &amp; \frac{9}{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 2.6

Solutions of Question 1 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $ 2 x_{1}-3 x_{2}+4 x_{3}=0$$x_{1}-2 x_{2}+3 x_{3}=0$$4 x_{1}+x_{2}-6 x_{3}=0$\begin{align*}
&amp;2 x_{1}-3 x_{2}+4 x_{3}=0\cdots (i)\\
&amp;x_{1}-2 x_{2}+3 x_{3}=0\cdots (ii)\\
&amp;4 x_{1}+x_{2}-6 x_{3}=0\cdots (iii)\\
\end{align*}\begin{align*}
A &amp;= \le…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 2.6

Solutions of Question 2 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\lambda$$\lambda$$2 x_{1}-\lambda x_{2}+x_{3}=0$$2 x_{1}+3 x_{2}-x_{3}=0$$3 x_{1}-2 x_{2}+4 x_{3}=0$\begin{align*}
&amp;2 x_{1}-\lambda x_{2}+x_{3}=0 \cdots(i)\\
&amp;2 x_{1}+3 x_{2}-x_{3}=0\cdots(ii)\\
&amp;3 x_{1}-2 x_{2}+4 x_{3}=0\cdots(iii)\\
\end{ali…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3, Exercise 2.6

Solutions of Question 3 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x+3 y+4 z=2$$2 x+y+z=5$$3 x-2 y+z=-3$\begin{align*}
\begin{aligned}
2x + 3y + 4z &amp;= 2 \\
2x + y + z &amp;= 5 \\
3x - 2y + z &amp;= -3
\end{aligned}\end{align*}\begin{align*}
A_{b} &amp;=\quad \left[\begin{array}{cccc}
2 &amp; 3 &amp; 4 &amp; 2 \\
2 &amp; 1 &amp; 1 &amp; 5 \\
3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 4, Exercise 2.6

Solutions of Question 4 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x_{1}-x_{2}-x_{3}=2$$3 x_{1}-4 x_{2}+3 x_{3}=7$$4 x_{1}+2 x_{2}-5 x_{3}=10$\begin{align*}
2x_1 - x_2 - x_3 &amp;= 2, \\
3x_1 - 4x_2 + 3x_3 &amp;= 7, \\
4x_1 + 2x_2 - 5x_3 &amp;= 10,
\end{align*}\begin{align*}	
A_b &amp;= \begin{bmatrix}
2 &amp; -1 &amp; -1 &amp; : &amp; 2 …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 5, Exercise 2.6

Solutions of Question 5 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $x_{1}+x_{2}+2 x_{3}=8$$-x_{1}-2 x_{2}+3 x_{3}=1$$3 x_{1}-7 x_{2}+4 x_{3}=10$$A X=B$\begin{align*}
&amp;A = \begin{bmatrix}
1 &amp; 1 &amp; 2 \\
-1 &amp; -2 &amp; 3 \\
3 &amp; -7 &amp; 4
\end{bmatrix}, \quad
X = \begin{bmatrix}
x_1 \\
x_2 \\
x_3
\end{bmatrix}, \quad
B = \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 6, Exercise 2.6

Solutions of Question 6 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $5 x+3 y+z=6$$2 x+y+3 z=19$$x+2 y+4 z=25$\begin{align*}
A &amp;= \begin{bmatrix}
5 &amp; 3 &amp; 1 \\
2 &amp; 1 &amp; 3 \\
1 &amp; 2 &amp; 4
\end{bmatrix}, \quad
X = \begin{bmatrix}
x \\
y \\
z
\end{bmatrix}, \quad
B = \begin{bmatrix}
6 \\
19 \\
25
\end{bmatrix}
\end{alig…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 2.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/ex2-6-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 2.6

Solutions of Question 7 and 8 of Exercise 2.6 of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}3 &amp; 2 &amp; 1 \\ 4 &amp; -1 &amp; 2 \\ 7 &amp; 3 &amp; -3\end{array}\right]$$A^{-1}$$3 x+4 y+7 z=14 ; 2 x-y+3 z=4 ; \quad x+2 y-3 z=0$\begin{align*}
A &amp;= \begin{bmatrix}
3 &amp; 2 &amp; 1 \\
4 &amp; -1 &amp; 2 \\
7 &amp; 3 &amp; -3
\end{bmatrix}\\
|…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/re-ex-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/re-ex-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Review Exercise

Solutions of Question 1 of Review Exercise of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A$$m \times n$$B$$n \times p$$A B$$n \times p$$m \times p$$p \times m$$n \times n$$A$$1 \times n$$A^{t} A$$1 \times n$$n \times 1$$1 \times 1$$n \times n$$a_{i j}$$A$$a_{i j}=(-1)^{i+j} A_{i j}$$a_{i j}=(-1)^{i+j} M_{i j}$$\frac{A_{i j}}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit02/re-ex-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit02/re-ex-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2 and 3, Review Exercise

Solutions of Question 2 and 3 of Review Exercise of Unit 02: Matrices and Determinants. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $A=\left[\begin{array}{ccc}1 &amp; 2 &amp; 0 \\ -3 &amp; 4 &amp; 9 \\ 2 &amp; 1 &amp; 6\end{array}\right]$$A_{13}, A_{23}$$A_{33}$$|A|$\begin{align*}
A&amp;=\left[\begin{array}{ccc}1 &amp; 2 &amp; 0 \\ -3 &amp; 4 &amp; 9 \\ 2 &amp; 1 &amp; 6\end{array}\right]\\
A_{13} &amp;= (-1)^{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.1

Solutions of Question 1 and 2 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{15}$$$a_{n}=3 n+1$$$$a_{n}=3 n+1$$\begin{align*}
a_1 &amp;= 3(1) + 1 = 3 + 1 = 4\\
a_2 &amp;= 3(2) + 1 = 6 + 1 = 7\\
a_3 &amp;= 3(3) + 1 = 9 + 1 = 10\\
a_4 &amp;= 3(4) + 1 = 12 + 1 = 13\\
\end{align*}\begin{align*}
a_{10} &amp;= 3(10) + 1 = 30…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.1

Solutions of Question 3 and 4 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{n}=\frac{n}{n+1}$$$a_n = \frac{n}{n+1}.$$\begin{align*}

a_1 &amp;= \frac{1}{1+1} = \frac{1}{2}\\
a_2 &amp;= \frac{2}{2+1} = \frac{2}{3}\\
a_3 &amp;= \frac{3}{3+1} = \frac{3}{4}\\
a_4 &amp;= \frac{4}{4+1} = \frac{4}{5}\\
\end{align*}\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.1

Solutions of Question 5 and 6 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{15}$$a_{n}=n^{2}-2 n$$$a_n = n^2 - 2n.$$\begin{align*}
a_1 &amp;= (1)^2 - 2(1) = 1 - 2 = -1\\
a_2 &amp;= (2)^2 - 2(2) = 4 - 4 = 0\\
a_3 &amp;= (3)^2 - 2(3) = 9 - 6 = 3\\
a_4 &amp;= (4)^2 - 2(4) = 16 - 8 = 8\\
\end{align*}\begin{align*}
a_{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.1

Solutions of Question 7 and 8 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{15}$$a_{n}=\left(\frac{-1}{2}\right)^{n-1}$$$a_n = \left( \frac{-1}{2} \right)^{n-1}.$$\begin{align*}a_1 &amp;= \left( \frac{-1}{2} \right)^{1-1} = \left( \frac{-1}{2} \right)^0 = 1 \\
a_2 &amp;= \left( \frac{-1}{2} \right)^{2-1} =…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.1

Solutions of Question 9 and 10 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$a_{10}$$a_{15}$$a_{n}=(-1)^{n}(n+3)$$n$$a_{10}$$a_{15}$$$a_{n}=(-1)^{n+1}(3 n-5).$$$$a_n = (-1)^{n+1}(3n - 5).$$\begin{align*}
a_1 &amp;= (-1)^{1+1}(3(1) - 5) = (1)(3 - 5) = -2 \\
a_2 &amp;= (-1)^{2+1}(3(2) - 5) = (-1)(6 - 5) = -1 \\
a_3 &amp;=…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.1

Solutions of Question 11 and 12 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}=4 n-3; a_8$$$a_n = 4n - 3.$$\begin{align*}
a_8 &amp;= 4(8) - 3 \\
&amp;= 32 - 3 \\
&amp;= 29
\end{align*}$a_8 = 29$$a_{n}=5 n+11 ; a_{9}$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 and 14, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 13 and 14, Exercise 4.1

Solutions of Question 13 and 14 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}=(3 n+4)(2 n-5) ; a_{7}$$a_{n}=(-1)^{n-1}(3.4 n-17.3) ; a_{12}$$$a_n = (-1)^{n-1}(3.4n - 17.3).$$\begin{align*}
a_{12} &amp;= (-1)^{12-1}(3.4 \cdot 12 - 17.3) \\
&amp;= (-1)^{11}(40.8 - 17.3) \\
&amp;= (-1)^{11}(23.5) \\
&amp;= -23.5
\end{align…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15 and 16, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 15 and 16, Exercise 4.1

Solutions of Question 15 and 16 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}=4 n^{2}(11 n+31) ; a_{22}$$$a_n = 4n^2(11n + 31).$$\begin{align*}
a_{22} &amp;= 4 \cdot 22^2 \cdot (11 \cdot 22 + 31) \\
&amp;= 4 \cdot 484 \cdot (242 + 31) \\
&amp;= 4 \cdot 484 \cdot 273 \\
&amp;= 4 \cdot 132132 \\
&amp;= 528528
\end{align*}$a_{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 17 and 18, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 17 and 18, Exercise 4.1

Solutions of Question 17 and 18 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}=\log 10^{n} ; a_{43}$$$a_n = \log 10^n.$$\begin{align*}
a_{43} &amp;= \log 10^{43} \\
&amp;= 43 \cdot \log 10 \\
&amp;= 43 \cdot 1 \\
&amp;= 43
\end{align*}$a_{43}= 43$$a_{n}=\ln e^{n} ; a_{67}$$$a_n = \ln e^n.$$\begin{align*}
a_{67} &amp;= \ln e^…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19 and 20, Exercise 4.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-1-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 19 and 20, Exercise 4.1

Solutions of Question 19 and 20 of Exercise 4.1 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{n}$$1,3,5,7,9, \ldots$$$1, 3, 5, 7, 9, \ldots$$$a_1=1$$d=3-1=2$$$a_n = a_1 + (n - 1) d$$\begin{align*}
\implies a_n &amp;= 1 + (n - 1) \cdot 2\\
 &amp;= 1 + 2n - 2\\
&amp;= 2n - 1 \end{align*}$a_n = 2n - 1$$a_{n}$$3,9,27,81,243, \ldots$\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1, Exercise 4.2

Solutions of Question 1 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=4, d=3$$a_1= 4$$d=3$$$a_n = a_1 + (n - 1)d.$$\begin{align*}
a_2&amp;=4+(2-1)3=4+3=7\\
a_3 &amp;= 4+ (3-1) 3 = 4 + 6 = 10\\
a_4&amp;=4+(4-1)3=4+9=13
\end{align*}$a_1=4$$a_2=7$$a_3=10$$a_4=13$$a_1=7$$d=5$$a_1= 7$$d=5$$$a_n = a_1 + (n - 1)d.$$\begin{align*}
…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 2, Exercise 4.2

Solutions of Question 2 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $5,9,13, \ldots$$$5, 9, 13, \ldots $$$a_1=5$$d=9-5=4$$$a_n=a_1+(n-1)d.$$\begin{align*}
a_4 &amp;=5+(4-1)(4)=5+12=17\\
a_5 &amp;=5+(5-1)(4)=5+16=21\\
a_6 &amp;=5+(6-1)(4)=5+20=25
\end{align*}$17$$21$$25$$11,14,17, \ldots$$$11, 14, 17, \ldots$$$a_1=11$$d=14-11=3$$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.2

Solutions of Question 3 and 4 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $0.07,0.12,0.7, \ldots$$$0.07,0.12,0.7, \ldots$$$a_1 = 0.07$$d=0.05$$a_{11}=?$\begin{align*}
a_n&amp;=a_1+(n-1)d \\
\implies a_{11}&amp;= 0.07+(11-1)(0.05)\\
&amp;=0.07+(10)(0.05)\\
&amp;=0.57
\end{align*}$a_{11}=0.57.$$a_3 = 14$$a_9 = -1$$$a_n = a_1 + (…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.2

Solutions of Question 5 and 6 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{17}=-40$$a_{28}=-73$$a_{1}$$d$$$a_n=a_1+(n-1)d$$\begin{align*}
&amp; a_{17} = -40 \\
\implies &amp;a_1 + 16d = -40 \quad \cdots (1)
\end{align*}\begin{align*}
&amp;a_{28}=-73\\
\implies &amp;a_1 + 27d = -73 \quad \cdots (2)
\end{align*}\begin{align*}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.2

Solutions of Question 7 and 8 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $-6,-2,2, \ldots$$70$$-6,-2,2, \ldots$$a_1=-6$$d=-2+6=4$$a_n=70$$n=?$$$a_n=a_1+(n-1)d.$$\begin{align*}
&amp;70=-6+(n-1)4\\
\implies &amp;70=-6+4n-4\\
\implies &amp;70=4n-10\\
\implies &amp;4n=80\\
\implies &amp; n=20
\end{align*}$a_{20}=70$$\dfrac{5}{2}, \df…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.2

Solutions of Question 9 and 10 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1}{a}, b, \dfrac{1}{c}$$\dfrac{a-c}{2 a c}$$\dfrac{1}{a}, b, \dfrac{1}{c}$\begin{align*}
d&amp;=b-\frac{1}{a}\cdots (i)\\
\end{align*}\begin{align*}
d&amp;=\frac{1}{c}-b \cdots (ii)
\end{align*}\begin{align*}
b-\frac{1}{a}&amp;=\frac{1}{c}-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.2

Solutions of Question 11 and 12 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $1000$$3000$$2$$5000$$3$$20$$$1000, 3000, 5000, \dots, \text{ upto 20 terms}.$$$a_1 = 1000$$d=3000-1000=2000$$S_20=?$$$S_n =\frac{n}{2}[2a_1+(n-1)d],$$\begin{align*}
S_{20} &amp;= \frac{20}{2}[2(1000)+(20-1)2000]\\
&amp;= 10 [2000+(19)2000] \…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 13, Exercise 4.2

Solutions of Question 13 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $7$$17$$a=7$$b=17$\begin{align*}
\text{A.M.} &amp;= \frac{a + b}{2}\\
&amp;= \frac{7 + 17}{2} \\
&amp;= \frac{24}{2} = 12.
\end{align*}$12$$3+3 \sqrt{2}$$7-3 \sqrt{2}$$a=3+3\sqrt{2}$$b=7-3\sqrt{2}$\begin{align*}
\text{A.M.} &amp;= \frac{a + b}{2}\\
&amp;= \frac{(3 + 3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 and 15, Exercise 4.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-2-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 14 and 15, Exercise 4.2

Solutions of Question 14 and 15 of Exercise 4.2 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $b$$10$$b$$20$$a= b$$b=20$\begin{align*}
&amp;\text{A.M.} = \frac{a + b}{2} \\
\implies &amp; 10 = \frac{b + 20}{2} \\
\implies &amp; 20 = b + 20 \\
\implies &amp; b = 20 - 20 \\
\implies &amp; b = 0
\end{align*}$b = 0$$b$$25$$b$$20$$b$$10$$b$$-10$$x$$y$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.3

Solutions of Question 1 and 2 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $4+7+10+13+16+19+22+25$$4+7+10+13+16+19+22+25$$a_1=4$$d=7-4=3$$n=8$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d]\\
\implies S_8&amp;=\frac{8}{2}[2(4)+(8-1)(3)]\\
&amp;=4[8+7\times 3] = 116
\end{align}$a_{1}=2$$a_{n}=200$$n=100$$a_{1}=2$$a_{n}=200$$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.3

Solutions of Question 3 and 4 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=5$$a_{n}=100$$n=200$$a_{1}=5$$a_{n}=100$$n=200$$a_{1}=5$$a_{n}=100$$n=200$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[a_1+a_n] \\
\implies S_{200}&amp;=\frac{200}{2}[5+100]\\
&amp;=10500.
\end{align}$S_{200}=10500$$a_{1}=4$$n=15$$d=3$$a_{1}=4$$n=1…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.3

Solutions of Question 5 and 6 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=50$$n=20$$d=-4$$a_{1}=50$$n=20$$d=-4$$a_{1}=50$$n=20$$d=-4$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d] \\
\implies S_{20}&amp;=\frac{20}{2}[2(50)+(20-1)(-4)]\\
&amp;=10\times [100-76]\\
&amp;=240.
\end{align}$S_{20}=240$$-3+(-7)+(-11)+\cd…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.3

Solutions of Question 7 and 8 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $9+11+13+15+\cdots$$n=12$$a_1=9$$d=11-9=2$$n=12$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d] \\
\implies S_{12}&amp;=\frac{12}{2}[2(9)+(12-1)(2)]\\
&amp;=6\times [18+22]\\
&amp;=240.
\end{align}$S_{12}=240$$2$$100$$2$$100$$$2+4+6+...+100 (50 \tex…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.3

Solutions of Question 9 and 10 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $1$$99$$1$$99$$$1+3+5+...+99 (50 \text{ terms}).$$$a_{1}=1$$n=50$$d=3-1=2$$S_n$\begin{align}
S_n&amp;=\frac{n}{2}[2a_1+(n-1)d] \\
\implies S_{50}&amp;=\frac{50}{2}[2(1)+(50-1)(2)]\\
&amp;=25\times [2+98]\\
&amp;=2500.
\end{align}$1$$99$$2500$$14$$523$$…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.3

Solutions of Question 11 and 12 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $S_{\boldsymbol{n}}$$a_{1}=3$$a_{n}=-38$$n=8$$a_{1}=3$$a_{n}=-38$$n=8$\begin{align}
S_n&amp;=\frac{n}{2}[a_1+a_n] \\
\implies S_{8}&amp;=\frac{8}{2}[3-38]\\
&amp;=4\times[-35] \\
&amp;=-140.
\end{align}$S_{8}=-140$$S_n$$a_{1}=85$$n=21$$a_{n}=25$$a_{1…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p7?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13 and 14, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 13 and 14, Exercise 4.3

Solutions of Question 13 and 14 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $S_s$$a_{1}=34$$n=9$$a_{n}=2$$a_{1}=34$$n=9$$a_{n}=2$\begin{align}
S_n&amp;=\frac{n}{2}[a_1+a_n] \\
\implies S_{9}&amp;=\frac{9}{2}[34+2]\\
&amp;=162.
\end{align}$S_{9}=162$$S_n$$a_{1}=5$$d=\frac{1}{2}$$n=13$$a_{1}=5$$d=\frac{1}{2}$$n=13$\begin{a…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15 and 16, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 15 and 16, Exercise 4.3

Solutions of Question 15 and 16 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $S_n$$a_{1}=91$$d=-4$$a_{n}=15$$a_{1}=91$$d=-4$$a_{n}=15$$n=?$\begin{align} 
&amp; a_n=a_1+(n-1)d \\
\implies &amp; 15=91+(n-1)(-4) \\
\implies &amp; 15=91-4n+4 \\
\implies &amp; 4n=95-15 \\
\implies &amp;  4n = 80\\ \implies &amp; n = 20.
\end{align}\begin{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 17, 18 and 19, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 17, 18 and 19, Exercise 4.3

Solutions of Question 17, 18 and 19 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $6+12+18+\ldots+96$$$6+12+18+\ldots+96.$$$a_{1}=6$$d=12-6=6$$a_{n}=96$$n=?$\begin{align} 
&amp; a_n=a_1+(n-1)d \\
\implies &amp; 96=6+(n-1)(6) \\
\implies &amp; 96=6+6n-6 \\
\implies &amp; 6n=96 \\
\implies &amp;  n = 24.
\end{align}\begin{align}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 20, 21 and 22, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 20, 21 and 22, Exercise 4.3

Solutions of Question 20, 21 and 22 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=7$$a_{n}=139$$S_{n}=876$$a_{1}=7$$a_{n}=139$$S_{n}=876$$n$$d$\begin{align}
&amp;S_n=\frac{n}{2}[a_1+a_n]\\
\implies &amp; 876=\frac{n}{2}[7+139]\\
\implies &amp; 1752=146n\\
\implies &amp; n=\frac{1752}{146}=12.
\end{align}\begin{align…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p11?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 23 and 24, Exercise 4.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-3-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 23 and 24, Exercise 4.3

Solutions of Question 23 and 24 of Exercise 4.3 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$ 14+16+18+...+a_{25}.$$$a_1=14$$d=16-14=2$$n=25$$a_25$$S_25$\begin{align}
a_n&amp;=a_1+(n-1)d\\
\implies a_{25}&amp;= 14+(25-1)(2)\\
&amp;=62.
\end{align}\begin{align}
S_n&amp;=\frac{n}{2}[a_1+a_n]\\
\implies S_{25}&amp; =\frac{25}{2}[14+62]\\
&amp; =25 \t…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.4

Solutions of Question 1 and 2 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $5,20,100,500, \ldots$$5, 20, 100, 500, \ldots $\begin{align*}
\frac{20}{5} = 4\neq \frac{100}{20} = 5.\end{align*}$5, 20, 100, 500, \ldots $\begin{align*}
r_1&amp; =\frac{20}{5} = 4\\
r_2&amp;=\frac{100}{20} = 5\\
r_3&amp;=\frac{500}{100} = 5.
\end{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p2?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p2?rev=1737476039&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.4

Solutions of Question 3 and 4 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{3}{2}, \frac{9}{4}, \frac{27}{8}, \frac{81}{16}, \ldots$\(\frac{3}{2}, \frac{9}{4}, \frac{27}{8}, \frac{81}{16}, \ldots\)\begin{align*}
r_1&amp;=\frac{9/4}{3/2} = \frac{9}{4} \times \frac{2}{3} = \frac{3}{2} \\
r_2&amp;=\frac{27/8}{9/4} = …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p3?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, 6 and 7, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p3?rev=1737476039&amp;do=diff</link>
        <description>Question 5, 6 and 7, Exercise 4.4

Solutions of Question 5, 6 and 7 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=3, r=-2$$a_{1}=3$$r=-2$$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
&amp; a_{2}=a_{1} r=(3)(-2)= -6 \\
&amp; a_{3}=a_{1} r^{2}=(3)(-2)^{2}=3 (4)= 12 \\
&amp; a_{4}=a_{1} r^{3}=(3)(-2)^{3}=3  (-8) = -24
\end{align*}$a_1=3$$a_2=-6$$a_3=12$$a_4=-…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p4?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 and 9, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p4?rev=1737476039&amp;do=diff</link>
        <description>Question 8 and 9, Exercise 4.4

Solutions of Question 8 and 9 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$90,30,10 \ldots$$$a_1=90$$r=\dfrac{30}{90}=\dfrac{1}{3}$$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
&amp; a_{4}=a_{1} r^3=(90)\left(\dfrac{1}{3} \right)^3=90 \times\dfrac{1}{27}=\dfrac{10}{3}\\
&amp; a_{5}=a_{1} r^3=(90)\left(\dfrac{1}{4} \right)^4=…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p5?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10 and 11, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p5?rev=1737476039&amp;do=diff</link>
        <description>Question 10 and 11, Exercise 4.4

Solutions of Question 10 and 11 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$20,30,45 \ldots$$\(a_1=20\)\(r=\frac{30}{20}=\frac{3}{2}\)$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
&amp; a_{4}=a_{1} r^3=(20)\left(\frac{3}{2}\right)^3=20 \times \frac{27}{8} = \frac{540}{8} = 67.5 \\ 
&amp; a_{5}=a_{1} r^4=(20)\left(\frac{3}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p6?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12 and 13, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p6?rev=1737476039&amp;do=diff</link>
        <description>Question 12 and 13, Exercise 4.4

Solutions of Question 12 and 13 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\frac{1}{27}, \frac{1}{9}, \frac{1}{3}, \ldots$$\(a_1=\frac{1}{27}\)\(r=\frac{\frac{1}{9}}{\frac{1}{27}}=3\)$a_{n}=a_{1} r^{n-1}.$\begin{align*}
&amp; a_{4}=a_{1} r^3=\left(\frac{1}{27}\right)(3)^3=\frac{1}{27} \times 27 = 1 \\ 
&amp; a_{5}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p7?rev=1737476039&amp;do=diff">
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        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14 and 15, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p7?rev=1737476039&amp;do=diff</link>
        <description>Question 14 and 15, Exercise 4.4

Solutions of Question 14 and 15 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=4, n=3, r=5$$a_{1}=4, n=3, r=5$$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
a_3&amp;= 4\times 5^2 \\
&amp;=4\times 25 = 100. 
\end{align*}$a_3=100$$a_{1}=2, n=5, r=2$$a_{1}=2$$n=5$$r=2$$a_{n}=a_{1} r^{n-1}.$\begin{align*}
a_5 &amp;= 2 \times 2^{…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p8?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 16 and 17, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p8?rev=1737476039&amp;do=diff</link>
        <description>Question 16 and 17, Exercise 4.4

Solutions of Question 16 and 17 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=7, n=4, r=2$$a_{1}=7$$n=4$$r=2$$a_{n}=a_{1} r^{n-1}.$\begin{align*}
a_4 &amp;= 7 \times 2^{4-1} \\ 
&amp;= 7 \times 2^3 \\ 
&amp;= 7 \times 8 = 56.
\end{align*}$a_4=56$$a_{1}=243, n=5, r=-\frac{1}{3}$$a_{1}=243$$n=5$$r=-\frac{1}{3}$$a_{n}=…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p9?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 18 and 19, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p9?rev=1737476039&amp;do=diff</link>
        <description>Question 18 and 19, Exercise 4.4

Solutions of Question 18 and 19 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=32, n=6, r=-\frac{1}{2}$$a_{1}=32$$n=6$$r=-\frac{1}{2}$$a_{n}=a_{1} r^{n-1}.$\begin{align*}
a_6 &amp;= 32 \times \left(-\frac{1}{2}\right)^{6-1} \\ 
&amp;= 32 \times \left(-\frac{1}{2}\right)^{5} \\ 
&amp;= 32 \times \left(-\frac{1}{32}\ri…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p10?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 20 and 21, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p10?rev=1737476039&amp;do=diff</link>
        <description>Question 20 and 21, Exercise 4.4

Solutions of Question 20 and 21 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$3 , \_\_\_ , \_\_\_ , \_\_\_ , 48$$$a_1=3$$a_5=48$$r$$$
a_n=ar^{n-1}.
$$\begin{align*}
&amp;a_5=a_1 r^4 \\
\implies &amp; 48=3r^4 \\
\implies &amp; r^4 = 16 \\
\implies &amp; r^4 = 2^4 \\
\implies &amp; r = 2.
\end{align*}\begin{align*}
&amp; a_2=a_1 r= (3…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p11?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 22 and 23, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p11?rev=1737476039&amp;do=diff</link>
        <description>Question 22 and 23, Exercise 4.4

Solutions of Question 22 and 23 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$8 , \_\_\_, \_\_\_, \_\_\_, \_\_\_, \dfrac{1}{4}$$$a_1=8$$a_6=\frac{1}{4}$$r$$n$$a_n = a_1 r^{n-1}.$\begin{align*}
a_6 &amp;= a_1 r^5 \\
\implies \frac{1}{4} &amp;= 8 \cdot r^5 \\
\implies r^5 &amp;= \frac{1}{4 \cdot 8} \\
\implies r^5 &amp;= \frac…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p12?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 24 and 25, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p12?rev=1737476039&amp;do=diff</link>
        <description>Question 24 and 25, Exercise 4.4

Solutions of Question 24 and 25 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$5 , \_\_\_, \_\_\_, \_\_\_, 80$$$a_1=5$$a_5=80$$r$$n$$$a_n = a_1 r^{n-1}.$$\begin{align*}
a_5 &amp;= a_1 r^4 \\
\implies 80 &amp;= 5 \cdot r^4 \\
\implies r^4 &amp;= \frac{80}{5} \\
\implies r^4 &amp;= 16 \\
\implies r &amp;= 2.
\end{align*}\begin{alig…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p13?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 26 and 27, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p13?rev=1737476039&amp;do=diff</link>
        <description>Question 26 and 27, Exercise 4.4

Solutions of Question 26 and 27 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $16\,\, ft$$6$$16\,\,ft$$a_1$$a_2$$a_3,...$$$a_1 = 16\times \dfrac{1}{4} = 4\,\, ft.$$$r=\dfrac{1}{4}$$a_6$$$a_{n}=a_{1} r^{n-1}.$$\begin{align*}
a_{6}&amp;=a_{1} r^5 \\
&amp;=(4)\left(\dfrac{1}{4} \right)^5 \\
&amp; = \dfrac{1}{256}
\end{align*}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p14?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 28 and 29, Exercise 4.4</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-4-p14?rev=1737476039&amp;do=diff</link>
        <description>Question 28 and 29, Exercise 4.4

Solutions of Question 28 and 29 of Exercise 4.4 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $=a_1= 1$$= a_2 = 2$$= a_3 = 2(2)=4$$= a_7$$$
1+2+4+...+a_7
$$$a_1=1$$r=2$$n=7$$$
S_n=\frac{a_1\left(1-r^n \right)}{1-r}, \quad r\neq 1.
$$\begin{align*}
S_6&amp;=\frac{(1)\left(1-2^7 \right)}{1-2} \\
&amp;=\frac{1-128}{-2}\\
&amp;=127
\end{align…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p1?rev=1737476039&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:13:59+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p1?rev=1737476039&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.5

Solutions of Question 1 and 2 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $16+16+16+\ldots$$a_1=16$$r=\dfrac{16}{16}=1$$r\neq 1$\begin{align*}
&amp;16+16+16+\ldots \text{ to 11 terms}\\
=&amp;11(16) \\
=&amp; 176
\end{align*}$75+15+3+...$$75+15+3+...$$a_1= 75$$r = \frac{15}{75} = \frac{1}{5}$$n = 10$$n$$$ S_n = \frac{a_1 \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.5

Solutions of Question 3 and 4 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=5$$r=3$$n=12$$a_{1}=5$$r=3$$n=12$$n$\[
S_n = \frac{a_1 \left(1 - r^n\right)}{1 - r}, \quad r\neq 1.
\]\begin{align*}
S_{12} &amp;= \frac{5\left(1 - 3^{12}\right)}{1 - 3} \\
&amp;= \frac{5\left(1 - 531441\right)}{-2} \\
&amp;= \frac{5(-531440)}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.5

Solutions of Question 5 and 6 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=7, r=2, n=14$$a_1 = 7$$r = 2$$n = 14$$n$$$S_n = \frac{a_1 \left(1 - r^n\right)}{1 - r}, \quad r \neq 1.$$\begin{align*}
S_{14} &amp;= \frac{7 \left(1 - 2^{14}\right)}{1 - 2} \\
&amp;= \frac{7 \left(1 - 16384\right)}{-1} \\
&amp;= \frac{7 \time…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.5

Solutions of Question 7 and 8 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=16, r=-\frac{1}{2}, n=10$$a_1 = 16$$r = -\frac{1}{2}$$n = 10$$n$$$S_n = \frac{a_1 \left(1 - r^n\right)}{1 - r}, \quad r \neq 1.$$\begin{align*}
S_{10} &amp;= \frac{16 \left(1 - \left(-\frac{1}{2}\right)^{10}\right)}{1 - \left(-\frac{1}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.5

Solutions of Question 9 and 10 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}=343, a_{4}=-1, r=-\frac{1}{7}$$a_{1}=343$$a_{4}=-1$$r=-\frac{1}{7}$$S_n$$$ S_n =\frac{a_1-a_n r}{1-r}, \quad r\neq 1.$$\begin{align*}
S_4 &amp; =\frac{343-(-1)\left(-\frac{1}{7}\right)}{1+\frac{1}{7}} \\
&amp;=\frac{\frac{2400}{7}}{\frac…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, 12 and 13, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11, 12 and 13, Exercise 4.5

Solutions of Question 11, 12 and 13 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $a_{1}$$S_{n}=244, r=-3, n=5$$S_{n}=244$$r=-3$$n=5$$$ S_n =\frac{a_1(1-r^n)}{1-r}, \quad r\neq 1.$$\begin{align*}
&amp; 244=\frac{a_1(1-(-3)^5)}{1-(-3)} \\
\implies &amp; 244=\frac{a_1(1+243)}{4} \\
\implies &amp; 976=244a_1\\
\implies &amp; …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 14, Exercise 4.5

Solutions of Question 14 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $0.444...$$$0.444... = 0.4+0.04+0.004+...$$$a_1=0.4$$r=\frac{0.04}{0.4}=0.1$$|r|=0.1 &lt; 1$\begin{align*}
S-\infty &amp; = \frac{a_1}{1-r} \\
&amp; = \frac{0.4}{1.0.1} = \frac{0.4}{0.9} \\
&amp; = \frac{4}{9}.
\end{align*}$S_{\infty} =\dfrac{4}{9}$$9.99999 ...$$…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p8?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 15, Exercise 4.5</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-5-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 15, Exercise 4.5

Solutions of Question 15 of Exercise 4.5 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $30 ft$$\frac{2}{5}$$= 30 ft$$= 30 \times \frac{2}{5} = 12 ft$$= 12 \times \frac{2}{5} = \frac{24}{5} ft$$= \frac{24}{5} \times \frac{2}{5} = \frac{48}{25} ft$$D$$$D=30+2\left(12+\frac{24}{5}+\frac{24}{5}+... \right)$$$$
12+\frac{24}{5}+\frac{24}{5…</description>
    </item>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.6

Solutions of Question 1 and 2 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{9}, \frac{1}{12}, \frac{1}{15}, \cdots \quad 7$$$\frac{1}{9}, \frac{1}{12}, \frac{1}{15}, \cdots \text{ is in H.P.}$$$$9, 12, 15, ... \text{ is in A.P.}$$$a_1=9$$d=12-9=3$$a_7=?$$$
a_n=a_1+(n-1)d.
$$\begin{align*}
a_7&amp;=9+(6)(3) …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 &amp; 4, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 &amp; 4, Exercise 4.6

Solutions of Question 3 &amp; 4 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{18}, \frac{1}{13}, \frac{1}{8}, \ldots \quad 20$\begin{align*}
&amp;\frac{1}{18}, \frac{1}{13}, \frac{1}{8}, \ldots \quad \text{ is in H.P.} \\
&amp;18, 13, 8, \ldots \quad \text{ is in A.P.}
\end{align*}$a_1 = 18$$d = 13 - 18 = -5$$a_{20}.…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p3?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 &amp; 6, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 &amp; 6, Exercise 4.6

Solutions of Question 5 &amp; 6 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1}{27}, \dfrac{1}{20}, \dfrac{1}{13}, \ldots \quad$\begin{align*}
&amp;\frac{1}{27}, \frac{1}{20}, \frac{1}{13}, \ldots \quad \text{ is in H.P.} \\
&amp;27, 20, 13, \ldots \quad \text{ is in A.P.}
\end{align*}$a_1 = 27$$d = 20 - 27 = -7$$a_n=…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p4?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 &amp; 8, Exercise 4.6

Solutions of Question 7 &amp; 8 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{4}, \frac{1}{7}, \frac{1}{10}, \frac{1}{13}, \ldots$$ \frac{1}{4}, \frac{1}{7}, \frac{1}{10}, \frac{1}{13}, \ldots $$ a_1 = \frac{1}{4} $$d = \frac{1}{7} - \frac{1}{4} = -\frac{3}{28},$$ n = 14$$$a_n = a_1 + (n-1)d.$$\begin{align*}
…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p5?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 &amp; 10, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 &amp; 10, Exercise 4.6

Solutions of Question 9 &amp; 10 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{7}, \frac{1}{6},-1,-\frac{1}{3}, \ldots$$$\frac{1}{7}, \frac{1}{6}, -1, -\frac{1}{3}, \ldots \text{ is in H.P.}$$$$7, 6, -1, -3, \ldots \text{ is in A.P.}$$$a_1 = 7$$d = 6 - 7 = -1$$a_8=?$$$
a_n = a_1 + (n-1)d.
$$\begin{align*}
a_…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 4.6</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-6-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11, Exercise 4.6

Solutions of Question 11 of Exercise 4.6 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{2}{3}$$\dfrac{4}{7}$$a=\dfrac{2}{3}$$b=\dfrac{4}{7}$\begin{align*}
\text{H.M.}&amp;=\frac{2ab}{a+b} \\
&amp;=\frac{2\times\frac{2}{3}\times\frac{4}{7}}{\frac{2}{3}+\frac{4}{7}} \\
&amp;=\frac{16/21}{26/21} \\
&amp;=\frac{8}{13} \\
\end{align*}$\dfrac{8}{13…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p1?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.7

Solutions of Question 1 and 2 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=1}^{5} \frac{1}{2 k}$\begin{align*}
\sum_{k=1}^{5} \frac{1}{2k} &amp;= \frac{1}{2(1)} + \frac{1}{2(2)} + \frac{1}{2(3)} + \frac{1}{2(4)} + \frac{1}{2(5)}\\
&amp;= \frac{1}{2} + \frac{1}{4} + \frac{1}{6} + \frac{1}{8} + \frac{1}{10}\\
&amp;= …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.7

Solutions of Question 3 and 4 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=0}^{5} 2^{k}$\begin{align*}
\sum_{k=0}^{5} 2^{k} &amp;= 2^0 + 2^1 + 2^2 + 2^3 + 2^4 + 2^5 \\
&amp;= 1 + 2 + 4 + 8 + 16 + 32 \\
&amp;= 63
\end{align*}$\sum_{k=0}^{9} \pi k$\begin{align*}
\sum_{k=0}^{9} \pi k &amp;= \pi(0) + \pi(1) + \pi(2) + \pi(…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.7

Solutions of Question 5 and 6 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=1}^{8} \frac{k}{k+1}$\begin{align*}
\sum_{k=1}^{8} \frac{k}{k+1} &amp;= \frac{1}{2} + \frac{2}{3} + \frac{3}{4} + \frac{4}{5} + \frac{5}{6}\\
&amp;+ \frac{6}{7} + \frac{7}{8} + \frac{8}{9} \\
&amp;= 0.5 + 0.6667 + 0.75 + 0.8 + 0.8333\\
&amp;+ 0.…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.7

Solutions of Question 7 and 8 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=0}^{5}\left(k^{2}-2 k+3\right)$\begin{align*}
\sum_{k=0}^{5} (k^{2} - 2k + 3) &amp;= (0^{2} - 2(0) + 3) + (1^{2} - 2(1) + 3) + (2^{2} - 2 (2) + 3) \\
&amp;+ (3^{2} - 2 (3) + 3) + (4^{2} - 2 (4) + 3) + (5^{2} - 2 (5) + 3) \\
&amp;= (0 - 0 + 3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.7

Solutions of Question 9 and 10 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+\frac{4}{5}+\frac{5}{6}+\dots$$$
\frac{1}{2} + \frac{2}{3} + \frac{3}{4} + \frac{4}{5} + \frac{5}{6} +... = \sum_{k=1}^{\infty}\frac{k}{k+1}
$$$3+6+9+12+15$$$3+6+9+12+15=\sum_{k=1}^{5}3k$$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, 12 and 13, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11, 12 and 13, Exercise 4.7

Solutions of Question 11, 12 and 13 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $-2+4-8+16-32+64$$$
-2 + 4 - 8 + 16 - 32 + 64 = \sum_{k=1}^{6} (-1)^k 2^k
$$$\frac{1}{1 \cdot 2}+\frac{1}{2 \cdot 3}+\frac{1}{3 \cdot 4}+\frac{1}{4 \cdot 5}+$$$
\frac{1}{1 \cdot 2} + \frac{1}{2 \cdot 3} + \frac{1}{3 \cdot 4} +…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 14, 15 and 16, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 14, 15 and 16, Exercise 4.7

Solutions of Question 14, 15 and 16 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$n$$n+1$$T_n$$n$$$
T_{n} = n+1.
$$\begin{align*}\sum_{n=1}^{\infty} T_{n} &amp;= \sum_{n=1}^{\infty} (n+1)\\
&amp; = \sum_{n=1}^{\infty} n + \sum_{n=1}^{\infty} 1 \\
&amp; = \frac{n(n+1)}{2} + n \\
&amp; = \frac{n(n+1)}{2} + \frac{2n}{2} \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p8?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 17 and 18, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 17 and 18, Exercise 4.7

Solutions of Question 17 and 18 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$2^{2}+5^{2}+8^{2}+\ldots$$2+5+8+\ldots$$a_k=2+(k-1)(3)=2+3k-3=3k-1$$T_k$$k$\begin{align*}T_k&amp;=(3k-1)^2 \\
&amp;=9k^2-6k+1. \end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (9k^{2} - 6k + 1)\\
&amp; = 9\sum_{k=1}^{n} k^{2} …</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p9?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19 and 20, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 19 and 20, Exercise 4.7

Solutions of Question 19 and 20 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1^{3}+3^{3}+5^{3}+$$1+3+5+\ldots$$a_k=1+(k-1)(2)=1+2k-2=2k-1$$T_k$$k$\begin{align*}T_k&amp;=(2k-1)^3 \\
&amp;=(2k)^3+3(2k)^2(-1)+3(2k)(-1)^2+(-1)^3 \\
&amp;=8k^3-12k^2+6k+1
\end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (8k^…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p10?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 19 and 20, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 19 and 20, Exercise 4.7

Solutions of Question 19 and 20 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1^{3}+3^{3}+5^{3}+$$1+3+5+\ldots$$a_k=1+(k-1)(2)=1+2k-2=2k-1$$T_k$$k$\begin{align*}T_k&amp;=(2k-1) \\
&amp;=9k^2-6k+1. \end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (2k - 1)\\
&amp; = 2 \sum_{k=1}^{n} k - \sum_{k=1}^{n} 1 \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p11?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 21 and 22, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p11?rev=1737476040&amp;do=diff</link>
        <description>Question 21 and 22, Exercise 4.7

Solutions of Question 21 and 22 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1 \times 4+2 \times 7+3 \times 10+\cdots$$4+7+10+\ldots$$a_k=4+(k-1)(3)=4+3k-3=3k+1$$1+2+3+...$$k$$k(3k+1)$$T_k$$k$\begin{align*}T_k&amp;=k(3k+1) \\
&amp;=3k^2+k. \end{align*}\begin{align*}\sum_{k=1}^{n} T_{k} &amp;= \sum_{k=1}^{n} (3k^2 +k)\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p12?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 23 and 24, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p12?rev=1737476040&amp;do=diff</link>
        <description>Question 23 and 24, Exercise 4.7

Solutions of Question 23 and 24 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$$1+2 \times 2+3 \times 2^{2}+4 \times 2^{3}+\ldots.$$$$1+2 \times 2+3 \times 2^{2}+4 \times 2^{3}+\ldots$$$$
1\times 1+2 \times 2+3 \times 2^{2}+4 \times 2^{3}+\ldots
$$$1,2,3,4,\ldots$$a=1$$d=1$$1, 2, 2^2, 2^3, \ldots$$r=\frac{2}…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p13?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 25 and 26, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p13?rev=1737476040&amp;do=diff</link>
        <description>Question 25 and 26, Exercise 4.7

Solutions of Question 25 and 26 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$1+\frac{4}{7}+\frac{7}{7^{2}}+\frac{10}{7^{3}}+\ldots$\[
1 + \frac{4}{7} + \frac{7}{7^2} + \frac{10}{7^3} + \ldots
\]\(1, 4, 7, 10, \ldots\)\(a = 1\)\(d = 3\)\(1, \frac{1}{7}, \frac{1}{7^2}, \frac{1}{7^3}, \ldots\)\(1\)\(r = \frac…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p14?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 27 and 28, Exercise 4.7</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-7-p14?rev=1737476040&amp;do=diff</link>
        <description>Question 27 and 28, Exercise 4.7

Solutions of Question 27 and 28 of Exercise 4.7 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$5+\frac{7}{3}+\frac{9}{9}+\frac{11}{27}+\ldots$$$$5+\frac{7}{3}+\frac{9}{9}+\frac{11}{27}+\ldots$$$$
5\times 1+7\times\frac{1}{3}+9\times\frac{1}{9}+11\times\frac{1}{27}+\ldots
$$$5,7,9,11,4,\ldots$$a=5$$d=7-5=2$$1, \dfrac{1}{3}, \d…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p1?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 4.8

Solutions of Question 1 and 2 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3+7+13+21+\ldots$$n$$$ S_{n}=3+7+13+21+31+\ldots +T_{n} $$$$ S_{n}=3+7+13+21+\ldots +T_{n-1}+T_{n}.$$\begin{align*}
S_{n}-S_{n}&amp; =3+7+13+21+31+\ldots +T_{n}  \\
&amp; -\left(3+7+13+21+\ldots +T_{n-1}+T_{n}\right)
\end{align*}\begin{align*}
\…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 4.8

Solutions of Question 3 and 4 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $1+4+13+40+121+ \ldots$$n$$$ S_{n}=1+4+13+40+121+\ldots +T_{n} $$$$ S_{n}=1+4+13+40+\ldots +T_{n-1}+T_{n}. $$\begin{align*}
	S_{n}-S_{n}&amp; =1+4+13+40+121+\ldots +T_{n}  \\
	&amp; -\left(1+4+13+40+\ldots +T_{n-1}+T_{n}\right)
\end{align*}\begin…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 4.8

Solutions of Question 5 and 6 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3+4+6+10+18+34+66+\dots$$n$$$ S_{n}=3+4+6+10+18+\ldots +T_{n} $$$$ S_{n}=3+4+6+10+\ldots +T_{n-1}+T_{n}. $$\begin{align*}
S_{n}-S_{n}&amp; =3+4+6+10+18+\ldots +T_{n}  \\
&amp; -\left(3+4+6+10+\ldots +T_{n-1}+T_{n}\right)
\end{align*}\begin{align…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 and 8, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 7 and 8, Exercise 4.8

Solutions of Question 7 and 8 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $n$$$\frac{1}{1 \times 4}+\frac{1}{4 \times 7}+\frac{1}{7 \times 10}+\ldots$$$$\frac{1}{1 \times 4}+\frac{1}{4 \times 7}+\frac{1}{7 \times 10}+\dots$$$T_k$\begin{align*}
T_k &amp;=\frac{1}{(3k-2)(3k+1)}.
\end{align*}\begin{align*}
\frac{1}{(3…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9 and 10, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 9 and 10, Exercise 4.8

Solutions of Question 9 and 10 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\frac{1}{1 \cdot 3}+\frac{1}{2 \cdot 5}+\frac{1}{3 \cdot 7}+\ldots \ldots \text{ up to } \infty$$$\sum_{k=3}^{n} \dfrac{1}{(k+1)(k+2)}$\begin{align*}
T_k &amp;= \frac{1}{(k+1)(k+2)}.
\end{align*}\begin{align*}
\frac{1}{(k+1)(k+2)} = \frac…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11 and 12, Exercise 4.8</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit04/ex4-8-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 11 and 12, Exercise 4.8

Solutions of Question 11 and 12 of Exercise 4.8 of Unit 04: Sequence and Series. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sum_{k=1}^{n} \frac{1}{k(k+2)}$$T_k$$k$\begin{align*}
T_k &amp;= \frac{1}{k(k+2)}.
\end{align*}\begin{align*}
\frac{1}{k(k+2)} = \frac{A}{k} + \frac{B}{k+2} \ldots (1)
\end{align*}$k(k+2)$\begin{align*}
	1 = A(k+2) + Bk \ldots (2)
\end{…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Exercise 5.1

Solutions of Question 1 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1(i)
$2 x^{3}+3 x^{2}-4 x+1$$x+2$$p(x)=2 x^{3}+3 x^{2}-4 x+1$$x-c=x+2 \implies c=-2$\begin{align*}
\text{Remainder} &amp; = p(c) = p(-2) \\
&amp; = 2(-2)^{3}+3 (-2)^{2}-4 (-2)+1 \\
&amp; = -16+12+8+1 \\
&amp;= 5.
\end{align*}$x^{4}+2 x^{3}-x^{2}+2 x+3$$x-2$\( p(x…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2 and 3, Exercise 5.1

Solutions of Question 2 and 3 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $x-3$$x^{3}-2 x^{2}-5 x+6$$p(x)=x^{3}-2 x^{2}-5 x+6$$x-c=x-3$$\implies c=3$$x-3$$p(x)$$p(3)=0$\begin{align*}
p(3)&amp;=3^3-2(3)^2-5(3)+6 \\
&amp; = 27-18-15+6 \\
&amp; = 0.
\end{align*}$x-3$$p(x)$$x-3$$x^{3}-2 x^{2}-5 x+1$$p(x)=x^{3}-2 x^{2}-5 x+1$$x-c=x-3$$…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p3?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 and 5, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 4 and 5, Exercise 5.1

Solutions of Question 4 and 5 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $4 y^{3}-4 y^{2}+10+2 y$$4 y^{2}-8 y+10$$q$$x^{3}+q x^{2}-7 x+6$$(x+1)$$p(x)=x^{3}+q x^{2}-7 x+6$$x-c=x+1$$\implies c=-1$$x+1$$p(x)$$p(-1)=0$\begin{align*}
&amp;(-1)^3+q(-1)^2-7(-1)+6=0 \\
-&amp;1+q+7+6=0\\
&amp;q+12=0\\
&amp;q=-12
\end{align*}</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 and 7, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 6 and 7, Exercise 5.1

Solutions of Question 6 and 7 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $m$$2 x^{3}+3 x^{2}-3 x-m$$x-2$$p(x)=2 x^{3}+3 x^{2}-3 x-m$$x-c=x-2$$\implies c=2$\begin{align*}
\text{Remainder} &amp; = p(c) = p(2) \\
&amp; = 2(2)^{3} + 3(2)^{2} - 3(2) - m \\
&amp; = 2(8) + 3(4) - 3(2) - m \\
&amp; = 16 + 12 - 6 - m \\
&amp; = 22 - m.
\end{align…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8 and 9, Exercise 5.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-1-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 8 and 9, Exercise 5.1

Solutions of Question 8 and 9 of Exercise 5.1 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x^{3}+3 x^{2}-11 x-6$$p(x)=2x^3+3x^2-11x-6$\begin{align}
p(2) &amp;= 2(2)^3+3(2)^2-11(2)-6 \\
&amp;=16+12-22-6 = 0 \end{align}$p(x)$\begin{align}
\begin{array}{r|rrrr}
2 &amp; 2 &amp; 3 &amp; -11 &amp; -6 \\
&amp; \downarrow  &amp;  4 &amp; 14 &amp; 6 \\
\hline
&amp; 2 &amp; 7 &amp; 3 &amp;  0 \\
\…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1 and 2, Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-2-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1 and 2, Exercise 5.2

Solutions of Question 1 and 2 of Exercise 5.2 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y^{3}-7 y-6$$f(y)=y^{3}-7 y-6$\begin{align*}
f(-1)&amp;=(-1)^{3}-7 (-1)-6 \\
&amp;= -1+7-6 =0.
\end{align*}$y+1$$f(y)$\begin{align}
\begin{array}{r|rrrr}
-1 &amp; 1 &amp; 0 &amp; -7 &amp; -6 \\
&amp; \downarrow  &amp;  -1 &amp; 1 &amp; 6 \\
\hline
&amp; 1 &amp; -1 &amp; -6 &amp;  0 \\
\end{array}\end…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3 and 4, Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-2-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 3 and 4, Exercise 5.2

Solutions of Question 3 and 4 of Exercise 5.2 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 x^{3}+5 x^{2}-9 x-18$\( f(x) = 2x^{3} + 5x^{2} - 9x - 18 \)\begin{align*}
f(-2) &amp;= 2(-2)^{3} + 5(-2)^{2} - 9(-2) - 18 \\
&amp;= 2(-8) + 5(4) + 18 - 18 \\
&amp;= -16 + 20 + 18 - 18 = 0.
\end{align*}\( x + 2 \)\( f(x) \)\[
\begin{array}{r|rrrr}
-2 &amp; 2 &amp;…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 5.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-2-p3?rev=1737476040&amp;do=diff</link>
        <description>;

Question 5 and 6, Exercise 5.2

Solutions of Question 5 and 6 of Exercise 5.2 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $t^{3}+t^{2}+3 t-5$\( f(t) = t^{3} + t^{2} + 3t - 5 \)\begin{align*}
f(1) &amp;= (1)^{3} + (1)^{2} + 3(1) - 5 \\
&amp;= 1 + 1 + 3 - 5 \\
&amp;= 0.
\end{align*}\( t - 1 \)\( f(t) \)\begin{align}
\begin{array}{r|rrrr}
1 &amp; 1 &amp; 1 &amp; 3 &amp; -5 \\
&amp;   &amp; 1 &amp; 2 &amp; 5 \…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Exercise 5.3

Solutions of Question 1 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1
$x$$x+3$$x+3+7=x+10$$120 cm^3$\begin{align*}
&amp; x(x+3)(x+10)=120 \\
\implies  &amp; x(x^2+3x+10x+30)-120=0\\
\implies &amp; x^3+13x^2+30x-120=0.
\end{align*}$$p(x)=x^3+13x^2+30x-120$$\begin{align*}
p(2)&amp;=2^3+13(2)^2+30(2)-120 \\
&amp;=8+52+60-120 =0
\end{ali…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Exercise 5.3

Solutions of Question 2 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 2
$t(x)=x^{3}-12 x^{2}+48 x+74$$x$$$t(x)=x^{3}-12 x^{2}+48 x+74.$$$t=12$\begin{align*}
t(12)&amp;=(12)^3-12(12)^2+48(12)+74 \\
&amp;=650.
\end{align*}</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 3, Exercise 5.3

Solutions of Question 3 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 3
$x$$2x$$2x+2$\begin{align*}
&amp; x(2x)(2x+2) = 144 \\
\implies &amp; 4x^2(x+1)=144 \\
\implies &amp; x^2(x+1)=36 \\
\implies &amp; x^3+x^2-36=0
\end{align*}$$p(x)=x^3+x^2-36.$$\begin{align*}
p(3)&amp;=3^3+3^2-36 \\
&amp;=27+9-36 = 0
\end{align*}$x=3$$p(x)$$2(3)$$2(3)+…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Exercise 5.3

Solutions of Question 4 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 4
$x$$2x+3$$x-2$\begin{align*}
&amp; x(2x+3)(x-2) = 2475 \\
\implies &amp; x(2x^2+3x-4x-6)=2475 \\
\implies &amp; x(2x^2-x-6)-2475=0 \\
\implies &amp; 2x^3-x^2-6x-2475=0
\end{align*}$$p(x)=2x^3-x^2-6x-2475.$$\begin{align*}
p(11)&amp;=2(11)^3-11^2-6(11)-2475 \\
&amp;=2662…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5, Exercise 5.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-3-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 5, Exercise 5.3

Solutions of Question 5 of Exercise 5.3 of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 5
$6 x^{2}+38 x+56$$2 x+8$$ACED$$ABFG$$ACED$$6 x^{2}+38 x+56$$2 x+8$\begin{align*}
&amp; 6 x^{2}+38 x+56 \\
= &amp; 2(3x^2+19x+28) \\
= &amp; 2(3x^2+12x+7x+28) \\
= &amp; 2(3x(x+4)+7(x+4)) \\
=&amp; 2(x+4)(3x+7) \\
=&amp; (2x+8)(3x+7)
\end{align*}\begin{align*}
&amp; Length …</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/ex5-4-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Review Exercise

Solutions of Question 2 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Go to</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Review Exercise

Solutions of Question 1 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 1
$-2-x+x^{2}$$(x-2)(x-1)$$(x+1)(x+2)$$(x+2)(x-1)$$(x+1)(x-2)$$9 y^{2}+9 y-10$$3 y-2$$ 0$$1$$2$$3$$\frac{x^{2}-x-9}{x-3}=x+2+\frac{?}{x-3}$$-27$$-3$$\frac{3}{x-3}+x+2$$ 3$$3 x^{3}-2 x^{2}+5$$x+1$$x+1$$x^{3}+5 x^{2}-4 x+k$$k$$-4$$-20$$20$$0$$…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 &amp; 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2 &amp; 3, Review Exercise

Solutions of Question 2 &amp; 3 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\left(64 y^{3}-8\right) \div(4 y-2) \quad$\begin{align*}
\frac{(64 y^{3}-8)}{(4 y-2)}&amp;= \frac{(4y - 2)(16y^{2} + 8y + 4)}{4y - 2}\\
&amp; = 16y^{2} + 8y + 4 .\end{align*}$\left(125 y^{3}-8\right) \div(5 y-2)$\begin{align*}
\frac{(125 y^{3}-8)}{(5 …</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 &amp; 5, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 4 &amp; 5, Review Exercise

Solutions of Question 4 &amp; 5 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $3 y-2$$6 y^{3}-y^{2}-5 y+2$\begin{align*}3y-2&amp;=0\\
3y&amp;=2\\
y&amp;=\frac{2}{3}\end{align*}\begin{align*}
f(y) &amp;= 6y^{3} - y^{2} - 5y + 2\\
f\left(\frac{2}{3}\right) &amp;= 6\left(\frac{2}{3}\right)^{3} - \left(\frac{2}{3}\right)^{2} - 5\left(\frac{2}{3…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 &amp; 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 6 &amp; 7, Review Exercise

Solutions of Question 6 &amp; 7 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $k$$\left(x^{2}+8 x+k\right)$$(x-4)$\( p(x) = x^{2} + 8x + k \)\( p(x) \)\( (x - 4) \)\( p(4) \)\( p(4) = 0 \)\begin{align*}
p(4) &amp;= (4)^2 + 8(4) + k \\
&amp;= 16 + 32 + k \\
&amp;= 48 + k.
\end{align*}\[
48 + k = 0.
\]\[
k = -48.
\]$3 x^{2}-x+32-\frac…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 6, Review Exercise

Solutions of Question 6 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 6
$k$$\left(x^{2}+8 x+k\right)$$(x-4)$</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit05/re-ex-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 7, Review Exercise

Solutions of Question 7 of Review Exercise of Unit 05: Polynomials. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. 

Question 7
$3 x^{2}-x+32-\frac{121}{x+4}$</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Exercise 8.1

Solutions of Question 1 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos (\alpha \pm \beta), \sin (\alpha \pm \beta)$$\tan (\alpha \pm \beta)$$\alpha=180^{\circ}, \beta=60^{\circ}$$\alpha=180^{\circ}$$\beta=60^{\circ}$\begin{align*}
 \cos (\alpha + \beta) &amp; = \cos \alpha \cos \beta - \sin \alpha \sin \beta \…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Exercise 8.1

Solutions of Question 2 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos 15^{\circ}$$\cos \left(45^{\circ}-30^{\circ}\right)$\begin{align*}
\cos 15^{\circ} &amp; = \cos \left(45^{\circ}-30^{\circ}\right)\\
&amp;= \cos 45 \cos 30 + \sin 45 \sin 30 \\
&amp;= \dfrac{1}{\sqrt{2}}\cdot \dfrac{\sqrt{3}}{2} + \dfrac{1}{\sqrt{2…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 3, Exercise 8.1

Solutions of Question 3 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos 120^{\circ}$$\cos \left(180^{\circ}-60^{\circ}\right)$$\cos \left(90^{\circ}+30^{\circ}\right)$\begin{align*}
\cos 120^{\circ} &amp; = \cos \left(180^{\circ}-60^{\circ}\right) \\
&amp;= - \cos 60 ^{\circ}\\
&amp;= -\dfrac{1}{2}.
\end{align*}\begin{…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Exercise 8.1

Solutions of Question 4 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos 6 \theta \cos 3 \theta-\sin 6 \theta \sin 3 \theta$\begin{align*}
&amp; \cos 6 \theta \cos 3 \theta-\sin 6 \theta \sin 3 \theta \\
&amp; = \cos (6\theta +3\theta) \\
&amp; = \cos 9\theta .
\end{align*}$\cos 7 \theta \cos 2 \theta+\sin 7 \theta \sin…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Exercise 8.1

Solutions of Question 5 and 6 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \alpha=\dfrac{4}{5}, \tan \beta=-\dfrac{5}{12}$$\cos (\alpha+\beta)$$\cos (\alpha-\beta)$$\sin \alpha=\dfrac{4}{5}$$\alpha$$\tan \beta=-\dfrac{5}{12}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$$\alpha$$\cos$\begin{alig…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 7, Exercise 8.1

Solutions of Question 7 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\alpha$$\beta$$\sin \alpha=\dfrac{12}{13}$$\tan \beta=\dfrac{4}{3}$$\sin(\alpha+\beta)$$\cos(\alpha+\beta)$$\tan(\alpha+\beta)$$\sin \alpha=\dfrac{12}{13}$$\alpha$$\tan \beta=\dfrac{4}{3}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$\(\a…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p7?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 8, Exercise 8.1

Solutions of Question 8 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \alpha=\dfrac{3}{5}$$0&lt;\alpha&lt;\dfrac{\pi}{2}$$\cos \beta=\dfrac{12}{13}$$\dfrac{3 \pi}{2}&lt;\beta&lt;2 \pi$$\csc (\alpha+\beta)$$\sec (\alpha+\beta)$$\cot (\alpha+\beta)$$\sin \alpha=\dfrac{3}{5}$$0&lt;\alpha&lt;\dfrac{\pi}{2}$$\alpha$\begin{align…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 9, Exercise 8.1

Solutions of Question 9 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\alpha$$\beta$$\sin \alpha=\dfrac{1}{\sqrt{2}}$$\cos \beta=-\dfrac{3}{5}$$\sin (\alpha \pm \beta)$$\sin \alpha=\dfrac{1}{\sqrt{2}}$$\alpha$$\cos \beta=-\dfrac{3}{5}$$\beta$$$\cos \alpha=\pm \sqrt{1-\sin^2\alpha}.$$$\alpha$$\cos$\begin{align*…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 10, Exercise 8.1

Solutions of Question 10 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \left(\dfrac{\pi}{2}-\alpha\right)=\cos \alpha$\begin{align*}
L.H.S &amp; = \sin \left(\frac{\pi}{2}-\alpha\right) \\
&amp; =\sin\frac{\pi}{2} \cos \alpha - \cos \frac{\pi}{2} \sin\alpha \\
&amp; = 1\times \cos \alpha - 0 \times \sin\alpha \\
&amp; =…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 11, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 11, Exercise 8.1

Solutions of Question 11 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{\sin \left(180^{\circ}+\lambda\right) \cos \left(270^{\circ}+\lambda\right)}{\sin \left(180^{\circ}-\lambda\right) \cos \left(270^{\circ}-\lambda\right)}=1$\begin{align*}
L.H.S &amp; = \dfrac{\sin \left(180^{\circ}+\lambda\right) \cos \…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 12, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p11?rev=1737476040&amp;do=diff</link>
        <description>Question 12, Exercise 8.1

Solutions of Question 12 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\alpha+\beta+\gamma=180^{\circ}$$\tan \alpha+\tan \beta+\tan \gamma=\tan \alpha \tan \beta \tan \gamma$$$\alpha+\beta+\gamma=180^{\circ}$$\begin{align*}
&amp; \alpha+\beta=180^{\circ}-\gamma \\
\implies &amp; \tan(\alpha+\beta) = \tan(180^{\circ}-…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 13, Exercise 8.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-1-p12?rev=1737476040&amp;do=diff</link>
        <description>Question 13, Exercise 8.1

Solutions of Question 13 of Exercise 8.1 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $r \sin (\theta+\phi)$$12 \sin \theta-5 \cos \theta$$12=r\cos \varphi $$-5=r\sin \varphi$\begin{align*}
&amp; (12)^2+(-5)^2=r^2 \cos^2\varphi+r^2 \sin^2 \varphi \\
\implies &amp; 144+25={{r}^{2}}\left( {{\cos }^{2}}\varphi +{{\sin }^{2}}\varphi  \r…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, 2 and 3 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, 2 and 3 Exercise 8.2

Solutions of Question 1, 2 and 3 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $P(-3,4)$$\theta$$\theta$$\cos 2 \theta$$\sin 2 \theta$$2 \theta$$x=-3$$y=4$\begin{align*}
r&amp;= \sqrt{(-3)^2+4^2} \\
&amp;=\sqrt{25} = 5.
\end{align*}$$\sin\theta = \frac{4}{5} \text{ and } \cos\theta = -\frac{3}{5}.$$\begin{align…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 4 Exercise 8.2

Solutions of Question 4 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin 2 \theta$$\cos 2 \theta$$\tan 2 \theta$$\sin \frac{\theta}{2}$$\cos \frac{\theta}{2}$$\tan \frac{\theta}{2}$$\cos \theta=\frac{3}{5}$$0&lt;\theta&lt;\frac{\pi}{2}$$\cos\theta=\dfrac{3}{5}$$0&lt;\theta&lt;\dfrac{\pi}{2}$$\theta$$$\sin\theta = \pm \sq…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 5 Exercise 8.2

Solutions of Question 5 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \theta$$\cos \theta$$\tan \theta$$\sin 2 \theta=\frac{24}{25}, 2 \theta$$\sin 2\theta=\dfrac{24}{25}$$2\theta$$$\cos 2\theta = \pm \sqrt{1-\sin^2 2\theta}$$$2\theta$$\cos 2\theta$\begin{align*}\cos 2\theta &amp; = - \sqrt{1-\sin^2 2\theta}\\…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 6 Exercise 8.2

Solutions of Question 6 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin 15^{\circ} \cos 15^{\circ}$$$\sin 2 \theta = 2\sin\theta \cos\theta$$$$\sin\theta \cos\theta = \frac{1}{2}\sin 2\theta$$$\theta = 15^{\circ}$\begin{align*}
\sin 15^{\circ} \cos 15^{\circ} &amp; = \frac{1}{2}\sin 2(15^{\circ}) \\
&amp; \frac{1}{2…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 7 Exercise 8.2

Solutions of Question 7 of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\sin ^{2} \alpha \cos ^{2} \alpha$$\begin{align*}
\sin ^{2} \alpha \cos ^{2} \alpha &amp;= \left(\frac{1-\cos 2\alpha}{2} \right)\left(\frac{1+\cos 2\alpha}{2} \right)\\
&amp;= \frac{1}{4}(1-\cos^2 2\alpha) \\
&amp;=\frac{1}{4}\left(1-\frac{1+\cos 4\alp…</description>
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(i, ii &amp; iii) Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 8(i, ii &amp; iii) Exercise 8.2

Solutions of Question 8(i, ii &amp; iii) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $(\sin \theta+\cos \theta)^{2}=1+\sin 2 \theta$\begin{align*}
LHS &amp; = (\sin \theta+\cos \theta)^{2} \\
&amp;=\sin^2\theta + \cos^2\theta +2\sin \theta \cos\theta\\
&amp;= 1+2\sin \theta \cos\theta \quad (\because \sin^2\theta…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(iv, v &amp; vi) Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 8(iv, v &amp; vi) Exercise 8.2

Solutions of Question 8(iv, v &amp; vi) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\csc 2 \alpha=\dfrac{\tan \alpha+\cot \alpha}{2}$\begin{align*}
RHS &amp; = \dfrac{\tan \alpha+\cot \alpha}{2} \\
&amp; = \dfrac{1}{2}\left(\frac{\sin\alpha}{\cos\alpha}+\frac{\cos\alpha}{\sin\alpha} \right)\\
\end{align*}$8 \…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(vii, viii &amp; ix) Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 8(vii, viii &amp; ix) Exercise 8.2

Solutions of Question 8(vii, viii &amp; ix) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin 2 \theta=2 \cot \theta \sin ^{2} \theta$\begin{align*}
RHS &amp;= 2 \cot \theta \sin ^{2} \theta\\
&amp;= 2 \frac{\cos \theta }{\sin \theta} \sin ^{2} \theta\\
&amp;= 2 \cos \theta \sin\theta\\
&amp;=  \sin2 \theta\\
&amp;=LH…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p9?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(x, xi &amp; xii) Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 8(x, xi &amp; xii) Exercise 8.2

Solutions of Question 8(x, xi &amp; xii) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sec 2 x=\dfrac{\cos x}{\cos x+\sin x}+\dfrac{\sin x}{\cos x-\sin x}$\begin{align*}
RHS &amp;= \dfrac{\cos x}{\cos x+\sin x}+\dfrac{\sin x}{\cos x-\sin x}\\
&amp;=\dfrac{\cos x(\cos x-\sin x)+\sin x(\cos x+\sin x)}{(\cos x+\…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p10?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(xiii, xiv &amp; xv)  Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 8(xiii, xiv &amp; xv)  Exercise 8.2

Solutions of Question 8(xiii, xiv &amp; xv) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\csc 2 \alpha-\cot 2 \alpha=\tan \alpha$\begin{align*}
LHS &amp;= \csc 2 \alpha-\cot 2 \alpha\\
&amp;=\frac{1}{\sin 2 \alpha}- \frac{\cos2 \alpha}{\sin 2\alpha }\\
&amp;=\frac{1-\cos2 \alpha}{\sin2 \alpha}\\
&amp;= \frac{2\si…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p11?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8(xvi, xvii &amp; xviii)  Exercise 8.2</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-2-p11?rev=1737476040&amp;do=diff</link>
        <description>Question 8(xvi, xvii &amp; xviii)  Exercise 8.2

Solutions of Question 8(xvi, xvii &amp; xviii) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1-\cos ^{2} \beta}{2-2 \cos \beta}=\cos ^{2} \dfrac{\beta}{2}$\begin{align*}
LHS &amp;= \dfrac{1-\cos ^{2} \beta}{2-2 \cos \beta}\\
&amp;= \dfrac{\sin ^{2} \beta}{2-2 \cos \beta}\\
&amp;=\dfrac{4\sin ^{2} \fr…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p1?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1(i, ii, iii &amp; iv)  Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1(i, ii, iii &amp; iv)  Exercise 8.3

Solutions of Question 1(i, ii, iii &amp; iv) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$4 \sin 16x \cos 10x $$\begin{align*}
&amp;4 \sin 16x \cos 10x \\
&amp; = 2 (2\sin 16x \cos 10x) \\
&amp;= 2[\sin(16x+10x)+\sin(16x-10x)]\\
&amp;= 2[\sin (26x)+\sin(6x)]
\end{align*}$10 \cos 10y \cos 6y$\begin{align*}
&amp;10 \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p2?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1(v, vi, vii &amp; viii) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 1(v, vi, vii &amp; viii) Exercise 8.3

Solutions of Question 1(v, vi, vii &amp; viii) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $ \sin(-u) \sin 5u$\begin{align*}
&amp;\sin(-u) \sin 5u \\
=&amp; -\sin u \sin 5u \\
=&amp; -\frac{1}{2}[\cos(u - 5u) - \cos(u + 5u)] \\
= &amp;-\frac{1}{2}[\cos(-4u) - \cos(6u)] \\
=&amp; \frac{1}{2}[\cos(6u) - \cos(4u) ]
\e…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p3?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1(ix, x &amp; xi) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 1(ix, x &amp; xi) Exercise 8.3

Solutions of Question 1(ix, x &amp; xi) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2 \sin 75{\circ} \sin 15{\circ}$\begin{align*}
&amp;\quad2 \sin 75^{\circ} \sin 15^{\circ} \\
&amp;= \cos(75^{\circ} - 15^{\circ}) - \cos(75^{\circ} + 15^{\circ}) \\
&amp;= \cos 60^{\circ} - \cos 90^{\circ} \\
\end{align*}$4 \sin …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p4?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2(i, ii, iii, iv and v) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 2(i, ii, iii, iv and v) Exercise 8.3

Solutions of Question 2(i, ii, iii, iv and v) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin 70^{\circ} + \sin 30^{\circ}$\begin{align*}
 &amp; \quad \sin 70^{\circ} + \sin 30^{\circ} \\
&amp; = 2 \sin \left(\frac{70+30}{2} \right) \cos \left(\frac{70-30}{2} \right) \\
&amp; = 2 \sin \left(\frac{1…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p5?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3(i, ii, iii, iv &amp; v) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 3(i, ii, iii, iv &amp; v) Exercise 8.3

Solutions of Question 3(i, ii, iii, iv &amp; v) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{\cos (\alpha + \beta)}{\cos(\alpha - \beta)}=\dfrac{1- \tan \alpha \tan \beta}{1+ \tan \alpha \tan \beta}$\begin{align*}
RHS &amp; = \dfrac{1- \tan \alpha \tan \beta}{1+ \tan \alpha \tan \beta} \\
&amp; …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p6?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3(vi, vii, viii, ix &amp; x) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 3(vi, vii, viii, ix &amp; x) Exercise 8.3

Solutions of Question 3(vi, vii, viii, ix &amp; x) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2\tan y \cos 3y= \sec y(\sin 4y-\sin 2y)$\begin{align*}
LHS &amp; = 2\tan y \cos 3y \\
&amp; = 2 \cdot \frac{\sin y}{\cos y} \cos 3y \\
&amp; = \sec y (2 \cos 3y \sin y) \\
&amp; = \sec y \left(\sin (3y+y)-\sin (…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p7?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3(xi, xii &amp; xiii) Exercise 8.3</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/ex8-3-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 3(xi, xii &amp; xiii) Exercise 8.3

Solutions of Question 3(xi, xii &amp; xiii) of Exercise 8.3 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $2\cos2u \cos u-\sin 2u \sin u=2\cos^3 u$\begin{align*}
LHS &amp; = 2\cos 2u \cos u - \sin 2u \sin u \\
&amp; = 2\left(\cos^2 u - \sin^2 u\right) \cos u - 2\sin u \cos u \sin u \\
&amp; = 2\cos^3 u - 2\sin^2 u \cos u \\
&amp; =…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p1?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Review Exercise

Solutions of Question 1 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \left(45^{\circ}-30^{\circ}\right)=\ldots$$\frac{\sqrt{6}-\sqrt{2}}{4}$$\frac{\sqrt{6}+\sqrt{2}}{4}$$\frac{\sqrt{6}-\sqrt{2}}{2}$$\frac{\sqrt{3}-\sqrt{2}}{2}$$\tan \left(\frac{\pi}{6}+\frac{\pi}{4}\right)=\ldots$$\frac{\sqrt{3}-1}…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p2?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Review Exercise

Solutions of Question 2 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin \theta=\dfrac{3}{5}, \sin \phi=\dfrac{5}{13}$$\theta$$\phi$$\sin (\theta-\phi)$$\sin \theta=\dfrac{3}{5}$$\sin \phi=\dfrac{5}{13}$$\theta$$\phi$\begin{align*}
\cos^2 \theta &amp;= 1-\sin^2\theta\\
&amp;= 1-\left(\frac{3}{5}\right)^2\\
&amp; =…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p3?rev=1737476040&amp;do=diff">
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        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 3, Review Exercise

Solutions of Question 3 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\frac{1}{\sqrt{2}}(\sin \beta+\cos \beta)$\begin{align*}
&amp;\frac{1}{\sqrt{2}}(\sin \beta+\cos \beta)\\
=&amp; \sin \frac{\pi}{4}\sin \beta+\cos \frac{\pi}{4}\cos \beta\\
=&amp; \cos(\beta -\frac{\pi}{4})
\end{align*}$\frac{1}{\sqrt{2}} \sin 75^…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p4?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Review Exercise

Solutions of Question 4 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{1+\tan 15^{\circ}}{1-\tan 15^{\circ}}$\begin{align*}
&amp;\frac{1+\tan 15^{\circ}}{1-\tan 15^{\circ}}\\
=&amp;\frac{1+\tan 15^{\circ}}{1-1 \cdot \tan 15^{\circ}}\\
=&amp;\frac{\tan 45^{\circ} + \tan 15^{\circ}}{1 - \tan 45^{\circ} \tan 15^{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p5?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Review Exercise

Solutions of Question 5 and 6 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\tan \theta$$\tan \left(\theta-45^{\circ}\right)=\frac{1}{3}$\begin{align*}
&amp; \frac{\tan \theta - \tan 45^{\circ}}{1 + \tan \theta \cdot \tan 45^{\circ}} =\frac{1}{3}\\
\implies &amp; \frac{\tan \theta - 1}{1 + \tan \theta}= \f…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p6?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 7, Review Exercise

Solutions of Question 7 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\dfrac{4 \sin ^{2} \theta \cos \theta}{\cos 3 \theta+\cos \theta}=\tan 2 \theta \tan \theta$\begin{align*}
LHS&amp;=\frac{4 \sin^2 \theta \cos \theta}{\cos 3 \theta + \cos \theta}\\
&amp;=\frac{4 \sin \theta\sin \theta \cos \theta}{4\cos^ 3 \t…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p7?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 8, Review Exercise

Solutions of Question 8 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\sqrt{\frac{\cos \left(90^{\circ}+x\right) \sec (-x) \tan \left(180^{\circ}-x\right)}{\sec \left(360^{\circ}-x\right) \sin \left(180^{\circ}+x\right) \cot \left(90^{\circ}-x\right)}}=i .$$\begin{align*}
LHS&amp;= \sqrt{\frac{\cos \left(90…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p8?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit08/re-ex-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 9, Review Exercise

Solutions of Question 9 of Review Exercise of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $$\sqrt{\frac{\left(1-\tan ^{2} x \cos (-x) \cos \left(360^{\circ}-x\right)\right) \tan 45^{\circ}}{\left\{\sin 90^{\circ}-\sin \left(180^{\circ}+x\right)\right\}\left\{\sin 90^{\circ}-\cos \left(90^{\circ}-x\right)\right\}}}$$\begin{al…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p1?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1, Exercise 9.1

Solutions of Question 1 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=2-2 \operatorname{Cos} \theta$\begin{align*} -1 \leq \operatorname{Cos} \theta \leq 1 \end{align*}$-2$\begin{align*} &amp; 2 \geq -2 \operatorname{Cos} \theta \geq -2 \end{align*}$2$\begin{align*}
 &amp; 4 \geq 2-2 \operatorname{Cos} \theta \geq 0 \\
…</description>
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2, Exercise 9.1

Solutions of Question 2 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=\dfrac{1}{4+3 \operatorname{Sin} \theta}$\begin{align*} -1 \leq \operatorname{Sin} \theta \leq 1 \end{align*}$3$\begin{align*}  -3 \leq 3 \operatorname{Sin} \theta \leq 3 \end{align*}$4$\begin{align*}
 &amp; 1 \leq 4+3 \operatorname{Sin} \theta \l…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p3?rev=1737476040&amp;do=diff">
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        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 3, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 3, Exercise 9.1

Solutions of Question 3 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=7 \cos 4x$\begin{align*} 
&amp; -1\leq \cos 4x \leq 1 \,\, \forall \,\, x\in \mathbb{R} \\
\implies &amp; -7\leq 7 \cos 4x \leq 7 \\
\end{align*}$= ]-\infty, \infty[ = \mathbb{R}$$=[-7,7]$$y=\cos \frac{x}{3}$\begin{align*} 
&amp; -1\leq \cos \frac{x}{3} \…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4(i-iv), Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 4(i-iv), Exercise 9.1

Solutions of Question 4(i-iv) of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=\sin x+x \cdot \cos x$$f(x)=\sin x+x \cdot \cos x$\begin{align*} f(-x)  = \sin (-x) + (-x)\cdot \cos (-x) \end{align*}$\sin(-x)=-\sin x$$\cos (-x) = \cos x$\begin{align*}
f(x) &amp; = -\sin x - x \cdot \cos x \\
&amp; = -(\sin x + x \cdot …</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4(v-viii), Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 4(v-viii), Exercise 9.1

Solutions of Question 4(v-viii) of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=\dfrac{\sin ^{2} x}{x+\tan x}$\[y = \frac{\sin^2 x}{x + \tan x}\]\begin{align*}
y(-x) &amp;= \frac{\big(-\sin x\big)^2}{-x - \tan x} \\
&amp;= \frac{\sin^2 x}{-x - \tan x}\\
&amp; = \frac{\sin^2 x}{-(x + \tan x)}\\
&amp; = -\frac{\sin^2 x}{x +…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5(i-v), Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 5(i-v), Exercise 9.1

Solutions of Question 5(i-v) of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=2 \operatorname{Sin} x$$y=2 \operatorname{Cos} 3 x$$y=2 \operatorname{Tan} 2 x$$\mathrm{y}=\operatorname{Cos} \frac{\mathrm{x}}{2}$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5(vi-x), Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 5(vi-x), Exercise 9.1

Solutions of Question 5(vi-x) of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=2 \operatorname{Sin} 3 x$$y=3 \operatorname{Cos} x$$y=\operatorname{Cos}^{2} x$$y=\operatorname{Sin}^{2} x$$y=\operatorname{Tan}^{2} x$$y=\operatorname{Sin} \frac{x}{2}$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p8?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 6, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 6, Exercise 9.1

Solutions of Question 6 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=6 \sec(2 x-3)$$\sec$$2\pi$\begin{align*}
6 \sec(2 x-3) &amp; = 6 \sec(2 x-3+2\pi) \\
&amp; = 6 \sec(2(x+\pi)-3)
\end{align*}$6 \sec(2 x-3)$$\pi$$y=\cos (5 x+4)$$\cos$$2\pi$\begin{align*}
\cos (5 x+4) &amp; = 6 \cos(5x+4+2\pi) \\
&amp; = \cos\left(5\left(x+\fr…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p9?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7 &amp; 8, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 7 &amp; 8, Exercise 9.1

Solutions of Question 7 &amp; 8 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $y=\operatorname{Sin} x$$y=\operatorname{Sin} 2 x$$[0,2 \pi]$$y=\operatorname{Cos} x$$y=\operatorname{Cos} 2 x$$[0,2 \pi]$</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p10?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Exercise 9.1</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/ex9-1-p10?rev=1737476040&amp;do=diff</link>
        <description>Question 9, Exercise 9.1

Solutions of Question 9 of Exercise 9.1 of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\sin x=\cos x$$\cos x=x$$\sin x=x$$\tan x=x$</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-1-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3,Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-1-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2 and 3,Review Exercise

Solutions of Question 2 and 3 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-1-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-1-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Review Exercise

Solutions of Question 4 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p1?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 1,Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p1?rev=1737476040&amp;do=diff</link>
        <description>Question 1,Review Exercise

Solutions of Question 1 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos \theta=\frac{\sqrt{3}}{2}$$\sin \theta=$$\frac{1}{2}$$-\frac{1}{2}$$\sqrt{3}$$-\frac{2}{\sqrt{3}}$$\tan (-15 \pi)=$$ 0$$-1$$1$$2 \sin \theta+\frac{1}{2}cosec \theta \theta $$\theta=45^{\circ}$$\frac{1}{\sqrt{2}}$$\frac{1}{3}$$\frac{3}{…</description>
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    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p2?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 2 and 3, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p2?rev=1737476040&amp;do=diff</link>
        <description>Question 2 and 3, Review Exercise

Solutions of Question 2 and 3 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan. $\cos \theta -\sin \theta=\sqrt{2}\sin \theta,$$\cos \theta+ \sin \theta=\sqrt{2} \cos \theta$$$\cos \theta -\sin \theta=\sqrt{2}\sin \theta$$\begin{align*}
&amp; \cos \theta=\sqrt{2}\sin \theta + \sin \theta \\
\implies &amp; \cos \the…</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p3?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 4, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p3?rev=1737476040&amp;do=diff</link>
        <description>Question 4, Review Exercise

Solutions of Question 4 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p4?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 5 and 6, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p4?rev=1737476040&amp;do=diff</link>
        <description>Question 5 and 6, Review Exercise

Solutions of Question 5 and 6 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p5?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 7, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p5?rev=1737476040&amp;do=diff</link>
        <description>Question 7, Review Exercise

Solutions of Question 7 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p6?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 8, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p6?rev=1737476040&amp;do=diff</link>
        <description>Question 8, Review Exercise

Solutions of Question 8 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p7?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 9, Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p7?rev=1737476040&amp;do=diff</link>
        <description>Question 9, Review Exercise

Solutions of Question 9 of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p8?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10(i-v), Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p8?rev=1737476040&amp;do=diff</link>
        <description>Question 10(i-v), Review Exercise

Solutions of Question 10(i-v) of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
    <item rdf:about="https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p9?rev=1737476040&amp;do=diff">
        <dc:format>text/html</dc:format>
        <dc:date>2025-01-21T16:14:00+00:00</dc:date>
        <dc:creator>Anonymous (anonymous@undisclosed.example.com)</dc:creator>
        <title>Question 10(vi-x), Review Exercise</title>
        <link>https://beta.mathcity.org/math-11-nbf/sol/unit09/re-ex-p9?rev=1737476040&amp;do=diff</link>
        <description>Question 10(vi-x), Review Exercise

Solutions of Question 10(vi-x) of Review Exercise of Unit 09: Trigonometric Functions. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.</description>
    </item>
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