This is beta site. https://beta.mathcity.org/ 2026-06-07T04:01:22+00:00 https://beta.mathcity.org/ https://beta.mathcity.org/_media/logo.png text/html 2025-01-21T16:13:57+00:00 Anonymous (anonymous@undisclosed.example.com) https://beta.mathcity.org/fsc-part1-ptb/important-questions/ch02-functions-and-groups?rev=1737476037&do=diff Ch 02: Functions and Groups The important questions of Chapter 2 of Textbook of Algebra and Trigonometry Class XI is published by Punjab Textbook Board (PTB) Lahore, Pakistan has been given on this page. These questions are selected from old papers. <list-group>$(2,4)$$\{a,\{b,c\}\}$$A-B=A \cup B^c$$p \longrightarrow q$$\{(1,2),(2,5),(3,7),(4,9),(5,11)\}$$\{a,b \}$$\{\{a,b\}\}$$~(p \longrightarrow q) \longrightarrow p$$A \cap(B \cup C)=(A \cap B)\cup(A \cap C)$$A=\{1,2,3,4\}$$B=\{3,4,5,6,7,8\}$… text/html 2025-01-21T16:13:57+00:00 Anonymous (anonymous@undisclosed.example.com) https://beta.mathcity.org/fsc-part1-ptb/important-questions/ch04-quadratic-equations?rev=1737476037&do=diff Ch 04: Quadratic Equations <list-group> * Reduce $x^{-2}-10=3x^{-1}$ to quadratic form --- BISE Gujrawala(2015) * Show that $x^3-y^3=(x-y)(x-wy)(x-w^2y)$ --- BISE Gujrawala(2015) * If $n$ is an odd integer, is $(x+a)$ factor of $(x^n+a^n)$? --- BISE Gujrawala(2015) * If the roots of $px^2+qx+q=0$ are $\alpha$, $\beta$,then prove that $$\sqrt {\frac{\alpha}{\beta}}+\sqrt {\frac{\beta}{\alpha}}+\sqrt{\frac{p}{q}}=0$$$${\begin{array}{c} x^2-5xy+6y^2=0\\x^2+y^2=45\end{array}}$$$4x^2+7x-… text/html 2025-01-21T16:13:57+00:00 Anonymous (anonymous@undisclosed.example.com) https://beta.mathcity.org/fsc-part1-ptb/important-questions/ch06-sequence-and-series?rev=1737476037&do=diff Ch 06: Sequences and Series <list-group> * If $\frac{1}{a}$, $\frac{1}{b}$ and $\frac{1}{c}$ are in $G.P$. Show that $r=\pm \sqrt{\frac{a}{c}}$ --- BISE Gujranwala(2015),BISE Sargodha(2015), BISE Sargodha(2017),BISE Lahore(2017) * With usual notation show that $AH=G^2$ --- BISE Gujrawala(2015) * Find $n$, so that $\frac{a^n+b^n}{a^{n-1}+b^{n-1}}$ maybe $A.M$$a$$b$$y=1+\frac{x}{2}+\frac{x^4}{4}+...$$x=2(\frac{y-1}{y})$$9th$$\frac{1}{3}, \frac{1}{5}, \frac{1}{7},...$$a=-2$$b=-6$$A.G$$\f… text/html 2025-01-21T16:13:57+00:00 Anonymous (anonymous@undisclosed.example.com) https://beta.mathcity.org/fsc-part1-ptb/important-questions/ch01-number-systems?rev=1737476037&do=diff Ch 01: Number Systems <list-group> * Simplify $(i)^{19}$ --- BISE Gujrawala(2015) * If $z$ be a complex number then prove that $\overline{z_1 + z_2}=\overline z_1 +\overline z_2$ --- BISE Sargodha(2015) * Simplify $\frac{2}{\sqrt{5}+\sqrt{-8}}$ in the form of $a+ib$ --- BISE Sargodha(2015) * Simplify by justify each step $\frac{\frac{1}{a}-\frac{1}{b}}{1-\frac{1}{a}\frac{1}{b}}$ --- $(\sqrt{2}, -\sqrt{5})$$\{0,-1\}$$a \div ib$$(-1)^\frac{-21}{2}$$(0,1)$$\{1,-1\}$$|z_1z_2|=… text/html 2025-01-21T16:13:57+00:00 Anonymous (anonymous@undisclosed.example.com) https://beta.mathcity.org/fsc-part1-ptb/important-questions/ch08-mathematical-induction-and-binomial-theorem?rev=1737476037&do=diff Ch 08: Mathematical Induction and Binomial Theorem <list-group> * Using binomial theorem,expand $\left(\frac{x}{2}-\frac{2}{x^2}\right)$ --- BISE Gujranwala(2015) * Find the $6$th term in the expansion of $\left( x^2-\frac{3}{2x}\right)$ --- BISE Gujranwala(2015) * Expand $\left( 8-2x\right)^{-1}$ up to two terms. --- BISE Gujranwala(2015)$1+\frac{1}{4}+\frac{1.3}{4.8}+\frac{1.3.5}{4.8.12},...=\sqrt{2}$$(1.03)^{\frac{1}{3}}$$(a+x)$$n$$x$$(x-\frac{2}{x})^{10}$$n^3-n$$6$$n=2,3$$4^n>3^n+… text/html 2025-01-21T16:13:57+00:00 Anonymous (anonymous@undisclosed.example.com) https://beta.mathcity.org/fsc-part1-ptb/important-questions/ch09-fundamentals-of-trigonometry?rev=1737476037&do=diff Ch 09: Fundamental of Trigonometry <list-group> * Find the value of the remaining trigonometric functions of $\theta$, If $cos \theta=\frac{12}{13}$ and the terminal side of the angle is not in the $I$ Quadrant. --- BISE Gujrawala(2015) * Express in radian $120'40''$ --- BISE Gujrawala(2017)$2 $$\sin 45^{\circ} +\frac{1}{2}\cos 45^{\circ}=\frac{3}{\sqrt{2}}$$cosce \theta+tan\theta sec \theta=cosec \theta sec^2 \theta$$(tan\theta+cot\theta)^2=sec^2\theta cosec^2\theta$$150^{\circ}$$\theta$$…