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- Question 2, Exercise 2.3
- PTBB) Peshawar, Pakistan. =====Question 2(i)===== Find the inverse of the matrix by using elementary row... d{bmatrix} \end{align} =====Question 2(ii)===== Find the inverse of the matrix by using elementary row... end{matrix} \right]$$ =====Question 2(iii)===== Find the inverse of the matrix by using elementary row... {1}{4} \end{bmatrix}$$ =====Question 2(iv)===== Find the inverse of the matrix by using elementary row
- Question 5 & 6, Exercise 2.1
- & 3 & -1 \end{bmatrix}$ is given to be symmetric. Find the value of $a$ and $b$. ====Solution==== Given... ion 6(i)===== Solve the matrix equations for $X.$ Find $X-3A=2B$, if $A=\begin{bmatrix} 1 & 0 & 3 \\-2 ... on 6(ii)===== Solve the matrix equations for $X.$ Find $2( X-A )=B$, if $A=\begin{bmatrix}1 & 2 & 2 \\
- Question 1, Exercise 2.2
- \\-1 & 2 & 0 \\2 & 0 & -2 \end{bmatrix}$ , then find $A_{11},A_{21},A_{23},A_{31},A_{32},A_{33}.$ Also find $|A|.$ =====Solution===== Given $$A=\left[ \begi
- Question 14 & 15, Exercise 2.2
- & 2 & 2 \\-1 & 3 & 2 \\1 & 0 & 5\end{bmatrix}$. Find $A^{-1}$. ====Solution==== Given $$A=\left[ \begi... 1 & 0 & 5 \\ \end{matrix} \right]$$ We have to find $A^{-1}$and we know that $$A^{-1}=\dfrac{Adj\,\,A
- Question 3, Exercise 2.3
- TBB) Peshawar, Pakistan. =====Question 3(i)===== Find the ranks of the matrix. $$\left[ \begin{matrix}... of given matrix is $3$. =====Question 3(ii)===== Find the ranks of the matrix. $$\left[ \begin{matrix}
- Question 2, Exercise 2.1
- in{bmatrix}0 & 1 & -2\\0 & -1 & -1\end{bmatrix}$. Find $2A+3B-4C.$ ====Solution==== Given: $A=\begin{bm
- Question 10, Exercise 2.1
- \end{matrix} \right]$$ For symmetric, we have to find out, $$A=A^t$$ $$B=B^t$$ $$( A+B )^t=A^t+B^t$$
- Question 12, Exercise 2.2
- KPTBB) Peshawar, Pakistan. =====Question 12===== Find the value of $\lambda $, if $A$ is singular matri
- Question 4, Exercise 2.3
- KPTBB) Peshawar, Pakistan. =====Question 4===== Find rank of matrix $\begin{bmatrix}2 & 3 & 4 & 5 \\3