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- Exercise 2.6 (Solutions)
- d write your answer in the form of $a+ib$ (i) $\frac{-2}{1+i}$\\ (ii) $\frac{2+3i}{4-i}$\\ (iii) $\frac{9-7i}{3+i}$\\ (iv) $\frac{2-6i}{3+i}-\frac{4+i}{3+i}$\\ (v) $({1+i}/{1-i})^2$\\ (vi) $\frac{1}{(2+3i)(1
- Exercise 2.4 (Solutions)
- 1==== Use law of exponent to simplify. * (i) $\frac{(243)^{\frac{-2}{3}}(32)^{\frac{-1}{5}}}{\sqrt(196)^{-1}}$ * (ii) $\left(2x^5y^{-4}\right)\left(-8x^{-3}y^2\right)$ * (iii) $\left(\frac{x^{-2}y^{-1}z^{-4}}{x^4y^{-3}z^0}\right)^{-3}$
- Exercise 2.1 (Solutions)
- al and irrational numbers: (i) $\sqrt{3}$ (ii) $\frac{1}{6}$ (iii) $\pi$ (iv) $\frac{15}{2}$ (v) $7.25$ (vi)$\sqrt{29}$ **Solution**\\ * Rational: $\frac{1}{6}$, $\frac{15}{2}$, $7.25$ * Irrational: $\sqrt{3}$, $\pi$, $\sqrt{29}$ ====Question 2==== Conve
- Exercise 2.3 (Solutions)
- (ii) $2^{35}$\\ * (iii) $-7^\frac{1}{3}$ * (iv) $y^\frac{-2}{3}$\\ **Solution**\\ * (i) $\sqrt[3]{-64} = -64^\frac{1}{3}$ ( Exponential form) * (ii) $2^\frac{3}{5} = \sqrt[5]{2}^{3}$ (Radical form) * (
- Exercise 2.2 (Solutions)
- $5 + (-5) = 0$ ... ... ... * (viii) $7 \times \frac{1}{7} = 1$ ... ... ... * (ix) $a > b \Rightarro... ... (Additive inverse) * (viii) $7 \times \frac{1}{7} = 1$ ... ... ... (Multiplicative inverse)... sqrt{24} + 0 = \sqrt{24}$ ... ... ... * (ii) $\frac{-2}{3} \left( 5 + \frac{7}{2}\right) = \left(\frac{-2}{3}\right){5} + \left(\frac{-2}{3}\right)\left(\f