Search

Fulltext results:

Question 3 and 4 Exercise 4.1

1 Hits, Last modified: 17 months ago

a_n}{n}$ ====Solution==== Given $$a_1=3, a_{n+1}=\frac{a_n}{n}$$ For $n=1$ \begin{align}&a_{1+1}=\dfrac{

Question 2 & 3 Exercise 4.4

1 Hits, Last modified: 17 months ago

{2}) \cdot \dfrac{1}{8} \\ \Rightarrow a_7&=-2^{-\frac{3}{2}}\end{align} ====Go To==== <text align="l