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Question 1 Exercise 5.1
1 Hits, Last modified: 5 months ago
] \\ & =n[16 n^3-16 n^2-2 n+3]\end{align} ====Go To==== <text align="right"><btn type="success">[[
Question 2 & 3 Exercise 5.1
1 Hits, Last modified: 5 months ago
+ \\ & \ldots+99^2=156850 . \end{aligned} $$ ====Go To==== <text align="left"><btn type="primary">[[m
Question 4 & 5 Exercise 5.1
1 Hits, Last modified: 5 months ago
\ & =\dfrac{n}{6}(2 n^2+3 n+7)\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 6 Exercise 5.1
1 Hits, Last modified: 5 months ago
&=\dfrac{n(n+1)(n+2) (n+3)}{4}\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 7 & 8 Exercise 5.1
1 Hits, Last modified: 5 months ago
=\dfrac{n}{3}(32 n^2+54 n+25)\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 9 Exercise 5.1
1 Hits, Last modified: 5 months ago
\\ &=4^{n+1}-4-n(n+1)(n^2- n-1)\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 1 Exercise 5.2
1 Hits, Last modified: 5 months ago
x\dfrac{(1-(-x))^{n-1}}{(1+x)^2}\end{align} ====Go To==== <text align="right"><btn type="success">[[
Question 2 & 3 Exercise 5.2
1 Hits, Last modified: 5 months ago
T_n=(n)\cdot(\dfrac{1}{2})^{n-1}\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 4 & 5 Exercise 5.2
1 Hits, Last modified: 5 months ago
& \Rightarrow r=\dfrac{17}{35} \end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 1 Exercise 5.3
1 Hits, Last modified: 5 months ago
2+1&;\dfrac{n}{2}(2 n^2+3 n+3)\end{align} ====Go To==== <text align="right"><btn type="success">[[
Question 2 Exercise 5.3
1 Hits, Last modified: 5 months ago
{Hence}\quad 3 n^2+n&;n(n+1)^2\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 3 Exercise 5.3
1 Hits, Last modified: 5 months ago
n^2+3 n;\dfrac{n}{3}(n+1)(n+5)\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 4 Exercise 5.3
1 Hits, Last modified: 5 months ago
n-1}+2; \dfrac{1}{2}(3^n-1)+2 n\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 5 Exercise 5.3
1 Hits, Last modified: 5 months ago
\quad 3(2^n-1);3(2^{n+1}-n-2)\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 6 Exercise 5.3
1 Hits, Last modified: 5 months ago
-1}+27; \dfrac{(5^n-1)}{4}+27 n\end{align} ====Go To==== <text align="left"><btn type="primary">[[m
Question 1 Exercise 5.3
1 Hits, Last modified: 5 months ago
Question 2 & 3 Exercise 5.4
1 Hits, Last modified: 5 months ago
Question 4 Exercise 5.4
1 Hits, Last modified: 5 months ago
Question 1 Review Exercise 5
1 Hits, Last modified: 5 months ago
Question 2 & 3 Review Exercise
1 Hits, Last modified: 5 months ago
Question 4 Review Exercise
1 Hits, Last modified: 5 months ago
Question 5 & 6 Review Exercise
1 Hits, Last modified: 5 months ago
Question 7 Review Exercise
1 Hits, Last modified: 5 months ago
Question 8 Review Exercise
1 Hits, Last modified: 5 months ago
Question 9 Review Exercise
1 Hits, Last modified: 5 months ago
Question 10 Review Exercise
1 Hits, Last modified: 5 months ago