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Exercise 2.8 (Solutions) @fsc-part1-ptb:sol:ch02

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ian? **Solutions**\\ (i) From the given table we have $0+0=0$ and $0+1=1$. This show that $0$ is the i... p. For $A\in P(S)$ where A is a subset of $S$ we have $S\in P(S)$ such that $A\cap S=S\cap A=A$. Thus

Exercise 1.1 (Solutions) @fsc-part1-ptb:sol:ch01

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notin \{0,-1\}$. $\Rightarrow \{0,-1\}$ does not have closure property w.r.t. '$\times$'. **Question 1