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Exercise 1.2 (Solutions)

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(i^2)^4 \cdot i$ $=1 \cdot i$ =$i$. **Question 4(ii)** Simplify: $i^{14}$ **Solutions** $i^{14}$ $=(i^2)^7 $ $=(-1)^7 $ $=-1$. **Question 4(iii)** Simplify: ${-i}^{19}$ **Solutions** \begin... *Solutions** $\sqrt{-1}b= bi$ ---- **Question 5(ii)** Write $\sqrt{-5}$ in term of $i$ **Solution... \sqrt{-1}\cdot \sqrt{5} =\sqrt{5}i$ **Question 5(iii)** Write $\sqrt{-\frac{16}{25}}$ in term of $i$

Exercise 1.1 (Solutions)

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closure property w.r.t. '$\times$'. **Question 1(ii)** Is the set $\{1\}$ has closure property w.r.t... closure property w.r.t. '$\times$' **Question 1(iii)** Is the set $\{0,-1\}$ has closure property w... roperty:** Commutative property w.r.t. '+'. ---- (ii) $(a+1)+ \frac{3}{4}= a+(1+\frac{3}{4})$ **Property:** Associative property w.r.t. '+'. ---- (iii) $(\sqrt{3}+\sqrt{5})+\sqrt{7}= \sqrt{3}(\sqrt{5