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Exercise 2.8 (Solutions)

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s: (i) Name the identity element if it exists? (ii) What is the inverse of 1? (iii) Is the set $G$, under the given operation a group? Abelian or non-... $. This show that $0$ is the identity element. (ii) Since $1+1=0$ (identity element) so the inverse of $1$ is $1$. (iii) It is clear from table that element of the give