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- Question 1, Exercise 5.1
- \end{align*} Hence remiander = 5. =====Question 1(ii)===== Find the remainder by using 'Remainder Theo
- Question 1, Review Exercise
- collapsed="true">%%(d)%%: $(x+1)(x-2)$</collapse> ii. Divide $9 y^{2}+9 y-10$ by $3 y-2$, then remaind