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- Question 7 and 8, Exercise 5.2
- \end{align} This gives: \begin{align*} f(x) &= \left(x - \frac{1}{2}\right)(2x^{2} - 14x + 20)\\ &=\left(x - \frac{1}{2}\right)(2x^{2} - 14x + 20) \\ &= \left(x - \frac{1}{2}\right)(2x^{2} - 10x - 4x + 20 )\\ &= \left(x - \frac{1}{2}\right)[2x(x - 5) - 4(x - 5) ]\\ &
- Question 4 & 5, Review Exercise
- begin{align*} f(y) &= 6y^{3} - y^{2} - 5y + 2\\ f\left(\frac{2}{3}\right) &= 6\left(\frac{2}{3}\right)^{3} - \left(\frac{2}{3}\right)^{2} - 5\left(\frac{2}{3}\right) + 2 \\ &= 6\left(\frac{8}{27}\right) - \left(\frac{4
- Question 2 & 3, Review Exercise
- rd, Islamabad, Pakistan. =====Question 2===== $\left(64 y^{3}-8\right) \div(4 y-2) \quad$ ** Solutio... 2} + 8y + 4 .\end{align*} =====Question 3===== $\left(125 y^{3}-8\right) \div(5 y-2)$ ** Solution. ** ... } \frac{(125 y^{3}-8)}{(5 y-2)} &= \frac{(5y - 2)\left(25y^{2} + 10y + 4\right)}{5y - 2} \\ & = 25y^{2} ... end{align*} ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:Re-
- Question 10, Exercise 5.1
- tion 10===== A rectangular room has a volume of $\left(x^{3}+11 x^{2}+34 x+24\right)$ cubic feet. The he... uare feet. GOOD ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5
- Question 6 & 7, Review Exercise
- of ' $k$ ' so that the remainder upon dividing $\left(x^{2}+8 x+k\right)$ by $(x-4)$ is zero. ** Solut... seem to solvable. ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:Re-
- Question 6, Review Exercise
- of ' $k$ ' so that the remainder upon dividing $\left(x^{2}+8 x+k\right)$ by $(x-4)$ is zero. ** Solution. ** ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:Re-
- Question 2 and 3, Exercise 5.1
- ctor of $p(x)$. GOOD ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5
- Question 4 and 5, Exercise 5.1
- \end{align*} ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5
- Question 6 and 7, Exercise 5.1
- P(x). GOOD ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5
- Question 8 and 9, Exercise 5.1
- -2)+3$$ GOOD ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5
- Question 3 and 4, Exercise 5.2
- nd{align*} ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5
- Question 5 and 6, Exercise 5.2
- \end{align*} ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5
- Question 2, Exercise 5.3
- sold. GOOD ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5
- Question 3, Exercise 5.3
- s by 3 units. GOOD ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5
- Question 4, Exercise 5.3
- 9 units. GOOD ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit05:ex5