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- Question 3, Exercise 9.1
- i}{2} x$. Then $$y=7 \cot \theta$$ Domain of $y=\left\{\theta: \theta\in \mathbb{R} \text{ and } \theta... es & x \neq 2n \end{align*} Hence domain of $y=\left\{x: x\in \mathbb{R} \text{ and } x \neq 2n, n\tex... a=\pi x$. Then $$y=4 \tan \theta$$ Domain of $y=\left\{\theta: \theta\in \mathbb{R} \text{ and } \theta... \frac{2n+1}{2} \end{align*} Hence domain of $y=\left\{x: x\in \mathbb{R} \text{ and } x \neq \frac{2n+
- Question 6, Exercise 9.1
- *} \cos (5 x+4) & = 6 \cos(5x+4+2\pi) \\ & = \cos\left(5\left(x+\frac{2\pi}{5}\right)+4\right) \end{align*} Hence period of $\cos (5 x+4)$ is $\dfrac{2\pi}{5}... sin(3x + 3) &= 7 \sin(3x + 3 + 2\pi) \\ &= 7 \sin\left(3\left(x + \frac{2\pi}{3}\right) + 3\right). \end{align*} Hence, the period of \( 7 \sin(3x + 3) \) is
- Question 2 and 3, Review Exercise
- qrt{2}+1}\cos \theta \quad \text{from (1)}\\ & = \left(1+ \frac{1}{\sqrt{2}+1}\right)\cos \theta \\ & = ... sqrt{2}}{\sqrt{2}+1} \cos \theta \\ & = \sqrt{2} \left(\frac{\sqrt{2}+1}{\sqrt{2}+1}\right) \cos \theta ... ** Solution. ** ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:Re-
- Question 1, Exercise 9.1
- {Maximum value (M)} & = a+|b|\\ & = \dfrac{2}{3}+\left|-\dfrac{1}{2} \right| \\ & = \dfrac{2}{3}+\dfrac{... {Minimum value (m)} & = a-|b|\\ & = \dfrac{2}{3}-\left|-\dfrac{1}{2} \right| \\ & = \dfrac{2}{3}-\dfrac{
- Question 2, Exercise 9.1
- m) = \dfrac{5}{17}$. ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:ex9
- Question 4(i-iv), Exercise 9.1
- n function is odd. ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:ex9
- Question 4(v-viii), Exercise 9.1
- en function is odd. ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:ex9
- Question 5(i-v), Exercise 9.1
- ** Solution. ** ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:ex9
- Question 5(vi-x), Exercise 9.1
- ** Solution. ** ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:ex9
- Question 7 & 8, Exercise 9.1
- ** Solution. ** ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:ex9
- Question 9, Exercise 9.1
- ** Solution. ** ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:ex9
- Question 10, Exercise 9.1
- ** Solution. ** ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:ex9
- Question 2 and 3,Review Exercise
- amabad, Pakistan. ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:Re-
- Question 4, Review Exercise
- amabad, Pakistan. ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:Re-
- Question 4, Review Exercise
- ** Solution. ** ====Go to ==== <text align="left"><btn type="primary">[[math-11-nbf:sol:unit09:Re-