Question 1 Review Exercise 6
Solutions of Question 1 of Review Exercise 6 of Unit 06: Permutation, Combination and Probablity. This is unit of A Textbook of Mathematics for Grade XI is published by Khyber Pakhtunkhwa Textbook Board (KPTB or KPTBB) Peshawar, Pakistan.
Chose the correct option. <panel>
i. In how many ways can we name the vertices of pentagon using any five of the letters $O, P, Q, R, S, T, U$ in any order?
- (a) $2520$
- (b) $9040$
- (c) $5140$
- (d) $4880$
<btn type=“link” collapse=“a1”>See Answer</btn>(a): $2520$
ii. How many two digits odd numbers can be formed form the digits $\{1,2,3,4,5,6,7\}$ if repeated digits are allowed?
- (a) $14$
- (b) $42$
- (c) $28$
- (d) $21$
<btn type=“link” collapse=“a2”>See Answer</btn>©: $28$
iii. How many six digits number can be formed from the digits $\{1,2,3,4,6,7,8\}$ without repetition if the digits $3$ and $7$ must together?
- (a) $120$
- (b) $180$
- (c) $144$
- (d) $96$
<btn type=“link” collapse=“a3”>See Answer</btn>(a): $120$
iv. Evaluate $\dfrac{(n+2) !(n-2) !}{(n+1) !(n-1) !}$
- (a) $(n-3)$
- (b) $(\dot{n}-1)$
- (c) $\dfrac{n+1}{n+2}$
- (d) $\dfrac{n+2}{n-1}$
<btn type=“link” collapse=“a4”>See Answer</btn>(d): $\dfrac{n+2}{n-1}$
v. In how many different ways can $5$ couples be seated around a circular table if the couple must not be separated?
- (a) $768$
- (b) $724$
- (c) $844$
- (d) $696$
<btn type=“link” collapse=“a5”>See Answer</btn>(a): $768)$
vi. A committee of 4 people will be selected from 8 girls and 12 boys in a class. How many different selections are possible if at least one boy must be selected?
- (a) $2865$
- (b) $3755$
- (c) $4225$
- (d) $4775$
<btn type=“link” collapse=“a6”>See Answer</btn>(d): $4775$
vii. The number of all possible matrices of order $3 \times 3$ with each entry 0 and 1 is:
- (a) $18$
- (b) $27$
- (c) $512$
- (d) $81$
<btn type=“link” collapse=“a7”>See Answer</btn>©: $512$
viii. How many diagonals can be drawn in plane figure of 8 sides?
- (a) $21$
- (b) $20$
- (c) $35$
- (d) $81$
<btn type=“link” collapse=“a7”>See Answer</btn>(b): $20$
ix. If $P(A)=\dfrac{1}{2}, P(B)=0$ then $P(A \mid B)$ is:
- (a) $0$
- (b) $\dfrac{1}{2}$
- (c) not defined
- (d) $1$
<btn type=“link” collapse=“a7”>See Answer</btn>©: not defined
x. If $A$ and $B$ are events such that $P(A / B)=P(B / A)$ then
- (a) $A \subset B$ but $A \neq B$
- (b) $A=B$
- (c) $A \cap B=\phi$
- (d) $P(A)-P(B)$
<btn type=“link” collapse=“a7”>See Answer</btn>(d): $A \cap B=\phi$
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