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Its about square root
6 Hits, Last modified: 5 months ago
*Definition:** Let $x$ be a non-negative number. Then a non-negative number $r$ is called square root o... d definition:** Let $x$ be a non-negative number. Then a number $r$ is called square root of $x$ iff $r^... must be equal. If we use the extended definition then it means we cannot consider to take square root o... answers. But if we consider the first definition then no doubt $\sqrt{4}=\sqrt{2^2}=\sqrt{(-2)^2}=2$.
Are the functions are same?
3 Hits, Last modified: 5 months ago
$A=\mathbb{R}$, $B=\mathbb{R}$ and $g(x)=x+1$,\\ then obviously Domain of $f=\mathbb{R}$. What we have... . If we write a real valued function $f(x)=x+3$, then the possible inputs (domain of $f$) is set of rea... function $\displaystyle g(x)=\frac{x^2-9}{x-3}$, then it doesn't give any output for $x=3$. Hence the p
Is it difficult to answer? 1−−−0.999…
3 Hits, Last modified: 5 months ago
For example, if we wish to round off $0.999...$, then we arrived, it cannot be 0.9 or 0.99 or 0.999 or ... Let we wish to rounding it off to three decimals. Then the 9 at third place become 10, something like, 0... e simple algebraic proof. Consider $x=0.999...$, then $10x=9.99...$. This gives us $10x=9+0.999...$, t