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- Question 5, Exercise 10.1
- asure $\alpha$ nor $\beta$ in the first Quadrant, then find: $\sin \left( \alpha +\beta \right)$. ====... asure $\alpha$ nor $\beta$ in the first Quadrant, then find: $\cos \left( \alpha +\beta \right)$. ====... asure $\alpha$ nor $\beta$ in the first Quadrant, then find: $\tan \left( \alpha +\beta \right)$. ====
- Question 2, Exercise 10.2
- minal ray of $\theta $ is in the second quadrant, then find $\sin 2\theta $. ====Solution==== Given: $\... minal ray of $\theta $ is in the second quadrant, then find $\cos 2\theta $. ====Solution==== Given: $\... minal ray of $\theta $ is in the second quadrant, then find $\tan 2\theta $. ====Solution==== Given: $\
- Question 3, Exercise 10.2
- rminal ray of $\theta$ is in the second quadrant, then find $\sin2\theta$. ====Solution==== Given: $\sin... rminal ray of $\theta$ is in the second quadrant, then find $\cos \dfrac{\theta }{2}$. ====Solution====
- Question 1, Review Exercise 10
- llapse> ii. If$\tan {{15}^{\circ }}=2-\sqrt{3}$, then the value of ${{\cot }^{2}}{{75}^{\circ }}$ is ... t)=\dfrac{1}{2}$, and $\tan \alpha =\dfrac{1}{3}$ then $\tan \beta =$ * (a) $\dfrac{1}{6}$ *
- Question 4 and 5, Exercise 10.2
- rminal ray of $\theta $ is in the third quadrant, then find $\sin \dfrac{\theta }{2}$. ====Solution====