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Exercise 2.6 (Solutions)

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i)(x+yi) = 4+i\\ 2(x+yi)-3i(x+yi) = 4+i\\ 2x+2yi-3xi-3yi^2 = 4+i\\ 2x+2yi-3yi-3y(-1) = 4+i\\ (2x+3y)+(... )+2i-1\\ 3(x+yi)-2i(x+yi) = 2x-4yi+2i-1\\ 3x+3yi-2xi-2yi^2 = 2x-1+(2-4y)i\\ 3x+(3y-2x)i-2y(-1) = 2x-1