Question 8(xix, xx, xxi & xxii) Exercise 8.2
Solutions of Question 8(xix, xx, xxi & xxii) of Exercise 8.2 of Unit 08: Fundamental of Trigonometry. This is unit of Model Textbook of Mathematics for Class XI published by National Book Foundation (NBF) as Federal Textbook Board, Islamabad, Pakistan.
Question 8(xix)
Verify the identity: $$\frac{\sin 2 \alpha}{\sin \alpha}-\frac{\cos 2 \alpha}{\cos \alpha}=\sec \alpha$$
Solution.
\begin{align*} LHS &= \dfrac{\sin 2 \alpha}{\sin \alpha}-\frac{\cos 2 \alpha}{\cos \alpha}\\ &= \dfrac{\sin 2 \alpha \cos\alpha - \cos 2 \alpha \sin \alpha}{\sin \alpha \cos\alpha}\\ &= \dfrac{\sin (2 \alpha - \alpha)}{\sin \alpha \cos\alpha}\\ &= \dfrac{\sin (\alpha)}{\sin \alpha \cos\alpha}\\ &= \dfrac{1}{\cos\alpha}\\ & = \sec\alpha \\ &=RHS \end{align*} GOOD
Question 8(xx)
Verify the identity: $2 \sin ^{2} \frac{\beta}{2}+\cos \beta=1$
Solution.
\begin{align*} LHS & = 2 \sin ^{2} \frac{\beta}{2}+\cos \beta \\ & = 2 \sin^2 \frac{\beta}{2}+\cos^2 \frac{\beta}{2} - \sin^2 \frac{\beta}{2}\\ & = \sin^2 \frac{\beta}{2}+\cos^2 \frac{\beta}{2} \\ & = 1 \\ & = RHS \end{align*} GOOD
Question 8(xxi)
Verify the identity: $$2 \cos y \sec 2 y=\frac{1}{\cos y-\sin y}+\frac{1}{\cos y+\sin y}$$
Solution.
\begin{align*} RHS & = \frac{1}{\cos y-\sin y}+\frac{1}{\cos y+\sin y} \\ & = \frac{\cos y+\sin y+\cos y-\sin y}{(\cos y-\sin y)(\cos y+\sin y)} \\ & = \frac{2\cos y}{\cos^2 y-\sin^2 y} \\ & = \frac{2\cos y}{\cos 2y} \\ & = 2\cos y \sec 2y \\ & = LHS \end{align*} GOOD
Question 8(xxii)
Verify the identity: $$2 \sin y \sec 2 y=\frac{1}{\cos y-\sin y}-\frac{1}{\cos y+\sin y}$$
Solution.
\begin{align*} RHS & = \frac{1}{\cos y-\sin y}-\frac{1}{\cos y+\sin y} \\ & = \frac{\cos y+\sin y-\cos y+\sin y}{(\cos y-\sin y)(\cos y+\sin y)} \\ & = \frac{2\sin y}{\cos^2 y-\sin^2 y} \\ & = \frac{2\sin y}{\cos 2y} \\ & = 2\sin y \sec 2y \\ & = LHS \end{align*} GOOD
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<btn type=“primary”>< 8(xvi, xvii & xviii) </btn>